[tex]\huge\textsf{Hey there!}[/tex]
[tex]\large\textsf{-6 + k}[/tex]
[tex]\large\textsf{If k = 18, then substitute it into the equation where k is at}[/tex]
[tex]\large\textsf{-6 + 18}[/tex]
[tex]= \boxed{\large\textsf{\bf 12}}[/tex]
[tex]\boxed{\boxed{\large\textsf{Answer: \huge \bf 12 }}}\huge\checkmark[/tex]
[tex]\large\textsf{Guide}\downarrow[/tex]
[tex]\large\textsf{Negative \& negative = \boxed{\bf positive}}[/tex]
[tex]\large\textsf{Negative \& positive = \boxed{\bf negative}}[/tex]
[tex]\large\textsf{Positive \& positive = \boxed{\bf positive}}[/tex]
[tex]\large\textsf{Positive \& negative = \boxed{\bf negative}}[/tex]
[tex]\large\textsf{SOME values results in the bigger number}[/tex]
[tex]\large\textsf{Good luck on your assignment and enjoy your day!}[/tex]
~[tex]\frak{Amphitrite1040:)}[/tex]
Suppose you obtain a $3,000 T-note with a 3% annual rate and maturity in 5 years. How much interest will you earn?
what is the least common denominator of 1/3 and 4/7?? plsss explain
Answer:
21
Step-by-step explanation:
The smallest number that can go into both 3 and 7 as our denominators is 21. This can be worked about by multiplying them together.
(FYI: In some cases, if the product is even, it may not always work to multiply them together)
Answer:
21
hope this helps
have a good day :)
Step-by-step explanation:
3 multiples are 3, 6, 9, 12, 15, 18, 21, 24
7 multiples are 7, 14, 21, 28
so would need to change both denominators to 21 and multiple 7 and to 1/3 to get 7/21 and 3 to 4/7 to get 12/21
A local steakhouse served 625 customers over a weekend. The distribution of each customer's food purchase is non-normal. The average cost of each customer's food purchase is 52 dollars, with a standard deviation of 17 dollars. Suppose that a random sample of 315 customers are selected from the weekend's customers. Would it be appropriate to model the distribution of the sample mean with a normal model?
No. The mean distribution theorem states that the sampling distribution of the sample mean can only be modeled by the non-normal model because the population distribution is non-normal.
There is not enough information to make assumptions regarding the distribution of the sample mean.
Yes. The central limit theorem states that the sampling distribution of a sample mean can be modeled by a normal model if the sample size is large enough, regardless of the shape of the population distribution.
No. The central limit theorem states that the sampling distribution of a sample mean can only be modeled by a normal model if the sample size is large enough and the shape of the population distribution is normal.
Yes. The mean distribution theorem states that the sampling distribution of a sample mean can be modeled by a normal model if the sample size is large enough regardless of the population distribution.
Answer:
yes. The central limit theorem states that the sampling distribution of a sample mean can be modeled by a normal model, regardless of the shape of the population distribution.
Step-by-step explanation:
In order for the distribution of the sample mean to be normal, the sample size, n, must be large enough. By the central limit theorem, if n > 30, the distribution of the sample mean can be modeled by a normal distribution.
The answer is yes the central limit theorem states that the sampling distribution of a sample mean can be modeled by a normal model, regardless of the shape of the population distribution.
Option (B) is correct.
It is required to find the appropriate to model the distribution of the sample.
What is arithmetic?science that deals with the addition, subtraction, multiplication, and division of numbers and properties and manipulation of numbers.
Given that:
A local steakhouse served 625 customers over a weekend.
The average cost of each customer's food purchase is 52 dollars, with a standard deviation of 17 dollars. random sample of 315 customers are selected from the weekend's customers.
In order for the distribution of the sample mean to be normal, the sample size, n, must be large enough. By the central limit theorem, if n > 30, the distribution of the sample mean can be modeled by a normal distribution.
So, the answer is yes the central limit theorem states that the sampling distribution of a sample mean can be modeled by a normal model, regardless of the shape of the population distribution.
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find the equation of the striaght line passing through (3, 5) which is perpendicular to the line y=3x+2
Answer:
pls provide with a graph
Solve using the quadratic formula
Answer:
-5, -1/2
Step-by-step explanation:
I could only show half of the steps, but you can use the app photo math, you just take a pic of the problem and it gives you the answer and explains the steps.
