A bicyclist rides 1.59 km due east, while the resistive force from the air has a magnitude of 7.00 N and points due west. The rider then turns around and rides 1.59 km due west, back to her starting point. The resistive force from the air on the return trip has a magnitude of 7.00 N and points due east. Find the work done by the resistive force during the round trip. Number Units

Answers

Answer 1

Answer:

The required work done by the resistive force = -22.3 kJ

Explanation:

We understand that the amount of work done for a force F and displacements is provided as the product of force multiplied by displacement, which can be represented as W = F.S

Now, when the cyclist travels east and returns west, the force and displacement directions will be opposite and they make an angle 180 degrees apart.

W = -2 × 7.00 × 1590

W = -22260 J

W = -22.3 kJ


Related Questions

3. How can a generator that otherwise produces AC
current be modified to produce DC current?

Answers

The change requires a commutator. ... The brushes attached to each half of the commutator are arranged so that at the moment the direction of the current in the coil reverses, they slip from one half of the commutator to the other.

A sample contains 36 g of a radioactive isotope. How much radioactive isotope remains in the sample after 3 half-lives?
A. 12 g
B. 18 g
C. 4.5 g
D. 9 g

Answers

Answer:

Option "C": "4.5 g"

Explanation:

N0 = 36 g, Let half-life is T.

t = 3 T, n is number of half lives = t / T = 3

By using the decay law of radioactivity

N / N0 = (1 / 2)^n

where

"N0" be the "initial amount"

"N" be the "amount left"

"n" be the "number of half-lives"

N / 36 = (1/2)^3

N / 36 = 1 / 8

N = 36 / 8 = 4.5 g

Answer:
4.5g

Explanation:

No = 36g Let half life is T

T= 3 T n number of half lives = t/T=3

N/No= (1/2)^n

Where, No be the initial amount

N be the amount left

n be the number of half lives

N/36 = (1/2)^3

N/36 = 1/8

N = 36/8 = 4.5g

A 500-nm wavelength light in vacuum illuminates a soap film with an index of refraction of 1.33. Air (n=1.00) is on both sides of the film. If the light strikes the film nearly perpindicularly, what is the smallest film thickness such that the film appears bright?
ANS --> 94.0

Please show your work as to how to end up with this answer.

Answers

Answer:

Wavelength of light in film (let y = lambda)

y = 500 nm / (4/3) = 375 nm    

There will be a phase change at the air/film interface (not the other side)

S = 4 t       thickness of film = S/4 where S equals 1 wavelength

This is because of the phase change at one surface

375 nm = 4 * t

t = 93.8 nm

A 0.200 m wire is moved parallel to a 0.500 T
magnetic field at a speed of 1.50 m/s. What emf is
induced across the ends of the wire?

Answers

Answer:

The required emf moved across the wire is zero

Explanation:

For a moving charge particle, the magnetic force can be determined by using the formula;

[tex]\varepsilon = Bvlsin \theta[/tex]

since the wire moves in parallel, the angle [tex]\theta[/tex] between magnetic field and velocity = 0°

B = 0.500 T

v = 1.50 m/s

l = 0.200 m

[tex]\varepsilon = (0.500 \ T )(1.50 \ m/s) \times (0.200 \ m)\times sin (0)[/tex]

[tex]\varepsilon = 0.15\times sin (0)[/tex]

[tex]\varepsilon = 0[/tex]

potential Energy is associated with position
True or false​

Answers

Answer:

yes.

Explanation:

potential Energy is associated with position

Answer:

true

Explanation:

the energy possessed by a body by virtue of its position or configuration is called potential energy.Everything at a height from the earth surface posseses potential energy.

A positive electric charge is moved at a constant speed between two locations in an electric field, with no work done by or against the field at any time during the motion. This situation can occur only if the

Answers

Answer:

The options are

A) charge is moved in the direction of the field

(B) charge is moved opposite to the direction of the field

(C) charge is moved perpendicular to an equipotential line

(D) charge is moved along an equipotential line

(E) electric field is uniform

The answer is (D) charge is moved along an equipotential line

For all the criteria in the question to be met it means that the motion is perpendicular to the field and the force is perpendicular to the displacement of the charge respectively. In this scenario,

Change in velocity is zero. Work can be calculated by multiplying charge and change in velocity which when calculated will give zero.

