9514 1404 393
Answer:
3.0
Step-by-step explanation:
The angle, its opposite side, and the hypotenuse are given. Then the relevant trig relation is ...
Sin = Opposite/Hypotenuse
sin(21°) = x/8.3 . . . . . . . . . . . . . . . . . . use the given values
x = 8.3·sin(21°) ≈ 8.3×0.3584 . . . . . . multiply by 8.3
x ≈ 3.0
Two angles of a triangle measure 22° and 530. What is the measure of the
third angle?
9514 1404 393
Answer:
105°
Step-by-step explanation:
The sum of measures of angles in a triangle is 180°. The third angle is ...
180° -22° -53° = 105°
A train traveled for T = 2.0 hours at a constant speed of R = 36 miles per hour. Use the formula D = R · T to find the total distance the train traveled (in miles). Do not include the units in your answer.
Answer: T=1700
Step-by-step explanation:
if the coordinates are ( -1 , 5) and moved 9 units to the left what is the final answer?
Answer:
Directions: Write the new coordinates for each point or figure.
Sample Question:
Point F has the coordinates (-9,6). What are the coordinates of its image point after the translation of six units down and three units to the left?
Answer:
The coordinates of its image point after the translation are (-12, 0).
Explanation: When you look at an ordered pair the x number comes first, followed by the y number (x,y). Moving a point left or right changes the x number. Moving a point up or down changes the y number. Left and down require subtraction, while right and up require addition. In the sample, we had to go 3 units to the left, -9 - 3 = -12. We also had to go 6 units down, so 6 - 6 = 0.
Point Q has the coordinates (9,5). What are the coordinates of its image point after a translation of six units up and three units to the right?
Point P has the coordinates (3,4). What are the coordinates of its image point after a translation of 8 units down and 5 units to the left?
Point Z has the coordinates (10,7). What are the coordinates of its image point after a translation of six units down and three units to the right?
Point Y has the coordinates (0,-4). What are the coordinates of its image point after a translation of 10 units up and 3 units to the left?
Point X has the coordinates (3,-8). What are the coordinates of its image points after a translation of 11 units down and 10 units to the right?
Answer:
(-10,5)
Step-by-step explanation:
calculate the circumference of a circle with a radius of 7.5. show or explain your reasoning.
Please show how you did it so I can learn :)
Answer:
[tex] x_{1} = 3 + \sqrt {6} [/tex]
[tex] x_{2} = 3 - \sqrt {6} [/tex]
Step-by-step explanation:
Given the quadratic equation;
x² - 6x + 3 = 0
To find the roots of the quadratic equation, we would use the quadratic formula;
Note: the standard form of a quadratic equation is ax² + bx + c = 0
a = 1, b = -6 and c = 3
The quadratic equation formula is;
[tex] x = \frac {-b \; \pm \sqrt {b^{2} - 4ac}}{2a} [/tex]
Substituting into the formula, we have;
[tex] x = \frac {-(-6) \; \pm \sqrt {-6^{2} - 4*1*(3)}}{2*1} [/tex]
[tex] x = \frac {6 \pm \sqrt {36 - (12)}}{2} [/tex]
[tex] x = \frac {6 \pm \sqrt {36 - 12}}{2} [/tex]
[tex] x = \frac {6 \pm \sqrt {24}}{2} [/tex]
[tex] x = \frac {6 \pm 2 \sqrt {6}}{2} [/tex]
[tex] x_{1} = \frac {6 + 2 \sqrt {6}}{2} [/tex]
[tex] x_{1} = \frac {6}{2} + \frac {2 \sqrt {6}}{2} [/tex]
[tex] x_{1} = 3 + \sqrt {6} [/tex]
Or
[tex] x_{2} = \frac {6 - 2 \sqrt {6}}{2} [/tex]
[tex] x_{2} = \frac {6}{2} - \frac {2 \sqrt {6}}{2} [/tex]
[tex] x_{2} = 3 - \sqrt {6} [/tex]