I need help ASAP please
Answer:
The perimeter is 35 units
Step-by-step explanation:
Given
The attached shape
Required
The perimeter of the shape
From the shape, we have:
[tex]AB = 11[/tex]
[tex]AD = 8[/tex]
[tex]BD = AD = 8[/tex] --- sides of an isosceles
Also:
[tex]BC = DC = BD = 8[/tex] --- sides of an equilateral
So, the perimeter (P) is:
[tex]P = AB + BC + DC + AD[/tex]
[tex]P = 11 + 8 + 8 + 8[/tex]
[tex]P = 35[/tex]
Properties of Isosceles triangles
2 sides are equal
2 angles are equal
Properties of equilateral triangles
All sides are equal
All angles are equal
BRAINLIEST NEED HELP ASAP ALOT OF POINNTS
Answer:I believe it is -4
Step-by-step explanation:
What is the tangent of 0?
Step-by-step explanation:
tan 0 = 5/ √11 = 5√11 /11
__________
Answer:
5 / √11
Step-by-step explanation:
tan θ = opposite side / adjacent side
tan θ = 5 / √11
reduce the 24 hour clock times in 12 hour clock time add am or pm
Answer:
1) 1:04 am
2) 6:22 pm
3) 6:42 pm
4) 1:30 pm
5) 12:40 pm
6) 5:35 pm
7) 3:24am
8) 11:25 am
9) 6:42 am
10) 9:20 am
Find the equation for the
following parabola.
Vertex (-2,-4)
Focus (-4,-4)
A. (7-4)2 = -8(x-2)
B. (x+4)2 = 8(y+2)
C. (y+4)2 = 8(x+2)
D. (y+4)2 = -8(x+2)
Answer:
[tex](y+4)^2 = -8(x+2)[/tex], option D.
Step-by-step explanation:
Equation of a parabola:
The equation of a parabola has the following format:
[tex](y - k)^2 = 4p(x-h)[/tex]
In which the center is (h,k) and the focus is (h+p,k).
Vertex (-2,-4)
This means that [tex]h = -2, k = -4[/tex]
So
[tex](y - k)^2 = 4p(x-h)[/tex]
[tex](y - (-4))^2 = 4p(x-(-2))[/tex]
[tex](y+4)^2 = 4p(x+2)[/tex]
Vertex (-2,-4)
Focus (-4,-4)
-4 - (-2) = -4 + 2 = -2
So p = -2 and
[tex](y+4)^2 = 4(-2)(x+2)[/tex]
[tex](y+4)^2 = -8(x+2)[/tex], option D.
Answer:
(y+4)2=−8(x+2)
The answer would be D.
iv)
The sum of
four numbers in G.P. is 80 and the A.M. between the
first and the last is 28. Show that the numbers are 2, 6, 18, 54.
Answer:
Step-by-step explanation:
Given numbers : 2 , 6, 18, 54
Since common ration between numbers,
[tex]common \ ratio \ in \ GP , \ r = \frac{a_n}{a_{n-1}} = \frac{6}{2} = 3[/tex]
So the numbers are in GP.
Now Sum of the numbers = 2 + 6 + 18 + 54 = 80
AM, arithmetic mean between first and last number :
[tex]\frac{54+2}{2} = \frac{56}{2} =28[/tex]
All the conditions are true.
Which statement implies that A and B are independent events?
O A. P(B|A) = P(B N A)
O B.
P(BA) = P(B)
P(A)
O C.
P(B|A) = P(A)
OD.
P(BA) = P(B)
Answer:
[tex]P(A \cap B) = P(A)P(B)[/tex]
Step-by-step explanation:
Independent events:
If two events, A and B are independent, the probability of both A and B happening is the same as the probability of A happening multiplied by the probability of B happenings, that is:
[tex]P(A \cap B) = P(A)P(B)[/tex]
In this question:
The statement is [tex]P(A \cap B) = P(A)P(B)[/tex]
Geometry work HELP ASAP trying to find the measure of a circumference!!
Answer:
65 degrees
Step-by-step explanation:
Since it is given that AB=DC
then we know that AO=DO and BO=CO because it is the radius of a same circle.
Hence the shapes are equal and thus DOC=65 degree as it serves as a corresponding angle to AOB
Algebra please help!!!!! 30 points!!!
