If f(1)=4f(1)=4 and f(n)=f(n-1)^2+2f(n)=f(n−1)
2
+2 then find the value of f(3)f(3).

Answer:

31.4

Step-by-step explanation

I think

Answer:

AOB = 65

DOE = 35

AOC = 90

EOB = 115

DOB = 80

14 containers

2.76 / 4 = 0.69

9.66/0.69= 14 containers

Answer:

x=3

Step-by-step explanation:

2 triangles are proportional so we have

4/6=x/4,5

--> x=(4.4,5)/6=3

You can also use sin cos but this way is faster

Answer:

Can you please organize them so that the exponents are marked as x^2?

Step-by-step explanation:

To me, none of this is in standard form because the numbers are before the variables.

[tex]\huge\textsf{Hey there!}[/tex]

[tex]\mathsf{1\times1=1}\\\\\bullet\large\textsf{This statement is TRUE because anything times (or multiplied)\ by 1}\\\large\textsf{is mostly likely 1}[/tex]

[tex]\mathsf{1+9=2\times5}\\\mathsf{1+9=\bf 10}\\\mathsf{2\times5}\\\mathsf{= 5+5}\\\mathsf{= 2 + 2 + 2 + 2 + 2}\\\mathsf{= \bf 10}\\\\\\\bullet\large\textsf{This statement is also TRUE because BOTH NUMBERS are EQUIVALENT}\\\large\textsf{to EACH OTHER}[/tex]

[tex]\mathsf{1 + 9 + 17 = 9\times3}\\\\\mathsf{1+9+17}\\\mathsf{1 + 9 = \bf 10}\\\mathsf{\bold{10}+ 17}\\\mathsf{= \bf 27}\\\\\\\\\\\mathsf{9\times3}\\\mathsf{= 9+9+9}\\\mathsf{3 +3 +3 +3+ 3 +3 + 3 + 3+ 3}\\\mathsf{= \bf 27}\\\\\\\\\\\bullet\large\textsf{This statement as well is TRUE because BOTH NUMBERS are}\\\large\textsf{equivalent to each other}[/tex]

[tex]\boxed{\boxed{\large\textsf{ANSWER: All statements to these equations are \bf \huge TRUE}}}\huge\checkmark[/tex]

[tex]\large\textsf{Good luck on your assignment and enjoy your day!}[/tex]

~[tex]\frak{Amphitrite1040:)}[/tex]

Answer

Step-by-step explanation:

Replace x and y

[tex](3 \: \: \: 25)[/tex]

[tex]y = 6x + 7 \\ 25 = 6 \times 3 + 7 \\ 25 = 18 + 7 \\ 25 = 25[/tex]

So, the point (3,25) lie on the line y=6x+7

hope this helps you.

Have a nice day!

Answer:

3.8

Step-by-step explanation:

We can use sohcahtoa to solve this. First, we know that this triangle is a right triangle, as well as one angle and the opposite side to that angle. We are trying to find the hypotenuse.

Therefore, as sin takes opposite and hypotenuse into account, we can use that to get that sin(41°) = 2.5/x . Multiply both sides by x and divide both sides by sin(41°) to get x = 2.5/sin(41°) =3.8

Answer: Feet

Step-by-step explanation:

Answer:

54cm and 36cm

Step-by-step explanation:

triangle a : triangle b

50cm² : 16cm²

25 : 8

thus,

area of triangle a :

2cm×25cm

=50cm²

area of triangle b :

2cm×16cm

=32cm²

then,

perimeter of triangle a:

2cm+2cm+25cm+25cm

=54cm

perimeter of triangle b:

2cm+2cm+16cm+16cm

=36cm

Answer:

1, 2, 3, 4

Step-by-step explanation:

x+(x+1)+(X+2)+(X+3)+2 = 3(X+3)

4X+8=3x+9

x=1

Answer:

5,6,7,8

Step-by-step explanation:

5+6+7+8=26

8*3=24

26-24=2

Answer:

Step-by-step explanation:

pythagoras theorem

a^2+b^2=c^2

21^2+20^2=29^2

441+400=841

841=841

since the sum of square of two smaller sides is equal to the square of longest side .The given triangle can form right angle.

