In which direction of the wave motion do longitude waves transfer energy ?

Answers

Answer 1

Answer:

Hello There!!

Explanation:

The answer is O parallel.

hope this helps,have a great day!!

~Pinky~


Related Questions

Which of the following never cause a change in the motion of an object? A. Net forces B. Unbalanced forces O C. Balanced forces O D. Contact forces​

Answers

Answer:

balanced force never changes its motion

A ball is spun around in circular motion such that its frequency is 10 Hz.
a. What is the period of its rotation?
b. How much time will be required to complete 100 rotations?

Answers

Answer:

a = 0.1 s b. 10 s

Explanation:

Given that,

The frequency in circular motion, f = 10 Hz

(a) Let T is the period of itsrotation. We know that,

T = 1/f

So,

T = 1/10

= 0.1 s

(b) Frequency is number of rotations per unit time. So,

[tex]t=\dfrac{n}{f}\\\\t=\dfrac{100}{10}\\\\t=10\ s[/tex]

Hence, this is the required solution.

A bicyclist rides 1.59 km due east, while the resistive force from the air has a magnitude of 7.00 N and points due west. The rider then turns around and rides 1.59 km due west, back to her starting point. The resistive force from the air on the return trip has a magnitude of 7.00 N and points due east. Find the work done by the resistive force during the round trip. Number Units

Answers

Answer:

The required work done by the resistive force = -22.3 kJ

Explanation:

We understand that the amount of work done for a force F and displacements is provided as the product of force multiplied by displacement, which can be represented as W = F.S

Now, when the cyclist travels east and returns west, the force and displacement directions will be opposite and they make an angle 180 degrees apart.

W = -2 × 7.00 × 1590

W = -22260 J

W = -22.3 kJ

What is the energy stored in food?

Answers

Hey there!

The energy that is stored in food is called CHEMICAL ENERGY

So, when humans/people eat foods their bodies transfigure the energy that is stored which is known as the calories.

Whereas the chains (bonds) in the middle of the atoms in the food humans eat that break up the check mal reactions that has been taken into place and newer compounds will be created. Each food that you eat stores unlikeable amounts of energy

Answer: Chemical energy

Good luck on your assignment and enjoy your day!

~Amphitrite1040:)

Which element is the biggest contributor to Climate Change?

Answers

Answer:

carbon dioxide (CO2)

Explanation:

the burning or combustion of these fossil fuels creates gases that are released into the atmosphere. Of these gases, carbon dioxide (CO2) is the most common and is the gas most responsible for exacerbating the green- house effect that is changing global climate patterns.

A spherical light bulb dissipates 100W and is of 5cm diameter. Assume the emissivity is 0.8 and the irradiation is negligible. What is the surface temperature of this spherical light bulb

Answers

Answer:

[tex]T=728.9K[/tex]

Explanation:

Power [tex]P=100W[/tex]

Diameter [tex]d=5[/tex]

Radius [tex]r=2.5cm=>2.5*10^{-2}m[/tex]

Emissivity [tex]e=0.8[/tex]

Generally the equation for Area of Spherical bulb is mathematically given by

[tex]A=4\pi r^2[/tex]

[tex]A=4\pi (2.5*10^{-2}m)^2[/tex]

[tex]A=7.85*10^{-3}m^2[/tex]

Generally the equation for Emissive Power bulb is mathematically given by

[tex]E=e\mu AT^4[/tex]

Where

[tex]\mu=Boltzmann constants\\\\\mu=5.67*10^{-8}[/tex]

Therefore

[tex]T^4=\frac{E}{e\mu A}[/tex]

[tex]T^4=\frac{100}{0.8*5.67*10^{-8}*7.85*10^{-3}m^2}[/tex]

[tex]T=^4\sqrt{2.80*10^{11}}[/tex]

[tex]T=728.9K[/tex]

A volleyball is served at a speed of 8 / at an angle 35° above the horizontal. What is the speed of the ball when received by the opponent at the same height?