9514 1404 393
Answer:
C. x < 0
Step-by-step explanation:
The curve opens downward and has its vertex is at x=0, so the largest increasing interval will be the one that has its right end at x = 0⁻.
x < 0
Answer:
C. x<0
Step-by-step explanation:
The curved open downward Vertex , x = 0Largest interval x = 0^-x <0Evaluate the following integral over the ellipse
The underlying vector field,
F(x, y) = -y/(4x ² + 9y ²) i + x/(4x ² + 9y ²) j,
is conservative, so any integral of F over a closed path is 0.
To establish that F is conservative, we want to find a scalar function f(x, y) whose gradient is equal to F(x, y), which entails solving
[tex]\dfrac{\partial f}{\partial x}=-\dfrac y{4x^2+9y^2}[/tex]
[tex]\dfrac{\partial f}{\partial y}=\dfrac x{4x^2+9y^2}[/tex]
Integrating the first equation with respect to x yields
[tex]f(x,y)=-\dfrac16\arctan\left(\dfrac{2x}{3y}\right)+g(y)[/tex]
and differentiating with respect to y gives
[tex]\dfrac x{4x^2+9y^2}=\dfrac x{4x^2+9y^2}+\dfrac{\mathrm dg}{\mathrm dy} \implies \dfrac{\mathrm dg}{\mathrm dy}=0 \implies g(y)=C[/tex]
4 to the power of -3 as fraction
Answer:
Step-by-step explanation:
4^-3
=1/4^3
=1/64
Answer:
[tex]\frac{1}{64}[/tex]
Step-by-step explanation:
[tex]4^{-3} = 0.015625[/tex]
[tex]0.015625 = \frac{1}{64}[/tex]
from 5 metres of cloth Alexa cut 217 cm how much cloth remaining after cutting
Answer:
2.83 meters
Step-by-step explanation:
Change 217 cm to meter
217 * 1 m/ 100 cm = 2.17 m
5 meter - 2.17 m = 2.83 meters
Answer:
283 cm Or 2.83 m of cloths remaining after cutting.
Step-by-step explanation:
Alexa have a cloth measures 5 metre and she cut 217 cm clothes.As we know that
1 m = 100 cm
so, 5 m = 5 × 100 = 500 cm
Alexa cut 217 cm of clothesSubtract 217 cm from 500 cm
➛ 500 - 217
➛ 283 cm Or 2.83 m
What is a inequality to represent -2 and -5
Answer:
-2 > -5
Step-by-step explanation:
Since -2 is greater than -5 we use the greater-than sign to represent this relationship.
Plz Help more than one !!!!!!!!!!!!!!!!!!
Answer:
The correct option is (b).
Step-by-step explanation:
We need to find the equivalent to -2(4-3x)+(5x-2)
Using the associative property,
-2(4-3x) = -2(4)+2(3x)
= -8+6x
So,
-2(4-3x)+(5x-2) = -8+6x +5x-2
taking like terms together,
-2(4-3x)+(5x-2) = 6x+5x-8-2
= 11x-10
The equivalent expression is equal to (11x-10).
The functions f(x) and g(x) are shown on the graph. f(x)=x² what is g(x)?
[tex]a. \: \: g(x) = ( x - 2) {}^{2} [/tex]
[tex]b. \: \: g(x) = 2 {x}^{2} [/tex]
[tex]c. \: \: g(x) = ( \frac{1}{2} x) {}^{2} [/tex]
[tex]d. \: \: g(x) = (x + 2) {}^{2} [/tex]
9514 1404 393
Answer:
b. g(x) = 2x²
Step-by-step explanation:
The vertices of the two curves are in the same place, so no translation has taken place. This eliminates choices 'a' and 'd'.
A point on the curve g(x) is given. You can test to see which of choices 'b' and 'c' it satisfies.
B: g(2) = 2(2²) = 8 . . . . matches point (2, 8)
C: g(2) = (1/2·2)² = 1² = 1 . . . . does not match point (2, 8)
The function g(x) is ...
g(x) = 2x²
Help please!! Step by step!!
