Answer:
1+78=133
1=133-78
1=55
9 x (-3) + (-15) ÷ 3
Answer:
-32
Step-by-step explanation:
9(-3) + (-15) ÷ 3 =
-27 + -5 = -32
If my answer is incorrect, pls correct me!
If you like my answer and explanation, mark me as brainliest!
-Chetan K
Answer:-32
Step-by-step explanation:
solve the following
2x+6 = 7x-14
Answer:
x=4 :)))))))))
Step-by-step explanation:
"-+_$-5_(#-3(
Answer:
x = 4
Step-by-step explanation:
2x + 6 = 7x - 14
2x + 6 - 2x + 14 = 7x - 14 - 2x + 14 ----> To put the variables on one side and the numbers on the other side
20 = 5x --> Simplifying
x = 20/5 --> Flipping the equation and then dividing 5 on both sides
x = 4 --> Simplifying
Hope this helps explain! <3
Evaluate: 2^-4=
A1/8
B-16
C1/16
D-8
Answer:
C) 1/16
Step-by-step explanation:
2*2*2*2=16
Therefore, 2^(-4)=1/16.
Answer:
C) [tex]\frac{1}{16}[/tex]
Step-by-step explanation:
2⁻⁴
2⁴ = 2 × 2 × 2 × 2 = 16
[tex]\frac{1}{16}[/tex]
Work out the following calculations and give your answers to the nearest 1000
a) 251 x 638
Answer:
160,000
Step-by-step explanation:
251
× 638
_______________
2008
753
+ 1506
__________________
160138
Product to the nearest thousand = 160,000
Which angle is NOT coterminal with 110 degrees
-250degrees
480degrees
-110 degrees
830 degrees
From a population of 200 elements, the standard deviation is known to be 14. A sample of 49 elements is selected. It is determined that the sample mean is 56. The standard error of the mean is _____. a. 2 b. greater than 2 c. 3 d. less than 2
Answer:
a. 2
Step-by-step explanation:
Central Limit Theorem
The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean [tex]\mu = p[/tex] and standard deviation [tex]s = \sqrt{\frac{p(1-p)}{n}}[/tex]
Standard deviation is known to be 14.
This means that [tex]\sigma = 14[/tex]
Sample of 49
This means that [tex]n = 49[/tex]
The standard error of the mean is
[tex]s = \frac{\sigma}{\sqrt{n}} = \frac{14}{\sqrt{49}} = \frac{14}{7} = 2[/tex]
So the correct answer is given by option a.
Which represents the value of s in s + 12 = 100?
Answer:
S = 88
Step-by-step explanation:
s + 12 = 100
-12 -12
s = 88
The value of s in s + 12 = 100 is 88
How to determine the value of s?The equation is given as:
s + 12 = 100
Add -12 to both sides of the equation
s = 100 -12
Evaluate
s = 88
Hence, the value of s in s + 12 = 100 is 88
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The width of rectangle is 6 fr less than the lengthThe area of the rectangle is 247f Find the lengthand with of the rectangle
Answer:
i don't know 241 I think sorry
Find the 8th term of the sequence
100, 20, 4, 4/5
__
1/4096
25/16394
25/256
4/3125
9514 1404 393
Answer:
(d) 4/3125
Step-by-step explanation:
The first term is 100 and the common ratio is 20/100 = 1/5. The explicit formula for terms of a geometric sequence is ...
an = a1·r^(n-1)
an = 100·(1/5)^(n-1)
Then the 8th term is ...
