Answer:
no
Explanation:
A solution of carbonic acid is at equilibrium. How would the system change is more carbonic acid was added to the solution
Answer:
The equilibrium position shifts to the right, in accordance to the constraint principle
At a certain temperature, 0.700 mol SO3 is placed in a 3.50 L container. 2SO3(g)↽−−⇀2SO2(g)+O2(g) At equilibrium, 0.180 mol O2 is present. Calculate c.
Answer: The value of [tex]K_c[/tex] for the given chemical equation is 0.0457.
Explanation:
Given values:
Initial moles of [tex]SO_3[/tex] = 0.700 moles
Volume of conatiner = 3.50 L
The given chemical equation follows:
[tex]2SO_3(g)\rightleftharpoons 2SO_2(g)+O_2(g)[/tex]
I: 0.700
C: -2x +2x x
E: 0.700-2x 2x x
Equilibrium moles of [tex]O_2[/tex] = x = 0.180 moles
Equilibrium moles of [tex]SO_2[/tex] = 2x = [tex](2\times 0.180)=0.360moles[/tex]
Equilibrium moles of [tex]SO_3[/tex] = 0.700 - 2x = [tex]0.700-(2\times 0.180)=0.340moles[/tex]
Molarity is calculated by using the equation:
[tex]Molarity=\frac{Moles}{Volume}[/tex]
So,
[tex][SO_3]_{eq}=\frac{0.340}{3.50}=0.0971M[/tex]
[tex][SO_2]_{eq}=\frac{0.360}{3.50}=0.103M[/tex]
[tex][O_2]_{eq}=\frac{0.180}{3.50}=0.0514M[/tex]
The expression of [tex]K_c[/tex] for above equation follows:
[tex]K_c=\frac{[SO_2]^2[O_2]}{[SO_3]^2}[/tex]
Plugging values in above expression:
[tex]K_c=\frac{(0.0971)^2\times 0.0514}{(0.103)^2}\\\\K_c=0.0457[/tex]
Hence, the value of [tex]K_c[/tex] for the given chemical equation is 0.0457.
In what kind of orbitals do the lone-pair electrons on the singly bonded oxygen of methyl acetate reside, and are they in the same plane as the group
Answer:
Both lone pairs reside in sp3 orbitals; they are co-planar with the CH3 group.
Explanation:
In the compound, methyl acetate, the lone-pair of electrons on the singly bonded oxygen atom is accommodated in sp3 hybridized orbitals.
If we look at the compound, we will notice the both lone pair of electrons on oxygen are accommodated in sp3 orbitals which are co-planar with the CH3 group in the molecule.
A metal forms the fluoride MF3. Electrolysis of the molten fluoride by a current of 3.86 A for 16.2 minutes deposits 1.25 g of the metal. Calculate the molar mass of the metal.
Answer: The molar mass of the metal is 96.45 g/mol
Explanation:
The fluoride of the metal formed is [tex]MF_3[/tex]
The oxidation half-reaction follows:
[tex]M\rightarrow M^{3+}+3e^-[/tex]
Calculating the theoretical mass deposited by using Faraday's law, which is:
[tex]m=\frac{M\times I\times t(s)}{n\times F}[/tex] ......(1)
where,
m = actual mass deposited = 1.25 g
M = molar mass of metal = ?
I = average current = 3.86 A
t = time period in seconds = 16.2 min = 972 s (Conversion factor: 1 min = 60 sec)
n = number of electrons exchanged = [tex]3mol^{-1}[/tex]
F = Faraday's constant = 96500 C
Putting values in equation 1, we get:
[tex]1.25g=\frac{M\times 3.86A\times 972s}{3mol^{-1}\times 96500 C}\\\\M=\frac{1.25g\times 3mol^{-1}\times 96500 C}{3.86A\times 972s}\\\\M=96.45g/mol[/tex]
Hence, the molar mass of the metal is 96.45 g/mol
The molar mass of metal present in MF₃ is calculated by using faraday's law and is equal to 96.45 g/mole.
How we calculate the molar mass?Molar mass of the metal will be calculated by using the Faraday's law as:
m = (M × I × t(s)) / n × F.
