Answer:
6.56x10⁻³ mol
Explanation:
First we calculate how many HCl moles are there in 50.0 mL of a 0.1800 M solution:
0.1800 M * 50.0 mL = 9.00 mmol HClThen we need to calculate how many HCl moles were in excess, that number is the same as the number of NaOH moles they reacted with:
0.0980 M * 24.90 mL = 2.44 mmol NaOH = 2.44 mmol HClFinally we calculate the difference between the original number of HCl moles and the number remaining after the reaction with XnCO₃:
9.00 mmol - 2.44 mmol = 6.56 mmol6.56 mmol / 1000 = 6.56x10⁻³ molCAN YOU HELP ME PLZ AND THANKS
Answer:
Question 7 the answer is B
Explanation:
In every nuclear reaction there is always formation of products either by nuclei bombardment or by the elements breaking into two elements of the same mass
Question 8
The answer is A
Nuclear reactions release a huge amount of energy than chemical reactions
Using dimensional analysis convert 238.0 cm3 to L
Answer:
= 0.238 L
Explanation:
From the given information:
To convert cm³ to L(liter), we utilize the advent of a unit fraction that comprises a liter in the upper part of the fraction(numerator) and a cubic centimeter in the lower part of the fraction(denominator)
Recall that:
1000 cm³ = 1 liter
∴
238.0 cm³ = [tex]\dfrac{238.0 \ cm^3}{1} \times \dfrac{1 \ L}{1000 \ cm^3}[/tex]
= 0.238 L
3. 78 mL of 2.5 M phosphoric acid is neutralized with 500 mL of potassium hydroxide. What is the
concentration of the base?
A pure copper cube has an edge length of 1.76 cm. How many copper atoms does it contain? (volume of a cube = (edge length)^3; density of copper = 8.96 g/cm^3 )
The Fischer esterification mechanism is examined in this question. The overall reaction is: Benzoic acid, C H 3 O H and H C l react to form a methyl ester, H 2 O and H C l. Benzoic acid is a carboxylic acid bonded to a benzene ring. Identify the results or mechanism of each step.
Answer:
See explanation and image attached
Explanation:
Fischer esterification is a type of reaction used to convert carboxylic acids to ester in the presence of excess alcohol and a strong acid which acts as a catalyst. Another final product formed in the reaction is water.
The mechanism for the fischer esterification of Benzoic acid and C H 3 O H in the presence of HCl as the catalyst is shown in the image attached to this answer.
The final products of the reaction are methyl benzoate, water and H^+ as shown in the image attached.
The methyl ester, water, and the acid catalyst (HCl) are byproducts of the Fischer esterification process, which involves protonation, nucleophilic attack, elimination, and deprotonation processes.
Carbonyl oxygen protonation: The carbonyl oxygen of the carboxylic acid (benzoic acid) is protonated by the acid catalyst (HCl) in the first step. The protonation of the carbonyl carbon increases its electrophilicity and promotes the alcohol's nucleophilic assault. Attack by the alcohol's nucleophilic oxygen (methanol, CH3OH) on the protonated carboxylic acid's carbonyl carbon results in the formation of a tetrahedral intermediate. The acid catalyst also helps with this phase. Elimination of water: In the following step, the water molecule must be removed from the tetrahedral intermediate. The hydroxyl group (-OH) from the carboxylic acid and a hydrogen from the hydroxyl group of the alcohol are removed to create this water molecule. Deprotonation: A deprotonation occurs after the removal of water.
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In what kind of orbitals do the lone-pair electrons on the singly bonded oxygen of methyl acetate reside, and are they in the same plane as the group
Answer:
Both lone pairs reside in sp3 orbitals; they are co-planar with the CH3 group.
Explanation:
In the compound, methyl acetate, the lone-pair of electrons on the singly bonded oxygen atom is accommodated in sp3 hybridized orbitals.
If we look at the compound, we will notice the both lone pair of electrons on oxygen are accommodated in sp3 orbitals which are co-planar with the CH3 group in the molecule.
Determain the number of moles in 2.24l of ch4 at stp
Answer:
0.1 mole of CH₄
Explanation:
From the question given above, the following data were obtained:
Volume of CH₄ = 2.24 L
Number of mole of CH₄ =?
