Answer:
[tex]68.0^{\circ}[/tex]
Explanation:
A projectile's vertical velocity at the top of its flight path must be zero, therefore the speed at the top of the trajectory must be referring to the object's horizontal velocity. Since there are exactly zero horizontal forces acting on the object, its horizontal velocity will remain the exact same throughout the entire launch. Thus, the horizontal component of the initial launch must be 45 meters per second, and we have the following equation using basic trigonometry for a right triangle:
Let [tex]\theta[/tex] be the unknown angle above the horizontal.
[tex]\cos \theta=\frac{45}{120},\\\theta=\arccos(\frac{45}{120})=67.97568716^{\circ}\approx \boxed{68.0^{\circ}}[/tex]
A model plane has a mass of 0.75 kg and is flying 12 m above the ground
with a speed of 18 m/s. What is the total mechanical energy of the plane?
The acceleration due to gravity is 9.8 m/s2.
Answer:
Option C. 210 J.
Explanation:
From the question given above, the following data were obtained:
Mass (m) = 0.75 Kg
Height (h) = 12 m
Velocity (v) = 18 m/s
Acceleration due to gravity (g) = 9.8 m/s²
Total Mechanical energy (ME) =?
Next, we shall determine the potential energy of the plane. This can be obtained as follow:
Mass (m) = 0.75 Kg
Height (h) = 12 m
Acceleration due to gravity (g) = 9.8 m/s²
Potential energy (PE) =?
PE = mgh
PE = 0.75 × 9.8 × 12
PE = 88.2 J
Next, we shall determine the kinetic energy of the plane. This can be obtained as follow:
Mass (m) = 0.75 Kg
Velocity (v) = 18 m/s
Kinetic energy (KE) =?
KE = ½mv²
KE = ½ × 0.75 × 18²
KE = ½ × 0.75 × 324
KE = 121.5 J
Finally, we shall determine the total mechanical energy of the plane. This can be obtained as follow:
Potential energy (PE) = 88.2 J
Kinetic energy (KE) = 121.5 J
Total Mechanical energy (ME) =?
ME = PE + KE
ME = 88.2 + 121.5
ME = 209.7 J
ME ≈ 210 J
Therefore, the total mechanical energy of the plane is 210 J.
YO giving 49 dollars if you answer this question .
. ( )
Trace the flow of energy through the food pyramid, label the missing units of energy found at each level by calculating the change in energy
Answer:
Energy Flow
The chemical energy of food is the main source of energy required by all living organisms. This energy is transmitted to different trophic levels along the food chain. This energy flow is based on two different laws of thermodynamics:
First law of thermodynamics, that states that energy can neither be created nor destroyed, it can only change from one form to another.
Second law of thermodynamics, that states that as energy is transferred more and more of it is wasted.
Energy Flow in Ecosystem
The energy flow in the ecosystem is one of the major factors that support the survival of such a great number of organisms. For almost all organisms on earth, the primary source of energy is solar energy. It is amusing to find that we receive less than 50 per cent of the sun’s effective radiation on earth. When we say effective radiation, we mean the radiation, which can be used by plants to carry out photosynthesis.
Explanation:
Energy Flow in Ecosystem
The energy flow in the ecosystem is one of the major factors that support the survival of such a great number of organisms. For almost all organisms on earth, the primary source of energy is solar energy. It is amusing to find that we receive less than 50 per cent of the sun’s effective radiation on earth. When we say effective radiation, we mean the radiation, which can be used by plants to carry out photosynthesis.
Most of the sun’s radiation that falls on the earth is usually reflected back into space by the earth’s atmosphere. This effective radiation is termed as the Photosynthetically Active Radiation (PAR).
Overall, we receive about 40 to 50 percent of the energy having Photosynthetically Active Radiation and only around 2-10 percent of it is used by plants for the process of photosynthesis. Thus, this percent of PAR supports the entire world as plants are the producers in the ecosystem and all the other organisms are either directly or indirectly dependent on them for their survival.
