Answer:
false
Explanation:
One gram of a compound requires the following quantities of solvent to dissolve: 47 mL of water, 8.1 mL of chloroform, 370 mL of diethyl ether, or 86 mL of benzene. Calculate the solubility of the compound in these four solvents (as g/100 mL). Estimate the partition coefficient of the compound between chloroform and water, ethyl ether and water, and benzene and water. Which solvent would you choose to extract the compound from an aqueous solution
Answer:
Chloroform.
Explanation:
Given,
Solvent requires 1g of compound per 100 mL
For water,
= 1g/47ml
= 2.1
For Chloroform,
= 1 g/8.1 mL
= 12.345679
For Diethyl ether,
= 1 g/370 mL
= 0.27
For Benzene,
= 1 g/86 mL
= 1.2
Partition coefficients:
Water = -
chloroform = 5.9
Diethyl = .13
Benzene = .57
The solvent chloroform would be chosen for drawing out the compound out of an aqueous solution as it has the maximum solubility.
Suppose a soap manufacturer starts with a triglyceride that has the fatty acid chains arachidic acid, palmitic acid and palmitic acid attached to the three backbone carbons. The manufacturer saponifies the triglyceride with NaOH. What are the fatty acid soaps that are produced in the process
Answer:
Sodium arachidate; Sodium palmitate and Sodium palmitate
Explanation:
Triglycerides are esters of fatty acids with glycerol. In triglycerides, three fatty acid molecules are linked by ester bonds to each of the three carbon atoms in a glycerol molecule. The fatty acids may be same or different fatty acid molecules. Hydrolysis of triglycerides yields the three fatty acid molecules and glycerol.
Saponification is the process by which a base is used to catalyst the hydrolysis of the ester bonds in glycerides. The products of this base-catalyzed hydrolysis of triglycerides are the metallic salts of the three fatty acids and glycerol. The salts of the fatty acids are known as soaps.
For a triglyceride that has the fatty acid chains arachidic acid, palmitic acid and palmitic acid attached to the three backbone carbons glycerol, the saponification of the triglyceride with NaOH will yield the sodium salts or soaps of the three fatty acids as well as glycerol.
Arachidic acid will react with NaOH to yield sodium arachidate.
The two palmitic acid molecules will each react with NaOH to yield sodium palmitate.
The molarity of an aqueous solution of hydrochloric acid, , is determined by titration with a M barium hydroxide, , solution. If 31.2 mL of barium hydroxide are required to neutralize 15.4 mL of the acid, what is the molarity of the hydrochloric acid solution?
Answer:
See explanation.
Explanation:
Hello there!
In this case, for this titration problem, we first need to set up the undergoing chemical equation between barium chloride and hydrochloric acid:
[tex]2HCl+Ba(OH)_2\rightarrow BaCl_2+2H_2O[/tex]
Which occurs in a 2:1 mole ratio of acid to base and thus, we can write the following:
[tex]2n_{base}=n_{acid}[/tex]
Which can be written in molarities and volumes:
[tex]2M_{base}V_{base}=M_{acid}V_{acid}[/tex]
And we solve for the molarity of the acid:
[tex]M_{acid}=\frac{2M_{base}V_{base}}{V_{acid}}[/tex]
Unfortunately, the molarity of the base was not given:
"The molarity of an aqueous solution of hydrochloric acid, , is determined by titration with a M barium hydroxide, , solution. If 31.2 mL of barium hydroxide are required to neutralize 15.4 mL of the acid, what is the molarity of the hydrochloric acid solution?"
Yet we can assume an arbitrary value, say 1.0 M in order to show you the solution so that you can modify it according to your given value:
[tex]M_{acid}=\frac{2(1.0M)(31.2mL)}{(15.4mL)}=4.05M[/tex]
So you just need to modify the (1.0 M) by the actually given molarity of the acid.
Regards!
The osmotic pressure exerted by a solution is equal to the molarity multiplied by the absolute temperature and the gas constant . Suppose the osmotic pressure of a certain solution is measured to be at an absolute temperature of .
Answer:
c = π/T*R
c = 0.199M
Explanation:
Is measured to be 5.1 atm at an absolute temperature of 312. K. Write an equation that will let you calculate the molarity c of this solution. Your equation should contain only symbols. Be sure you define each symbol other than R.