The number of mole of CH₄ can be obtained as follow:
Recall:
1 mole of a gas occupy 22.4 L at stp. This implies that 1 mole of CH₄ occupies 22.4 L at stp.
22.4 L = 1 mole of CH₄
Therefore,
2.24 L = 2.24 × 1 mole of CH₄ / 22.4
2.24 L = 0.1 mole of CH₄.
3 enzimas presentes en nuestro organismo e indique en que procesos actúan
Answer:
ATP asa, Helicasa, Proteasa, ARN polimerasa
Explanation:
Las enzimas son un tipo de biomoleculas que se corresponden con las proteinas.
Al momento de referirse a ellas, se utiliza la terminación asa.
ATPasa → Sintetizando ATP para el funcionamiento celular
Helicasa → Abre las hebras de ADN permitiendo el paso de la horquilla para el proceso de replicación de ADN.
Proteasas → Enzimas que degradan proteinas mal plegadas, rompen los enlaces peptídicos.
ARN polimerasa → Sintesis de ARN mensajero a partir de ADN en el proceso de la Transcripción. Se la puede conocer a veces, como primasa.
predict the major and minor products of the reaction. name the products using systematic names. ch3ch=ch2+h2o-->h+
Answer:
major will be propan-2-ol
minor will be propan-1-ol
Select all the true statements.
a. Ionic bonding is more prevalent for the higher oxidation states and covalent bonding is more prevalent for the lower states.
b. The highest oxidation state of elements in Groups 3A through 7B is +3.
c. In the transition series, atomic size across a period decreases at first but then remains relatively constant.
d. The transition elements in a period show a steady increase in electronegativity.
Answer:
In the transition series, atomic size across a period decreases at first but then remains relatively constant.
The transition elements in a period show a steady increase in electronegativity.
Explanation:
In considering the transition series, we observe that atomic sizes of the elements decreases first and subsequently remain constant. The reason for the initial decrease in atomic size is the increase in nuclear charge across the period. After the first few elements in the period, the atomic size remains relatively constant due to shielding effect of the inner d electrons which opposes the increase in effective nuclear charge.
It is also observed that electro negativity increases smoothly across the period for the transition series. Consequently, the transition series become less electro positive across the period.
Sodium hydrogen carbonate, also called baking soda, is an active ingredient in some antacids used for the relief of indigestion. Determine the percent of carbon in sodium hydrogen carbonate.
Answer:
14.30%
Explanation:
Step 1: Given data
Chemical formula of sodium hydrogen carbonate: NaHCO₃
Step 2: Determine the mass of C in 1 mole of NaHCO₃
The is 1 atom of C in 1 molecule of NaHCO₃ and the molar mass of C is 12.01 g/mol. Then, there are 12.01 g of C in 1 mole of NaHCO₃.
Step 3: Determine the mnolar mass of NaHCO₃
M(NaHCO₃) = 1 × M(Na) + 1 × M(H) + 1 × M(C) + 3 × M(O)
M(NaHCO₃) = 1 × 22.98 g/mol + 1 × 1.01 g/mol + 1 × 12.01 g/mol + 3 × 16.00 g/mol = 84.00 g/mol
Step 4: Determine the mass percent of C in NaHCO₃
We will use the following expression.
%C = mC / mNaHCO₃ × 100%
%C = 12.01 g / 84.00 g × 100% = 14.30%
The acid-base reaction between HCl and NaOH produces a solution with a pH of 7 at the equivalence point (NaCl H2O). Why does an acid-base indicator that changes color at pH 5 or 9 work just as well for this reaction as one that changes color at pH 7
Answer:
Answer is in the explanation.
