HBHBVHBHEBCB PLEASE HELP WHAT IS :

x/6= -2

Answer:

B

Step-by-step explanation:

bro trust me

Step-by-step explanation:

f(x)=4x+5

f(-3)=-12+5=-7

Answer:

-7

Step-by-step explanation:

f(x) = 4x + 5

write - 3 inplace of x

f(-3) = 4*-3 + 5

=-12 + 5

=-7

Answer:

(-2 , 5) (2 , 3)

m = y2 - y1 / x2 - x1

= 3 - 5 / 2 + 2

- 2 / 4 = - 1/2

- 1/2 = y - 3 / x - 2

cross multiply and u get

y = -0.5x + 4

Answer:

Line AC

Step-by-step explanation:

Given

See attachment for triangles

Required

60 degrees clockwise rotation about A

Since [tex]\triangle ABC[/tex] and [tex]\triangle ABD[/tex] are equilateral, then all angles in both triangles are [tex]60^o[/tex]

So, rotating in clockwise direction of A means that a line segment in the right of A will be considered.

The closest is line AC;

Hence, AC is [tex]60^o[/tex] clockwise of point A

We will form the equations for this problem:

(1) 1100*y + z = 113

(2) 1500*y + z = 153

z = ? Monthly administration fee is notated with z, and that is the this problem's question.

Number of kilowatt hours of electricity used are numbers 1100 and 1500 respectively.

Cost per kilowatt hour is notated with y, but its value is not asked in this math problem, but we can calculate it anyway.

The problem becomes two equations with two unknowns, it is a system, and can be solved with method of replacement:

(1) 1100*y + z = 113

(2) 1500*y + z = 153

----------------------------

(1) z = 113 - 1100*y [insert value of z (right side) into (2) equation instead of z]:

(2) 1500*y + (113 - 1100*y) = 153

-------------------------------------------------

(1) z = 113 - 1100*y

(2) 1500*y + 113 - 1100*y = 153

------------------------------------------------

(1) z = 113 - 1100*y

(2) 400*y + 113 = 153

------------------------------------------------

(1) z = 113 - 1100*y

(2) 400*y = 153 - 113

------------------------------------------------

(1) z = 113 - 1100*y

(2) 400*y = 40

------------------------------------------------

(1) z = 113 - 1100*y

(2) y = 40/400

------------------------------------------------

(1) z = 113 - 1100*y

(2) y = 1/10

------------------------------------------------

if we insert the obtained value of y into (1) equation, we get the value of z:

(1) z = 113 - 1100*(1/10)

(1) z = 113 - 110

(1) z = 3 dollars is the monthly fee.

credit: freesparrow

Answer:

3

Step-by-step explanation:

bc it is

Answer:

x +3y -9

Step-by-step explanation:

2x + 3y - x - (8 + 1)

Combine terms in the parentheses

2x + 3y - x - 9

Combine like terms

2x-x  +3y -9

x +3y -9

Answer:

2−9  

Step-by-step explanation:

You take redundant away, then do subtract, then combine terms. It will give solution.

Answer:

4 inches.

Step-by-step explanation:

Answer:

[tex]x = \frac{1 + \sqrt{41} }{10} \: \: or \: \: x = \frac{1 - \sqrt{41} }{10} [/tex]

Step-by-step explanation:

Ensure that the equation is in the form of ax² +bx +c= 0.

5x² -x +1= 3

5x² -x +1 -3= 0 (-3 on both sides)

5x² -x -2=0

Here, a= 5, b= -1, c= -2.

Use the quadratic formula below to solve for x.

[tex]\boxed{x = \frac{ - b± \sqrt{b^{2} - 4ac } }{2a} }[/tex]

[tex]x = \frac{ - ( - 1)± \sqrt{( -1 )^{2} - 4(5)( - 2)} }{2(5)} [/tex]

[tex]x = \frac{1± \sqrt{1 + 40} }{10} [/tex]

[tex]x = \frac{1± \sqrt{41} }{10} [/tex]

[tex]∴x = \frac{1 + \sqrt{41} }{10} \: \: or \: \: x = \frac{1 - \sqrt{41} }{10} [/tex]

Step-by-step explanation:

First, lets understand the question. When it says to find all the "real" solutions, that means you should not give any solutions containing an imaginary number.  An imaginary number is basically where we accept that there exists an i  (imaginary number) that is equal to [tex]\sqrt{-1\\}[/tex]  (square root of negative 1). So we are not considering this concept in this question.