Chemical reaction for the given metal will be represented as:
M → M³⁺ + 3e⁻
And according to the Faraday's law given entities are:
m = given deposited mass = 1.25 g
I = average current = 3.86 A
t = time period in seconds = 16.2 min = 972 s
n = number of electrons exchanged = 3
F = Faraday's constant = 96500 C
M = molar mass of metal = to find?
Putting all these values in the above equation and calculate for M as:
M = (1.25)(3)(96500) / (3.86)(972) = 96.45 g/mole
Hence, the molar mass of metal is 96.45 g/mole.
To know more about Faraday's law, visit the below link:
https://brainly.com/question/1640558
Use the following balanced equation to answer the questions below.
Answer:
A. 4.5 mol Mg(OH)₂
B. 6 mol NaOH
Explanation:
Let's consider the following balanced equation.
Mg(NO₃)₂ + 2 NaOH ⇒ Mg(OH)₂ + 2 NaNO₃
PART A
The molar ratio of NaOH to Mg(OH)₂ is 2:1. The moles of Mg(OH)₂ produced from 9 moles of NaOH are:
9 mol NaOH × 1 mol Mg(OH)₂/2 mol NaOH = 4.5 mol Mg(OH)₂
PART B
The molar ratio of NaOH to NaNO₃ is 2:2. The moles of NaOH needed to produce 6 moles of NaNO₃ are:
6 mol NaNO₃ × 2 mol NaOH/2 mol NaNO₃ = 6 mol NaOH
Given the following: 30 grams of H3PO4, find the number of moles
Answer:
Number of mole of H₃PO₄ = 0.306 mole
Explanation:
From the question given above, the following data were obtained:
Mass of H₃PO₄ = 30 g
Number of mole of H₃PO₄ =?
Next, we shall determine the molar mass of H₃PO₄. This can be obtained as follow:
Molar mass of H₃PO₄ = (3×1) + 31 + (4×16)
= 3 + 31 + 64
= 98 g/mol
Finally, we shall determine the number of mole in 30 g of H₃PO₄ as follow:
Mass of H₃PO₄ = 30 g
Molar mass of H₃PO₄ = 98
Number of mole of H₃PO₄ =?
Mole = mass / molar mass
Number of mole of H₃PO₄ = 30 / 98
Number of mole of H₃PO₄ = 0.306 mole
Is [Ni(CO)4] considered as coordination compounds?
If A Reaction Takes 10s To Go To Completion At 0°C, How Long Will It Take To Go At 100°C?
Answer:
1,000s
Explanation:
i just multiply it
If a reaction takes 10s to go to completion at 0°C,then 1000s will It take to go at 100°C.
What is reaction ?A chemical reaction is a procedure that causes one group of chemical components to change chemically into another.
Combination, decomposition, single-replacement, double-replacement, and combustion are the five fundamental types of chemical reactions. You can classify a reaction into one of these groups by looking at the reactants and products. Several categories will apply to some reactions.
When atoms establish or break chemical bonds, chemical processes take place. Reactants are the substances that begin a chemical reaction, while products are the compounds that are created as a result of the reaction.
Thus,If a reaction takes 10s to go to completion at 0°C,then 1000s will It take to go at 100°C.
To learn more about reaction, follow the link;
https://brainly.com/question/3664113
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paano pakalmahin ang leon
15 points po
Answer:
lo siento señor, yo no hablo taka taka
Explanation:
5 puntos gratis pa
Determain the number of moles in 2.24l of ch4 at stp
Answer:
0.1 mole of CH₄
Explanation:
From the question given above, the following data were obtained:
Volume of CH₄ = 2.24 L
Number of mole of CH₄ =?
The number of mole of CH₄ can be obtained as follow:
Recall:
1 mole of a gas occupy 22.4 L at stp. This implies that 1 mole of CH₄ occupies 22.4 L at stp.
22.4 L = 1 mole of CH₄
Therefore,
2.24 L = 2.24 × 1 mole of CH₄ / 22.4
2.24 L = 0.1 mole of CH₄.
HELP WITH QUESTION 3,4 and 5 PLEASE
Answer:
I have no idea never get this in class before.