The osmotic pressure of a solution, π, is defined as:
π = c*T*R
As we know osmotic pressure π = 5.1atm, T = 312K and R = 0.082atmL/molK
we can replace in the equation as follows:
π= c*T*R
c = π/T*Rc = 5.1atm/312K*0.082atmL/molK
c = 0.199M
How many products might be formed on chlorination of o-xylene (o-dimethylbenzene), m-xylene, and p-xylene
1.Consider the molecule azulene and
a) set the secular determinant for azulene within the huckel approximation and using the out of plane C2p orbitals as basis set.
b) Estimate pi electron binding energy within the Huckel approximation
c) Approximate the delocalization energy
Someone pls help me ::/:/
How much energy must be added to 250.0 g of ice at 0.00 °C to raise the
temperature of the water to 50.0 °C? The heat of fusion for water is 334
J/g. The specific heat of water is 4.184 J/g.K.
Answer:
136 KJ
Explanation:
We'll begin by calculating the heat required to melt the ice. This can be obtained as follow:
Mass (M) = 250 g
Heat of fusion (Hբ) = 334 J/gºC
Heat (Q₁) required to melt the ice =?
Q₁ = MHբ
Q₁ = 250 × 334
Q₁ = 83500 J
Next, we shall determine the heat required to change the temperature. This can be obtained as follow:
Mass (M) = 250 g
Initial temperature (T₁) = 0 °C
Final temperature (T₂) = 50 °C
Specific heat capacity (C) = 4.184 J/gºC
Heat (Q₂) required to change the temperature =?
Q₂ = MC(T₂ – T₁)
Q₂ = 250 × 4.184 (50 – 0)
Q₂ = 1046 × 50
Q₂ = 52300 J
Next, we shall determine the total heat required.
Heat (Q₁) required to melt the ice = 83500 J
Heat (Q₂) required to change the temperature = 52300 J
Total heat (Qₜ) required =?
Qₜ = Q₁ + Q₂
Qₜ = 83500 + 52300
Qₜ = 135800 J
Finally, we shall convert 135800 J to KJ. This can be obtained as follow:
1000 J = 1 KJ
Therefore,
135800 J = 135800 J × 1 KJ / 1000 J
135800 J ≈ 136 KJ
Thus, the total heat required is 136 KJ.
A 59.0 mL portion of a 1.80 M solution is diluted to a total volume of 258 mL. A 129 mL portion of that solution is diluted by adding 183 mL of water. What is the final concentration
Answer:
0.170 M
Explanation:
As this is a series of dilutions, we can continuosly use the C₁V₁=C₂V₂ formula to solve this problem:
For the first step:
59.0 mL * 1.80 M = 258 mL * C₂C₂ = 0.412 MThen for when 129 mL of that 0.412 M are diluted by adding 183 mL of water:
V₂ = 129 mL + 183 mL = 312 mLUsing C₁V₁=C₂V₂:
129 mL * 0.412 M = 312 mL * C₂C₂ = 0.170 M1. An ion has a net charge of - 3, and 12 electrons, what is its atomic number? What element has that atomic number?
2. An ion of Celsius has a net charge of -5, how many electrons does it have?
3. Some atom has an atomic number of 46, how many electrons does it have if it has a net charge of +2?
4. How many neutrons are in an atom of Helium, and what is its mass number?
5. There are 3 neutrons in an isotope of Helium, what is its mass number?
6. n isotope has 83 neutrons and a mass number of 167, what is its atomic number? What element is defined by that atomic number?
7. What element has 54 neutrons and a mass number of 112?
8. What element has 10 electrons, a net charge of -2?
Answer:
19 because it gained 3 electron so 12-3=9 beryllium
2
3 is 46-2=44
4 is 2
5 is 5
6 84 polonium
7
8 oxygen
Explanation:
plz let me know if they are right or wrong:)
. Which is instinctive behavior? A. A puppy cuddling its human owner.C. A young child learned how to read. B. A duckling swimming after its mother.D. A kitten learning to use a litter box.
Answer:
A duckling swimming after its own mother
Explanation:
How many grams of 02 are present in 7.49 L of oxygen gas?
Answer:
10.70grams
Explanation:
Density of a substance = mass/volume
At STP of a gas (standard temperature and pressure), the density of oxygen gas is 1.429 g/L
Hence, according to this question, in 7.49 L of oxygen gas, there would be:
Using D = m/V
1.429 = m/7.49
m = 1.429g/L × 7.49L
m = 10.70g
A 100.0 mL sample of natural water was titrated with NaOH. The titration required 14.53 mL of 0.1031 M NaOH solution to reach a light pink phenolphthalein end point.
Calculate the number of millimoles of NaOH required for the titration.
Answer:
The correct answer is 1.498.
Explanation:
Based on the given information, the volume of NaOH needed for the titration is 14.53 ml, and the concentration of NaOH given is 0.1031 M.
