A simplified global food web is shown in the diagram above. If human pollution causes the removal of zooplankton from the food web, how many different organisms in this food web would be affected?

The first liquid (milk) that comes out of a woman's breast after delivery is called [tex]\sf\purple{colostrum}[/tex].

[tex]\large\mathfrak{{\pmb{\underline{\orange{Happy\:learning }}{\orange{!}}}}}[/tex]

Answer:

% yield = 200%

Explanation:

By using 145 gram of aluminium

Using 26.982 g/mol of Al, 101.96 g/mol of Aluminium oxide is produced

Using 145 grams of aluminium, the yield of Aluminium oxide  would have been = (101.96 g/mol/26.982 g/mol)/145 grams

= 547.9282485 gram

Now % yield = actual yield /theoretical yield * 100

Substituting the given values, we get -

% yield = (547.928/270) *100

% yield = 200%

Answer: The balanced equation is [tex]2SO_{2} + O_{2} + 2H_{2}O \rightarrow 2H_{2}SO_{4}[/tex].

Explanation:

A chemical equation which contains same number of atoms on both reactant and product side is called a balanced chemical equation.

For example, [tex]SO_{2} + O_{2} + H_{2}O \rightarrow H_{2}SO_{4}[/tex]

Here, number of atoms present on reactant side are as follows.

Number of atoms present on product side are as follows.

To balance this equation, multiply [tex]SO_{2}[/tex] by 2 and [tex]H_{2}O[/tex] by 2 on reactant side. Also, multiply [tex]H_{2}SO_{4}[/tex] by 2 on product side.

Hence, the equation can be re-written as follows.

[tex]2SO_{2} + O_{2} + 2H_{2}O \rightarrow 2H_{2}SO_{4}[/tex]

Now, the number of atoms present on reactant side are as follows.

Number of atoms present on product side are as follows.

Since, the atoms present on both reactant and product side are equal. Hence, the equation is now balanced.

Thus, we can conclude that the balanced equation is [tex]2SO_{2} + O_{2} + 2H_{2}O \rightarrow 2H_{2}SO_{4}[/tex].

Answer:

The cyanidin indicator turns blue within a pH range of 5 - 7. The pH of the solution could be 5, 6 or 7.

An indicator is used to determine the endpoint of a titration.

Explanation:

Cyanidin indicator changes colour with each change in pH. In acidic solutions (pH < 7) cyanidin indicator will turn red, through to purple and blue, while in basic solutions (pH > 7), cyanidin indicator will change colour from aquamarine through to green and yellow. The cyanidin indicator turns blue within a pH range of 5 - 7.

Titration is a technique used in analytical chemistry to determine the unknown concentration of a solution. A solution of known concentration is added from a burette to the solution of unknown concentration until the reaction between the two solutions is complete. This known as the endpoint of the experiment. The endpoint of a titration is determined using an indicator which is added to reaction mixture. A colour charge is produced by the indicator at the endpoint of the reaction.

Note: An indicator is a dye of weak organic acids or bases which changes colour with changes in the pH of a solution. Some common indicators are methyl orange, methyl red, phenolphthalein, etc. These indicators are used to monitor the changes in the pH of solutions during a reaction.

Answer:

5,7,6

Explanation:

Took the quiz! Good luck!

Answer:

a. molecules that gain or lose an atom to develop a bonding charge

Explanation:

Answer:

See explanation and image attached

Explanation:

2‑methylhept‑3‑yne can be made by the reaction of the compound shown in the image attached with soidamide in liquid ammonia and 1‑bromopropane.

The first step in the reaction is the deprotonation of the alkyne starting material by the amide ion.

This step is followed a nucleophilic substitution reaction of the alkyne with 1‑bromopropane to yield the 2‑methylhept‑3‑yne product.

