An electron in a hydrogen atom drops from the n= 3
energy level to the n=2 energy level. The energy of
the emitted photon is
A) 1.89 eV
C) 1.51 eV
B) 3.40 eV
D) 4.91 eV

Answer:

In a truss bridge, two long - usually straight members known as chords - form the top and bottom; they are connected by a web of vertical posts and diagonals. The bridge is supported at the ends by abutments and sometimes in the middle by piers.

Explanation:

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Answer:

9.7 miles per second

Explanation:

divide 200 by 20.6

Answer:

10N/m

Explanation:

Using F=kx

F=mg

k=mg/x

k=0.1*10/0.1 (kg*m/s^2)/m

10N/m

Answer: 43.7

Explanation: Simply round the number so that there are only three digits in the number.

We have that 43.659 rounded to three significant digits is

[tex]43.659=43.7[/tex]

From the Question we are Given

Integer=43.659

To round off to three significant digits means to represent only three digits

Therefore

43.659 in  three digits is

[tex]43.659=43.7[/tex]

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Answer is 29.1 mol or 525 g

Explanation:

Light is a form of electromagnetic radiation with a wavelength which can be detected by the human eye. It is a small part of the electromagnetic spectrum and radiation given off by stars like the sun. Animals can also see light. The study of light, known as optics, is an important research area in modern physics.

Answer:

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Answer:

it reheated and use form another

[tex] \orange{\underline{\huge{\bold{\textit{\green{\bf{QUESTION}}}}}}}[/tex]

The apparent depth of an object at the bottom of a tank filled with a liquid of refractive index 1.3 is 7.7 cm. What is the actual depth of the liquid in the tank?

[tex]{\bold{\blue{GIVEN}}}[/tex]

REFRACTIVE INDEX = 1.3

APPARENT DEPTH = 7.7 cm

[tex]{ \bold{\green{To \: Find}}}[/tex]

REAL DEPTH OF THE OBJECT.

[tex]{\red{FORMULA \: \: USED }}[/tex]

[tex]Reflective \: Index = \frac{Real \: Depth}{Apparent \: Depth } [/tex]

[tex] \huge\mathbb{\red A \pink{N}\purple{S} \blue{W} \orange{ER}}[/tex]

Refractive Index = 1.3

Apparent Depth = 7.7 cm

Putting the values in the formula:-

[tex]Reflective \: Index = \frac{Real \: Depth}{Apparent \: Depth } \\ \\ 1.3 = \frac{Real \: Depth}{7.7 \: cm} \\ \\ 1.3 \times 7.7 = Real \: Depth \\ \\ 10.01 \: \: cm = Real \: Depth[/tex]

Answer:

 U = 25 J

Explanation:

The energy in a set of charges is given by

          U = [tex]k \sum \frac{q_i}{r_i}[/tex]

in this case we have three charges of equal magnitude

          q = q₁ = q₂ = q₃

with the configuration of an equilateral triangle all distances are worth

          d = a

          U = k ( [tex]\frac{q_1q_2}{ r_1_2 } + \frac{q_1q_3}{r_1_3} + \frac{q_2q_3}{r_2_3}[/tex] )

we substitute

           15 = k q² (3 / a)

            k q² /a = 5

For the second configuration a load is moved to the measured point of the other two

          d₁₃ = a

The distance to charge 2 that is at the midpoint of the other two is

          d₁₂ = d₂₃ = a / 2

           U = k (\frac{q_1q_2}{ r_1_2 } + \frac{q_1q_3}{r_1_3} + \frac{q_2q_3}{r_2_3})

            U = k q² (  [tex]\frac{2}{a} + \frac{1}{a} + \frac{2}{a}[/tex] )

            U = (kq² /a) 5

substituting

            U = 5 5

            U = 25 J

Answer:

8.5 Ω

Explanation:

La resistencia de un material es directamente proporcional a su longitud e inversamente proporcional al área de la sección transversal.

La fórmula de la resistencia (R) viene dada por:

R = ρL/A

Donde ρ es la resistividad del material, L es la longitud del material y A es el área de la sección transversal del material.

Dado que:

L = 1 km = 1000 m, A = 2 mm² = 2 * 10⁻⁶ m², ρ (cobre) = 1.7 * 10⁻⁸ Ωm

Sustituyendo da:

R = 1,7 * 10⁻⁸ * 1000/2 * 10⁻⁶

R = 8.5 Ω

Explanation:

the rate at which someone or something moves or operates or is able to move or operate.

Answer:

   I = 2.667 kg m²

Explanation:

The moment of inertia of a body can be calculated by the expression

         I = ∫ L² dm

For high symmetry bodies the expressions of the moment of inertia are tabulated, for a rod with its axis of rotation at its midpoint it is

         I = [tex]\frac{1}{12}[/tex] m L²

let's calculate

         I = [tex]\frac{1}{12}[/tex]  2  4²

         I = 2.667 kg m²