Answer:
See Explaination
Step-by-step explanation:
According To Question
In Quadrant-1 (0* to 90*) ( All the Trignometry Functions are Positive )In Quadrant-2 (90* to 180*) (Only Sine & Cosecant are Positive)In Quadrant-3 (180* to 270*) (Only Tangent & Cotangent Are Positive)In Quadrant-4 (270* to 360*) ( Only Cosine & Secant Are Positive)(Diagram, Please Find In Attachment)
Question 38 . Cos ∅ = 12/13 ∅ in Quadrant-4(Where only Cos & Sec are Positive all other Functions Are Negative in this Quadrant)
Now ∅ Represent a Right Angle Triangle with Base=12 Perpendicular=5 & Hypothenese=13
other Five Trignometry Functions Are as FollowSin∅ = -5/13 , Cosec∅=-13/5 , Tan∅=-5/12 , Cot∅=-12/5 & Sec∅=13/12
Question 39 . SinX=-3/4 X Lies in Quadrant-3(Where only Tan & Cot are Positive all other Functions Are Negative in this Quadrant)
Now For Other Trignometry FunctionsFind By Using Basic Formulas
[tex]SinX^{2}+CosX^{2}=1[/tex] ↔ Put Value of Sin∅=-3/4
We get CosX= ±[tex]\frac{\sqrt{5} }{4}[/tex] (but X Lies in Quadrant-3 Where Cosine Is Negative , So Neglect CosX= +[tex]\frac{\sqrt{5} }{4}[/tex])
So CosX= -[tex]\frac{\sqrt{5} }{4}[/tex] ...... now you get the point . All Questions Will Solve like This .
Challenge: Solve x+3y=-6 for x. Then use your value for x to solve for y.
X=
Y=
Answer:
X = -6 - 3y
Y = -1
Step-by-step explanation: Solve for X first using basic algebra. Plug in X vaalue to original equation and solve. -6 - 3y + 3y = -6. Solve by adding 6 to both sides of the equation and dividing -3y by 3y.
identify EFG
Answer Options:
= 45
= 35
= 22.5
=27.5
Answer:
22.5
Step-by-step explanation:
Inscribed Angle =1/2 Intercepted Arc
F = 1/2 (45)
<F = 22.5
A wave with a frequency of 60 hertz would generate 60 wave crests every
- 1 7/8 + 2 1/4
Plz help im confused
[tex]0.375[/tex] ✅
Step-by-step explanation:
[tex] - 1 \frac{7}{8} + 2 \frac{1}{4} \\ = - \frac{15}{8} + \frac{9}{4} \\ = - \frac{15}{8} + \frac{9 \times 2}{4 \times 2} \\ = \frac{ - 15 + 18}{8} \\ = \frac{3}{8} \\ = 0.375[/tex]
[tex]\large\mathfrak{{\pmb{\underline{\orange{Happy\:learning }}{\orange{!}}}}}[/tex]
Determine the time 2 hours and 7 minutes after 22:57
Answer:
01:04
Step-by-step explanation:
add 7 minutes to 22:57 to get 23:04. then add 2 hours to get to 01:04.
Graph the inequality. y ≥ |x + 5| - 3
Answer:
1
Step-by-step explanation:
Rewrite each side with a common base and solve. Round your answer to two decimal places.
3^4x=1/27
Jen factored x² - 4x - 21 as (x - 3)(x + 7) What did she do wrong?
Answer:
She didn't put the sign's in the proper place, it should be ( x + 3 ) ( x - 7 )
Step-by-step explanation:
( x - 3 ) ( x + 7 ) = x² + 7x - 3x - 21 = x² + 4x - 21
( x + 3 ) ( x - 7 ) = x² - 7x + 3x - 21 = x² - 4x - 21
[Pre-Calc] Please Help! I don’t know where to start. How do I do this?
Answer:
See Below.
Step-by-step explanation:
Problem A)
We have:
[tex]\displaystyle \csc^2\theta \tan^2\theta -1=\tan^2\theta[/tex]
When in doubt, convert all reciprocal trig functions and tangent into terms of sine and cosine.