Answer:
[tex]P(Ice Cream|Frogtown) = 67.4\%[/tex]
Step-by-step explanation:
Given
The attached plot
Required
P(Ice Cream|Frogtown)
This is calculated as:
[tex]P(Ice Cream|Frogtown) = \frac{P(Ice\ Cream\ n\ Frogtown)}{P(Frogtown)}[/tex]
From the attachment;
[tex]P(Ice\ Cream\ n\ Frogtown) = 0.31[/tex]
[tex]P(Frogtown) = 0.31 + 0.15 = 0.46[/tex]
So, we have:
[tex]P(Ice Cream|Frogtown) = \frac{P(Ice\ Cream\ n\ Frogtown)}{P(Frogtown)}[/tex]
[tex]P(Ice Cream|Frogtown) = \frac{0.31}{0.46}[/tex]
[tex]P(Ice Cream|Frogtown) = 0.6739[/tex]
Express as percentage
[tex]P(Ice Cream|Frogtown) = 0.6739 * 100\%[/tex]
[tex]P(Ice Cream|Frogtown) = 67.39\%[/tex]
[tex]P(Ice Cream|Frogtown) = 67.4\%[/tex] -- approximated
f(x) = 4x -1 find f(-2)
g(x) = 3x^2 - 2 find g(6)
Answer:
f(-2) = -9
g(6) = 106
General Formulas and Concepts:
Pre-Algebra
Order of Operations: BPEMDAS
Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to RightAlgebra I
FunctionsFunction NotationStep-by-step explanation:
Step 1: Define
Identify
f(x) = 4x - 1
f(-2) is x = -2 for function f(x)
g(x) = 3x² - 2
g(6) is x = 6 for function g(x)
Step 2: Evaluate
f(-2)
Substitute in x [Function f(x)]: f(-2) = 4(-2) - 1Multiply: f(-2) = -8 - 1Subtract: f(-2) = -9g(6)
Substitute in x [Function g(x)]: g(6) = 3(6)² - 2Exponents: g(6) = 3(36) - 2Multiply: g(6) = 108 - 2Subtract: g(6) = 106Which inequality shows all possible values for the measure of the third side, x, in inches?
Answer:
[tex]26 > c > 58[/tex]
Step-by-step explanation:
Given
[tex]a,b =42; 16[/tex] --- 2 sides
Required
The inequality for the third side
To do this, we make use of:
[tex]a + b < c[/tex]
[tex]a + c < b[/tex]
[tex]b + c < a[/tex]
So, we have:
[tex]42 + 16 < c[/tex]
[tex]16 + c < 42[/tex]
[tex]42 + c < 16[/tex]
This gives:
[tex]58 < c[/tex]
[tex]c < 26[/tex]
[tex]c<-26[/tex]
The usable inequalities are:
[tex]c < 26[/tex] and [tex]58 < c[/tex]
Rewrite:
[tex]c < 26[/tex] and [tex]c > 58[/tex]
So, the inequality is:
[tex]26 > c > 58[/tex]
Pleas help will mark brainlist!
Geometry
This makes a cube because a cube has 6 faces, 8 vertices, and 12 edges.
What is 5x5 answer for a cookie
Answer:
25
Step-by-step explanation:
graph the function h (x)=4x-7
Answer:
abcdefghijklmnopqrstuvwxyz
Step-by-step explanation:
zyxwvutsrqponmlkjihgfedcba
a rectangular container of length 40cm and width 36cm was filled with 57600cm of water. find the depth of the water in the container.
Answer:
40 cm
Step-by-step explanation:
57600 is the volume here
Because "was filled with 57600cm of water."
- NOTE : Volume can Never change unless There is a Subtracted amount of water That's Removed36 x 40 x n = 57600
n = 40
Determine the values of the parameter s for which the system has a unique solution, and describe the solution. x 1 - 5 sx 2
Answer:
[tex]s \ne \±2[/tex]
[tex]x_1 = \frac{3s - 2}{3(s^2 -4)}[/tex]
[tex]x_2 = \frac{2(s- 6)}{5(s^2 - 4)}[/tex]
Step-by-step explanation:
Given
[tex]3sx_1 +5x_2 = 3[/tex]
[tex]12x_1 + 5sx_2 =2[/tex]
Required
Determine the value of s
Express the equations as a matrix
[tex]A =\left[\begin{array}{cc}3s&5\\12&5s\end{array}\right][/tex]
Calculate the determinant
[tex]|A|= (3s*5s -5 *12)[/tex]
[tex]|A|= (15s^2 -60)[/tex]
Factorize
[tex]|A|= 15(s^2 -4)[/tex]
Apply difference of two squares
[tex]|A|= 15(s -2)(s + 2)[/tex]
For the system to have a unique solution;
[tex]|A| =0[/tex]
So, we have:
[tex]15(s -2)(s+2) = 0[/tex]
Divide both sides by 15
[tex](s -2)(s+2) = 0[/tex]
Solve for s
[tex]s -2 = 0\ or\ s +2 = 0[/tex]
[tex]s = 2\ or\ s = -2[/tex]
The result can be combined as:
[tex]s =\±2[/tex]
Hence, the system has a unique solution when [tex]s \ne \±2[/tex]
Next, we solve for s using Cramer's rule.
