Answer:
5.92×10⁷ J
Explanation:
We'll begin by converting 15 tons to Newton. This can be obtained as follow:
1 ton = 9806.65 N
Therefore,
15 ton = 15 ton × 9806.65 N / 1 ton
15 ton = 147099.75 N
Next, we shall convert one-quarter (¼) or 0.25 mile to metre. This can be obtained as follow:
100 mi = 160934 m
0.25 mi = 0.25 mi × 160934 / 100 mi
0.25 mi = 402.335 m
Finally, we shall determine the Workdone. This can be obtained as follow:
Force (F) = 147099.75 N
Distance (d) = 402.335 m
Workdone (Wd) =?
Wd = F × d
Wd = 147099.75 × 402.335
Wd = 5.92×10⁷ J
Thus, the Workdone is 5.92×10⁷ J
A 4.38 kg sphere makes a perfectly inelastic collision with a second sphere that is initially at rest. The composite system moves with a speed equal to one third the original speed of the 4.38 kg sphere. What is the mass of the second sphere?
Answer: The mass of the second sphere is 8.76 kg
Explanation:
The equation for a perfectly inelastic collision follows:
[tex]m_1u_1+m_2u_2=(m_1+m_2)v[/tex]
where,
[tex]m_1\text{ and }u_1[/tex] are the mass and initial velocity of first sphere
[tex]m_2\text{ and }u_2[/tex] are the mass and initial velocity of second sphere
v = final velocity of the system
We are given:
[tex]m_1=4.38kg\\u_2=0m/s\\v=\frac{u_1}{3}[/tex]
Rearranging the above equation, we get:
[tex]m_1u_1-m_1v=m_2v\\\\m_2=m_1\frac{u_1-v}{v}\\\\m_2=m_1(\frac{u_1}{v}-1)[/tex]
Plugging values in the above equation, we get:
[tex]m_2=4.38(\frac{3u_1}{u_1}-1)\\\\m_2=(4.38\times 2)=8.76kg[/tex]
Hence, the mass of the second sphere is 8.76 kg
potential Energy is associated with position
True or false
Answer:
yes.
Explanation:
potential Energy is associated with position
Answer:
true
Explanation:
the energy possessed by a body by virtue of its position or configuration is called potential energy.Everything at a height from the earth surface posseses potential energy.
A 5.0 A electric current passes through an aluminum wire of 4.0~\times~10^{-6}~m^2 cross-sectional area. Aluminum has one free electron per atom. The density of aluminum is 2.7~grams/cm^3, and the aluminum molar mass is 27 g. What is the electron number density (the number of electrons per unit volume) in the wire
Answer: The electron number density (the number of electrons per unit volume) in the wire is [tex]6.0 \times 10^{28} m^{-3}[/tex].
Explanation:
Given: Current = 5.0 A
Area = [tex]4.0 \times 10^{-6} m^{2}[/tex]
Density = 2.7 [tex]g/cm^{3}[/tex], Molar mass = 27 g
The electron density is calculated as follows.
[tex]n = \frac{density}{mass per atom}\\= \frac{\rho}{\frac{M}{N_{A}}}\\[/tex]
where,
[tex]\rho[/tex] = density
M = molar mass
[tex]N_{A}[/tex] = Avogadro's number
Substitute the values into above formula as follows.
[tex]n = \frac{\rho \times N_{A}}{M}\\= \frac{2.7 g/cm^{3} \times 6.02 \times 10^{23}/mol}{27 g/mol}\\= \frac{16.254 \times 10^{23}}{27} cm^{3}\\= 0.602 \times 10^{23} \times \frac{10^{6} cm^{3}}{1 m^{3}}\\= 6.0 \times 10^{28} m^{-3}[/tex]
Thus, we can conclude that the electron number density (the number of electrons per unit volume) in the wire is [tex]6.0 \times 10^{28} m^{-3}[/tex].
How does the thickness of a planets atmosphere affect a planets average temperature
Answer:
The atmosphere of planets will block or enable heat coming from the sun
dipole moment are used to calculate the
Answer:
Explanation:
ádasdasdasd
6) The temperature of 10 kg of a substance rises by 55°C when heated. Calculate the
temperature rise when 22 kg of the substance is heated with the same quantity of heat.
Answer:
121
Explanation:
Explain how ultrasound devices use the Doppler effect to create images of body parts.
HELP ME ASAP!! Will give brainliest answer!!
Answer:
Transmits high-frequency (1 to 5 megahertz) sound pulses into your body using a probe. The sound waves travel into your body and hit a boundary between tissues (e.g. between fluid and soft tissue, soft tissue and bone).
Explanation:
Doppler ultrasound works by measuring sound waves that are reflected from moving objects, such as red blood cells.
