Consider this example on how different a median can be from a sample. Suppose there is a company that mentions the average salary at Company A last year was $ 135,750 per year. Being interested in this you try to investigate this. You discover there are 8 individuals, including the business owner, that works at the company. You discover that the salaries of the 7 individuals are surprisingly low. The salaries of those 7 individuals are $8,000, $8,000, $7,000, $11,000, $15,000, $17,000, and $20,000. You then discover the salary of the business owner to be $1,000,000.
Compare the mean with the median? What does this show?
Find Q1 (first quartile) , Q3 (third quartile) , and Interquartile Range (IQR)?
Are there outliers? Please prove there is an outlier using the Q1-1.5*IQR and Q3 + 1.5*IQR formulas?
Find the 10% trimmed mean of the 8 salaries above. Compare this with the median found in part a.
What do you think represents a more typical salary of the organization above? Would you want to work for this company?
Answer:
Kindly check explanation
Step-by-step explanation:
Given the data :
8000, 8000, 7000, 11000, 15000, 17000, 20000, 1000000.
Mean = Σx / n = 1086000 / 8 = 135750
Median = 1/2(n+1)th term = 8000
The lower quartile :
Q1 = 1/4(n+1)th term
Q1 = 8000
Q3 = 3/4 (n+1)th term
Q3 = 18500
IQR = 18500 - 8000 = 10500
OUTLIER :
8000 - (1.5*(10500)) = - 7750
18500 + (1.5*(10500)) = 34250
10% trimmed mean
10% * 8
Cut off 1 from the top and bottom
Data becomes : 8000, 8000, 11000, 15000, 17000, 20000
Trimmed mean = 13166
A mixture of 40 liters of paint is 25% red tint, 30% yellow tint and 45% water. 8 líters of yellow tint are added to the original mixture.
Answer:
The amount of yellow tint would be 33.84%
Step-by-step explanation:
por favor ayudaaaaaa
Answer:
D
Step-by-step explanation:
Pitágoras
A^2 = B^2 + C^2
A^2 = 14^2 +5^2
A^2 = 196 + 25
A = √221
Identify the value for C in the following equation that would make the conic section a parabola: 2x2 + Cy2 + 3x + 5y + 1 = 0
Given:
The conic equation is:
[tex]2x^2+Cy^2+3x+5y+1=0[/tex]
To find:
The value of C such that the given conic equation make a parabola.
Solution:
The general for of conic equation is:
[tex]Ax^2+Cy^2+Dx+Ey+F=0[/tex]
This equation represents a parabola is either A=0 or C=0 but not both equal to zero.
The given equation is:
[tex]2x^2+Cy^2+3x+5y+1=0[/tex]
Here, coefficient of [tex]x^2[/tex] is A=2 and coefficient of [tec]y^2[/tex] is C.
Since A is not equal to 0, therefore C must be equal to 0 to form a parabola.
Therefore, the only value of C is 0.
IM BEING TIMEDDD PLEASE HELPPPPPP
Choose the correct simplification of (6x3 − 7x − 4) + (4x3 + 8x + 3). (5 points)
2x3 − 15x − 7
10x3 + x − 1
2x3 + 15x + 6
10x3 − x − 1
Answer:
10x^3 + x - 1
Step-by-step explanation:
(6x^3 -7x - 4) + (4x^3 + 8x + 3)
Combine like terms
6x^3 + 4x^3 = 10x^3
Combine like terms
-7x + 8x = x
Combine like terms
-4 + 3 = -1
Combine the results of the terms
10x^3 + x - 1
A right triangle has side lengths 5, 12, and 13 as shown below. Use these lengths to find tan B, sinB, and cos B. (marking brainlist)
Answer:
tan B = 12 /5
sin B = 12/13
cos B = 5/13
Step-by-step explanation:
Since this is a right triangle, we can use trig functions
tan B = opp/ adj = 12 /5
sin B = opp/hyp = 12/13
cos B = adj/hyp = 5/13
Answer:
Sine of B = 12/13
Cos of B = 5/13
Tan of B = 12/5
Step-by-step explanation:
In this case, the opposite is 12, the adjacent is 5 and the hypotenuse is 13.
sin is opposite/hypotenuse
cos is adjacent/hypotenuse
and
tan is opposite/adjacent
At LaGuardia Airport for a certain nightly flight, the probability that it will rain is 0.14 and the probability that the flight will be delayed is 0.16. The probability that it will not rain and the flight will leave on time is 0.79. What is the probability that it is not raining if the flight has been delayed?a. P(delayed | rain) = 0.08.
b. P(delayed | rain) = 0.083.
c. P(rain | delayed) = 0.06.
d. P(rain | delayed) = 0.056.