Answers

the speed of the ball is how hard u hit it

What is the current running through a parallel circuit containing a 10 V battery and three resistors, each 3 ohms

Answers

Answer:

the current through the circuit is 10 A.

Explanation:

Given;

voltage of the battery, V = 10 V

number of the parallel resistors, = 3

resistance of each resistor, r = 3 ohms

The equivalent resistance is calculated as;

[tex]\frac{1}{R_t} = \frac{1}{r_1}+ \frac{1}{r_2} + \frac{1}{r_3} \\\\\frac{1}{R_t} = \frac{1}{3}+ \frac{1}{3} + \frac{1}{3}\\\\\frac{1}{R_t} =\frac{3}{3} \\\\\frac{1}{R_t} = 1\\\\R_t = 1 \ ohms[/tex]

The current through the circuit is calculated as;

V = IRt

I = V/Rt

I = 10/1

I = 10 A

Therefore, the current through the circuit is 10 A.

write the full form of MBBS pliz now​

Answers

Answer:

The full form of MBBS is Bachelor of Medicine, Bachelor of Surgery

pls mark me brainliest :))

The full form of MBBS in India is 'Bachelor of Medicine, Bachelor of Surgery'. However, MBBS is an abbreviation of Medicinae Baccalaureus Baccalaureus Chirurgiae, which is the term used for this course in Latin.

A model plane has a mass of 0.75 kg and is flying 12 m above the ground
with a speed of 18 m/s. What is the total mechanical energy of the plane?
The acceleration due to gravity is 9.8 m/s2.

Answers

Answer:

Option C. 210 J.

Explanation:

From the question given above, the following data were obtained:

Mass (m) = 0.75 Kg

Height (h) = 12 m

Velocity (v) = 18 m/s

Acceleration due to gravity (g) = 9.8 m/s²

Total Mechanical energy (ME) =?

Next, we shall determine the potential energy of the plane. This can be obtained as follow:

Mass (m) = 0.75 Kg

Height (h) = 12 m

Acceleration due to gravity (g) = 9.8 m/s²

Potential energy (PE) =?

PE = mgh

PE = 0.75 × 9.8 × 12

PE = 88.2 J

Next, we shall determine the kinetic energy of the plane. This can be obtained as follow:

Mass (m) = 0.75 Kg

Velocity (v) = 18 m/s

Kinetic energy (KE) =?

KE = ½mv²

KE = ½ × 0.75 × 18²

KE = ½ × 0.75 × 324

KE = 121.5 J

Finally, we shall determine the total mechanical energy of the plane. This can be obtained as follow:

Potential energy (PE) = 88.2 J

Kinetic energy (KE) = 121.5 J

Total Mechanical energy (ME) =?

ME = PE + KE

ME = 88.2 + 121.5

ME = 209.7 J

ME ≈ 210 J

Therefore, the total mechanical energy of the plane is 210 J.

An open 1-m-diameter tank contains water at a depth of 0.5 m when at rest. As the tank is rotated about its vertical axis the center of the fluid surface is depressed. At what angular velocity will the bottom of the tank first be exposed

Answers

Answer:

Angular velocity (w) = 8.86 rad/s

Explanation:

Angular velocity (w) = [tex]\sqrt{} 4ghi/R^{2}[/tex]

g= 9.81 m/s

R= 0.5

hi (initial depth) = 0.5m

Hence= [tex]\sqrt4* 9.81* 0.5/0.5^{2}[/tex]  = 8.86 rad/s

3. How can a generator that otherwise produces AC
current be modified to produce DC current?

Answers

The change requires a commutator. ... The brushes attached to each half of the commutator are arranged so that at the moment the direction of the current in the coil reverses, they slip from one half of the commutator to the other.