So, let cscθ = 1/sinθ and tanθ = sinθ/cosθ. Hence:
[tex]\displaystyle \left(\frac{1}{\sin^2\theta}\right)\left(\frac{\sin^2\theta}{\cos^2\theta}\right)-1=\tan^2\theta[/tex]
Cancel:
[tex]\displaystyle \frac{1}{\cos^2\theta}-1=\tan^2\theta[/tex]
Let 1/cosθ = secθ:
[tex]\sec^2\theta -1=\tan^2\theta[/tex]
From the Pythagorean Identity, we know that tan²θ + 1 = sec²θ. Hence, sec²θ - 1 = tan²θ:
[tex]\tan^2\theta =\tan^2\theta[/tex]
Problem B)
We have:
[tex]\sin^3x=\sin x-\sin x \cos^2 x[/tex]
Factor out a sine:
[tex]\sin x(\sin^2 x)=\sin x-\sin x\cos^2 x[/tex]
From the Pythagorean Identity, sin²θ + cos²θ = 1. Hence, sin²θ = 1 - cos²θ:
[tex]\sin x(1-\cos^2 x)=\sin x-\sin x\cos^2x[/tex]
Distribute:
[tex]\sin x- \sin x \cos^2 x=\sin x-\sin x\cos^2 x[/tex]
Problem C)
We have:
[tex]\displaystyle \frac{\cos 2x+1}{\sin 2x}=\cot x[/tex]
Recall that cos2θ = cos²θ - sin²θ and that sin2θ = 2sinθcosθ. Hence:
[tex]\displaystyle \frac{\cos^2 x-\sin^2 x+1}{2\sin x\cos x}=\cot x[/tex]
From the Pythagorean Identity, sin²θ + cos²θ = 1 so cos²θ = 1 - sin²θ:
[tex]\displaystyle \frac{2\cos^2 x}{2\sin x\cos x}=\cot x[/tex]
Cancel:
[tex]\displaystyle \frac{\cos x}{\sin x}=\cot x[/tex]
By definition:
[tex]\cot x = \cot x[/tex]
hey this is my first post, does anyone know how to do this and find V?
Answer:
16
Step-by-step explanation:
8/1/2
8 divided by 1/2
8 x 2/1 = 16
Answer:
Step-by-step explanation:
P=8/V
1/2=8/V
do cross multiplication
2*8=V*1
16=V
calculate the circumference of a circle with a radius of 7.5. show or explain your reasoning.
Find the value of unknown angles.
Х
50
Answer:
[tex]x = 70^o[/tex]
Step-by-step explanation:
Given
See attachment for triangle
Required
Find x
To solve for x, we make use of:
[tex]x + 50^o + 60^o = 180^o[/tex] --- angles in a triangle
[tex]x + 110^o = 180^o[/tex]
Collect like terms
[tex]x = 180^o-110^o[/tex]
[tex]x = 70^o[/tex]
You choose a marble at random from a bag contains 12 red 10 blue 5 green 4 yellow and 29 black marbles. The marble is red.
Step-by-step explanation:
P(red) = 12/(12+10+5+4+29)
= 12/60
= 1/5
= 0.2
= 20%
Which equation can be used to solve for x?
A. sin (x) =
30
18
B. cos (x)
30
24
C. cos (x)
24
30
D.
tan (x)
24
18
NÉED HELP ASAP PLEASE check the picture
Answer:
[tex] \cos(x) = \frac{24}{30} [/tex]
OPTION C
The number of road construction projects that take place at any one time in a certain city follows a Poisson distribution with a mean of 6. Find the probability that less than 3 road construction projects are currently taking place in this city.a) 0.050409b) 0.089235c) 0.301168d) 0.014936
Answer:
The probability that less than 3 road construction projects are currently taking place in this city is 0.06197
Step-by-step explanation:
In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:
[tex]P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}[/tex]
In which
x is the number of sucesses
e = 2.71828 is the Euler number
[tex]\mu[/tex] is the mean in the given interval.
Poisson distribution with a mean of 6.
This means that [tex]\mu = 6[/tex]
Find the probability that less than 3 road construction projects are currently taking place in this city.