What is the thinnest soap film (excluding the case of zero thickness) that appears black when illuminated with light with a wavelength of 555 nmnm

Answers

Answer:

The minimum thickness of soap film is [tex]2.086\times 10^{-7} m[/tex].

Explanation:

wavelength = 555 nm

refractive index, n = 1.33

For the destructive interference,

the thickness is given by

[tex]t =\frac{m \lambda }{2 n}[/tex]

Here, m is the order, n is the refractive index and [tex]\lambda[/tex] is the wavelength.

For minimum thickness, m = 1

So the thickness is  

[tex]t =\frac{1 \times 555\times 10^{-9} }{2 \times 1.33}\\\\t = 2.086\times 10^{-7} m[/tex]

A small planet having a radius of 1000 km exerts a gravitational force of 100 N on an object that is 500 km above its surface. If this object is moved 500 km farther from the planet, the gravitational force on it will be closest to Group of answer choices 56 N. 24 N. 77 N. 45 N. Flag question: Question 14 Question 14

Answers

Answer:

The gravitational force will be closest to group A: 56 N.

Explanation:

The gravitational force of the planet is given by:

[tex] F = \frac{GmM}{r^{2}} [/tex]

Where:

G: is the gravitational constant

m: is the mass of the object

M: is the mass of the planet

r: is the distance

When the object is 500 km above the surface of the planet, the gravitational force is 100 N:

[tex] F_{1} = \frac{GmM}{r_{1}^{2}} = \frac{GmM}{(500 km + 1000 km)^{2}} = \frac{GmM}{(1500 km)^{2}} [/tex]

And when the object is 500 km farther from the planet, the gravitational force is given by:

[tex] F_{2} = \frac{GmM}{r_{2}^{2}} = \frac{GmM}{(500 km + 1500 km)^{2}} = \frac{GmM}{(2000 km)^{2}} [/tex]  

By dividing F₂ by F₁ we can calculate F₂:

[tex] \frac{F_{2}}{F_{1}} = \frac{\frac{GmM}{(2000 km)^{2}}}{\frac{GmM}{(1500 km)^{2}}} [/tex]

[tex] F_{2} = 100 N*\frac{(1500 km)^{2}}{(2000 km)^{2}} = 56.2 N [/tex]

Therefore, the gravitational force will be closest to group A: 56 N.

                               

I hope it helps you!                                                                                              

A stalled car is being pushed up a hill at constant velocity by three people. The net force on the car is Group of answer choices Zero down the hill and greater than the weight of the car. down the hill and equal to the weight of the car up the hill and equal to the weight of the car. up the hill and greater than the weight of the car.

Answers

Answer:

Zero

Explanation:

Net force can be defined as the vector sum of all the forces acting on a body or an object i.e the sum of all forces acting simultaneously on a body or an object.

Mathematically, net force is given by the formula;

[tex] Fnet = Fapp + Fg[/tex]

Where;

Fnet is the net force.

Fapp is the applied force.

Fg is the force due to gravitation.

In this scenario, a stalled car is being pushed up a hill at constant velocity by three people. Thus, the net force on the car is zero because all the forces acting on any physical object is equal to zero and represents a constant velocity; by balancing or cancelling each other out.

According to Sir Isaac Newton's First Law of Motion which is known as Law of Inertia, it states that an object or a physical body in motion will continue in its state of motion at continuous velocity (the same speed and direction) or, if at rest, will remain at rest unless acted upon by an external force.

what is the length of x of the side of the triangle below?

Answers

The answer is c. I hope it’s clear

Why do nuclear power plants use fission rather than fusion to generate
electric energy?
A. Fusion requires very high pressure and temperature.
B. A problem might lead to an explosion in a fusion reactor, but not
in a fission reactor.
C. The isotope used in fission is more common than the one used
in fusion.
D. Fission produces less radioactive waste than fusion does.

Answers

Answer:

Fission is used in nuclear power reactors since it can be controlled, while fusion is not utilized to produce power since the reaction is not easily controlled and is expensive to create the needed conditions for a fusion reaction.

Explanation:

Answer:

Hello There!!

Explanation:

I think it is A. Fusion requires very high pressure and temperature. Sorry if I am wrong.

hope this helps,have a great day!!