A sample contains 36 g of a radioactive isotope. How much radioactive isotope remains in the sample after 3 half-lives?
A. 12 g
B. 18 g
C. 4.5 g
D. 9 g

Answers

Answer:

Option "C": "4.5 g"

Explanation:

N0 = 36 g, Let half-life is T.

t = 3 T, n is number of half lives = t / T = 3

By using the decay law of radioactivity

N / N0 = (1 / 2)^n

where

"N0" be the "initial amount"

"N" be the "amount left"

"n" be the "number of half-lives"

N / 36 = (1/2)^3

N / 36 = 1 / 8

N = 36 / 8 = 4.5 g

Answer:
4.5g

Explanation:

No = 36g Let half life is T

T= 3 T n number of half lives = t/T=3

N/No= (1/2)^n

Where, No be the initial amount

N be the amount left

n be the number of half lives

N/36 = (1/2)^3

N/36 = 1/8

N = 36/8 = 4.5g

A 500-nm wavelength light in vacuum illuminates a soap film with an index of refraction of 1.33. Air (n=1.00) is on both sides of the film. If the light strikes the film nearly perpindicularly, what is the smallest film thickness such that the film appears bright?
ANS --> 94.0

Please show your work as to how to end up with this answer.

Answers

Answer:

Wavelength of light in film (let y = lambda)

y = 500 nm / (4/3) = 375 nm    

There will be a phase change at the air/film interface (not the other side)

S = 4 t       thickness of film = S/4 where S equals 1 wavelength

This is because of the phase change at one surface

375 nm = 4 * t

t = 93.8 nm

A 0.200 m wire is moved parallel to a 0.500 T
magnetic field at a speed of 1.50 m/s. What emf is
induced across the ends of the wire?

Answers

Answer:

The required emf moved across the wire is zero

Explanation:

For a moving charge particle, the magnetic force can be determined by using the formula;

[tex]\varepsilon = Bvlsin \theta[/tex]

since the wire moves in parallel, the angle [tex]\theta[/tex] between magnetic field and velocity = 0°

B = 0.500 T

v = 1.50 m/s

l = 0.200 m

[tex]\varepsilon = (0.500 \ T )(1.50 \ m/s) \times (0.200 \ m)\times sin (0)[/tex]

[tex]\varepsilon = 0.15\times sin (0)[/tex]

[tex]\varepsilon = 0[/tex]

potential Energy is associated with position
True or false​

Answers

Answer:

yes.

Explanation:

potential Energy is associated with position

Answer:

true

Explanation:

the energy possessed by a body by virtue of its position or configuration is called potential energy.Everything at a height from the earth surface posseses potential energy.

6) The temperature of 10 kg of a substance rises by 55°C when heated. Calculate the
temperature rise when 22 kg of the substance is heated with the same quantity of heat.​

Answers

Answer:

121

Explanation:

When a person sits erect, increasing the vertical position of their brain by 38.6 cm, the heart must continue to pump blood to the brain at the same rate. (a) What is the gain in gravitational potential energy (in J) for 110 mL of blood raised 38.6 cm

Answers

Answer:

the gain in gravitational potential energy is 0.4369 J

Explanation:

Given the data in the question;

from the definition of density, we know that;

ρ = m / V

where ρ is density, m is the mass and V is the volume.

Now, lets make mass the subject of the formula

m = ρV  ------ let this be equation 1

Now, we know that potential energy PE = mgh ------- let this be equation 2

where m is mass, g is acceleration due gravity, and h is the height.

substitute equation 1 into 2

PE = ρVgh

given that; V =  110 mL = 110 × 10⁻⁶ m³, h = 38.6 cm = 38.6 × 10⁻² m, g = 9.8 m/s², ρ = 1.05 × 10³ kg/m³

we substitute

PE = (1.05 × 10³ kg/m³) × (110 × 10⁻⁶ m³) × 9.8 m/s² × 38.6 × 10⁻² m

PE =  0.4369 J

Therefore,  the gain in gravitational potential energy is 0.4369 J

A positive electric charge is moved at a constant speed between two locations in an electric field, with no work done by or against the field at any time during the motion. This situation can occur only if the

Answers

Answer:

The options are

A) charge is moved in the direction of the field

(B) charge is moved opposite to the direction of the field

(C) charge is moved perpendicular to an equipotential line

(D) charge is moved along an equipotential line

(E) electric field is uniform

The answer is (D) charge is moved along an equipotential line

For all the criteria in the question to be met it means that the motion is perpendicular to the field and the force is perpendicular to the displacement of the charge respectively. In this scenario,

Change in velocity is zero. Work can be calculated by multiplying charge and change in velocity which when calculated will give zero.