The energy flow takes place via the food chain and food web. During the process of energy flow in the ecosystem, plants being the producers absorb sunlight with the help of the chloroplasts and a part of it is transformed into chemical energy in the process of photosynthesis.
This energy is stored in various organic products in the plants and passed on to the primary consumers in the food chain when the herbivores consume (primary consumers) the plants as food. Then conversion of chemical energy stored in plant products into kinetic energy occurs, degradation of energy will occur through its conversion into heat.
Then followed by the secondary consumers. When these herbivores are ingested by carnivores of the first order (secondary consumers) further degradation will occur. Finally, when tertiary consumers consume the carnivores, energy will again be degraded. Thus, the energy flow is unidirectional in nature.
Moreover, in a food chain, the energy flow follows the 10 percent law. According to this law, only 10 percent of energy is transferred from one trophic level to the other; rest is lost into the atmosphere. This is clearly explained in the following figure and is represented as an energy pyramid.
An open 1-m-diameter tank contains water at a depth of 0.5 m when at rest. As the tank is rotated about its vertical axis the center of the fluid surface is depressed. At what angular velocity will the bottom of the tank first be exposed
Answer:
Angular velocity (w) = 8.86 rad/s
Explanation:
Angular velocity (w) = [tex]\sqrt{} 4ghi/R^{2}[/tex]
g= 9.81 m/s
R= 0.5
hi (initial depth) = 0.5m
Hence= [tex]\sqrt4* 9.81* 0.5/0.5^{2}[/tex] = 8.86 rad/s
3. How can a generator that otherwise produces AC
current be modified to produce DC current?
A sample contains 36 g of a radioactive isotope. How much radioactive isotope remains in the sample after 3 half-lives?
A. 12 g
B. 18 g
C. 4.5 g
D. 9 g
Answer:
Option "C": "4.5 g"
Explanation:
N0 = 36 g, Let half-life is T.
t = 3 T, n is number of half lives = t / T = 3
By using the decay law of radioactivity
N / N0 = (1 / 2)^n
where
"N0" be the "initial amount"
"N" be the "amount left"
"n" be the "number of half-lives"
N / 36 = (1/2)^3
N / 36 = 1 / 8
N = 36 / 8 = 4.5 g
A 500-nm wavelength light in vacuum illuminates a soap film with an index of refraction of 1.33. Air (n=1.00) is on both sides of the film. If the light strikes the film nearly perpindicularly, what is the smallest film thickness such that the film appears bright?
ANS --> 94.0
Please show your work as to how to end up with this answer.
Answer:
Wavelength of light in film (let y = lambda)
y = 500 nm / (4/3) = 375 nm
There will be a phase change at the air/film interface (not the other side)
S = 4 t thickness of film = S/4 where S equals 1 wavelength
This is because of the phase change at one surface
375 nm = 4 * t
t = 93.8 nm
A 0.200 m wire is moved parallel to a 0.500 T
magnetic field at a speed of 1.50 m/s. What emf is
induced across the ends of the wire?
Answer:
The required emf moved across the wire is zero
Explanation:
For a moving charge particle, the magnetic force can be determined by using the formula;
[tex]\varepsilon = Bvlsin \theta[/tex]
since the wire moves in parallel, the angle [tex]\theta[/tex] between magnetic field and velocity = 0°
B = 0.500 T
v = 1.50 m/s
l = 0.200 m
∴
[tex]\varepsilon = (0.500 \ T )(1.50 \ m/s) \times (0.200 \ m)\times sin (0)[/tex]
[tex]\varepsilon = 0.15\times sin (0)[/tex]
[tex]\varepsilon = 0[/tex]
potential Energy is associated with position
True or false
Answer:
yes.
Explanation:
potential Energy is associated with position
Answer:
true
Explanation:
the energy possessed by a body by virtue of its position or configuration is called potential energy.Everything at a height from the earth surface posseses potential energy.