Answer:

270

Step-by-step explanation:

Answer:

the answer is 270

Answer:

(4,-5)

Explanation:

Answer:

D. 14.73

Step-by-step explanation:

According to Pythagoras,

19^2 = 12^2 + x^2

x^2 = 19^2 - 12^2

x^2 = 361 - 144

x^2 = 217

x = [tex]\sqrt{217}[/tex]

x = 14.73

Step-by-step explanation:

This is your answer for the question

9=6y + 33 the answer is  y=−4

the next one is   x=10

Step-by-step explanation:

Answer:

hope it helped u :)

Step-by-step explanation:

[tex]9 + 6y = 33\\6y = 33 - 9\\6y = 24\\y = 4\\\\\\-4(2-1.2x) = 40\\-8 + 4.8x = 40\\4.8x = 48\\x = \frac{48}{4.8} = \frac{48 \times 10}{48} = 10[/tex]

Answer:

The numbers are 11 and -4

Step-by-step explanation:

Given

Let the two numbers be [tex]x[/tex] and [tex]y[/tex]

such that:

[tex]x + y = 7[/tex]

[tex]x*y = -44[/tex]

Required

Find x and y

Make y the subject in: [tex]x + y = 7[/tex]

[tex]y = 7 - x[/tex]

Substitute [tex]y = 7 - x[/tex] in [tex]x*y = -44[/tex]

[tex]x(7-x) = -44[/tex]

Open bracket

[tex]-x^2 +7x = -44[/tex]

Rewrite as:

[tex]x^2 -7x -44=0[/tex]

Expand

[tex]x^2 +4x-11x -44=0[/tex]

Factorize

[tex]x(x +4)-11(x +4)=0[/tex]

Factor out x + 4

[tex](x -11)(x +4)=0[/tex]

Solve for x

[tex]x =11; x =-4[/tex]

Recall that:

[tex]y = 7 - x[/tex]

So:

[tex]y = 7-11 = -4[/tex]

or

[tex]y = 7--4 = 11[/tex]

Answer:

I apologize for not being able to hang out but, I have a situation I need to take care of. I wish I wasn't in this current predicament but I can not leave this problem unsolved. I need to (take care of my younger siblings, finish an assignment, study for a test/quiz, or am simply tired and need to relax). Any of those options could be acceptable.

I hope this helps! :D

I think it is, I have no clue.

Here's some examples though, 5 example of not well defined sets: - Number of fire damages. - Number of reported crime scenes. ... - Numbers of illegal settlers.

Red, blue, yellow, green, purple is well-defined since it is clear what is in the set.

Answer:

No

Step-by-step explanation:

Answer: its not right triangle

Step-by-step explanation: no becauce  [tex]11^2+15^2\neq 18^2=> 346\neq 324[/tex]

Hope this helps. Sorry for wrong answers

Answer:

C = 3

Answer:

the awnser is A i was just studing about it

Answer:

2700

Step-by-step explanation:

108*25=2700

100*25=2500

            +

    8*25=200

-------------------------------

               2700

Answer:

I'm not 100% positive, but I think it's 30

9514 1404 393

Answer:

  x = -6/11

Step-by-step explanation:

We assume you want the solution to ...

  3/x +2/(x+1) = 3/(5x)

Subtracting the term on the right, we get the form f(x) = 0.

  [tex]\displaystyle\frac{3}{x}+\frac{2}{x+1}-\frac{3}{5x}=0\\\\\frac{15-3}{5x}+\frac{2}{x+1}=0\\\\\frac{12(x+1)+10x}{5x(x+1)}=0\\\\22x+12=0\quad\text{numerator must be zero}\\\\x+\frac{6}{11}=0\quad\text{divide by 22, simplify}\\\\\boxed{x=-\frac{6}{11}}[/tex]

_____

If you really intend 3/x +2/(x+1) = (3/5)x as you have written, the solution is 3 irrational values for x. I find a graphing calculator a convenient way to find them.