The volume of NaOH, that is, 14.53 ml can also be written as 14.53 × 10⁻³ L.
The concentration of NaOH, that is, 0.1031 M can also be written as 0.1031 moles/Litre.
Molarity (M) is determined as,
M = No of moles/Volume in litres
No of moles = Molarity × Litres
No of moles = 0.1031 moles/Litres × 14.53 × 10⁻³ L
No of moles = 1.498 × 10⁻³ L
Now, number of millimoles = 1.498 × 10⁻³ L × 1000 (millimoles = moles × 1000)
Number of millimoles = 1.498
The number of millimoles of NaOH required for the titration is 1.50 mmol
From the question,
We are to determine the number of millimoles of NaOH required for the titration
From the given information
The titration required 14.53 mL of 0.1031 M NaOH solution
From the formula
Number of moles = Concentration × Volume
Concentration of the NaOH = 0.1031 M
Volume of the NaOH = 14.53 mL
∴ Number of millimoles of NaOH required = 0.1031 × 14.53
Number of millimoles of NaOH required = 1.498043 mmol
Number of millimoles of NaOH required ≅ 1.50 mmol
Hence, the number of millimoles of NaOH required for the titration is 1.50 mmol
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A solution has a pH of 2.5. what is the H+
Answer: The concentration of [tex]H^+[/tex] in the solution is [tex]3.16\times 10^{-3}M[/tex]
Explanation:
pH is defined as the negative logarithm of hydrogen ion concentration present in the solution.
[tex]pH=-\log [H^+][/tex] .....(1)
We are given:
pH of solution = 2.5
Putting values in equation 1, we get:
[tex]2.5=-\log [H^+][/tex]
[tex][H^+]=10^{-2.5}[/tex]
[tex][H^+]=3.16\times 10^{-3}M[/tex]
Hence, the concentration of [tex]H^+[/tex] in the solution is [tex]3.16\times 10^{-3}M[/tex]
What mass of sodium hydroxide is needed to make 12.5 L of a 0.150M solution?
a) 1.88g
b) 40.0g
c) 75.0g
d) 83.0g
Answer:
75g
Explanation:
n=Cmxv
=0,15x12,5
=1,875 mol
m=nxM
=1,875x40
=75g
When aqueous solutions of AgNO3 and MgCl2 are mixed, a precipitate forms. What is the correct formula for the precipitate
Answer:
AgCl
Explanation:
The reaction that takes place is:
2AgNO₃ (aq) + MgCl₂ (aq) → Mg(NO₃) (aq) + 2AgCl (s)The precipitate (meaning a solid substance) formed is silver chloride, AgCl.
All salts formed with silver and a halogen (F, Cl, Br, I) are insoluble in water, meaning that when working with aqueous solutions they will be precipitates.
Provide the IUPAC names for
the following structures
CH2CH3
w
CH2CH:
(b) H-C-N
CH.CH
H-EN
N
H
(c)
OCH2CH3
Answer:
For a: The IUPAC name of the compound is N-ethylethaneamide.
For b: The IUPAC name of the compound is N,N-diethylmethaneamide.
For c: The IUPAC name of the compound is ethyl pentanoate
Explanation:
To name a compound, first look for the longest possible carbon chain.
For a:Amide group is a type of functional group where an amine group is attached to a carbonyl group. The general formula of amide is [tex]R-CO-NH_2[/tex], where R is an alkyl or aryl group.
In part (a), the alkyl group has 2 carbon atoms and thus, the prefix used is 'eth-'
Also, an ethyl substituent is directly attached to N-atom. It is an alkane structured hydrocarbon thus, the suffix used will be '-ane'
Hence, the IUPAC name of the compound is N-ethylethaneamide.
For b:Amide group is a type of functional group where an amine group is attached to a carbonyl group. The general formula of amide is [tex]R-CO-NH_2[/tex], where R is an alkyl or aryl group.
In part (b), the alkyl group has 1 carbon atoms and thus, the prefix used is 'meth-'
Also, two ethyl substituents are directly attached to N-atom. It is an alkane structured hydrocarbon thus, the suffix used will be '-ane'
Hence, the IUPAC name of the compound is N,N-diethylmethaneamide.
For c:Esters are a kind of organic molecules having functional groups, [tex]R-COO-R'[/tex] where R and R' are the alkyl or aryl groups. They are formed by the combination of alcohol and carboxylic acid.