a8 = 100 ·(1/5)^(8-1) = 100·5^(-7) = 4/3125
Answer:
[tex]d. \: \frac{4}{3125} [/tex]
Step-by-step explanation:
HOPE IT HELPS MUCH UNTO YOUHelppppp 78 squared to the 3rd
Given the Graph, identify the y-intercept
Answer:
5
Step-by-step explanation:
Draw and label the circle given by the equation (x - 5 + y + 10 = 6^2
Answer:
See attachment for circle
Step-by-step explanation:
Given
[tex](x -5)^2 + (y + 10)^2 = 6^2[/tex]
Required
Draw and label the circle
The equation of a circle is:
[tex](x -a)^2 + (y - b)^2 = r^2[/tex]
Where:
[tex]Center = (a,b)[/tex]
[tex]Radius = r[/tex]
So, we have:
[tex]Center = (5,-10)[/tex]
[tex]Radius = 6[/tex]
See attachment for circle
You have land that you would like to use to create two distinct fenced-in areas in the shape given below. You have 410 meters of fencing materials to use. What values of x and y would result in the maximum area that you can enclose
Answer:
[tex]x = \frac{205}{3}[/tex]
[tex]y =\frac{195}{4}[/tex]
Step-by-step explanation:
Given
[tex]p = 410[/tex] --- perimeter
See attachment for fence
Required
x and y
The perimeter of the fence is:
[tex]p = 2(x + y +5 + y) +x[/tex]
Open bracket
[tex]p = 2x + 2y +10 + 2y +x[/tex]
Collect like terms
[tex]p = 2x+x + 2y + 2y+10[/tex]
[tex]p = 3x + 4y+10[/tex]
Substitute: [tex]p = 410[/tex]
[tex]3x + 4y+10 =410[/tex]
Make 4y the subject
[tex]4y =410-10-3x[/tex]
[tex]4y =400-3x[/tex]
Make y the subject
[tex]y =\frac{400-3x}{4}[/tex]
The area (A) of the fence is:
[tex]A = (y + y + 5) * x[/tex]
[tex]A = (2y + 5) * x[/tex]
Substitute: [tex]y =\frac{400-3x}{4}[/tex]
[tex]A = (2*\frac{400-3x}{4} + 5) * x[/tex]
[tex]A = (\frac{400-3x}{2} + 5) * x[/tex]
Take LCM
[tex]A = (\frac{400-3x+10}{2}) * x[/tex]
Solve like terms
[tex]A = (\frac{410-3x}{2}) * x[/tex]
Open bracket
[tex]A = \frac{410x-3x^2}{2}[/tex]
Remove fraction
[tex]A = 205x-1.5x^2[/tex]
Differentiate both sides
[tex]A' = 205 - 3x[/tex]
To maximize; set [tex]A' =0[/tex]
[tex]205 - 3x =0[/tex]
Solve for 3x
[tex]3x = 205[/tex]
Solve for x
[tex]x = \frac{205}{3}[/tex]
Recall that: [tex]y =\frac{400-3x}{4}[/tex]
So, we have:
[tex]y =\frac{400-3*205/3}{4}[/tex]
[tex]y =\frac{400-205}{4}[/tex]
[tex]y =\frac{195}{4}[/tex]
j-27.5=3.9 solve for the variable
Answer:
31.4
Step-by-step explanation
I think
Use the order of operations to simplify the given expression. −2⋅[16÷(8−4)2]2
2. Identify the variables that are contained in the expression.
2m2 + 3mn + 4p
Answer:
m, n and p
Step-by-step explanation:
Given
[tex]2m^2 + 3mn + 4p[/tex]
Required
List out the variables
Literally, the variables are the alphabets in the expression
And they are:
m, n and p
please help me pleaseee!!
Answer:
AOB = 65
DOE = 35
AOC = 90
EOB = 115
DOB = 80
a line and a line segment are exactly the same. true or false
Answer:
false
Step-by-step explanation:
a line is infinite but a line segment has starting and end point. line segment is a small segment taken out from that infinite line
PLS HELP!! need the answer asap
Answer:
1.) 113 degrees and 2.) 67 degrees
Step-by-step explanation:
(x + 33) + (x - 13) = 180
Add like terms:
2x + 20 = 180
2x = 160
x = 80
x + 33 =
80 + 33 =
113 =
x - 13 =
80 - 13 =
67 =
Which associations best describe the scatter plot?
Select each correct answer.
A) Nonlinear association
B) Positive association
C) Negative association
D) Linear association
Answers:
C) Negative association
D) Linear association
PLEASE HELP! Two gears are connected and are rotating simultaneously. The smaller gear has a radius of 4 inches, and the larger gear has a radius of 9 inches. Part 1: What is the angle measure, in degrees and rounded to the nearest tenth, through which the larger gear has rotated when the smaller gear has made one complete rotation? Part 2: How many rotations will the smaller gear make during one complete rotation of the larger gear?
Step-by-step explanation:
(1) 4/9 × 360° = 160°
(2) 9/4 rotations or 2¼ rotations
If f(x)=1/x
and g(X) = x-2, which of the following is the graph of
(f•g)(x)?
Answer:
The correct answer would be A) on edge.
