What are the major components of a truss bridge?
Answer:
In a truss bridge, two long - usually straight members known as chords - form the top and bottom; they are connected by a web of vertical posts and diagonals. The bridge is supported at the ends by abutments and sometimes in the middle by piers.
Explanation:
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is the Matter is made up of motionless particles.
Answer:
All matter is made up of atoms.
An engine has an imput of 100 j and gives out 27 j of useful kenetic energy what is the efficiency of the engine
Answer:
Based on what we have learned so far, in what ways have the experiences of Asian-Canadians stayed the same over time? Why do you think these similarities exist? Please give specific examples to support your ideas.
Explanation:
38. Joey set a school record for running the 200 m race. He completed the distance in
20.6s. What was his average speed?
Answer:
9.7 miles per second
Explanation:
divide 200 by 20.6
A spring extends by 10cm when a mass of 100g is attached to it. What is the spring constant?
Answer:
10N/m
Explanation:
Using F=kx
F=mg
k=mg/x
k=0.1*10/0.1 (kg*m/s^2)/m
10N/m
Jeremy is pushing his two children on a set of swings. He gives his daughter a push and she swings
Jeremy gives his son the same push, but he only swings about two feet high. What could account f
the kids got?
Jeremy's daughter has more mass, so it takes less force to get her into the air.
Jeremy's son has more mass, so it would take more force to reach the same height as his da
O
Jeremy's son has less mass, so it would take more force to reach the same height as his da
O
Jeremy's daughter has more mass, so she accelerates faster than his son.
Round off the following numbers to three significant digits:
43.659
Answer: 43.7
Explanation: Simply round the number so that there are only three digits in the number.
We have that 43.659 rounded to three significant digits is
[tex]43.659=43.7[/tex]
From the Question we are Given
Integer=43.659
To round off to three significant digits means to represent only three digits
Therefore
43.659 in three digits is
[tex]43.659=43.7[/tex]
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If 175 kJ of heat caused a chunk of ice at 0°C to melt to liquid water at 0°C, how many moles were in the ice? How many grams of ice? (Note: molar mass of ice/water is 18.02 g/mol)
Answer is 29.1 mol or 525 g
Explanation:
Pls explain the nature of the image formed by the pin-hole camera
Answer:
→Inverted image ( upside down )
→Real image ( because it is formed on the screen )
→Magified image ( image size is greater than object size)
. What is the mass of an object if it is pulled by a 5 Newton force and it accelerates at a rate of 20 m/s/s?
Please help ASAP
F = ma
so, we can write it as;
= 5 = m × 20
= 5/20 = m
= 1/4 = m
= 0.25 kg = m
[tex]what \: is \: light \: {?} [/tex]
Light is a form of electromagnetic radiation with a wavelength which can be detected by the human eye. It is a small part of the electromagnetic spectrum and radiation given off by stars like the sun. Animals can also see light. The study of light, known as optics, is an important research area in modern physics.
Answer:
Light is a form of energy which produces the sensation of sight .hope it is helpful to you
what happens to the piece of plastic?
Answer:
it reheated and use form another
Look at the diagrams. Each model the arrangement of particles in a substance.
Which diagram is the best model for a solid?
Substance A
Substance B
Substance C
Answer:
a
Explanation:
because it has compact molecules
The apparent depth of an object at the bottom of a tank filled with a liquid of refractive index 1.3 is 7.7 cm. What is the actual depth of the liquid in the tank?
[tex] \orange{\underline{\huge{\bold{\textit{\green{\bf{QUESTION}}}}}}}[/tex]
The apparent depth of an object at the bottom of a tank filled with a liquid of refractive index 1.3 is 7.7 cm. What is the actual depth of the liquid in the tank?
[tex]{\bold{\blue{GIVEN}}}[/tex]
REFRACTIVE INDEX = 1.3
APPARENT DEPTH = 7.7 cm
[tex]{ \bold{\green{To \: Find}}}[/tex]
REAL DEPTH OF THE OBJECT.
[tex]{\red{FORMULA \: \: USED }}[/tex]
[tex]Reflective \: Index = \frac{Real \: Depth}{Apparent \: Depth } [/tex]
[tex] \huge\mathbb{\red A \pink{N}\purple{S} \blue{W} \orange{ER}}[/tex]
Refractive Index = 1.3
Apparent Depth = 7.7 cm
Putting the values in the formula:-
[tex]Reflective \: Index = \frac{Real \: Depth}{Apparent \: Depth } \\ \\ 1.3 = \frac{Real \: Depth}{7.7 \: cm} \\ \\ 1.3 \times 7.7 = Real \: Depth \\ \\ 10.01 \: \: cm = Real \: Depth[/tex]
The energy stored by any pair of positive charges is inversely proportional to the distance between them, and directly proportional to their charges. Three identical point charges start at the vertices of an equilateral triangle, and this configuration stores 15 Joules of energy. How much more energy, in Joules, would be stored if one of these charges was moved to the midpoint of the opposite side
Answer:
U = 25 J
Explanation:
The energy in a set of charges is given by
U = [tex]k \sum \frac{q_i}{r_i}[/tex]
in this case we have three charges of equal magnitude
q = q₁ = q₂ = q₃
with the configuration of an equilateral triangle all distances are worth
d = a
U = k ( [tex]\frac{q_1q_2}{ r_1_2 } + \frac{q_1q_3}{r_1_3} + \frac{q_2q_3}{r_2_3}[/tex] )
we substitute
15 = k q² (3 / a)
k q² /a = 5
For the second configuration a load is moved to the measured point of the other two
d₁₃ = a
The distance to charge 2 that is at the midpoint of the other two is
d₁₂ = d₂₃ = a / 2
U = k (\frac{q_1q_2}{ r_1_2 } + \frac{q_1q_3}{r_1_3} + \frac{q_2q_3}{r_2_3})
U = k q² ( [tex]\frac{2}{a} + \frac{1}{a} + \frac{2}{a}[/tex] )
U = (kq² /a) 5
substituting
U = 5 5
U = 25 J
Tenemos un Cable de cobre de 1 km de longitud cuya sección es de 2 milímetros al cuadrado y queremos saber la resistencia que señalara el ohmetro , su temperatura es de 20°
Answer:
8.5 Ω
Explanation:
La resistencia de un material es directamente proporcional a su longitud e inversamente proporcional al área de la sección transversal.
La fórmula de la resistencia (R) viene dada por:
R = ρL/A
Donde ρ es la resistividad del material, L es la longitud del material y A es el área de la sección transversal del material.
Dado que:
L = 1 km = 1000 m, A = 2 mm² = 2 * 10⁻⁶ m², ρ (cobre) = 1.7 * 10⁻⁸ Ωm
Sustituyendo da:
R = 1,7 * 10⁻⁸ * 1000/2 * 10⁻⁶
R = 8.5 Ω