Wind, hydropower, and solar can all be used to make ___​

Answers

Answer: reusable energy or just energy but i think its just energy

Explanation:

What is the thinnest soap film (excluding the case of zero thickness) that appears black when illuminated with light with a wavelength of 555 nmnm

Answers

Answer:

The minimum thickness of soap film is [tex]2.086\times 10^{-7} m[/tex].

Explanation:

wavelength = 555 nm

refractive index, n = 1.33

For the destructive interference,

the thickness is given by

[tex]t =\frac{m \lambda }{2 n}[/tex]

Here, m is the order, n is the refractive index and [tex]\lambda[/tex] is the wavelength.

For minimum thickness, m = 1

So the thickness is  

[tex]t =\frac{1 \times 555\times 10^{-9} }{2 \times 1.33}\\\\t = 2.086\times 10^{-7} m[/tex]

An electromagnetic wave is generated by:

Answers

Answer:

Electromagnetic waves are produced whenever electric charges are accelerated. This makes it possible to produce electromagnetic waves by letting an alternating current flow through a wire, an antenna. The frequency of the waves created in this way equals the frequency of the alternating current.

Explanation:

A small planet having a radius of 1000 km exerts a gravitational force of 100 N on an object that is 500 km above its surface. If this object is moved 500 km farther from the planet, the gravitational force on it will be closest to Group of answer choices 56 N. 24 N. 77 N. 45 N. Flag question: Question 14 Question 14

Answers

Answer:

The gravitational force will be closest to group A: 56 N.

Explanation:

The gravitational force of the planet is given by:

[tex] F = \frac{GmM}{r^{2}} [/tex]

Where:

G: is the gravitational constant

m: is the mass of the object

M: is the mass of the planet

r: is the distance

When the object is 500 km above the surface of the planet, the gravitational force is 100 N:

[tex] F_{1} = \frac{GmM}{r_{1}^{2}} = \frac{GmM}{(500 km + 1000 km)^{2}} = \frac{GmM}{(1500 km)^{2}} [/tex]

And when the object is 500 km farther from the planet, the gravitational force is given by:

[tex] F_{2} = \frac{GmM}{r_{2}^{2}} = \frac{GmM}{(500 km + 1500 km)^{2}} = \frac{GmM}{(2000 km)^{2}} [/tex]  

By dividing F₂ by F₁ we can calculate F₂:

[tex] \frac{F_{2}}{F_{1}} = \frac{\frac{GmM}{(2000 km)^{2}}}{\frac{GmM}{(1500 km)^{2}}} [/tex]

[tex] F_{2} = 100 N*\frac{(1500 km)^{2}}{(2000 km)^{2}} = 56.2 N [/tex]

Therefore, the gravitational force will be closest to group A: 56 N.

                               

I hope it helps you!                                                                                              

A stalled car is being pushed up a hill at constant velocity by three people. The net force on the car is Group of answer choices Zero down the hill and greater than the weight of the car. down the hill and equal to the weight of the car up the hill and equal to the weight of the car. up the hill and greater than the weight of the car.

Answers

Answer:

Zero

Explanation:

Net force can be defined as the vector sum of all the forces acting on a body or an object i.e the sum of all forces acting simultaneously on a body or an object.

Mathematically, net force is given by the formula;

[tex] Fnet = Fapp + Fg[/tex]

Where;

Fnet is the net force.

Fapp is the applied force.

Fg is the force due to gravitation.

In this scenario, a stalled car is being pushed up a hill at constant velocity by three people. Thus, the net force on the car is zero because all the forces acting on any physical object is equal to zero and represents a constant velocity; by balancing or cancelling each other out.