A 5.0 A electric current passes through an aluminum wire of 4.0~\times~10^{-6}~m^2 cross-sectional area. Aluminum has one free electron per atom. The density of aluminum is 2.7~grams/cm^3, and the aluminum molar mass is 27 g. What is the electron number density (the number of electrons per unit volume) in the wire
Answer: The electron number density (the number of electrons per unit volume) in the wire is [tex]6.0 \times 10^{28} m^{-3}[/tex].
Explanation:
Given: Current = 5.0 A
Area = [tex]4.0 \times 10^{-6} m^{2}[/tex]
Density = 2.7 [tex]g/cm^{3}[/tex], Molar mass = 27 g
The electron density is calculated as follows.
[tex]n = \frac{density}{mass per atom}\\= \frac{\rho}{\frac{M}{N_{A}}}\\[/tex]
where,
[tex]\rho[/tex] = density
M = molar mass
[tex]N_{A}[/tex] = Avogadro's number
Substitute the values into above formula as follows.
[tex]n = \frac{\rho \times N_{A}}{M}\\= \frac{2.7 g/cm^{3} \times 6.02 \times 10^{23}/mol}{27 g/mol}\\= \frac{16.254 \times 10^{23}}{27} cm^{3}\\= 0.602 \times 10^{23} \times \frac{10^{6} cm^{3}}{1 m^{3}}\\= 6.0 \times 10^{28} m^{-3}[/tex]
Thus, we can conclude that the electron number density (the number of electrons per unit volume) in the wire is [tex]6.0 \times 10^{28} m^{-3}[/tex].
6) The temperature of 10 kg of a substance rises by 55°C when heated. Calculate the
temperature rise when 22 kg of the substance is heated with the same quantity of heat.
Answer:
121
Explanation:
When a person sits erect, increasing the vertical position of their brain by 38.6 cm, the heart must continue to pump blood to the brain at the same rate. (a) What is the gain in gravitational potential energy (in J) for 110 mL of blood raised 38.6 cm
Answer:
the gain in gravitational potential energy is 0.4369 J
Explanation:
Given the data in the question;
from the definition of density, we know that;
ρ = m / V
where ρ is density, m is the mass and V is the volume.
Now, lets make mass the subject of the formula
m = ρV ------ let this be equation 1
Now, we know that potential energy PE = mgh ------- let this be equation 2
where m is mass, g is acceleration due gravity, and h is the height.
substitute equation 1 into 2
PE = ρVgh
given that; V = 110 mL = 110 × 10⁻⁶ m³, h = 38.6 cm = 38.6 × 10⁻² m, g = 9.8 m/s², ρ = 1.05 × 10³ kg/m³
we substitute
PE = (1.05 × 10³ kg/m³) × (110 × 10⁻⁶ m³) × 9.8 m/s² × 38.6 × 10⁻² m
PE = 0.4369 J
Therefore, the gain in gravitational potential energy is 0.4369 J
A positive electric charge is moved at a constant speed between two locations in an electric field, with no work done by or against the field at any time during the motion. This situation can occur only if the
Answer:
The options are
A) charge is moved in the direction of the field
(B) charge is moved opposite to the direction of the field
(C) charge is moved perpendicular to an equipotential line
(D) charge is moved along an equipotential line
(E) electric field is uniform
The answer is (D) charge is moved along an equipotential line
For all the criteria in the question to be met it means that the motion is perpendicular to the field and the force is perpendicular to the displacement of the charge respectively. In this scenario,
Change in velocity is zero. Work can be calculated by multiplying charge and change in velocity which when calculated will give zero.
What was the earliest energy source for humans?
A. coal
B. oil
C. natural gas
D. wood
Answer:
i think its oil
Explanation:
It was made & used as early as the fourth century BC.