Đốt cháy hoàn toàn 0,06 mol hỗn hợp X gồm hai amin no, đơn chức, mạch hở và một hiđrocacbon cần
vừa đủ 0,18 mol O2, thu được hỗn hợp Y gồm H2O, 0,11 mol CO2 và 0,01 mol N2. Mặt khác, cho 9,4
gam X tác dụng với dung dịch HCl dư, thu được m gam muối amoni. Giá trị của m là
A. 8,25. B. 7,45. C. 9,65. D. 8,95.
bạn nào việt giúp mình với
3 enzimas presentes en nuestro organismo e indique en que procesos actúan
Answer:
ATP asa, Helicasa, Proteasa, ARN polimerasa
Explanation:
Las enzimas son un tipo de biomoleculas que se corresponden con las proteinas.
Al momento de referirse a ellas, se utiliza la terminación asa.
ATPasa → Sintetizando ATP para el funcionamiento celular
Helicasa → Abre las hebras de ADN permitiendo el paso de la horquilla para el proceso de replicación de ADN.
Proteasas → Enzimas que degradan proteinas mal plegadas, rompen los enlaces peptídicos.
ARN polimerasa → Sintesis de ARN mensajero a partir de ADN en el proceso de la Transcripción. Se la puede conocer a veces, como primasa.
Which of the metals would reduce an iron ion
F
Fe
Cr
Cu
Ag
Sn
Answer:
Cu
Explanation:
Copper since it is more reactive than Iron. Hence, it can easily displace ions in an iron based compound.
Please help
Calculate the sodium ion (Na+) concentration for a 0.812 M Na3PO4 solution.
[Na+]=____M
Explanation:
Correct option is
B
0.750 M
Na3PO4 dissociates as:
Na3PO4⇌3Na++PO43−
∴ conc. of Na+ would be =3×0.250=
hope help
PLS HELP ME WITH THESE QUESTIONS ITS DUE TOMORROW I WILL MARK U AS BRAINLIEST
Answer:
See Explanation
Explanation:
1 mole of Cl2 gas occupies 22.4 L
x moles of Cl2 gas occupies 5.24 L
x= 1 × 5.24/22.4
x= 0.23 moles of Cl2
According to the kinetic theory of gases, the particles of a gas are in constant random motion and collide with each other and the walls of the container. Collision between gas particles are perfectly elastic.
Hence the statement that particles must not be able to move in any fixed or open container is false according to the kinetic theory of gases.
predict the major and minor products of the reaction. name the products using systematic names. ch3ch=ch2+h2o-->h+
Answer:
major will be propan-2-ol
minor will be propan-1-ol
Select all the true statements.
a. Ionic bonding is more prevalent for the higher oxidation states and covalent bonding is more prevalent for the lower states.
b. The highest oxidation state of elements in Groups 3A through 7B is +3.
c. In the transition series, atomic size across a period decreases at first but then remains relatively constant.
d. The transition elements in a period show a steady increase in electronegativity.
Answer:
In the transition series, atomic size across a period decreases at first but then remains relatively constant.
The transition elements in a period show a steady increase in electronegativity.
Explanation:
In considering the transition series, we observe that atomic sizes of the elements decreases first and subsequently remain constant. The reason for the initial decrease in atomic size is the increase in nuclear charge across the period. After the first few elements in the period, the atomic size remains relatively constant due to shielding effect of the inner d electrons which opposes the increase in effective nuclear charge.
It is also observed that electro negativity increases smoothly across the period for the transition series. Consequently, the transition series become less electro positive across the period.
2. A student was asked to make up a 10% w/w solution of sodium carbonate. Calculate the amount of solute and solvent required to prepare that solution?
please explain step by step
Answer:
The amount of the solute and solvent can be calculated by the molality. The equation for the molality is as following:
Molality= (mass of solute*1000)/(molar mass*mass of solvent)
it is given that, 10% of Na2CO3 is made,
It means 100gram solution contains 10gram Na2CO3
So, the Mass of solute = 10 gram
then,
Mass of solvent= 100–10 = 90 gram
And, the molar mass of the Na2CO3 = 106 gram
from, now with the help of formula, we can calculate the amount of solute and solvent.