Answer:

Explanation:

The chemical reaction of the well-balanced equation is as follows:

[tex]\mathbf{2NiCl_{2(aq)}+2Na_2S_{(aq)} \to 4NaCl_{(aq)}+2NiS_{s}}[/tex]

The aforementioned reaction's ionic equation is:

[tex]\mathbf{2Ni^{2+}_{(aq)}+4Cl^-_{(aq)}+ 4Na^+_{(aq)}+2S^{2-}_{(aq)} \to 4Na^+_{(aq)}+4Cl^-_{(aq)}+2NiS_{(s)}}[/tex]

From above; Na⁺ and Cl⁻ appear on both sides;

Hence, the net ionic equation is:

[tex]\mathbf{2Ni^{2+}_{(aq)}+2S^{2-}_{(aq)} \to 2NiS_{(s)}}[/tex]

Explanation:

Magnesium reacts with dilute hydrochloric acid in a conical flask which is connected to an inverted measuring cylinder in a trough of water. The volume of hydrogen gas produced is measured over a few minutes, and the results are used to plot a graph

This is intended as a class practical. It is best if the students work in pairs because setting up and starting the experiment requires more than one pair of hands. One student can add the magnesium ribbon to the acid and stopper the flask, while the other starts the stopclock. During the experiment, one student can take the readings while the other records them. The experiment itself takes only a few minutes. But allow at least 30 minutes to give students time to set up, take readings and draw graph.

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Answer:

Chloroform.

Explanation:

Given,

Solvent requires 1g of compound per 100 mL

For water,

= 1g/47ml

= 2.1

For Chloroform,

= 1 g/8.1 mL

= 12.345679

For Diethyl ether,

= 1 g/370 mL

= 0.27

For Benzene,

=  1 g/86 mL

= 1.2

Partition coefficients:

Water = -

chloroform = 5.9

Diethyl = .13

Benzene  = .57

The solvent chloroform would be chosen for drawing out the compound out of an aqueous solution as it has the maximum solubility.

Answer:

Sodium arachidate; Sodium palmitate and Sodium palmitate

Explanation:

Triglycerides are esters of fatty acids with glycerol. In triglycerides, three fatty acid molecules are linked by ester bonds to each of the three carbon atoms in a glycerol molecule. The fatty acids may be same or different fatty acid molecules. Hydrolysis of triglycerides yields the three fatty acid molecules and glycerol.

Saponification is the process by which a base is used to catalyst the hydrolysis of the ester bonds in glycerides. The products of this base-catalyzed hydrolysis of triglycerides are the metallic salts of the three fatty acids and glycerol. The salts of the fatty acids are known as soaps.

For a triglyceride that has the fatty acid chains arachidic acid, palmitic acid and palmitic acid attached to the three backbone carbons glycerol, the saponification of the triglyceride with NaOH will yield the sodium salts or soaps of the three fatty acids as well as glycerol.

Arachidic acid will react with NaOH to yield sodium arachidate.

The two palmitic acid molecules will each react with NaOH to yield sodium palmitate.

Answer:

See explanation.

Explanation:

Hello there!

In this case, for this titration problem, we first need to set up the undergoing chemical equation between barium chloride and hydrochloric acid:

[tex]2HCl+Ba(OH)_2\rightarrow BaCl_2+2H_2O[/tex]

Which occurs in a 2:1 mole ratio of acid to base and thus, we can write the following:

[tex]2n_{base}=n_{acid}[/tex]

Which can be written in molarities and volumes:

[tex]2M_{base}V_{base}=M_{acid}V_{acid}[/tex]

And we solve for the molarity of the acid:

[tex]M_{acid}=\frac{2M_{base}V_{base}}{V_{acid}}[/tex]

Unfortunately, the molarity of the base was not given:

"The molarity of an aqueous solution of hydrochloric acid, , is determined by titration with a M barium hydroxide, , solution. If 31.2 mL of barium hydroxide are required to neutralize 15.4 mL of the acid, what is the molarity of the hydrochloric acid solution?"