~Pinky~

A proton accelerates from rest in a uniform electric field of 595 N/C. At one later moment, its speed is 1.15 Mm/s (nonrelativistic because v is much less than the speed of light). (a) Find the acceleration of the proton. (b) Over what time interval does the proton reach this speed? (c) How far does it move in this time interval? (d) What is its kinetic energy at the end of this interval?

Answers

At one later moment, its speed is 1. 20Mm/s (non relativistic because v is much less than the speed of light).

Select the correct answer.
A car traveling south is 200 kilometers from its starting point after 2 hours. What is the average velocity of the car?
O A 100 khmeters/hour south
OB. 200 kilometers/hour
Ос.
200 kilometers/hour north
OD.
100 kilometers/hour

Answers

Answer:

D

Explanation:

The velocity of the car would be 100 kilometer per hour.

D that should be correct boo

An aircraft is in level flight at 225 km/hr through air at standard conditions. The lift coefficient at this speed is 0.45 and the drag coefficient is 0.065. The mass of the aircraft is 900 kg. Calculate the effective lift area for the aircraft and the required engine thrust and power to maintain level flight.

Answers

Answer:

- the effective lift area for the aircraft is 8.30 m²

- the required engine thrust is 1275 N

- required power is 79.7 kW

Explanation:

Given the data in the question;

Speed V = 225 km/hr = 62.5 m/s

The lift coefficient CL = 0.45

drag coefficient CD = 0.065

mass = 900 kg

g = 9.81 m/s²

a)  the effective lift area for the aircraft

we know that for a steady level flight, weight = lift and thrust = drag

Using the equation for the lift force

F[tex]_L[/tex] = C[tex]_L[/tex][tex]\frac{1}{2}[/tex]ρV²A = W

we substitute

0.45 × [tex]\frac{1}{2}[/tex] × 1.21 × ( 62.5 )² × A = ( 900 × 9.81 )

1081.05 × A = 8829

A = 8829 / 1081.05

A = 8.30 m²

Therefore, the effective lift area for the aircraft is 8.30 m²

b) the required engine thrust and power to maintain level flight.

we use the expression for drag force

F[tex]_D[/tex] = T = C[tex]_D[/tex][tex]\frac{1}{2}[/tex]ρV²A

we substitute

= 0.065 × [tex]\frac{1}{2}[/tex] × 1.21 × ( 62.5 )² × 8.30

T = 1275 N

Since drag and thrust force are the same,

Therefore, the required engine thrust is 1275 N

Power required;

P = TV

p = 1275 × 62.5

p = 79687.5 W

p = ( 79687.5 / 1000 )kW

p = 79.7 kW

Therefore, required power is 79.7 kW

option are
cerebrum, cortex, cerebellum, brain stem, medulla, pons, midbrain , thalamus, hypothalamus, reticular formation

1.________regulates and maintains brain's awareness level.

2. _______controls the activity of the pituitary gland.

3._______relays impulses from one part of the brain to another.

4._______regulates body temperature, hunger, and other internal body conditions.

5______connects nerve impulses from body to cortex.

Answers

Answer:

1. Reticular formation.

2. Hypothalamus.

3. Thalamus.

4. Hypothalamus.

5. Thalamus.

Explanation:

The human brain consists of various sections and these includes;

I. Anterior Cingulate Cortex (ACC) which resembles a bow or collar surrounding the frontal part of the corpus callosum. This is the frontal part of the cingulate cortex which helps to make complex cognitive functions such as impulse control, decision-making, emotions and empathy.

II. Ventral prefrontal cortex in humans are interconnected with the brain and are responsible for the processing of risk, empathy, fear and social decision-making

III. The Cerebral Cortex: this part of the brain primarily comprises of grey matter, foldable sheets of neurons and forms its outermost layer. Therefore, cerebral cortex is known as the outermost layer of the brain (cerebrum) and thus, makes up half of its weight. It is about 2.5 millimeters in thickness and as such it's able to fold.