Answer:
The appropriate answer is "0.437".
Step-by-step explanation:
Given:
P(rain) = 0.14
then,
P(no-rain) = 1-P(rain)
= 1-0.14
= 0.86
P(delay) = 0.16
P(rain and on time) = 0.79
then,
By using the conditional probability, we get
⇒ [tex]P(A|B)=\frac{P(A \cap B)}{P(B)}[/tex]
or,
⇒ [tex]P(no \ rain|delay) = \frac{P(no \ rain \cap delay)}{P(delay)}[/tex]
By substituting the values, we get
⇒ [tex]=\frac{0.07}{0.16}[/tex]
⇒ [tex]=0.437[/tex]
If f(1)=4f(1)=4 and f(n)=f(n-1)^2+2f(n)=f(n−1)
2
+2 then find the value of f(3)f(3).
Answer:
f(3) = 326
Step-by-step explanation:
Given the function
f(n)=f(n-1)^2+2
If f(1) = 4
f(2) = f(1)^2 + 2
f(2) = 4^2 + 2
f(2) = 16 + 2
f(2) = 18
f(3) = f(2)^2 + 2
f(3) = 18^2 + 2
f(3) = 324 + 2
f(3) = 326
Help and explain pls and thankyouuu
Answer:
third one
Step-by-step explanation:
l 3q-2 l = 7
drop absolute value symbols and set up two equations
3q - 2 = 7 or 3q - 2 = -7
3q = 9 3q = -5
q = 3 q = [tex]\frac{-5}{3}[/tex]
Answer:
3q-2=7
The two will move other side of equal sign from - 2 to +2
3q=7+2
3q=9
/3 in both side
q=3
5th grade math. correct answer will be marked brainliest, answer the blank one!!
An object has a mass of 630 kg and a volume of 7 m cube.
Find the density of the object in kg/m cube.
Step-by-step explanation:
Hey there!
According to the question;
Mass of an object (m) = 630 kg
Volume of an object (v) = 7m³
We know that;
[tex]density = \frac{mass(kg) \: }{volume( {m}^{3} )} [/tex]
or, density = (630/7) kg/m³
Therefore, density of the substance is 90kg/m².
Hope it helps!
Angle 0 corresponds to a point (x,y) on the unit circle in quadrant 1. Which quadrant does 0+pi lie in?
Answer: Quadrant 3
============================================================
Explanation:
pi radians = 180 degrees
If angle [tex]\theta[/tex] (greek letter theta) is in quadrant 1, then this places the angle in the northeast quadrant. Adding 180 degrees to theta will move it to the third quadrant, which is in the southwest.
Note: when incrementing through the quadrants (1,2,3,4) we move counterclockwise.
NASA estimates that the probability that a certain component in a communication satellite fails is .005. There is an independent backup system, and the probability that it fails is .01. What is the probability that both systems fail
Answer: [tex]0.00005[/tex]
Step-by-step explanation:
Given
The probability that a certain component in a communication satellite fails is 0.005.
There is an independent backup system, and the probability that is fails is 0.01
The probability that both the system fails is given by
[tex]\Rightarrow P=0.005\times 0.01\\\Rightarrow P=0.00005[/tex]
Simon uses 2/3 cup of sugar to bake a cake. How many cups of sugar does he needs to bake 6 cakes?
Answer:
4
Step-by-step explanation:
2/3x6=4
true or false? like terms have the same variable and the same exponent.
the distance from kevins home to his school is 2 kilometers. adrian lives 750 meters from the same school. how much closer does adrian live next to the school than kevin
Find the difference.
(-ab+3a-3) - (3ab+2)
Answer:
3a-4ab-5
Step-by-step explanation:
(-ab+3a-3) - (3ab+2)
Distribute the minus sign
(-ab+3a-3) - 3ab-2
Combine like terms
3a-4ab-5
Answer:
[tex]-4ab+3a-5[/tex]
Step-by-step explanation:
Hi there!