These functional group compounds are named in two words which is alkyl alkanoates, where alkyl refers to the alcoholic part and alkanoate refers to the carboxylic acid part of the molecule. The numbering of the parent chain in esters is done from the carboxylic carbon. The alkyl part is not given any numbers.
In part (c), there are 5 carbon atoms present in a straight chain and thus, the prefix used is 'pent-'
Also, an ethyl group forms the alcoholic part.
Hence, the IUPAC name of the compound is ethyl pentanoate
Gasoline and motor oil are chemically similar. They are both mixtures of nonpolar hydrocarbons
containing carbon and hydrogen atoms. However, motor oil is much more viscous than gasoline. Which
substance probably has the higher average molar mass?
Answer:
motor oil
Explanation:
According to Oxford dictionary, viscosity refers to ''a quantity expressing the magnitude of internal friction in a fluid, as measured by the force per unit area resisting uniform flow.''
The higher the molecular weight of a substance, the greater its viscosity. This is because, the long chains in the viscous substance become entangled thereby increasing the internal friction in the liquid.
Motor oil is a heavier hydrocarbon than gasoline hence it is more viscous than gasoline.
Answer:
Motor oil
Heat it
Water
Explanation:
The pH of the ocean is 8.1. What is the concentration of hydronium ions?
Answer:
7.9 × 10⁻⁹ M
Explanation:
Step 1: Given data
pH of the ocean: 8.1
Step 2: Calculate the concentration of hydronium ions
We will use the definition of pH.
pH = -log [H⁺] = -log [H₃O⁺]
[H₃O⁺] = [H⁺] = antilog -pH
[H₃O⁺] = antilog -8.1 = 7.9 × 10⁻⁹ M
Since [H₃O⁺] < 10⁻⁷ M, the solution is basic.
How many molecules are in 4.44 mol of CF4? 4.44 mol CF4 =
I am not sure abt the ans
molar mass= 88
1 molecule = 6.022×10^23
4.44 moles = 6.022×10^23×4.44/88
= 26.73768 × 10^23/88
= 0.3038372727 ×10^23
Which example shows a double replacement reaction?
Answer:
KCl + AgNO₃ —> AgCl + KNO₃
Explanation:
To answer the question correctly, we must understand the definition of a double displacement reaction.
A double displacement reaction is a reaction in which the ions of the two reacting compounds exchange to form new compounds different from the two reacting compounds. Example is given below:
XY + AB —> XB + AY
Considering the options given in the question above, only the equation:
KCl + AgNO₃ —> AgCl + KNO₃
Satisfy the definition of a double displacement reaction.
Define solubility. the amount of a substance that will dissolve in a given amount of solvent a solid mixed with another solid a liquid that does not dissolve in another liquid the amount of a substance that will dissolve in a given amount of solute a solid that does not dissolve in a gas
Answer:
You answered your own question
The solubility of a substance is the amount of the substance that can be dissolved in a given amount of solvent at a specified temperature. Hence, option A is correct.
What is solubility ?Solubility of a substance can be defined as the fraction of concentration of the substance which can be dissolved in a particular amount of a solvent at a specified temperature.
Solubility of a substance depends on the bond type, temperature, pressure and presence of impurities if any. If the bond strength is greater, less will be the solubility because, greater energy is needed to weaken the bonds in the salt.
Similarly, for most of the salts, as the temperature increases, solubility increases, but some salt's solubility is independent of the temperature such as for NaCl. Therefore, the correct definition of solubility is option A.
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Which additional product balances the reaction h2so4+2naoh>na2so4
Answer:
H 4so8 is the answer of balance the reaction
what will happen to the initial rate of the reaction if the concentration of iron(III) chloride is tripled
Answer:
Concentration and reaction rate is directly proportional
Explanation:
Basically, concentration is directly proportional to the concentration, so the higher the concentration, the higher the reaction rate.
Once the concentration is increased, more chemical will be added hence the reaction rate will increase
g Draw the most stable chair conformation for each of the following compounds (a) Cis-1-ethyl-2-methyl cyclohexane (b) Trans-1-ethyl-2-methyl cyclohexane (c) Which one is more stable, a or b
Answer:
See explanation
Explanation:
Image 1 is the chair conformation of trans-1-ethyl-2-methyl cyclohexane while image 2 is the chair conformation of Cis-1-ethyl-2-methyl cyclohexane.
Now let us look at the two structures closely. In the chair conformation, the more stable structure is the structure that has the bulky groups placed in the equatorial position.
Clearly, in trans-1-ethyl-2-methylcyclohexane, the ethyl and methyl groups are found to be in equatorial positions. Hence, trans-1-ethyl-2-methylcyclohexane is more stable in the chair conformation than cis-1-ethyl-2-methyl cyclohexane which has its methyl and ethyl groups in axial position.