1. Reticular formation: regulates and maintains brain's awareness level.

2. Hypothalamus: controls the activity of the pituitary gland.

3. Thalamus: relays impulses from one part of the brain to another.

4. Hypothalamus: regulates body temperature, hunger, and other internal body conditions.

5. Thalamus: connects nerve impulses from body to cortex.

4. A 268 kg boulder rolls down a hill. If it had 50,000 J of energy to start with, how high was the hill? (Can anyone explain or give the equation for it? Thank you!)​

Answers

Answer:

h = 18.65 m

Explanation:

Given that,

The mass of a boulder, m = 268 kg

The potential energy at the hill, E = 50,000 J

We need to find the height of the hill.

We know that, the potential energy of an object is given by :

E = mgh

Where

h is the height of the hill

So,

[tex]h=\dfrac{E}{mg}\\\\h=\dfrac{50000}{268\times 10}\\\\h=18.65\ m[/tex]

So, the height of the hill is 18.65 m.

Mass=268kg=mP.E=50000Jacceleration due to gravity=g=10m/s^2Height be h

[tex]\\ \sf\longmapsto PE=mgh[/tex]

[tex]\\ \sf\longmapsto 50000=268(10)h[/tex]

[tex]\\ \sf\longmapsto 50000=2680h[/tex]

[tex]\\ \sf\longmapsto h=\dfrac{50000}{2680}[/tex]

[tex]\\ \sf\longmapsto h=18.65m[/tex]

Calculate the force exerted on a thresher shark's eye by the hydrostatic pressure in ocean water at a depth of 380 m. (Assume the water's mass density at this depth is 1000 kg/m3k.)

Answers

Answer:

Explanation:

Hydrostatic pressure due to a water column of height  h can be given by the following expression.

P = hρg

where ρ is density of water and g is acceleration due to gravity .

Substituting the values.

P = 380 x 1000 x 9.8

= 3.72 x 10⁶ Pa.

Answer:

[tex]F=\dfrac{3.72\times 10^6\ Pa}{A}\ N[/tex]

Explanation:

Given that,

The density of water, d = 1000 kg/m³

Depth, h = 380 m

We need to find the force exerted on a thresher shark's eye by the hydrostatic pressure in ocean water. The force exerted by the hydrostatic pressure is given by :

[tex]P=\rho gh[/tex]

Put all the values,

[tex]P=1000\times 9.8\times 380\\\\P=3.72\times 10^6\ Pa[/tex]

Force exerted,

F = P/A

So,

[tex]F=\dfrac{3.72\times 10^6\ Pa}{A}\ N[/tex]

Where

A is the area of crosss section

Hence, this is the required solution.

The conversion of thermal energy into mechanical energy requires
a thermometer.
D. Beat engine
C vaporizer.
d thermostat.

Answers

Temperature difference is required, so i’m guessing - a. thermometer - would be required to check that temperature.

Long Shore Drift is the ...
A. landforms along the shoreline of an ocean or sea
B. submerged or partly exposed ridge of sand along an ocean front
C. accumulation of sand grains along a beach front
D. movement of material along a coast by waves that approach at an angle to the shore.​

Answers

Answer: D. movement of material along a coast by waves that approach at an angle to the shore.​

Explanation:

Longshore drift is also referred to as the littoral druft and it means the sediment that is moved by the longshore current.

Longshore drift is the movement of material along a coast by waves which approach at an angle to the shore but then recede down the beach.

Therefore, the correct option is D.

write the chemical equation of rust ​

Answers

ANSWER

4Fe+ 3O2 → 2Fe2O.

EXPLANATION

iron (Fe) combines with oxygen (O2) to form rust, or iron oxide (Fe2O3). The equation for this reaction is: 4Fe+ 3O2 → 2Fe2O.

The answer is O2+Fe+H20—>Fe2O3H20

Is an object on the surface of Earth sitting still relative to outer space?

Answers

Answer:

The object is not still as it observe from the outer space.

Explanation:

Our earth is not stationary.

It rotates about its own axis with the period of 24 hours and it revolves around the sun with the period of 1 year.

An object is said to be at rest if the position of the object with respect to time changes.

An object is said to be in motion when the position of the object changes with respect to time.

Both the terms rest and motion are relative to each other.  

If an observer observe an object on the earth from the outer space, he observe that the object s not still it is also moving as the earth is moving.

So, the object is not still as it observe from the outer space.

