Answer:
1
Step-by-step explanation:
What is the slope of the line that contains the points (-2, 2) and (3, 4)?
O A.
-
5
2
B.
UIN
O c.
O D.
Answer:
2/5
Step-by-step explanation:
(-2 , 2) = (x1 , x2)
(3 , 4) = (x2 , y2)
slope = y2 - y1/x2 - x1
=4 - 2/3 - (-2)
=2/3+2
=2/5
Two angles of a triangle measure 22° and 530. What is the measure of the
third angle?
9514 1404 393
Answer:
105°
Step-by-step explanation:
The sum of measures of angles in a triangle is 180°. The third angle is ...
180° -22° -53° = 105°
help with this please. Thanks
9514 1404 393
Answer:
3.0
Step-by-step explanation:
The angle, its opposite side, and the hypotenuse are given. Then the relevant trig relation is ...
Sin = Opposite/Hypotenuse
sin(21°) = x/8.3 . . . . . . . . . . . . . . . . . . use the given values
x = 8.3·sin(21°) ≈ 8.3×0.3584 . . . . . . multiply by 8.3
x ≈ 3.0
A train traveled for T = 2.0 hours at a constant speed of R = 36 miles per hour. Use the formula D = R · T to find the total distance the train traveled (in miles). Do not include the units in your answer.
Answer: T=1700
Step-by-step explanation:
anyone know the missing angle ?
Answer:48.013
Step-by-step explanation: just found it
Bob has been alive for 21,900 days. How old is Bob?
Answer:
32 Years, 7 Months, 2 Days old
Step-by-step explanation:
if the coordinates are ( -1 , 5) and moved 9 units to the left what is the final answer?
Answer:
Directions: Write the new coordinates for each point or figure.
Sample Question:
Point F has the coordinates (-9,6). What are the coordinates of its image point after the translation of six units down and three units to the left?
Answer:
The coordinates of its image point after the translation are (-12, 0).
Explanation: When you look at an ordered pair the x number comes first, followed by the y number (x,y). Moving a point left or right changes the x number. Moving a point up or down changes the y number. Left and down require subtraction, while right and up require addition. In the sample, we had to go 3 units to the left, -9 - 3 = -12. We also had to go 6 units down, so 6 - 6 = 0.
Point Q has the coordinates (9,5). What are the coordinates of its image point after a translation of six units up and three units to the right?
Point P has the coordinates (3,4). What are the coordinates of its image point after a translation of 8 units down and 5 units to the left?
Point Z has the coordinates (10,7). What are the coordinates of its image point after a translation of six units down and three units to the right?
Point Y has the coordinates (0,-4). What are the coordinates of its image point after a translation of 10 units up and 3 units to the left?
Point X has the coordinates (3,-8). What are the coordinates of its image points after a translation of 11 units down and 10 units to the right?
Answer:
(-10,5)
Step-by-step explanation:
calculate the circumference of a circle with a radius of 7.5. show or explain your reasoning.
The missing number in the arithmetic sequence 60, 51,
33 is:
43.
41.
ОООО
40.
42.
Step-by-step explanation:
missing where ?
I guess you mean that there is one element missing between 51 and 33 (based on the readable answer options).
if that is true, then the missing element is 42.
the difference between 60 and 51 is 9.
the difference between 51 and 33 is 18.
if there is an engender missing in between 51 and 33, then it is logical to put it in the middle cutting the interval of 18 in half to 2 times 9. which is also supported by the first interval between 60 and 51 (9).
so, it would be 51 -9 = 42
Which point is a good approximation of a turning point
of the graph?
0 (-1.5,3)
0 (-0.5, -1)
0 (0,0)
O (1.0)
Answer:
(-0.5, -1)
Step-by-step explanation:
A turning point is a point of the graph where the graph changes from increasing to decreasing (rising to falling) or decreasing to increasing (falling to rising)
Please show how you did it so I can learn :)
Answer:
[tex] x_{1} = 3 + \sqrt {6} [/tex]
[tex] x_{2} = 3 - \sqrt {6} [/tex]
Step-by-step explanation:
Given the quadratic equation;
x² - 6x + 3 = 0
To find the roots of the quadratic equation, we would use the quadratic formula;
Note: the standard form of a quadratic equation is ax² + bx + c = 0
a = 1, b = -6 and c = 3
The quadratic equation formula is;
[tex] x = \frac {-b \; \pm \sqrt {b^{2} - 4ac}}{2a} [/tex]
Substituting into the formula, we have;
[tex] x = \frac {-(-6) \; \pm \sqrt {-6^{2} - 4*1*(3)}}{2*1} [/tex]
[tex] x = \frac {6 \pm \sqrt {36 - (12)}}{2} [/tex]
[tex] x = \frac {6 \pm \sqrt {36 - 12}}{2} [/tex]
[tex] x = \frac {6 \pm \sqrt {24}}{2} [/tex]
[tex] x = \frac {6 \pm 2 \sqrt {6}}{2} [/tex]
[tex] x_{1} = \frac {6 + 2 \sqrt {6}}{2} [/tex]
[tex] x_{1} = \frac {6}{2} + \frac {2 \sqrt {6}}{2} [/tex]
[tex] x_{1} = 3 + \sqrt {6} [/tex]
Or
[tex] x_{2} = \frac {6 - 2 \sqrt {6}}{2} [/tex]
[tex] x_{2} = \frac {6}{2} - \frac {2 \sqrt {6}}{2} [/tex]
[tex] x_{2} = 3 - \sqrt {6} [/tex]