Explanation:
Before the equivalence point, the pH of the solution of HCl that is titrated with NaOH has a pH <<< 7. When you are adding more NaOH nearing, thus, to the equivalence point the change in pH occurs quickly, and, with 1 drop of excess of NaOH after equivalence, the pH of the solution change to a pH >>> 7
That means the volume added at pH 5 or pH 9 is, almost, the same doing the indicator work just as well as an indicator with change color at pH 7
Some glucose produced by gluconeogenesis is stored in the body as glycogen. Order the steps of glycogen synthesis.
a. Pyrophosphatase converts PPi and water into two Pi
b. Glycogen synthase adds a glucose unit from UDP-glucose to glycogen, producing a larger glycogen molecule and UDP
c. Glvcogen synthase removes a glucose unit from a glycogen molecule producing a smaller glycogen molecule and IJDP
d. ADP-glucose pyrophosphorylase catalyzes the reaction of glucose-I -phosphate and ATP to ADP-glucose and PPi
e. UDP-glucose pyrophosphorylase catalyzes the reaction of glucose-I-phosphate and UTP to UDP-glucose and PPi
Answer:
e. UDP-glucose pyrophosphorylase catalyzes the reaction of glucose-I-phosphate and UTP to UDP-glucose and PPi
a. Pyrophosphatase converts PPi and water into two Pi
b. Glycogen synthase adds a glucose unit from UDP-glucose to glycogen, producing a larger glycogen molecule and UDP
Explanation:
Glycogen synthesis or glycogenesis is the process of synthesis of glycogen molecules from glucose molecules in living organisms. Glycogen is a polysaccharide storage form of glucose and helps to store excess glucose in the body form use when required by the body.
The synthesis of glycogen involves sugar nucleotides. Sugar nucleotides are compounds in which a sugar molecule is attached to a nucleotide through phosphate ester bond, resulting in the activation of the sugar molecule. The sugar nucleotides then are used as substrates for the polymerization of the monosaccharide sugars into disaccharides, oligosaccharides and polysaccharides.
In the synthesis of glycogen, glucose-6-phosphate from phosphorylation of free glucose by hexokinase is first isomerized to glucose-1-phosphate by phosphoglucomutase.
Glucose-1-phosphate is then converted to UDP-glucose by its reaction with UTP catalyse by UDP-glucose pyrophosphorylase. The reaction is favoured by the rapid hydrolysis of PPi produced to two molecules of inorganic phosphate by the enzyme pyrophosphatase.
Glycogen synthase then adds a glucose unit from UDP-glucose to a growing chain of glycogen, producing a larger glycogen molecule and free UDP.
What is the molar mass of H2SO4?
(Molar mass of H = 1.0079 g/mol; S = 32.065 g/mol; O = 15.999 g/mol)
Answer: 98.08 g/mol
Explanation:
i just took this test and got it right
Answer:
A
Explanation:
What volume of water must be added to 10.5 mL of a pH 2.0 solution of HNO3 in order to change the pH to 4.0 g
Answer:
[tex]V'=1040ml[/tex]
Explanation:
From the question we are told that:
Initial Volume [tex]V_1=10.5mL[/tex]
Initial Aciditity of [tex]HN0_3 pH_1=2.0g[/tex]
Finial Aciditity of [tex]HN0_3 pH_2=4.0g[/tex]
Generally the equation for Acidity &Volume Relationship is mathematically given by
[tex]N_1V_1=N_2V_2[/tex]
Therefore
[tex]V_2=\frac{N_1V_2}{N_2}[/tex]
[tex]V_2=\frac{10^{-2}*10.5}{10^{-4}}V_2=1050ml[/tex]
Therefore
Change in Water volume is
[tex]V'=V_2-V_1[/tex]
[tex]V'=1050ml-10ml[/tex]
[tex]V'=1040ml[/tex]
STRONGEST METALL ON EARTH
Answer:
tungstun
Explanation:
Answer:
tungsten
Explanation:
strongest out of any natural metal (142,000 psi).
When does a redox reaction produce electricity?
A. Only when an electrical device is attached
B. Whenever electrons are transferred between atoms
C. When electrons are transfered, and a pathway for electrons is provided
D. Whenever a pathway for electrons is provided
help i’ll give u points
Answer:
60ug
Explanation:
If it has experienced two half lives, that means it has been halved twice. in that case, to undo it, just multiply it by two twice. 0.15ug * 2 = 0.30ug. 0.30ug * 2 = 0.60ug. Hope this helps.