According to Sir Isaac Newton's First Law of Motion which is known as Law of Inertia, it states that an object or a physical body in motion will continue in its state of motion at continuous velocity (the same speed and direction) or, if at rest, will remain at rest unless acted upon by an external force.

The
of a waveform is the number of cycles per second.
O period
O intensity
O frequency
O amplitude

Answers

Answer:

frequency is the correct answer for the question if the answer is correct plz mark me as brainliest.

what is the length of x of the side of the triangle below?

Answers

The answer is c. I hope it’s clear

Why do nuclear power plants use fission rather than fusion to generate
electric energy?
A. Fusion requires very high pressure and temperature.
B. A problem might lead to an explosion in a fusion reactor, but not
in a fission reactor.
C. The isotope used in fission is more common than the one used
in fusion.
D. Fission produces less radioactive waste than fusion does.

Answers

Answer:

Fission is used in nuclear power reactors since it can be controlled, while fusion is not utilized to produce power since the reaction is not easily controlled and is expensive to create the needed conditions for a fusion reaction.

Explanation:

Answer:

Hello There!!

Explanation:

I think it is A. Fusion requires very high pressure and temperature. Sorry if I am wrong.

hope this helps,have a great day!!

~Pinky~

A proton accelerates from rest in a uniform electric field of 595 N/C. At one later moment, its speed is 1.15 Mm/s (nonrelativistic because v is much less than the speed of light). (a) Find the acceleration of the proton. (b) Over what time interval does the proton reach this speed? (c) How far does it move in this time interval? (d) What is its kinetic energy at the end of this interval?

Answers

At one later moment, its speed is 1. 20Mm/s (non relativistic because v is much less than the speed of light).

Select the correct answer.
A car traveling south is 200 kilometers from its starting point after 2 hours. What is the average velocity of the car?
O A 100 khmeters/hour south
OB. 200 kilometers/hour
Ос.
200 kilometers/hour north
OD.
100 kilometers/hour

Answers

Answer:

D

Explanation:

The velocity of the car would be 100 kilometer per hour.

D that should be correct boo

An aircraft is in level flight at 225 km/hr through air at standard conditions. The lift coefficient at this speed is 0.45 and the drag coefficient is 0.065. The mass of the aircraft is 900 kg. Calculate the effective lift area for the aircraft and the required engine thrust and power to maintain level flight.

Answers

Answer:

- the effective lift area for the aircraft is 8.30 m²

- the required engine thrust is 1275 N

- required power is 79.7 kW

Explanation:

Given the data in the question;

Speed V = 225 km/hr = 62.5 m/s

The lift coefficient CL = 0.45

drag coefficient CD = 0.065

mass = 900 kg

g = 9.81 m/s²

a)  the effective lift area for the aircraft

we know that for a steady level flight, weight = lift and thrust = drag

Using the equation for the lift force

F[tex]_L[/tex] = C[tex]_L[/tex][tex]\frac{1}{2}[/tex]ρV²A = W

we substitute

0.45 × [tex]\frac{1}{2}[/tex] × 1.21 × ( 62.5 )² × A = ( 900 × 9.81 )

1081.05 × A = 8829

A = 8829 / 1081.05

A = 8.30 m²

Therefore, the effective lift area for the aircraft is 8.30 m²

b) the required engine thrust and power to maintain level flight.

we use the expression for drag force

F[tex]_D[/tex] = T = C[tex]_D[/tex][tex]\frac{1}{2}[/tex]ρV²A

we substitute

= 0.065 × [tex]\frac{1}{2}[/tex] × 1.21 × ( 62.5 )² × 8.30

T = 1275 N

Since drag and thrust force are the same,

Therefore, the required engine thrust is 1275 N

Power required;

P = TV

p = 1275 × 62.5

p = 79687.5 W

p = ( 79687.5 / 1000 )kW

p = 79.7 kW

Therefore, required power is 79.7 kW

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