Answer:
The guy above is pretty good
Explanation:
I'd go with that answer, give them brainliest
A rider on a bike with the combined mass of 100kgattains aterminal speed of 15m/son a 12% slope. Assuming that the only forces affecting thespeed are the weight and the drag, calculate the drag coefficient. The frontal area is0.9m2.
Answer:
C_d = 0.942
Explanation:
Let's first calculate the angle of inclination.
Formula is;
tan θ = (%slope)
% Slope is given as 12%
Thus;
θ = tan^(-1) (12/100)
θ = 6.843°
Let's now calculate the force due to the weight of the rider and bike combined from;
F = mg sin θ
We are given; m = 100 kg.
Thus;
F = 100 × 9.81 × sin 6.843
F = 116.885 N
The drag force will also be the same as the force due to the weight of the body. Thus;
Drag force; F = C_d(½ρu²A)
Where;
C_d is drag coefficient
ρ is density
U is terminal speed
A is area
We are given;
A = 0.9 m²
U = 15 m/s
From online tables, density of air is approximately 1.225 kg/m³
Thus;
116.885 = C_d(½ × 1.225 × 15² × 0.9)
116.885 = 124.03125C_d
C_d = 116.885/124.03125
C_d = 0.942
When a person sits erect, increasing the vertical position of their brain by 38.6 cm, the heart must continue to pump blood to the brain at the same rate. (a) What is the gain in gravitational potential energy (in J) for 110 mL of blood raised 38.6 cm
Answer:
the gain in gravitational potential energy is 0.4369 J
Explanation:
Given the data in the question;
from the definition of density, we know that;
ρ = m / V
where ρ is density, m is the mass and V is the volume.
Now, lets make mass the subject of the formula
m = ρV ------ let this be equation 1
Now, we know that potential energy PE = mgh ------- let this be equation 2
where m is mass, g is acceleration due gravity, and h is the height.
substitute equation 1 into 2
PE = ρVgh
given that; V = 110 mL = 110 × 10⁻⁶ m³, h = 38.6 cm = 38.6 × 10⁻² m, g = 9.8 m/s², ρ = 1.05 × 10³ kg/m³
we substitute
PE = (1.05 × 10³ kg/m³) × (110 × 10⁻⁶ m³) × 9.8 m/s² × 38.6 × 10⁻² m
PE = 0.4369 J
Therefore, the gain in gravitational potential energy is 0.4369 J
true or False? PLEASE HELP ME
Answer:
a. True - Joules is the unit measure for energy.
b. False - Potential energy is associated with position
c. False - Kinetic energy is associated with movement.
d. False - It's climbing, which means it also has kinetic energy.
What are the sign and magnitude in coulomb's of a point charge that produces a potential of -1.50 V at a distance of 2.00 mm
Answer:
The sign of the charge is negative
The magnitude of the charge is 3.33 x 10⁻¹³ C
Explanation:
Given;
potential difference, V = -1.5 V
distance of the point charge, r = 2 mm = 2 x 10⁻³ m
The magnitude of the charge is calculated as follows;
[tex]V = \frac{kq}{r} \\\\q = \frac{Vr}{k} \\\\where;\\\\k \ is \ coulomb's \ constant = 9\times 10^9 \ Nm^2/C^2\\\\q = \frac{-1.5 \times 2\times 10^{-3}}{9\times 10^9 } \\\\q = -3.33 \times 10^{-13} \ C\\\\Magnitude \ of \ the\ charge, q = 3.33 \times 10^{-13} \ C[/tex]
A positive electric charge is moved at a constant speed between two locations in an electric field, with no work done by or against the field at any time during the motion. This situation can occur only if the
Answer:
The options are
A) charge is moved in the direction of the field
(B) charge is moved opposite to the direction of the field
(C) charge is moved perpendicular to an equipotential line
(D) charge is moved along an equipotential line
(E) electric field is uniform
The answer is (D) charge is moved along an equipotential line
For all the criteria in the question to be met it means that the motion is perpendicular to the field and the force is perpendicular to the displacement of the charge respectively. In this scenario,
Change in velocity is zero. Work can be calculated by multiplying charge and change in velocity which when calculated will give zero.
a charge particle moves along a circle under the action of possible electric and magnetic field
Answer:
The correct answer is - B ≠ 0, E = 0.
Explanation:
A force q E is exerted by the electric field on the charged particle that accelerates always, that is, it increases the speed of the particle. The particle can never be rotated in a rotation in the circle in an electric field.
The magnitude of the velocity cannot be changed by the magnetic field but changes only the velocity of the direction.
If the particle moves in a circle it means that the speed should begin for a year. The only direct velocity is constant and only the change be b can be achieved. So, B ≠ 0 and E = 0.
What was the earliest energy source for humans?