A monoprotic weak acid when dissolved in water is 0.66% dissociated and produces a solution with a pH of 3.04. Calculate the Ka of the acid. g
Answer:
Ka = 6.02x10⁻⁶
Explanation:
The equilibrium that takes place is:
HA ⇄ H⁺ + A⁻Ka = [H⁺][A⁻]/[HA]We calculate [H⁺] from the pH:
pH = -log[H⁺][H⁺] = [tex]10^{-pH}[/tex][H⁺] = 9.12x10⁻⁴ MKeep in mind that [H⁺]=[A⁻].
As for [HA], we know the acid is 0.66% dissociated, in other words:
[HA] * 0.66/100 = [H⁺]We calculate [HA]:
[HA] = 0.138 MFinally we calculate the Ka:
Ka = [tex]\frac{[9.12x10^{-4}]*[9.12x10^{-4}]}{[0.138]}[/tex] = 6.02x10⁻⁶B. Directions: Identify the factors affecting the different seasons in the Philippines.
1. Areas with less rainfall, has a pronounced dry
season. When it always rain, that place has wet season most of the year.
2. The higher the particular place, the cooler its
temperature.
3. Climate near in coastal areas is cooler because
water does not absorb heat as fast as land area.
4. . When large amount of warm air cool, if gives off
lots of rain over the land
5. Philippines lies near the equator, has warm climate
during certain times of the year.
Answer:
The correct answer is -
1. Latitude
2. Altitude
3. Bodies of water
4. Wind system
5. Amount of rainfall
Explanation:
Lattitude is the angle from the earth's equator towards the north or south to the poles. This is one of the important factors that lead to different seasons and define the temperature of the area.
Altitude is the elevation from the sea that also helps in affecting the seasons as the higher the altitude cooler the temperature. Water bodies like the sea affect the wind and climate as they are not able to absorb heat faster in comparison to the land.
Wind also affects the seasons and climate of the area as a large amount of warm air cools, it gives off lots of rain over the land. Precipitation or rainfall determines and influences the climate.
How does the neutron number in each compare
Answer:
Neutrons are all identical to each other, just as protons are. Atoms of a particular element must have the same number of protons but can have different numbers of neutrons.
Explanation:
Since the vast majority of an atom's mass is found its protons and neutrons, subtracting the number of protons (i.e. the atomic number) from the atomic mass will give you the calculated number of neutrons in the atom. In our example, this is: 14 (atomic mass) – 6 (number of protons) = 8 (number of neutrons).
g An ionic bond involves ____ a. molecules that gain or lose an atom to develop a bonding charge b. molecules that bond together through a weak force c. atoms that either lose or gain an electron in order to bond d. atoms that share an electron to tightly bond
Answer:
a. molecules that gain or lose an atom to develop a bonding charge
Explanation:
PLS HELP THESE ARE RHE ONLY QUESTIONS I HAVE LEFT DUE SOON
Explanation:
Magnesium reacts with dilute hydrochloric acid in a conical flask which is connected to an inverted measuring cylinder in a trough of water. The volume of hydrogen gas produced is measured over a few minutes, and the results are used to plot a graph
This is intended as a class practical. It is best if the students work in pairs because setting up and starting the experiment requires more than one pair of hands. One student can add the magnesium ribbon to the acid and stopper the flask, while the other starts the stopclock. During the experiment, one student can take the readings while the other records them. The experiment itself takes only a few minutes. But allow at least 30 minutes to give students time to set up, take readings and draw graph.
please mark as brainliest
1. An ion has a net charge of - 3, and 12 electrons, what is its atomic number? What element has that atomic number?
2. An ion of Celsius has a net charge of -5, how many electrons does it have?
3. Some atom has an atomic number of 46, how many electrons does it have if it has a net charge of +2?
4. How many neutrons are in an atom of Helium, and what is its mass number?
5. There are 3 neutrons in an isotope of Helium, what is its mass number?
6. n isotope has 83 neutrons and a mass number of 167, what is its atomic number? What element is defined by that atomic number?