Select the correct answer.
A force of 100 newtons is applied to a box at an angle
acceleration of the box?
36° with the horizontal. If the mass of the box is 25 kilograms, what is the horizontal
OA
1.52 meters/second2
3.24 meters/second
C.
5.48 meters/second
Ο Ο Ο Ο
6.87 meters/seconda
7.15 meters/second

Answers

Answer:

3

Explanation:

first you find the original component of the force be a cause in 36 degrees then with ka sin 36 find the average interforce by multiplying it with hundred Newton then divide the original force by the mass 25 Kg is equals tto ma

Answer:

See image

Explanation:

Plato

Thiết kế mạch điện tử sử dụng chân ngõ ra (I/O) của arduino UNO để lái relay 12VDC/500mA sao cho chân Arduino xuất ra tín hiệu 5V thì relay đóng, ngược lại chân I/O arduino xuất tín hiệu 0V thì relay hở. Mạch lái dùng BJT

Answers

Answer:

Mình cũng không biết làm bạn ơi =)))

Explanation:

5
What is back-lash error and how it is avoided​

Answers

Answer:

The correct answer is - it is an error in the observation.

Explanation:

Backlash error is the error in the motion that takes place during shifting the direction of gears. A backlash error is an error in the observation which occurs due to the wear and tear of threads of the screw observed that takes place at the time of reversing the direction of rotation of the thimble where the tip of the screw does not move in the opposite direction but remains stationary for a part of the rotation.

Avoid backlash error:

While taking measurements, the screw should be rotated in one direction only.

Describe how the human ear hears sound.

Answers

Answer:

sound waves enter the outer ear and travel through a narrow passageway called the ear canal, which leads to the eardrum. The eardrum vibrates from the incoming sound waves and sends these vibrations to three tiny bones in the middle ear.

Explanation:

As part of an exercise program, a woman walks south at a speed of 2.8 m/s for 46 minutes. She then turns around and walks north a distance 3,132 m in 54 minutes . What is the woman's average speed in m/s during her entire motion

Answers

Answer:

[tex]A_[avg}=1.81m/s[/tex]

Explanation:

From the question we are told that:

North Movement

Velocity[tex]V=2.8[/tex]

Time  [tex]t=46 minuites[/tex]

South movement

Distance [tex]d=3,132[/tex]

Time [tex]t'= 54 minutes[/tex]

Generally the equation for Average Velocity is mathematically given by

[tex]A_[avg}\]frac{Total distance}{Total time}[/tex]

Where

Total distance d_t

[tex]d_t=Souther\ distance\ traveled\ +Northern\ distance\ traveled[/tex]

[tex]d_t=(2.8*46*60)+(3132)[/tex]

[tex]d_t=10860[/tex]

An

Total Time

[tex]T=(46+54)60[/tex]

[tex]T=6000[/tex]

Therefore

[tex]A_[avg}=\frac{d_t}{T}[/tex]

[tex]A_[avg}=\frac{10860}{6000}[/tex]

[tex]A_[avg}=1.81m/s[/tex]

a given mass of an ideal gas law occupies a volume V of a temperature T under a pleasure p, if the pressure is increased to 2 p and temperature 1/2 T what is the percentage change in the volume of the gas​

Answers

Answer:

75%

Explanation:

We'll begin by calculating the final volume of the gas. This can be obtained as follow:

Initial volume (V₁) = V

Initial temperature (T₁) = T

Initial pressure (P₁) = P

Final pressure (P₂) = 2P

Final temperature (T₂) = ½T

Final volume (V₂) =?

P₁V₁/T₁ = P₂V₂/T₂

PV/T = 2P × V₂ / ½T

Cross multiply

T × 2P × V₂ = PV × ½T

T × 2P × V₂ = PV × ½T

Divide both side by T × 2P

V₂ = (PV × ½T) / T × 2P

V₂ = ¼V

Next, we shall determine the absolute change in the volume of the gas. This can be obtained as follow:

Initial volume (V₁) = V

Final volume (V₂) = ¼V

Absolute change in volume |ΔV| =?

|ΔV| = |V₂ – V₁|

|ΔV| = |¼V – V|

|ΔV| = |0.25V – V|

|ΔV| = 0.75V

Finally, we shall determine percentage change in the volume of the gas. This can be obtained as follow:

Initial volume (V₁) = V

Absolute change in volume |ΔV| = 0.75V

Percentage change =?