This is:
[tex]P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2)[/tex]
So
[tex]P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}[/tex]
[tex]P(X = 0) = \frac{e^{-6}*6^{0}}{(0)!} = 0.00248[/tex]
[tex]P(X = 1) = \frac{e^{-6}*6^{1}}{(1)!} = 0.01487[/tex]
[tex]P(X = 2) = \frac{e^{-6}*6^{2}}{(2)!} = 0.04462[/tex]
[tex]P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2) = 0.00248 + 0.01487 + 0.04462 = 0.06197[/tex]
The probability that less than 3 road construction projects are currently taking place in this city is 0.06197
13/10+2/100=?/100 do you guys know what it os
Answer:
132/100 or 1.32
Step-by-step explanation:
13/10=130/100
130/100+2/100=132/100
Answer:
132
Step-by-step explanation:
13/10+2/100=?/100
Get a common denominator of 100 for the first term
13/10 * (10/10) +2/100=?/100
130/100 + 2/100 = ?/100
132/100 = ? /100
I need help with this math problem please
Answer:
C) 3(x+7)²
Step-by-step explanation:
Answer:
A) (3x + 21)(x + 7)
Step-by-step explanation:
If we look at the equation we can see that it is a quadratic equation, therefore we can factor it in the following way...
[tex]3x^{2} + 42x + 147 = 3x^{2} + 21x + 21x + 147 = 3x(x + 7) + 21(x + 7) = (3x + 21)(x + 7)[/tex]
Therefore the answer is A)
Insert a digit to make the number divisible by 24 if possible:
44_8
pls help
Answer:
it's 4488 Wich would make 187
The missing number in the arithmetic sequence 60, 51,
33 is:
43.
41.
ОООО
40.
42.
Step-by-step explanation:
missing where ?
I guess you mean that there is one element missing between 51 and 33 (based on the readable answer options).
if that is true, then the missing element is 42.
the difference between 60 and 51 is 9.
the difference between 51 and 33 is 18.
if there is an engender missing in between 51 and 33, then it is logical to put it in the middle cutting the interval of 18 in half to 2 times 9. which is also supported by the first interval between 60 and 51 (9).
so, it would be 51 -9 = 42
A planet has a circumference of approximately 39,750 km. with this circumference, what is it's radius?
the radius of the planet is_____ (round to the nearest integer as needed)
use the measurement above to determine the length of an arc from the North Pole of the planet to the Equator.
Answers:
radius = 6326 kmdistance from north pole to equator = 1582 kmThese values are approximate
=============================================================
Explanation:
The circumference formula is
C = 2*pi*r
which rearranges to
r = C/(2pi)
when solving for r.
Plug in the given circumference to find that
r = C/(2pi)
r = (39,750)/(2pi)
r = 6,326.40898790283
For the sake of the most accuracy possible, I'm using my calculator's stored version of pi (and not something like pi = 3.14); if your teacher requires you to use pi = 3.14 then follow those instructions of course.
The radius is roughly 6326 km when rounded to the nearest integer.
Keep in mind that the earth isn't a perfect sphere, but rather a slightly squished one. This means the earth is slightly fatter than it is tall. However, for the sake of this problem, we'll assume it's a sphere.
------------------------
Once you determine the circumference, aka distance around the circle, we can figure out the next problem: determining the distance from the north pole to the equator. This distance runs along a line of longitude, so it's a north-south distance.
Again, imagine the earth is a perfect sphere. This means that the equator circumference is the same as the circumference as a full longitude line when we travel the globe only along that line. In other words, start at the north pole, travel along that specific longitude only until you reach the south pole. Then staying on that line, travel back to the north pole going around the backend of the earth.
That full circular path we traveled will get cut into 1/4 because 1/2 the circumference is the portion from north to south pole, and then we cut that distance in half when going from north pole to the equator.
(1/4)*(6,326.40898790283) = 1,581.6022469757
That rounds to 1582 km
------------------------
Side notes:
39750 km = 24700 miles (approximate)6326 km = 3931 miles (approximate)1582 km = 983 miles (approximate)To convert from km to miles, you divide by roughly 1.609344Pamela's age is three times Jiri's age. The sum of their ages is 28 . What is Jiri's age?
Answer:
So, if we say Jiri's age is j (we can pick any letter), then Pamela's age is 2j, right?
j + 2j = 72
j is the same as 1j, but we wouldn't call you 1James, just James.
3j = 72
To isolate j, we do the opposite operation to both sides.
3j/3 = 72/3
j/j = 1, so that cancels out. 72/3 = 24.
j = 24
Jiri is 24 years old.
Answer:
Jiri is 7 years old.
explanation:
3j + j = 28
4j = 28
4j/4 = 28/4
j = 7
this can be proven:
Pamela's age: 3×7 = 21
the sum of their ages = 28
7 + 21 = 28
Which point is a good approximation of a turning point
of the graph?