A. coal
B. oil
C. natural gas
D. wood
Answer:
i think its oil
Explanation:
It was made & used as early as the fourth century BC.
If v = 4.00 meters/second and makes an angle of 60° with the positive direction of the y–axis, what is the magnitude of vx?
Adverb of place:
1
Adverb of time:
2
Adverb of place:
3
Adverb of time:
4
Adverb of place:
5
Answer:
1 there,here, somewhere,nowhere,everywhere
2.now,yesterday,then,
find the equivalent resistance.
Answer:
Explanation:
Note the connection between D-L-H shorts out the resistors on the right. Those 4 resistors can be ignored.
The connection between D-L-K means the 2 resistors between C-D and C-K are in parallel. The equivalent resistance of 2 6-ohm resistors in parallel is 3 ohms.
Similarly the connection between K-L-H means the 2 resistors between J-K and J-H are in parallel. The equivalent resistance of 2 6-ohm resistors in parallel is 3 ohms.
Adding the resistors in series together:
A-C-L-J-D = 6 + 3 + 3 + 6
= 18 ohms
Wind, hydropower, and solar can all be used to make ___
Answer: reusable energy or just energy but i think its just energy
Explanation:
a net force of 5N is applied to a 13kg mass. what is its acceleration?
Answer:
[tex]\boxed {\boxed {\sf a \approx 0.4 \ m/s^2}}[/tex]
Explanation:
According to Newton's Second Law of Motion, force is the product of mass and acceleration.
[tex]F= m \times a[/tex]
The net force is 5 Newtons and the mass is 13 kilograms. Let's convert the units for force to make the problem and unit cancellation easier.
1 Newton (N) is equal to 1 kilogram meter per square second (1 kg*m/s²) The net force of 5 N is equal to 5 kg*m/s²Now we know the values for 2 variables:
F= 5 kg*m/s²m= 13 kgSubstitute the values into the formula.
[tex]5 \ kg *m/s^2 = 13 \ kg * a[/tex]
Since we are solving for the accleration we must isolate the variable, a. It is being multiplied by 13 kilograms and the inverse of multiplication is division. Divide both sides by 13 kg
[tex]\frac {5 \ kg *m/s^2}{13 \ kg}= \frac{ 13 \ kg *a}{13 \ kg}[/tex]
[tex]\frac {5 \ kg *m/s^2}{13 \ kg}=a[/tex]
The units of kilograms (kg) cancel.
[tex]\frac {5 m/s^2}{13 }=a[/tex]
[tex]0.384615385\ m/s^2=a[/tex]
The original measurements of force and mass ( 5 and 13) have 1 and 2 significant figures. We must round our answer to the least number of sig figs: 1.
For the number we found, that is the tenths place. The 8 in the hundredth place (0.384615385) tells us to round the 3 up to a 4.
[tex]0.4 \ m/s^2 \approx a[/tex]
The acceleration is approximately 0.4 meters per square second.
mấy bạn việt nam giúp mình với. cần gấp quá
What is the thinnest soap film (excluding the case of zero thickness) that appears black when illuminated with light with a wavelength of 555 nmnm
Answer:
The minimum thickness of soap film is [tex]2.086\times 10^{-7} m[/tex].
Explanation:
wavelength = 555 nm
refractive index, n = 1.33
For the destructive interference,
the thickness is given by
[tex]t =\frac{m \lambda }{2 n}[/tex]
Here, m is the order, n is the refractive index and [tex]\lambda[/tex] is the wavelength.
For minimum thickness, m = 1
So the thickness is
[tex]t =\frac{1 \times 555\times 10^{-9} }{2 \times 1.33}\\\\t = 2.086\times 10^{-7} m[/tex]
An electromagnetic wave is generated by:
Answer:
Electromagnetic waves are produced whenever electric charges are accelerated. This makes it possible to produce electromagnetic waves by letting an alternating current flow through a wire, an antenna. The frequency of the waves created in this way equals the frequency of the alternating current.
Explanation:
A small planet having a radius of 1000 km exerts a gravitational force of 100 N on an object that is 500 km above its surface. If this object is moved 500 km farther from the planet, the gravitational force on it will be closest to Group of answer choices 56 N. 24 N. 77 N. 45 N. Flag question: Question 14 Question 14
Answer:
The gravitational force will be closest to group A: 56 N.