Let's start solving then. Can you think of an equation that may help you solve this problem? The biggest clue is that x is squared.  If you said the quadratic formula, then you are perfectly correct!

Remember in order to use the quadratic formula, you must get your equation into the form:

[tex]ax^{2} +bx +c=0[/tex]

Let's do it! Right now we have:

[tex]5x^{2} - x +1=3[/tex]

Get rid of the 3 by subtracting it from both sides:

[tex]5x^{2} -x+1 -3 = 3 - 3\\5x^{2} -x-2=0[/tex]

Okay! it looks like our quadratic form now! By comparing it we can figure out what a, b, and c are in this case:

[tex]a = 5,{ }\\ b = -1, { }\\c = -2[/tex]

Let's get out our quadratic formula now:

[tex]\frac{ -b\frac{+}{} \sqrt{b^{2} -4ac} }{2a}[/tex]

All that's left to do is insert values and solve! (Be really careful when dealing with the negatives):

[tex]\frac{ -1\frac{+}{} \sqrt{(-1)^{2} -4(5)(-2)} }{2(5)}[/tex]

[tex]=\frac{ -1\frac{+}{} \sqrt{41} }{10}[/tex]

Removing the plus/minus we get two answers:

[tex]=\frac{ -1+ \sqrt{41} }{10}\\\\or\\\\=\frac{ -1-\sqrt{41} }{10}[/tex]

These are the most simplified forms!  It turns out we didn't even have to worry about imaginary solutions because we didn't end up with a negative sign under the square root. Hope this helps, and good luck!

Technically, we don't have enough info so it could go either way.

==========================================================

Explanation:

We can see that the sides are proportional to each other, but we don't know anything about the angles. We need to know if the angles are the same. If they are, then the hexagons are similar. If the angles are different, then the figures are not similar.

Right now we simply don't have enough info. So they could be similar, or they may not be. The best answer (in my opinion) is "not enough info". However, your teacher likely wants you to pick one side or the other. We can't pick "similar" so it's best to go with "not similar" until more info comes along the way.

Answer:

Adobe Family Tools

Step-by-step explanation:

Answer:

0.07

Step-by-step explanation:

To round a decimal to the nearest hundredth, look at the thousandths place.

If the number in the thousandths place is greater than or equal to 5, we will round up the hundredths place.

If it is smaller than 5, we will keep the number the same.

In the number 0.065, the thousandths place value is 0.005. So, we will round up the hundredths place.

The hundredths place value is 0.06, so we will round it up to 0.07.

So, 0.065 will round to 0.07.

Answer:

l=40

Step-by-step explanation:

The area is calculated as

A = wl

1200=30l

1200/30=l

40=l

Answer:

"Consecutive y-values change by multiplying previous value by a constant amount. So, the table represents an exponential function."

Step-by-step explanation:

In reality, the table represents an exponential function instead of a linear function, since values on domain change arithmetically at constant rate, whereas values on range change geometrically at constant rate.

Correct phrase may be: "Consecutive y-values change by multiplying previous value by a constant amount. So, the table represents an exponential function."

Answer:

(10x5+15x3)-7

Step-by-step explanation:

Answer:

-1

Step-by-step explanation:

To find the slope given two points

m = ( y2-y1)/(x2-x1)

    = ( 8 - 2)/( -3 -3)

    = 6 / -6

    = -1

Answer:

Step-by-step explanation:

go to the back of the book

Answer:

f(4) = -4

Step-by-step explanation:

f(x) = 4x - 20

Let x= 4

f(4) = 4*4 - 20

Multiply first

     = 16 -20

Then subtract

    = -4

Answer:

-4

Step-by-step explanation:

Hope it helps

Answer:

Step-by-step explanation:

I attached a picture below of what this situation looks like. As you can see, it is a right triangle problem. In order to solve for the speed of the boat, we first need to find out the difference between his distances when the angle is 60 and when it is 45. That's the same thing as finding x and y then subtracting. To find x:

[tex]sin60=\frac{200}x}[/tex] so

x = 231 meters (I rounded to the nearest whole numbers in this problem.

To find y:

[tex]sin45=\frac{200}{231+y}[/tex] so

[tex]y=\frac{200}{sin45}-231[/tex] and

y = 52.