Step-by-step explanation:
Edge 2021.
Which expression is equivalent to 250 + 150 ?
Answer:
if 25c + 15d = 0, then d = -25/15c
Step-by-step explan
just yes, that
Find the value x in the triangle shown below
Answer: 70º
Step-by-step explanation:there are two angles with the same measurement on the vertices, therefore with the same angle. A triangle has a sum of 180º in the inside angles. 55º+55º=110º, and 180º-110=70º
If 4 containers of yogurt cost $2.76, how many containers of yogurt can you purchase with $9.66?
14 containers
2.76 / 4 = 0.69
9.66/0.69= 14 containers
Joe bought a car for $9,000 in 2013. His purchase has depreciated 2.5% every year since then. What was his car worth in 2019 to the nearest dollar?
a. $7650
b. $7732
C. $8350
d. $1602
Answer:
b. $7732
Step-by-step explanation:
Value of a depreciating product:
The value of a depreciating product, after t years, is given by:
[tex]V(t) = V(0)(1 - r)^t[/tex]
In which V(0) is the initial value and r is the decay rate, as a decimal.
Joe bought a car for $9,000 in 2013. His purchase has depreciated 2.5% every year since then.
This means that [tex]V(0) = 9000, r = 0.025[/tex]. So
[tex]V(t) = V(0)(1 - r)^t[/tex]
[tex]V(t) = 9000(1 - 0.025)^t[/tex]
[tex]V(t) = 9000(0.975)^t[/tex]
What was his car worth in 2019 to the nearest dollar?
2019 is 2019 - 2013 = 6 years after 2013, so this is V(6).
[tex]V(6) = 9000(0.975)^6 = 7732[/tex]
The correct answer is given by option b.
FAST HELP PLEASE
A Square weighs 7 grams and a Triangle weighs 8 grams. How much does a Circle weight
Answer:
69420
Step-by-step explanation:
6
ayudaaaaa por favor
Answer:
La respuesta es treinta coma seis.
Espero que esto ayude.
PLEASE ANSWER ASAP!!! FULL ANSWERS ONLY!!!!!! WILL GIVE BRAINLIEST!!!!!!!!!
Two cyclists, 68 miles apart, start riding toward each other at the same time. One cycles 3 miles per hour faster than the other, and they meet after 4 hours of riding.
a. Write an equation using the information as it is given above that can be solved to answer this problem. Use the variable r to represent the speed of the slower cyclist.
b. What are the speeds of the two cyclists? _______________
Answer:
4r + 4(r + 3) = 68
r = 7 miles per hour
r + 3 = 10 miles per hour
Step-by-step explanation:
distance = rate * time
a)
4r + 4(r + 3) = 68
Distribute
4r + 4r + 12 = 68
8r + 12 = 68
8r = 56
r = 7 miles per hour
r + 3 = 10 miles per hour
a) The given equation using the information as it is given above that can be solved to answer this problem is 4r + 4(r+3) = 68
b) The speed of both cyclists are 3mi/hr and 10mi/hr respectively
The formula for calculating the distance covered is expressed as:
Distance = speed * time
Let the speed covered by one cyclist be t
If one cycles 3 miles per hour faster than the other, the speed of the other will be t + 3
If both meet after 4 hours of riding, then their time will be 4 hours
Distance covered the first cyclist = 4r
Distance covered by the second = 4(r+3)
If the two cyclists are 68 miles apart, then:
4r + 4(r+3) = 68
a) The given equation using the information as it is given above that can be solved to answer this problem is 4r + 4(r+3) = 68
b) Expand the equation in a to get "r"
4r + 4r + 12 = 68
8r + 12 = 68
8r = 68 - 12
8r = 56
r = 56/8
r = 7miles per hour
Speed of the first cyclist = 7mi/hr
Speed of the second cyclist = 3 + 7mi/hr = 10mi/hr
Hence the speed of both cyclists are 3mi/hr and 10mi/hr respectively
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I need help solving this. Help!!!!!
Answer:
48
Step-by-step explanation:
MPQ + QPN = MPN
9x-6 + 5x+7 = 85
Combine like terms
14x+1 = 85
Subtract 1 from each side
14x+1-1 = 85-1
14x = 84
Divide by 14
14x/14 = 84/4
x=6
We want MPQ
MPW = 9x-6 = 9*6 -6 = 54-6 =48