Explanation:
The gravitational force of the planet is given by:
[tex] F = \frac{GmM}{r^{2}} [/tex]
Where:
G: is the gravitational constant
m: is the mass of the object
M: is the mass of the planet
r: is the distance
When the object is 500 km above the surface of the planet, the gravitational force is 100 N:
[tex] F_{1} = \frac{GmM}{r_{1}^{2}} = \frac{GmM}{(500 km + 1000 km)^{2}} = \frac{GmM}{(1500 km)^{2}} [/tex]
And when the object is 500 km farther from the planet, the gravitational force is given by:
[tex] F_{2} = \frac{GmM}{r_{2}^{2}} = \frac{GmM}{(500 km + 1500 km)^{2}} = \frac{GmM}{(2000 km)^{2}} [/tex]
By dividing F₂ by F₁ we can calculate F₂:
[tex] \frac{F_{2}}{F_{1}} = \frac{\frac{GmM}{(2000 km)^{2}}}{\frac{GmM}{(1500 km)^{2}}} [/tex]
[tex] F_{2} = 100 N*\frac{(1500 km)^{2}}{(2000 km)^{2}} = 56.2 N [/tex]
Therefore, the gravitational force will be closest to group A: 56 N.
I hope it helps you!
A stalled car is being pushed up a hill at constant velocity by three people. The net force on the car is Group of answer choices Zero down the hill and greater than the weight of the car. down the hill and equal to the weight of the car up the hill and equal to the weight of the car. up the hill and greater than the weight of the car.
Answer:
Zero
Explanation:
Net force can be defined as the vector sum of all the forces acting on a body or an object i.e the sum of all forces acting simultaneously on a body or an object.
Mathematically, net force is given by the formula;
[tex] Fnet = Fapp + Fg[/tex]
Where;
Fnet is the net force.
Fapp is the applied force.
Fg is the force due to gravitation.
In this scenario, a stalled car is being pushed up a hill at constant velocity by three people. Thus, the net force on the car is zero because all the forces acting on any physical object is equal to zero and represents a constant velocity; by balancing or cancelling each other out.
According to Sir Isaac Newton's First Law of Motion which is known as Law of Inertia, it states that an object or a physical body in motion will continue in its state of motion at continuous velocity (the same speed and direction) or, if at rest, will remain at rest unless acted upon by an external force.
The
of a waveform is the number of cycles per second.
O period
O intensity
O frequency
O amplitude
Answer:
frequency is the correct answer for the question if the answer is correct plz mark me as brainliest.
Part
A block of mass 2 kg is acted upon by two forces: 3 N (directed to the left) and 4 N (directed to the right). What can you say about the blocks motion?
Answer:
Explanation:
the block will move to the right side with small velocity because the force from the left side greater than force from right side. Velocity will be less because of friction and gravitational attraction.
If a block of mass 2 kg is acted upon by two forces: 3 N (directed to the left) and 4 N (directed to the right), then the block would move towards the right side.
What is Newton's second law?Newton's Second Law states that The resultant force acting on an object is proportional to the rate of change of momentum.
As given in the problem statement If a block of mass 2 kg is acted upon by two forces: 3 N (directed to the left) and 4 N (directed to the right),
The net force acting on the block = 4 Newtons - 3 newtons
= 1 Newton
Thus, we can say that the block would move to the right side.
To learn more about Newton's second law here, refer to the link given below;
brainly.com/question/13447525
#SPJ2
Explain whether or not you would trust any conclusions obtained from this data. When formulating your answer, consider whether or not the effects of friction could account for the results these students obtained. What could the students have done wrong
Answer:
Please find the complete question in the attached file.
Explanation:
This graph as seen in the question must not be trusted. The reason for this is the plotted line of genesis desnt.
F=Ma
When F is in the axis (x,y) and mass of the system of the arc must be plotted F = 0 if a = 0 is considered as the perfectly friction-less ground.
This might be the case, as noted correctly, with such a surface tension opposite our twisting motion, in there is a coercing vertex even when the velocity of the body is zero, that is an example of friction force where the beginning pressure is working against frictional without moving or speeding up the body.
Concerning whatever the students got right, the complete experiment I knew is only evaluated correctly, but some of the suggestions clean the surface before exp, place the oil surface film and doing the experiment on an emptied ship; minimize that friction component.
Preocupada com o aumento da tarifa na conta de luz, uma pessoa resolve economizar diminuindo o tempo de banho de 20 para 15 minutos. Seu chuveiro possui as seguintes especificações: 4200 W e 220V. Sabendo que o kWh custa R$0,30, a economia feita em 10 dias foi de aproximadamente
What is the reaction force when baseball catcher catches and stops a baseball?
When the baseball catcher catches a baseball, then ... during the time that he is slowing the ball down and stopping it ... he is exerting an action force with his glove on the ball, and the ball is exerting an equal and opposite reaction force on his glove.
WILL GIVE 50 POINTS
Three resistors of 100, 40.0, and
10.0 Ohms are in series with a
24.0 V power supply. What is the
voltage drop across the 40.0 Ohm
resistor?
Answer:
6.4
Explanation:
stole the answer from Chegg and it was right on Acellus
Answer:
Explanation:
did he just say "don't break an arm wanking yourself off!??"
lol funny little comment section not gonna lie