Adverb of place:
1
Adverb of time:
2
Adverb of place:
3
Adverb of time:
4
Adverb of place:
5
Answer:
1 there,here, somewhere,nowhere,everywhere
2.now,yesterday,then,
find the equivalent resistance.
Answer:
Explanation:
Note the connection between D-L-H shorts out the resistors on the right. Those 4 resistors can be ignored.
The connection between D-L-K means the 2 resistors between C-D and C-K are in parallel. The equivalent resistance of 2 6-ohm resistors in parallel is 3 ohms.
Similarly the connection between K-L-H means the 2 resistors between J-K and J-H are in parallel. The equivalent resistance of 2 6-ohm resistors in parallel is 3 ohms.
Adding the resistors in series together:
A-C-L-J-D = 6 + 3 + 3 + 6
= 18 ohms
Wind, hydropower, and solar can all be used to make ___
Answer: reusable energy or just energy but i think its just energy
Explanation:
What is the thinnest soap film (excluding the case of zero thickness) that appears black when illuminated with light with a wavelength of 555 nmnm
Answer:
The minimum thickness of soap film is [tex]2.086\times 10^{-7} m[/tex].
Explanation:
wavelength = 555 nm
refractive index, n = 1.33
For the destructive interference,
the thickness is given by
[tex]t =\frac{m \lambda }{2 n}[/tex]
Here, m is the order, n is the refractive index and [tex]\lambda[/tex] is the wavelength.
For minimum thickness, m = 1
So the thickness is
[tex]t =\frac{1 \times 555\times 10^{-9} }{2 \times 1.33}\\\\t = 2.086\times 10^{-7} m[/tex]
An electromagnetic wave is generated by:
Answer:
Electromagnetic waves are produced whenever electric charges are accelerated. This makes it possible to produce electromagnetic waves by letting an alternating current flow through a wire, an antenna. The frequency of the waves created in this way equals the frequency of the alternating current.
Explanation:
A small planet having a radius of 1000 km exerts a gravitational force of 100 N on an object that is 500 km above its surface. If this object is moved 500 km farther from the planet, the gravitational force on it will be closest to Group of answer choices 56 N. 24 N. 77 N. 45 N. Flag question: Question 14 Question 14
Answer:
The gravitational force will be closest to group A: 56 N.
Explanation:
The gravitational force of the planet is given by:
[tex] F = \frac{GmM}{r^{2}} [/tex]
Where:
G: is the gravitational constant
m: is the mass of the object
M: is the mass of the planet
r: is the distance
When the object is 500 km above the surface of the planet, the gravitational force is 100 N:
[tex] F_{1} = \frac{GmM}{r_{1}^{2}} = \frac{GmM}{(500 km + 1000 km)^{2}} = \frac{GmM}{(1500 km)^{2}} [/tex]
And when the object is 500 km farther from the planet, the gravitational force is given by:
[tex] F_{2} = \frac{GmM}{r_{2}^{2}} = \frac{GmM}{(500 km + 1500 km)^{2}} = \frac{GmM}{(2000 km)^{2}} [/tex]
By dividing F₂ by F₁ we can calculate F₂:
[tex] \frac{F_{2}}{F_{1}} = \frac{\frac{GmM}{(2000 km)^{2}}}{\frac{GmM}{(1500 km)^{2}}} [/tex]
[tex] F_{2} = 100 N*\frac{(1500 km)^{2}}{(2000 km)^{2}} = 56.2 N [/tex]
Therefore, the gravitational force will be closest to group A: 56 N.
I hope it helps you!
A stalled car is being pushed up a hill at constant velocity by three people. The net force on the car is Group of answer choices Zero down the hill and greater than the weight of the car. down the hill and equal to the weight of the car up the hill and equal to the weight of the car. up the hill and greater than the weight of the car.
Answer:
Zero
Explanation:
Net force can be defined as the vector sum of all the forces acting on a body or an object i.e the sum of all forces acting simultaneously on a body or an object.