7. What element has 54 neutrons and a mass number of 112?
8. What element has 10 electrons, a net charge of -2?
Answer:
19 because it gained 3 electron so 12-3=9 beryllium
2
3 is 46-2=44
4 is 2
5 is 5
6 84 polonium
7
8 oxygen
Explanation:
plz let me know if they are right or wrong:)
When aqueous solutions of AgNO3 and MgCl2 are mixed, a precipitate forms. What is the correct formula for the precipitate
Answer:
AgCl
Explanation:
The reaction that takes place is:
2AgNO₃ (aq) + MgCl₂ (aq) → Mg(NO₃) (aq) + 2AgCl (s)The precipitate (meaning a solid substance) formed is silver chloride, AgCl.
All salts formed with silver and a halogen (F, Cl, Br, I) are insoluble in water, meaning that when working with aqueous solutions they will be precipitates.
Which additional product balances the reaction h2so4+2naoh>na2so4
Answer:
H 4so8 is the answer of balance the reaction
what will happen to the initial rate of the reaction if the concentration of iron(III) chloride is tripled
Answer:
Concentration and reaction rate is directly proportional
Explanation:
Basically, concentration is directly proportional to the concentration, so the higher the concentration, the higher the reaction rate.
Once the concentration is increased, more chemical will be added hence the reaction rate will increase
Which of the following is most likely to make a -3 ion?
Bі
P
Se
Be
All
The element whose atom may likely make a -3 ion is P.
Elements in the periodic table are classified into groups and periods. The elements in the same group have similar physical and chemical properties.
Phosphorus (P) is a member of group 15 in the periodic table. The most common ion formed by the members of this group is the -3 ion.
It is formed by accepting three electrons to complete their octet since they have five electrons on their outermost shell.
Hence P is most likely to form a -3 ion.
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What is the pH of a 0.086 M HCl solution?
Answer: pH = 1.066
Explanation: HCl is strong acid and it protolyzes totally:
HCl + H2O ⇒ H3O+ + Cl-
Concentrations are same: [H3O+] = c(HCl)
pH = - log[H3O+] = - log(0.086) = 1.0655
Calculate the number of cations and anions in each of the following compounds. Enter your answers in scientific notation. (a) 6.42 g of KBr:
Answer: The number of cations are [tex]3.24 \times 10^{22}[/tex] and number of anions are [tex]3.24 \times 10^{22}[/tex] in 6.42 g of KBr.
Explanation:
The molar mass of KBr is (39.10 + 79.90) g/mol = 119.00 g/mol
Now, the dissociation equation for KBr is as follows.
[tex]KBr \rightarrow K^{+} + Br^{-}[/tex]
This means that 1 mole of KBr is forming 1 mole of [tex]K^{+}[/tex] (cation) and 1 mole of [tex]Br^{-}[/tex] (anion).
According to mole concept, 1 mole of every substance contains [tex]6.022 \times 10^{23}[/tex] atoms. Hence, number of cations present in 6.42 g KBr is calculated as follows.
[tex]No. of cations = Moles \times 6.022 \times 10^{23}\\= \frac{mass}{molar mass} \times 6.022 \times 10^{23}\\= \frac{6.42 g}{119.00 g/mol} \times 6.022 \times 10^{23}\\= 3.24 \times 10^{22}[/tex]
As according to the equation, there are equal number of moles of both cation and anions.
This means that the number of anions are also [tex]3.24 \times 10^{22}[/tex].
Thus, we can conclude that the number of cations are [tex]3.24 \times 10^{22}[/tex] and number of anions are [tex]3.24 \times 10^{22}[/tex] in 6.42 g of KBr.
The number of cations and anions present in potassium bromide is 3.24 × 10²².
How we calculate atoms from moles?In one mole of any substance 6.022 × 10²³ atoms of that substance is present and this is known as Avogadro's number.
KBr is a strong electrolyte means it fully dissociates into their constitute ions. So, the number of moles of produced ions is equal to the moles of KBr and dissociation is represented as:
KBr → K⁺ + Br⁻
From this it is clear that 1 mole of cation and 1 mole of anion is produced from 1 mole of KBr. Moles of KBr will be calculated as:
n = W/M, where
W = given mass = 6.42g
M = molar mass = 119
n = 6.42 / 119 = 0.053 moles
No. of cations and anions present in 0.053 moles = 0.053 × 6.022 × 10²³ = 3.24 × 10²².
Hence, 3.24 × 10²² is the no. of cations and anions.
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