The distance between the angles 60 and 45 as 52 meters, and it took him 2 minutes to travel that 52 meters. Assuming that his rate doesn't change, he can travel 52/2 meters per minute, or 26 meters per minute.

Answer:

1. e

2. c

3. d

4. a

5. b

Step-by-step explanation:

Answer:

see below

Step-by-step explanation:

The minimum is the left side of the whisker = 0

The maximum is the right side of the whisker = 13

Range is max - min = 13-0 = 13

Median is the middle line in the box = 4

Interquartile range is the right side of the box - left side of the box = 6 - 1 = 5

Answer:

D

Step-by-step explanation:

Given that :

Mean = 14

Range = 7

Evaluating the options given :

A. $14, $14, $14, $14, $7, $7

For option A :

Mean = (14 + 14 + 14 + 14 + 7 + 7) = 70 / 6 = 11.66 (incorrect)

B. $14, $14, $14, $14, $14, $21

Mean = (14 + 14 + 14 + 14 + 14 + 21) = 91 / 6 = 15.17 (Incorrect)

C. $13, $13, $13, $15, $15, $15

Range = 15 - 13 = 2 ( Incorrect)

D. $13, $12, $15, $15, $11, $18

Range = (18 - 11) = 7

Mean = (13+12+(15*2)+11+18) / 6 = 84/6 = 14

Option D is Correct

Answer:

79 inches

Step-by-step explanation:

2 m * 100cm/m * 1 in/2.54cm = 78.7401574803 in

rounded

79 inches

Answer:

5 is the median

Step-by-step explanation:

The "median" is the "middle" of the set of numbers. Considering there are 13 total numbers, making it un-even, there can be an equal amount of numbers taken off of each side with a middle number remaining. That middle number will be your median..

Answer:

42

Step-by-step explanation:

The equation is, c/7 = 6

c/7= 6

By multi[lying both sides with seven,

c = 6*7

c = 42

Hope this helps you

Please mark as brainliest

Thank You

Answer:

maybe 90%?

Step-by-step explanation:

if im wrong im sorry

Answer:

90%

Step-by-step explanation:

[tex]\frac{18}{20} :\frac{y}{100}[/tex]

y × 20 = 18 × 100

20y = 1800

20y ÷ 20 = 1800 ÷ 20

y = 90

Answer:

The equation of the line that passes through the points

(-4,4) and (6,4)

is

y=+4

Step-by-step explanation:

First of all, remember what the equation of a line is:

y = mx+b

Where:

m is the slope, and

b is the y-intercept

First, let's find what m is, the slope of the line...

The slope of a line is a measure of how fast the line "goes up" or "goes down". A large slope means the line goes up or down really fast (a very steep line). Small slopes means the line isn't very steep. A slope of zero means the line has no steepness at all; it is perfectly horizontal.

For lines like these, the slope is always defined as "the change in y over the change in x" or, in equation form:

m= y2-y1/ x2-x1

So what we need now are the two points you gave that the line passes through. Let's call the first point you gave, (-4,4), point #1, so the x and y numbers given will be called x1 and y1. Or, x1=-4 and y1=4.

Also, let's call the second point you gave, (6,4), point #2, so the x and y numbers here will be called x2 and y2. Or, x2=6 and y2=4.

Now, just plug the numbers into the formula for m above, like this:

m=0

So, we have the first piece to finding the equation of this line, and we can fill it into y=mx+b like this:

y=0x+b

Now, what about b, the y-intercept?

To find b, think about what your (x,y) points mean:

(-4,4). When x of the line is -4, y of the line must be 4.

(6,4). When x of the line is 6, y of the line must be 4.

Because you said the line passes through each one of these two points, right?

Now, look at our line's equation so far: y=0x+b. b is what we want, the 0 is already set and x and y are just two "free variables" sitting there. We can plug anything we want in for x and y here, but we want the equation for the line that specfically passes through the two points (-4,4) and (6,4).

So, why not plug in for x and y from one of our (x,y) points that we know the line passes through? This will allow us to solve for b for the particular line that passes through the two points you gave!

You can use either (x,y) point you want..the answer will be the same:

(-4,4). y=mx+b or 4=0 × -4+b, or solving for b: b=4-(0)(-4). b=4.

(6,4). y=mx+b or 4=0 × 6+b, or solving for b: b=4-(0)(6). b=4.

See! In both cases we got the same value for b. And this completes our problem.

m came out to be zero, so there is no "mx" term.