We have:
[tex]mat\ x_1 = \left[\begin{array}{cc}3&5\\2&5s\end{array}\right][/tex]
Calculate the determinant
[tex]|x_1| = (3 * 5s - 5 *2)[/tex]
[tex]|x_1| = 15s - 10[/tex]
So:
[tex]x_1 =\frac{|x_1|}{|A|}[/tex]
[tex]x_1 = \frac{15s - 10}{15(s -2)(s+2)}[/tex]
Factorize
[tex]x_1 = \frac{5(3s - 2)}{15(s -2)(s+2)}[/tex]
Divide by 5
[tex]x_1 = \frac{3s - 2}{3(s -2)(s+2)}[/tex]
[tex]x_1 = \frac{3s - 2}{3(s^2 -4)}[/tex]
Similarly:
[tex]mat\ x_2 =\left[\begin{array}{cc}3s&3\\12&2\end{array}\right][/tex]
Calculate the determinant
[tex]|x_2| = 3s * 2 - 3 * 12[/tex]
[tex]|x_2| = 6s- 36[/tex]
So:
[tex]x_2 =\frac{|x_2|}{|A|}[/tex]
[tex]x_2 = \frac{6s- 36}{15(s -2)(s+2)}[/tex]
Factorize
[tex]x_2 = \frac{6(s- 6)}{15(s -2)(s+2)}[/tex]
Divide by 3
[tex]x_2 = \frac{2(s- 6)}{5(s -2)(s+2)}[/tex]
[tex]x_2 = \frac{2(s- 6)}{5(s^2 - 4)}[/tex]
For a left-tailed test, the critical value of z so that a hypothesis test would reject the null hypothesis at 1% significance level would be __________. Answer choices are rounded to the hundredths place. -1.03 -3.09 -2.33 -1.28
Answer:
C.-2.33
Step-by-step explanation:
We are given that
Significance level, [tex]\alpha =1[/tex]%=0.01
We have to find the critical value of z for a left-tailed test.
To find the critical value , we will use the z-table at significance level 0.01 for left-tailed test.
By using the z-table at significance level 0.01 for left-tailed test
The critical value of z at 1% significance level for left-tailed test
=-2.33
We get p-value by using z-critical value
P-value=0.0099<0.01
So, hypothesis test would be reject the null hypothesis at at 1% significance level.
Hence, the critical value of z=-2.33
Option C is true.
Suppose the company decided to allow the sales representatives to choose whether to participate in the field-training program or to opt out. There are 400 who have chosen to participate in the field-training program and 600 who have opted out of the program. How might the self-selection process affect the statistical validity of the comparison of the change in the proportion of sales orders from new stores? Support your answer with a specific example.
Answer:
Part C
you would only be able to have 200 people from each region train. this would lower the percentage of the impact the training had on the amount of sales ( if any) . For example, if the original 250 trained people in a region increased the sales in that region by 20 percent and 50 of those people ended up not actually training, the sales would have only increased by 16 percent.
Step-by-step explanation:
The self-selection process of allowing sales representatives to choose whether to participate in the field-training program or opt out can potentially affect the statistical validity of comparing the change in the proportion of sales orders from new stores.
What's the process about?This is because the two groups (participants and non-participants) may differ systematically in ways that could influence the outcome being measured.
For example, let's consider that the field-training program is designed to improve sales skills and provide strategies for targeting new stores effectively. Sales representatives who actively choose to participate in the program might be more motivated, enthusiastic, or confident in their abilities compared to those who opt out. This self-selection process can introduce a bias into the results.
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