Yet we can assume an arbitrary value, say 1.0 M in order to show you the solution so that you can modify it according to your given value:

[tex]M_{acid}=\frac{2(1.0M)(31.2mL)}{(15.4mL)}=4.05M[/tex]

So you just need to modify the (1.0 M) by the actually given molarity of the acid.

Regards!

Answer:

0.46 L

Explanation:

In order to solve this problem we need to keep in mind the following definition of molarity:

We now input the given number of moles and molarity:

And calculate how many liters are required:

Answer:

c = π/T*R

c = 0.199M

Explanation:

Is measured to be 5.1 atm at an absolute temperature of 312. K. Write an equation that will let you calculate the molarity c of this solution. Your equation should contain only symbols. Be sure you define each symbol other than R.

The osmotic pressure of a solution, π, is defined as:

π = c*T*R

As we know osmotic pressure π = 5.1atm, T = 312K and R = 0.082atmL/molK

we can replace in the equation as follows:

π= c*T*R

c = 5.1atm/312K*0.082atmL/molK

Answer:

=64.73..

Explanation:

0.750=5L

9.71=x

0.750*x÷0.750=5L*9.71÷0.750

x=48.55÷0.750

x=64.73..

Answer: For the given reaction [tex]Pb(NO_{3})_{2} + AlBr_{3}[/tex] the products are [tex]PBr_{2} + Al(NO_{3})_{3}[/tex].

Explanation:

A reaction in which two substances chemically combine together and results in the formation of a new substance is called a chemical reaction.

For example, [tex]3Pb(NO_{3})_{2} + 2AlBr_{3} \rightarrow 2Al(NO_{3})_{3} + 3PbBr_{2}[/tex]

Products are the species that are written on the right side of an arrow in a chemical reaction equation.

Hence, we can conclude that for the given reaction [tex]Pb(NO_{3})_{2} + AlBr_{3}[/tex] the products are [tex]PBr_{2} + Al(NO_{3})_{3}[/tex].

A distillation column is a process unit in which a feed mixture is separated by multiple partial vaporizations.

It should be noted that distillation simply means a process that has to do with the conversion of liquid into vapor.

In this case, distillation column is a process unit in which a feed mixture is separated by multiple partial vaporizations.

Learn more about distillation on:

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Answer:

The nitrogen atom is sp³ hybridized

This is trigonal pyrymid shape

Explanation:

Step 1: Data given

A compound contains only nitroen (N) and Iodine (I)

The procent of nitrogen by mass = 3.55%

Atomic mass of N = 14.0 g/mol

Atomic mass of I = 126.9 g/mol

Step 2: Calculate mass % of iodine

Mass % iodine = 100 % - 3.55%

Mass % iodine = 96.45 %

Step 3: Calculate number of moles

Let's suppose the total mass = 100 grams

Mass of N = 3.55 grams

Mass of I = 96.45 grams

Moles N = 3.55 grams / 14.0 g/mol = 0.254 moles

Moles I = 96.45 grams / 126.9 g/mol = 0.760 moles

Step 4: Calculate empirical formula

For 0.254 moles N we have 0.760 moles I this is 1:3

This means that for 1 mol N we have 3 moles I

The empirical ( and also the molecular) formula is I3N

The nitrogen atom is sp³ hybridized.

This is trigonal pyrymid shape

Answer:

136 KJ

Explanation:

We'll begin by calculating the heat required to melt the ice. This can be obtained as follow:

Mass (M) = 250 g

Heat of fusion (Hբ) = 334 J/gºC

Heat (Q₁) required to melt the ice =?

Q₁ = MHբ

Q₁ = 250 × 334

Q₁ = 83500 J

Next, we shall determine the heat required to change the temperature. This can be obtained as follow:

Mass (M) = 250 g

Initial temperature (T₁) = 0 °C

Final temperature (T₂) = 50 °C

Specific heat capacity (C) = 4.184 J/gºC

Heat (Q₂) required to change the temperature =?