0 (-1.5,3)
0 (-0.5, -1)
0 (0,0)
O (1.0)
Answer:
(-0.5, -1)
Step-by-step explanation:
A turning point is a point of the graph where the graph changes from increasing to decreasing (rising to falling) or decreasing to increasing (falling to rising)
What is the value of x in the figure below? If necessary, round your answer to
the nearest tenth of a unit.
X
12
D 4 B
A. 3.1
O
B. 12
C. 6.9
O D. 4
Answer:
O A. 3.1
Step-by-step explanation:
it's correct if I'm rwong (*´ω｀*)
Answer: The answer is C. 6.9
Step-by-step explanation:
Find the focus of the parabola whose equation is y=1/8 x^2
Answer:
The focus is: [tex](0,2)[/tex]
Step-by-step explanation:
Given
[tex]y = \frac{1}{8}x^2[/tex]
Required
Determine the focus
The focus of a parabola
[tex](x- h)^2 = 4p(y - k)[/tex]
is:
[tex](h,k+p)[/tex]
So, we have:
[tex]y = \frac{1}{8}x^2[/tex]
Cross multiply
[tex]8y = x^2[/tex]
Rewrite as:
[tex]x^2 = 8y[/tex]
Rewrite as:
[tex](x - 0)^2 = 8(y - 0)[/tex]
Express 8 as 4 * 2
[tex](x - 0)^2 = 4 * 2(y - 0)[/tex]
By comparison with: [tex](x- h)^2 = 4p(y - k)[/tex]
[tex]h = 0[/tex] [tex]p =2[/tex] [tex]k = 0[/tex]
So, the focus [tex](h,k+p)[/tex] is:
[tex](h,k+p) = (0,0+2)[/tex]
[tex](h,k+p) = (0,2)[/tex]
A carpenter is designing rectangular picture frames to sell at a local craft fair. The frames will be made of wood with a uniform width around the picture, and each frame will have an opening for a 5-inch by 7-inch picture.
Quieres un chocolate?
Please help reply correctly in Spanish
Answer:
sí, (yo) quiero un chocolate
Find the perimeter of quadrilateral ABCD. Round to the nearest tenth.
Kite A B C D on a coordinate plane with coordinates A 3 comma 5, B 1 comma 3, C 3 comma negative 1, and D 5 comma 3.
11.3 units
14.6 units
17.4 units
56.0 units
Answer:
14.6 units
Step-by-step explanation:
AB = [tex]\sqrt{(1-3)^2+(3-5)^2}[/tex]
AB =[tex]\sqrt{8}[/tex]
BC = [tex]\sqrt{(3-1)^2+(-1-3)^2}=\sqrt{20}[/tex]
CD = [tex]\sqrt{(5-3)^2+(3-(-1))} = \sqrt{20}[/tex]
DA = [tex]\sqrt{(5-3)^2+(3-5)^2} = \sqrt{8}[/tex]
Primeter = [tex]\sqrt{8} + \sqrt{20} + \sqrt{20} +\sqrt{8} = 14.6[/tex]
tan(pi/2)=_
A. -1
B. 0
C. 1
D. Undefined
AP3X
Answer:
I don't know the answer
Step-by-step explanation:
c.1
Candace invests $636 in an investment that pays 7% interest compounded quarterly. What is her annual effective yield? Input answer as a percentage to two decimal places.
Answer:
7.19%
Step-by-step explanation:
let i be the effective rate
[tex](1+\frac{.07}{4})^4=(1+i)\\.071859031[/tex]
The annual effective yield will be 7.19% for the investment.
What is compound interest?Compound interest, also known as interest on principal and interest, is the practice of adding interest to the principal amount of a loan or deposit.
Given that Candace invests $636 in an investment that pays 7% interest compounded quarterly.
The annual effective yield will be calculated as below:-
[ ( 1 + ( 0.07 / 4 )⁴ ] = ( 1 + i)
Solve the equation:-
i = 0.0718
i = 0.0718 x 100 = 7.19%
Therefore, the annual effective yield will be 7.19% for the investment.
To know more about compound interest follow
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I need help Thank you i will give brinalist
Answer:
the answer to this is c no association.
Answer:
C
Step-by-step explanation:
The scatter plot doesn't look linear at all. Therefore, there is no association to game attendance and games won.