Percentage change = |ΔV| / V × 100

Percentage change = 0.75V / V × 100

Percentage change = 0.75 × 100

Percentage change = 75%

Thus, the percentage change in the volume of the gas is 75%

A trumpet player hears 5 beats per second when she plays a note and simultaneously sounds a 440 Hz tuning fork. After pulling her tuning valve out to slightly increase the length of her trumpet, she hears 3 beats per second against the tuning fork. Was her initial frequency 435 Hz or 445 Hz? Explain.

Answers

Answer:

her initial frequency is 445 Hz

Explanation:

Given;

initial beat frequency, [tex]F_B[/tex] = 5

observed frequency, F = 440 Hz

let the initial frequency = F₁

F₁ = F  ±  5 Hz

F₁ = 440 Hz  ±  5 Hz

F₁ = 435 or 445 Hz

This result obtained shows that her initial frequency can either be 435 Hz or 445 Hz

The last beat frequency will be used to determine the actual initial frequency.

F = v/λ

Frequency (F) is inversely proportional to wavelength. That is an increase in length will cause a proportional decrease in frequency.

This shows that the final frequency is smaller than the initial frequency because of the increase in length.

Initial frequency   -  frequency of tuning fork = 5 beat frequency

Reduced initial frequency - frequency of tuning fork = 3 beat frequency

Initial frequency = 5Hz + 440 Hz = 445 Hz

Final frequency (Reduced initial frequency) = 440 + 3 = 443 Hz

Check: 445 Hz - 440 Hz = 5 Hz

            443 Hz - 440 Hz = 3 Hz

What kind of force are you using when you squish a marshmallow?

Answers

The answer is compression because when you are squishing a marshmello you are compressing it.

Imagine an alternate universe where all of the quantum number rules were identical to ours except m_{s} had three allowed values (rather than two as it does in our universe). If this were the case, and the Pauli Exclusion Principle still applies, how many electrons would be allowed in each orbital

Answers

Answer:

so in a given orbital there can be 3 electrons.

Explanation:

The Pauli exclusion principle states that all the quantum numbers of an electron cannot be equal, if the spatial part of the wave function is the same, the spin part of the wave function determines how many electrons fit in each orbital.

In the case of having two values, two electrons change. In the case of three allowed values, one electron fits for each value, so in a given orbital there can be 3 electrons.

Other Questions
In an open economy, gross domestic product equals $2,450 billion, consumption expenditure equals $1,390 billion, government expenditure equals $325 billion, investment equals $510 billion, and net capital outflow equals $225 billion. What is national saving Who was involved in the Vietnam war 1)) Click on the obtuse angle.L The height of the mercury column in a barometer is 756 mm Hg ona cloudy day.Calculate the atmospheric pressure at that time in pascal.( Density of mercury p= 13 600 kg/m^3, gravitational acceleration, g = 9.81m/s) Should localities maintain energy reserves for their own use? In the United States, Interest groups can be found (PRECALC) I need help on this one plz help a girl out & the favor will be returned What is the volume of a cube with 3-inch edges, in cubic inches? What name is given to a proposed explanation for a set of observations Describe the slope of a line if either the rise or the run is a negative number Which information can be determined using half-life? age of materialtype of particle releasedpercentage of rock that has agednumber of radioactive particles left 25 POINTS GIVING BRAINLIEST TO WHOEVER ANSWERS UT RIGHT!!A right triangle has hypotenuse with a length of 13 cm. The length of one leg is 5 cm. What is the area of the triangle?A.65 B.60C.32.5D.30 Help giving brainlest. HCF Of 14608 And 720 please help me with this question Which equation represents the relationship between the x-and y-values shown in the table.x. y7. 175. 113. 52. 2 A. y=2x-1 B. y=x + 10 C. y=3x -4 D. y=2x + 1 Consider the system of equations 2x + y = 11 and 4x y = 25. What is the value of the x-coordinate of its solution? Which of the following choices shows another way to write the ratio 7:13? A. 7 out of 13 b. 13 to 7 c. 52.84% d. All of these choices are correct. Would you classify a fruit, such as an apple, as a cell, tissue, organ, or organ system? explain. WORTH 40 POINTS!!!!!!!! I WILL MAKE U BRAINLIEST!!!! PLEASE ANSWER ALL QS