Why should a science teacher know how to prepare stock solution
Answer:
because they were thought in college
Explanation:
hope that helps
Which of the following is most likely to make a -3 ion?
Bі
P
Se
Be
All
The element whose atom may likely make a -3 ion is P.
Elements in the periodic table are classified into groups and periods. The elements in the same group have similar physical and chemical properties.
Phosphorus (P) is a member of group 15 in the periodic table. The most common ion formed by the members of this group is the -3 ion.
It is formed by accepting three electrons to complete their octet since they have five electrons on their outermost shell.
Hence P is most likely to form a -3 ion.
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What is the pH of a 0.086 M HCl solution?
Answer: pH = 1.066
Explanation: HCl is strong acid and it protolyzes totally:
HCl + H2O ⇒ H3O+ + Cl-
Concentrations are same: [H3O+] = c(HCl)
pH = - log[H3O+] = - log(0.086) = 1.0655
Carbon 14 and carbon 12 are both isotopes of the element carbon check all answers that are true about them
Answer:
CARBON 14 INCLUDES:
-six protons
-eight neutrons in the nucleus
CARBON 12 INCLUDES:
-six protons
-Six neutrons
Calculate the number of cations and anions in each of the following compounds. Enter your answers in scientific notation. (a) 6.42 g of KBr:
Answer: The number of cations are [tex]3.24 \times 10^{22}[/tex] and number of anions are [tex]3.24 \times 10^{22}[/tex] in 6.42 g of KBr.
Explanation:
The molar mass of KBr is (39.10 + 79.90) g/mol = 119.00 g/mol
Now, the dissociation equation for KBr is as follows.
[tex]KBr \rightarrow K^{+} + Br^{-}[/tex]
This means that 1 mole of KBr is forming 1 mole of [tex]K^{+}[/tex] (cation) and 1 mole of [tex]Br^{-}[/tex] (anion).
According to mole concept, 1 mole of every substance contains [tex]6.022 \times 10^{23}[/tex] atoms. Hence, number of cations present in 6.42 g KBr is calculated as follows.
[tex]No. of cations = Moles \times 6.022 \times 10^{23}\\= \frac{mass}{molar mass} \times 6.022 \times 10^{23}\\= \frac{6.42 g}{119.00 g/mol} \times 6.022 \times 10^{23}\\= 3.24 \times 10^{22}[/tex]
As according to the equation, there are equal number of moles of both cation and anions.
This means that the number of anions are also [tex]3.24 \times 10^{22}[/tex].
Thus, we can conclude that the number of cations are [tex]3.24 \times 10^{22}[/tex] and number of anions are [tex]3.24 \times 10^{22}[/tex] in 6.42 g of KBr.
The number of cations and anions present in potassium bromide is 3.24 × 10²².
How we calculate atoms from moles?In one mole of any substance 6.022 × 10²³ atoms of that substance is present and this is known as Avogadro's number.
KBr is a strong electrolyte means it fully dissociates into their constitute ions. So, the number of moles of produced ions is equal to the moles of KBr and dissociation is represented as:
KBr → K⁺ + Br⁻
From this it is clear that 1 mole of cation and 1 mole of anion is produced from 1 mole of KBr. Moles of KBr will be calculated as:
n = W/M, where
W = given mass = 6.42g
M = molar mass = 119
n = 6.42 / 119 = 0.053 moles
No. of cations and anions present in 0.053 moles = 0.053 × 6.022 × 10²³ = 3.24 × 10²².
Hence, 3.24 × 10²² is the no. of cations and anions.
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You are working on a project where you need the volume of a box. You take the length, height, and width measurements and then multiply the values together to find the volume. You re- port the volume of the box as 0.310 ml. If two of your mea- surements were 0.7120 m and 0.52458 m, what was the other measurement?
Answer and Explanation:
If we remember from school, we should know that the equation for finding the volume of a box (rectangular) is length times width times height.
Since we know the volume, we can divide the two sides given from the volume to find the remaining side.
0.310 ÷ 0.7120 ÷ 0.52458 = 0.83
The answer is 0.83 for the remaining side measurement.
#teamtrees #PAW (Plant And Water)
Answer:
The answer is: 0.82998448
Explanation:
If you multiply 0.7120 × 0.52458, it will equal: 0.37350096.
if you divide 0.310 ÷ 0.37350096, you will get 0.82998448.
Hope it helps!!
(also, i don't want to be "that" person, but brainliest would be apreciated!)