[tex](-ab+3a-3) - (3ab+2)[/tex]
Open up the parentheses
[tex]-ab+3a-3- 3ab-2[/tex]
Combine like terms
[tex]-ab- 3ab+3a-3-2\\-4ab+3a-5[/tex]
I hope this helps!
Which pair of figures has the same number of faces as vertices?
triangular prism and triangular pyramid
triangular prism and rectangular prism
rectangular pyramid and triangular pyramid
rectangular pyramid and rectangular prism
Answer:
Rectangular pyramid and triangular pyramid
Step-by-step explanation:
A rectangular pyramid and triangular pyramid has the same number of faces as vertices
What is a Pyramid?A pyramid is a three dimensional shape (has length, width and height) with a polygonal base and flat triangular faces.
A rectangular pyramid have same number of faces as vertices with each being 5 in number. A triangular pyramid have same number of faces as vertices with each being 3 in number.
Find out more on Pyramid at: https://brainly.com/question/25823102
how is the graph of y=4x^(2)+2 different from the graph of y=4x^(2)
Answer:
y=mx+b
Step-by-step explanation:
so that is b right?
that means its what number you start the y on
The number of points scored by the home team at a basketball game is represented by (x+6). The number of points scored by the visiting team is represented by (3x −6). Write an expression to find how many more runs the home team scored than the visiting team. Then evaluate the expression if the value of x is 5.
Answer:
2
Step-by-step explanation:
(x + 6) - (3x - 6) Remove the brackets.
x + 6 - 3x + 6 Collect like terms
Difference in points = 12 - 2x
If x = 5 then
Difference in points = 12 - 2*5
Difference in points = 12 - 10
Difference in points = 2
Please show how you did it so I can learn :)
Answer:
[tex] x_{1} = 3 + \sqrt {6} [/tex]
[tex] x_{2} = 3 - \sqrt {6} [/tex]
Step-by-step explanation:
Given the quadratic equation;
x² - 6x + 3 = 0
To find the roots of the quadratic equation, we would use the quadratic formula;
Note: the standard form of a quadratic equation is ax² + bx + c = 0
a = 1, b = -6 and c = 3
The quadratic equation formula is;
[tex] x = \frac {-b \; \pm \sqrt {b^{2} - 4ac}}{2a} [/tex]
Substituting into the formula, we have;
[tex] x = \frac {-(-6) \; \pm \sqrt {-6^{2} - 4*1*(3)}}{2*1} [/tex]
[tex] x = \frac {6 \pm \sqrt {36 - (12)}}{2} [/tex]
[tex] x = \frac {6 \pm \sqrt {36 - 12}}{2} [/tex]
[tex] x = \frac {6 \pm \sqrt {24}}{2} [/tex]
[tex] x = \frac {6 \pm 2 \sqrt {6}}{2} [/tex]
[tex] x_{1} = \frac {6 + 2 \sqrt {6}}{2} [/tex]
[tex] x_{1} = \frac {6}{2} + \frac {2 \sqrt {6}}{2} [/tex]
[tex] x_{1} = 3 + \sqrt {6} [/tex]
Or
[tex] x_{2} = \frac {6 - 2 \sqrt {6}}{2} [/tex]
[tex] x_{2} = \frac {6}{2} - \frac {2 \sqrt {6}}{2} [/tex]
[tex] x_{2} = 3 - \sqrt {6} [/tex]
how can u stand applying math to every thing doesn't it make every thing repetitive and why does every thing need a pattern doesn't that just make every thing worthless cause what's the point if every thing repeats and no this is not about history
The roots of [tex]10x^2-14x+k[/tex] are sin a and cos a for some real value of a. Compute k.
Answer:
10
Step-by-step explanation:
10x²-14x+k = 0
x1 = sin a
x2= cos a
x1+x2 ≤ 2
x1. x2 ≤ 1 => k/10 ≤ 1
k ≤ 10
so the value of k should be 10
What is the value of Y if x=1
Answer:
y=6
the first equation:
3(1)+y=9
3+y=9
y=6
the second equation:
y= -4(1)+10
y= -4+10
y=6
I hope this helped! :)
Following a strategy of product differentiation, Westwood Corporation (W) makes a high-end kitchen range hood, KE8. W’s data for 2012 and 2013 follow on the next slide.In 2013, W produced no defective units and reduced direct materials usage per unit of KE8. Conversion costs in each year are tied to manufacturing capacity. Selling and customer service costs are related to the number of customers that the functions are designed to support. W has 23 customers (wholesalers) in 2012 and 25 customers in 2013.