Mathematically, net force is given by the formula;
[tex] Fnet = Fapp + Fg[/tex]
Where;
Fnet is the net force.
Fapp is the applied force.
Fg is the force due to gravitation.
In this scenario, a stalled car is being pushed up a hill at constant velocity by three people. Thus, the net force on the car is zero because all the forces acting on any physical object is equal to zero and represents a constant velocity; by balancing or cancelling each other out.
According to Sir Isaac Newton's First Law of Motion which is known as Law of Inertia, it states that an object or a physical body in motion will continue in its state of motion at continuous velocity (the same speed and direction) or, if at rest, will remain at rest unless acted upon by an external force.
The
of a waveform is the number of cycles per second.
O period
O intensity
O frequency
O amplitude
Answer:
frequency is the correct answer for the question if the answer is correct plz mark me as brainliest.
Part
A block of mass 2 kg is acted upon by two forces: 3 N (directed to the left) and 4 N (directed to the right). What can you say about the blocks motion?
Answer:
Explanation:
the block will move to the right side with small velocity because the force from the left side greater than force from right side. Velocity will be less because of friction and gravitational attraction.
If a block of mass 2 kg is acted upon by two forces: 3 N (directed to the left) and 4 N (directed to the right), then the block would move towards the right side.
What is Newton's second law?Newton's Second Law states that The resultant force acting on an object is proportional to the rate of change of momentum.
As given in the problem statement If a block of mass 2 kg is acted upon by two forces: 3 N (directed to the left) and 4 N (directed to the right),
The net force acting on the block = 4 Newtons - 3 newtons
= 1 Newton
Thus, we can say that the block would move to the right side.
To learn more about Newton's second law here, refer to the link given below;
brainly.com/question/13447525
#SPJ2
what is the length of x of the side of the triangle below?
In order to increase his gravitational potential energy by an amount equal to his kinetic energy at full speed, how high would such a sprinter need to climb
Answer:
Hola eres nuevo yo nací en el 2021 del 4 de junioWhy do nuclear power plants use fission rather than fusion to generate
electric energy?
A. Fusion requires very high pressure and temperature.
B. A problem might lead to an explosion in a fusion reactor, but not
in a fission reactor.
C. The isotope used in fission is more common than the one used
in fusion.
D. Fission produces less radioactive waste than fusion does.
Answer:
Fission is used in nuclear power reactors since it can be controlled, while fusion is not utilized to produce power since the reaction is not easily controlled and is expensive to create the needed conditions for a fusion reaction.
Explanation:
Answer:
Hello There!!
Explanation:
I think it is A. Fusion requires very high pressure and temperature. Sorry if I am wrong.
hope this helps,have a great day!!
~Pinky~
A proton accelerates from rest in a uniform electric field of 595 N/C. At one later moment, its speed is 1.15 Mm/s (nonrelativistic because v is much less than the speed of light). (a) Find the acceleration of the proton. (b) Over what time interval does the proton reach this speed? (c) How far does it move in this time interval? (d) What is its kinetic energy at the end of this interval?
Select the correct answer.
A car traveling south is 200 kilometers from its starting point after 2 hours. What is the average velocity of the car?
O A 100 khmeters/hour south
OB. 200 kilometers/hour
Ос.
200 kilometers/hour north
OD.
100 kilometers/hour
Answer:
D
Explanation:
The velocity of the car would be 100 kilometer per hour.
An aircraft is in level flight at 225 km/hr through air at standard conditions. The lift coefficient at this speed is 0.45 and the drag coefficient is 0.065. The mass of the aircraft is 900 kg. Calculate the effective lift area for the aircraft and the required engine thrust and power to maintain level flight.