Q₂ = MC(T₂ – T₁)

Q₂ = 250 × 4.184 (50 – 0)

Q₂ = 1046 × 50

Q₂ = 52300 J

Next, we shall determine the total heat required.

Heat (Q₁) required to melt the ice = 83500 J

Heat (Q₂) required to change the temperature = 52300 J

Total heat (Qₜ) required =?

Qₜ = Q₁ + Q₂

Qₜ = 83500 + 52300

Qₜ = 135800 J

Finally, we shall convert 135800 J to KJ. This can be obtained as follow:

1000 J = 1 KJ

Therefore,

135800 J = 135800 J × 1 KJ / 1000 J

135800 J ≈ 136 KJ

Thus, the total heat required is 136 KJ.

Answer:

1. 12 molecules

2. 10 grams

3. ?

Explanation:

for number one, you simply. multiblu the 02 by 6 an that is 12, the same goes for number two. now for the third one i di not know. i am sorry and i hope this helps.

Answer:

0.170 M

Explanation:

As this is a series of dilutions, we can continuosly use the C₁V₁=C₂V₂ formula to solve this problem:

For the first step:

Then for when 129 mL of that 0.412 M are diluted by adding 183 mL of water:

Using C₁V₁=C₂V₂:

Answer:

19 because it gained 3 electron so 12-3=9 beryllium

2

3 is 46-2=44

4 is 2

5 is 5

6 84 polonium

7

8 oxygen

Explanation:

plz let me know if they are right or wrong:)

Answer:

A duckling swimming after its own mother

Explanation:

Answer:

10.70grams

Explanation:

Density of a substance = mass/volume

At STP of a gas (standard temperature and pressure), the density of oxygen gas is 1.429 g/L

Hence, according to this question, in 7.49 L of oxygen gas, there would be:

Using D = m/V

1.429 = m/7.49

m = 1.429g/L × 7.49L

m = 10.70g

Answer:

The correct answer is 1.498.

Explanation:

Based on the given information, the volume of NaOH needed for the titration is 14.53 ml, and the concentration of NaOH given is 0.1031 M.

The volume of NaOH, that is, 14.53 ml can also be written as 14.53 × 10⁻³ L.

The concentration of NaOH, that is, 0.1031 M can also be written as 0.1031 moles/Litre.

Molarity (M) is determined as,

M = No of moles/Volume in litres

No of moles = Molarity × Litres

No of moles = 0.1031 moles/Litres × 14.53 × 10⁻³ L

No of moles = 1.498 × 10⁻³ L

Now, number of millimoles = 1.498 × 10⁻³ L × 1000 (millimoles = moles × 1000)

Number of millimoles = 1.498

The number of millimoles of NaOH required for the titration is 1.50 mmol

From the question,

We are to determine the number of millimoles of NaOH required for the titration

From the given information

The titration required 14.53 mL of 0.1031 M NaOH solution

From the formula

Number of moles = Concentration × Volume

Concentration of the NaOH = 0.1031 M

Volume of the NaOH = 14.53 mL

∴ Number of millimoles of NaOH required = 0.1031 × 14.53

Number of millimoles of NaOH required = 1.498043 mmol

Number of millimoles of NaOH required ≅ 1.50 mmol

Hence, the number of millimoles of NaOH required for the titration is 1.50 mmol

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Answer:

Explanation:

here is your answer:

Answer: The concentration of [tex]H^+[/tex] in the solution is [tex]3.16\times 10^{-3}M[/tex]

Explanation:

pH is defined as the negative logarithm of hydrogen ion concentration present in the solution.

[tex]pH=-\log [H^+][/tex]      .....(1)

We are given:

pH of solution = 2.5

Putting values in equation 1, we get:

[tex]2.5=-\log [H^+][/tex]

[tex][H^+]=10^{-2.5}[/tex]

[tex][H^+]=3.16\times 10^{-3}M[/tex]

Hence, the concentration of [tex]H^+[/tex] in the solution is [tex]3.16\times 10^{-3}M[/tex]