If the mass of an object is 5 kg, the gravitational field strength is 2 and the change in height is 5 m, what is the change in gravitational potential energy stored?

Answer:

In a truss bridge, two long - usually straight members known as chords - form the top and bottom; they are connected by a web of vertical posts and diagonals. The bridge is supported at the ends by abutments and sometimes in the middle by piers.

Explanation:

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Answer:

All matter is made up of atoms.

Answer:

Based on what we have learned so far, in what ways have the experiences of Asian-Canadians stayed the same over time? Why do you think these similarities exist? Please give specific examples to support your ideas.

Explanation:

Answer:

9.7 miles per second

Explanation:

divide 200 by 20.6

Answer:

10N/m

Explanation:

Using F=kx

F=mg

k=mg/x

k=0.1*10/0.1 (kg*m/s^2)/m

10N/m

Answer: 43.7

Explanation: Simply round the number so that there are only three digits in the number.

We have that 43.659 rounded to three significant digits is

[tex]43.659=43.7[/tex]

From the Question we are Given

Integer=43.659

To round off to three significant digits means to represent only three digits

Therefore

43.659 in  three digits is

[tex]43.659=43.7[/tex]

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Answer is 29.1 mol or 525 g

Explanation:

Answer:

→Inverted image ( upside down )

→Real image ( because it is formed on the screen )

→Magified image ( image size is greater than object size)

F = ma

so, we can write it as;

= 5 = m × 20

= 5/20 = m

= 1/4 = m

= 0.25 kg = m

Light is a form of electromagnetic radiation with a wavelength which can be detected by the human eye. It is a small part of the electromagnetic spectrum and radiation given off by stars like the sun. Animals can also see light. The study of light, known as optics, is an important research area in modern physics.

Answer:

hope it is helpful to you

Answer:

it reheated and use form another

Answer:

a

Explanation:

because it has  compact  molecules  

[tex] \orange{\underline{\huge{\bold{\textit{\green{\bf{QUESTION}}}}}}}[/tex]

The apparent depth of an object at the bottom of a tank filled with a liquid of refractive index 1.3 is 7.7 cm. What is the actual depth of the liquid in the tank?

[tex]{\bold{\blue{GIVEN}}}[/tex]

REFRACTIVE INDEX = 1.3

APPARENT DEPTH = 7.7 cm

[tex]{ \bold{\green{To \: Find}}}[/tex]

REAL DEPTH OF THE OBJECT.

[tex]{\red{FORMULA \: \: USED }}[/tex]

[tex]Reflective \: Index = \frac{Real \: Depth}{Apparent \: Depth } [/tex]

[tex] \huge\mathbb{\red A \pink{N}\purple{S} \blue{W} \orange{ER}}[/tex]

Refractive Index = 1.3

Apparent Depth = 7.7 cm

Putting the values in the formula:-

[tex]Reflective \: Index = \frac{Real \: Depth}{Apparent \: Depth } \\ \\ 1.3 = \frac{Real \: Depth}{7.7 \: cm} \\ \\ 1.3 \times 7.7 = Real \: Depth \\ \\ 10.01 \: \: cm = Real \: Depth[/tex]

Answer:

 U = 25 J

Explanation:

The energy in a set of charges is given by

          U = [tex]k \sum \frac{q_i}{r_i}[/tex]

in this case we have three charges of equal magnitude

          q = q₁ = q₂ = q₃

with the configuration of an equilateral triangle all distances are worth

          d = a

          U = k ( [tex]\frac{q_1q_2}{ r_1_2 } + \frac{q_1q_3}{r_1_3} + \frac{q_2q_3}{r_2_3}[/tex] )

we substitute

           15 = k q² (3 / a)

            k q² /a = 5

For the second configuration a load is moved to the measured point of the other two

          d₁₃ = a

The distance to charge 2 that is at the midpoint of the other two is

          d₁₂ = d₂₃ = a / 2

           U = k (\frac{q_1q_2}{ r_1_2 } + \frac{q_1q_3}{r_1_3} + \frac{q_2q_3}{r_2_3})

            U = k q² (  [tex]\frac{2}{a} + \frac{1}{a} + \frac{2}{a}[/tex] )

            U = (kq² /a) 5

substituting

            U = 5 5

            U = 25 J

Answer:

8.5 Ω

Explanation:

La resistencia de un material es directamente proporcional a su longitud e inversamente proporcional al área de la sección transversal.