Sodium hydrogen carbonate, also called baking soda, is an active ingredient in some antacids used for the relief of indigestion. Determine the percent of carbon in sodium hydrogen carbonate.
Answer:
14.30%
Explanation:
Step 1: Given data
Chemical formula of sodium hydrogen carbonate: NaHCO₃
Step 2: Determine the mass of C in 1 mole of NaHCO₃
The is 1 atom of C in 1 molecule of NaHCO₃ and the molar mass of C is 12.01 g/mol. Then, there are 12.01 g of C in 1 mole of NaHCO₃.
Step 3: Determine the mnolar mass of NaHCO₃
M(NaHCO₃) = 1 × M(Na) + 1 × M(H) + 1 × M(C) + 3 × M(O)
M(NaHCO₃) = 1 × 22.98 g/mol + 1 × 1.01 g/mol + 1 × 12.01 g/mol + 3 × 16.00 g/mol = 84.00 g/mol
Step 4: Determine the mass percent of C in NaHCO₃
We will use the following expression.
%C = mC / mNaHCO₃ × 100%
%C = 12.01 g / 84.00 g × 100% = 14.30%
How to convert chloroform to chloretone
Consider the statement below "When nitrogen is liquified, heat is released" true or false?
Answer:
false
Explanation:
1.00 mL of 12.0 M HCl is added to 1.00 L of a buffer that contains 0.110 M HNO2 and 0.170 M NaNO2. How many moles of HNO2 and NaNO2 remain in solution after addition of the HCl
Answer:
Moles of NaNO2 = 0.158
Moles of HNO2 final = 0.098
Explanation:
Given
Moles of HCl = 12
Moles of HNO2 = 0.11
Moles of NaNO2 = 0.170
HCl +NaNO2 --> HNO2 + NaCl
1 mole of HCl react with one mole of NaNO2 to produce 1 mole of NaCl and 1 mole of HNO2
Moles of NaNO2 = 0.17 - 0.012 = 0.158
Moles of HNO2 final = 0.11 - 0.012 = 0.098
Which one of the mixtures would most likely produce a chemical reaction?
F2 + At- OR At2 + F-
Answer:
F₂ + At⁻
Explanation:
Astatine is the only Halogen that does not exist as a diatomic molecule. One Astatine atom would have a charge of 1⁻. Fluorine is the most electronegative element, and therefore very reactive and commonly forms a diatomic molecule.
The acid-base reaction between HCl and NaOH produces a solution with a pH of 7 at the equivalence point (NaCl H2O). Why does an acid-base indicator that changes color at pH 5 or 9 work just as well for this reaction as one that changes color at pH 7
Answer:
Answer is in the explanation.
Explanation:
Before the equivalence point, the pH of the solution of HCl that is titrated with NaOH has a pH <<< 7. When you are adding more NaOH nearing, thus, to the equivalence point the change in pH occurs quickly, and, with 1 drop of excess of NaOH after equivalence, the pH of the solution change to a pH >>> 7
That means the volume added at pH 5 or pH 9 is, almost, the same doing the indicator work just as well as an indicator with change color at pH 7
52.1 mL of aqueous 0.255 M Pb(NO3)2 is mixed with 38.5 mL of 0.415 M NaCl. The equation for the precipitate reaction is: Pb(NO3)2 (aq) 2 NaCl (aq) --> PbCl2 (s) 2 NaNO3 (aq) The concentration of Pb2 ion in the solution is _____ M after the reaction is complete.