Units of KE8 produced and sold 40,000 42,000
Selling Price $100 $110
Direct Materials (sq ft) 120,000 123,000
DM cost per sq ft $10 $11
Manufacturing capacity for KE 850,000units 50,000units
Conversion Costs $1,000,000 $1,100,000
CC per unit $20 $22
Selling & Customer Service capacity 30customers 29customers
Selling & Customer Service Costs$720,000 $725,000
Cost per customer$24,000 $25,000
Required:
(1) Describe elements you would expect to see in W’s BSC.
(2)Calculate the growth, price recovery and productivity components that explain the change in the 2012 to 2013 income. Can you use the worksheet to get the variances?(3) Suppose during 2013, the market size for high-end rangehoods grew 3% and all increases in market share are due to W’s product differentiation strategy. How much of the change in OI is due to the industry market size factor, cost leadership and product differentiation?
(4) How successful was the strategy implementation?
Work out the following calculations and give your answers to the nearest 1000
a) 251 x 638
Answer:
160,000
Step-by-step explanation:
251
× 638
_______________
2008
753
+ 1506
__________________
160138
Product to the nearest thousand = 160,000
Which angle is NOT coterminal with 110 degrees
-250degrees
480degrees
-110 degrees
830 degrees
The width of rectangle is 6 fr less than the lengthThe area of the rectangle is 247f Find the lengthand with of the rectangle
Answer:
i don't know 241 I think sorry
Draw and label the circle given by the equation (x - 5 + y + 10 = 6^2
Answer:
See attachment for circle
Step-by-step explanation:
Given
[tex](x -5)^2 + (y + 10)^2 = 6^2[/tex]
Required
Draw and label the circle
The equation of a circle is:
[tex](x -a)^2 + (y - b)^2 = r^2[/tex]
Where:
[tex]Center = (a,b)[/tex]
[tex]Radius = r[/tex]
So, we have:
[tex]Center = (5,-10)[/tex]
[tex]Radius = 6[/tex]
See attachment for circle
You have land that you would like to use to create two distinct fenced-in areas in the shape given below. You have 410 meters of fencing materials to use. What values of x and y would result in the maximum area that you can enclose
Answer:
[tex]x = \frac{205}{3}[/tex]
[tex]y =\frac{195}{4}[/tex]
Step-by-step explanation:
Given
[tex]p = 410[/tex] --- perimeter
See attachment for fence
Required
x and y
The perimeter of the fence is:
[tex]p = 2(x + y +5 + y) +x[/tex]
Open bracket
[tex]p = 2x + 2y +10 + 2y +x[/tex]
Collect like terms
[tex]p = 2x+x + 2y + 2y+10[/tex]
[tex]p = 3x + 4y+10[/tex]
Substitute: [tex]p = 410[/tex]
[tex]3x + 4y+10 =410[/tex]
Make 4y the subject
[tex]4y =410-10-3x[/tex]
[tex]4y =400-3x[/tex]
Make y the subject
[tex]y =\frac{400-3x}{4}[/tex]
The area (A) of the fence is:
[tex]A = (y + y + 5) * x[/tex]
[tex]A = (2y + 5) * x[/tex]
Substitute: [tex]y =\frac{400-3x}{4}[/tex]
[tex]A = (2*\frac{400-3x}{4} + 5) * x[/tex]
[tex]A = (\frac{400-3x}{2} + 5) * x[/tex]
Take LCM
[tex]A = (\frac{400-3x+10}{2}) * x[/tex]
Solve like terms
[tex]A = (\frac{410-3x}{2}) * x[/tex]
Open bracket
[tex]A = \frac{410x-3x^2}{2}[/tex]
Remove fraction
[tex]A = 205x-1.5x^2[/tex]
Differentiate both sides
[tex]A' = 205 - 3x[/tex]
To maximize; set [tex]A' =0[/tex]
[tex]205 - 3x =0[/tex]
Solve for 3x
[tex]3x = 205[/tex]
Solve for x
[tex]x = \frac{205}{3}[/tex]
Recall that: [tex]y =\frac{400-3x}{4}[/tex]
So, we have:
[tex]y =\frac{400-3*205/3}{4}[/tex]
[tex]y =\frac{400-205}{4}[/tex]
[tex]y =\frac{195}{4}[/tex]