La fórmula de la resistencia (R) viene dada por:

R = ρL/A

Donde ρ es la resistividad del material, L es la longitud del material y A es el área de la sección transversal del material.

Dado que:

L = 1 km = 1000 m, A = 2 mm² = 2 * 10⁻⁶ m², ρ (cobre) = 1.7 * 10⁻⁸ Ωm

Sustituyendo da:

R = 1,7 * 10⁻⁸ * 1000/2 * 10⁻⁶

R = 8.5 Ω

Answer:

The factors affecting climate are latitude, altitude, land and water distribution, distance from the sea, distance from the sun, prevailing winds and ocean currents, surface covering the land, volcanism, solar constant sunspots, wind direction and nature of mountain chains, mountain barriers.

There are six major climatic controls. They are:

Latitude: As the earth is round, sunlight does not reach everywhere equally. The temperature decreases as we move from the equator to the poles.

Altitude: As we move from the surface of the earth to the higher altitudes, the temperature decreases.

Pressure and wind system: The pressure and wind system of any area depend on the latitude and altitude of that place. Thus, it influences the temperature accordingly.

Distance from the sea: Coastal regions are cooler as compared to interior regions. As the distance from the sea increases, its influence decreases and the people experience extreme weather conditions.

Ocean currents: Cold ocean currents flowing over a region will decrease the temperature of that area whereas warm currents will increase the temperature.

Relief features: Relief features are the barriers that block currents from entering the country. High mountains act as barriers for cold or hot winds.

Explanation:

the rate at which someone or something moves or operates or is able to move or operate.

Answer:

   I = 2.667 kg m²

Explanation:

The moment of inertia of a body can be calculated by the expression

         I = ∫ L² dm

For high symmetry bodies the expressions of the moment of inertia are tabulated, for a rod with its axis of rotation at its midpoint it is

         I = [tex]\frac{1}{12}[/tex] m L²

let's calculate

         I = [tex]\frac{1}{12}[/tex]  2  4²

         I = 2.667 kg m²

There are approximately 6.24 x 10¹⁸ electrons contained in 1.0 C of charge. The mass of the electron in 1.0 C of charge remains the same as the mass of an electron, which is approximately 9.109 x 10⁻³¹ kg.

We may utilise the elementary charge, which represents the charge of a single electron, to calculate how many electrons are present in 1.0 C of charge. It is estimated that the elementary charge is 1.602 x 10-19 C.

Number of electrons = Charge ÷ Elementary charge

Number of electrons = 1.0 C ÷ (1.602 x 10⁻¹⁹ C)

Calculating the division:

Number of electrons ≈ 6.24 x 10¹⁸ electrons

Therefore, there are approximately 6.24 x 10¹⁸ electrons contained in 1.0 C of charge.

It is crucial to remember that the electron's mass is unaffected by the charge when considering the electron's mass in 1.0 C of charge. Regardless of the charge it carries, an electron has a mass of about 9.109 x 10⁻³¹ kg.

Thus, the mass of one electron, which is roughly 9.109 x 10⁻³¹ kg, remains constant in 1.0 C of charge.

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Answer:

Concave mirrors reflect light to a central point (converging)

Suppose the source is to the left of the  mirror in  question.

Parallel rays into the mirror are always reflected towards the focal point.

In the case of a concave mirror the real parallel rays pass thru the focal point.

If the mirror is convex the rays will diverge to the left and act as if they were emanating from the focal point to the right of the mirror.