Answer:
0.0585 M
Explanation:
Pb(NO₃)₂ (aq) + 2NaCl (aq) → PbCl₂ (s) + 2NaNO₃ (aq)First we calculate the inital number of moles of each reagent, using the given volumes and concentrations:
0.255 M Pb(NO₃)₂ * 52.1 mL = 13.3 mmol Pb(NO₃)₂ 0.415 M NaCl * 38.5 mL = 16.0 mmol NaClThen we calculate how many Pb(NO₃)₂ moles reacted with 16.0 mmoles of NaCl, using the stoichiometric coefficients of the reaction:
16.0 mmol NaCl * [tex]\frac{1mmolPb(NO_3)_2}{2mmolNaCl}[/tex] = 8.00 mmol Pb(NO₃)₂Now we calculate the remaining number of Pb(NO₃)₂ moles after the reaction:
13.3 mmol - 8.00 mmol = 5.30 mmol Pb(NO₃)₂Finally we divide the number of moles by the final volume to calculate the concentration:
5.30 mmol / (52.1 mL + 38.5 mL) = 0.0585 Mwhat is the correct symbol for the element copper
Answer:
the correct symbol for copper is:CUAnswer:Cu
Explanation
First letter is usually capital then the other letters are usually in small letters
The ratio of zinc to copper in some alloy is 2 to 5. If 60 kilograms of zinc are used, how many kilograms of copper are needed to make this alloy
Answer:
The correct answer is 150 kilograms.
Explanation:
Based on the given information, the ratio of zinc and copper within the alloy is 2:5. The amount of zinc used in the alloy is 60 kg. Now the amount of copper used within the alloy would be,
Zinc/Copper = 2/5
60/Copper = 2/5
Copper(Cu) = 60*5/2
Cu = 150 Kilograms.
Thus, the amount of Cu used in the alloy is 150 Kg.
Acetylene gas, C2H2, is produced as a result of the following reaction: CaC2 + 2H2O ----> C2H2 + Ca(OH)2.
(a) If 32 grams of CaC2 are consumed in this reaction, how many moles of water are needed ?
(b) How Many moles of each product would form ?
Given the data from the question,
A. The number of mole of water needed for the reaction is 1 mole
Bi. The number of mole of C₂H₂ formed is 0.5 mole
Bii. The number of mole of Ca(OH)₂ formed is 0.5 mole
How to determine the mole of CaC₂Mass of CaC₂ = 32 gMolar mass of CaC₂ = 40 + (12×2) = 64 g/mol Mole of CaC₂ =?Mole = mass / molar mass
Mole of CaC₂ = 32 / 64
Mole of CaC₂ = 0.5 mole
A. How to determine the mole of water needeBalanced equation
CaC₂ + 2H₂O —> C₂H₂ + Ca(OH)₂
From the balanced equation above,
1 mole of CaC₂ required 2 moles of H₂O
Therefore,
0.5 mole of CaC₂ will require = 0.5 × 2 = 1 mole of H₂O
Thus, 1 mole of H₂O is needed for the reaction.
Bi. How to determine the mole of C₂H₂ produced
Balanced equation
CaC₂ + 2H₂O —> C₂H₂ + Ca(OH)₂
From the balanced equation above,
1 mole of CaC₂ reacted to produce 1 mole of C₂H₂
Therefore,
0.5 mole of CaC₂ will also react to produce 0.5 mole of C₂H₂
Thus, 0.5 mole of C₂H₂ was obtained from the reaction
Bii. How to determine the mole of Ca(OH)₂ producedBalanced equation
CaC₂ + 2H₂O —> C₂H₂ + Ca(OH)₂
From the balanced equation above,
1 mole of CaC₂ reacted to produce 1 mole of Ca(OH)₂
Therefore,
0.5 mole of CaC₂ will also react to produce 0.5 mole of Ca(OH)₂
Thus, 0.5 mole of Ca(OH)₂ was obtained from the reaction
Learn more about stoichiometry:
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How many moles of oxygen atom are there in 0.5 moles of Ca(ClO3) 2?
Answer:
Do a quick conversion: 1 moles Ca(ClO3)2 = 206.9804 gram using the molecular weight calculator and the molar mass of Ca(ClO3)2. ... How many moles Ca(ClO3 )2 in 1 grams? ... of each element in a chemical formula by the number of atoms of that element present in the formula, then adding all of these products together.
Explanation:
(jayaanilanmol's answer)