Answer:
- the effective lift area for the aircraft is 8.30 m²
- the required engine thrust is 1275 N
- required power is 79.7 kW
Explanation:
Given the data in the question;
Speed V = 225 km/hr = 62.5 m/s
The lift coefficient CL = 0.45
drag coefficient CD = 0.065
mass = 900 kg
g = 9.81 m/s²
a) the effective lift area for the aircraft
we know that for a steady level flight, weight = lift and thrust = drag
Using the equation for the lift force
F[tex]_L[/tex] = C[tex]_L[/tex][tex]\frac{1}{2}[/tex]ρV²A = W
we substitute
0.45 × [tex]\frac{1}{2}[/tex] × 1.21 × ( 62.5 )² × A = ( 900 × 9.81 )
1081.05 × A = 8829
A = 8829 / 1081.05
A = 8.30 m²
Therefore, the effective lift area for the aircraft is 8.30 m²
b) the required engine thrust and power to maintain level flight.
we use the expression for drag force
F[tex]_D[/tex] = T = C[tex]_D[/tex][tex]\frac{1}{2}[/tex]ρV²A
we substitute
= 0.065 × [tex]\frac{1}{2}[/tex] × 1.21 × ( 62.5 )² × 8.30
T = 1275 N
Since drag and thrust force are the same,
Therefore, the required engine thrust is 1275 N
Power required;
P = TV
p = 1275 × 62.5
p = 79687.5 W
p = ( 79687.5 / 1000 )kW
p = 79.7 kW
Therefore, required power is 79.7 kW
option are
cerebrum, cortex, cerebellum, brain stem, medulla, pons, midbrain , thalamus, hypothalamus, reticular formation
1.________regulates and maintains brain's awareness level.
2. _______controls the activity of the pituitary gland.
3._______relays impulses from one part of the brain to another.
4._______regulates body temperature, hunger, and other internal body conditions.
5______connects nerve impulses from body to cortex.
Answer:
1. Reticular formation.
2. Hypothalamus.
3. Thalamus.
4. Hypothalamus.
5. Thalamus.
Explanation:
The human brain consists of various sections and these includes;
I. Anterior Cingulate Cortex (ACC) which resembles a bow or collar surrounding the frontal part of the corpus callosum. This is the frontal part of the cingulate cortex which helps to make complex cognitive functions such as impulse control, decision-making, emotions and empathy.
II. Ventral prefrontal cortex in humans are interconnected with the brain and are responsible for the processing of risk, empathy, fear and social decision-making
III. The Cerebral Cortex: this part of the brain primarily comprises of grey matter, foldable sheets of neurons and forms its outermost layer. Therefore, cerebral cortex is known as the outermost layer of the brain (cerebrum) and thus, makes up half of its weight. It is about 2.5 millimeters in thickness and as such it's able to fold.
1. Reticular formation: regulates and maintains brain's awareness level.
2. Hypothalamus: controls the activity of the pituitary gland.
3. Thalamus: relays impulses from one part of the brain to another.
4. Hypothalamus: regulates body temperature, hunger, and other internal body conditions.
5. Thalamus: connects nerve impulses from body to cortex.
4. A 268 kg boulder rolls down a hill. If it had 50,000 J of energy to start with, how high was the hill? (Can anyone explain or give the equation for it? Thank you!)
Answer:
h = 18.65 m
Explanation:
Given that,
The mass of a boulder, m = 268 kg
The potential energy at the hill, E = 50,000 J
We need to find the height of the hill.
We know that, the potential energy of an object is given by :
E = mgh
Where
h is the height of the hill
So,
[tex]h=\dfrac{E}{mg}\\\\h=\dfrac{50000}{268\times 10}\\\\h=18.65\ m[/tex]
So, the height of the hill is 18.65 m.
[tex]\\ \sf\longmapsto PE=mgh[/tex]
[tex]\\ \sf\longmapsto 50000=268(10)h[/tex]
[tex]\\ \sf\longmapsto 50000=2680h[/tex]
[tex]\\ \sf\longmapsto h=\dfrac{50000}{2680}[/tex]
[tex]\\ \sf\longmapsto h=18.65m[/tex]
