PLS HELP ME PLZ AND THANKS

Answer:

136 KJ

Explanation:

We'll begin by calculating the heat required to melt the ice. This can be obtained as follow:

Mass (M) = 250 g

Heat of fusion (Hբ) = 334 J/gºC

Heat (Q₁) required to melt the ice =?

Q₁ = MHբ

Q₁ = 250 × 334

Q₁ = 83500 J

Next, we shall determine the heat required to change the temperature. This can be obtained as follow:

Mass (M) = 250 g

Initial temperature (T₁) = 0 °C

Final temperature (T₂) = 50 °C

Specific heat capacity (C) = 4.184 J/gºC

Heat (Q₂) required to change the temperature =?

Q₂ = MC(T₂ – T₁)

Q₂ = 250 × 4.184 (50 – 0)

Q₂ = 1046 × 50

Q₂ = 52300 J

Next, we shall determine the total heat required.

Heat (Q₁) required to melt the ice = 83500 J

Heat (Q₂) required to change the temperature = 52300 J

Total heat (Qₜ) required =?

Qₜ = Q₁ + Q₂

Qₜ = 83500 + 52300

Qₜ = 135800 J

Finally, we shall convert 135800 J to KJ. This can be obtained as follow:

1000 J = 1 KJ

Therefore,

135800 J = 135800 J × 1 KJ / 1000 J

135800 J ≈ 136 KJ

Thus, the total heat required is 136 KJ.

Answer:

0.170 M

Explanation:

As this is a series of dilutions, we can continuosly use the C₁V₁=C₂V₂ formula to solve this problem:

For the first step:

Then for when 129 mL of that 0.412 M are diluted by adding 183 mL of water:

Using C₁V₁=C₂V₂:

Answer:

19 because it gained 3 electron so 12-3=9 beryllium

2

3 is 46-2=44

4 is 2

5 is 5

6 84 polonium

7

8 oxygen

Explanation:

plz let me know if they are right or wrong:)

Answer:

A duckling swimming after its own mother

Explanation:

Answer:

10.70grams

Explanation:

Density of a substance = mass/volume

At STP of a gas (standard temperature and pressure), the density of oxygen gas is 1.429 g/L

Hence, according to this question, in 7.49 L of oxygen gas, there would be:

Using D = m/V

1.429 = m/7.49

m = 1.429g/L × 7.49L

m = 10.70g

Answer: The concentration of [tex]H^+[/tex] in the solution is [tex]3.16\times 10^{-3}M[/tex]

Explanation:

pH is defined as the negative logarithm of hydrogen ion concentration present in the solution.

[tex]pH=-\log [H^+][/tex]      .....(1)

We are given:

pH of solution = 2.5

Putting values in equation 1, we get:

[tex]2.5=-\log [H^+][/tex]

[tex][H^+]=10^{-2.5}[/tex]

[tex][H^+]=3.16\times 10^{-3}M[/tex]

Hence, the concentration of [tex]H^+[/tex] in the solution is [tex]3.16\times 10^{-3}M[/tex]

Answer:

75g

Explanation:

n=Cmxv

=0,15x12,5

=1,875 mol

m=nxM

=1,875x40

=75g

Answer:

AgCl

Explanation:

The reaction that takes place is:

The precipitate (meaning a solid substance) formed is silver chloride, AgCl.

All salts formed with silver and a halogen (F, Cl, Br, I) are insoluble in water, meaning that when working with aqueous solutions they will be precipitates.

Answer:

For a: The IUPAC name of the compound is N-ethylethaneamide.

For b: The IUPAC name of the compound is N,N-diethylmethaneamide.

For c: The IUPAC name of the compound is ethyl pentanoate

Explanation:

To name a compound, first look for the longest possible carbon chain.

Amide group is a type of functional group where an amine group is attached to a carbonyl group. The general formula of amide is [tex]R-CO-NH_2[/tex], where R is an alkyl or aryl group.

In part (a), the alkyl group has 2 carbon atoms and thus, the prefix used is 'eth-'

Also, an ethyl substituent is directly attached to N-atom. It is an alkane structured hydrocarbon thus, the suffix used will be '-ane'

Hence, the IUPAC name of the compound is N-ethylethaneamide.

Amide group is a type of functional group where an amine group is attached to a carbonyl group. The general formula of amide is [tex]R-CO-NH_2[/tex], where R is an alkyl or aryl group.

In part (b), the alkyl group has 1 carbon atoms and thus, the prefix used is 'meth-'

Also, two ethyl substituents are directly attached to N-atom. It is an alkane structured hydrocarbon thus, the suffix used will be '-ane'

Hence, the IUPAC name of the compound is N,N-diethylmethaneamide.

Esters are a kind of organic molecules having functional groups, [tex]R-COO-R'[/tex] where R and R' are the alkyl or aryl groups. They are formed by the combination of alcohol and carboxylic acid.

These functional group compounds are named in two words which is alkyl alkanoates, where alkyl refers to the alcoholic part and alkanoate refers to the carboxylic acid part of the molecule. The numbering of the parent chain in esters is done from the carboxylic carbon. The alkyl part is not given any numbers.

In part (c), there are 5 carbon atoms present in a straight chain and thus, the prefix used is 'pent-'

Also, an ethyl group forms the alcoholic part.

Hence, the IUPAC name of the compound is ethyl pentanoate

Answer:

motor oil

Explanation:

According to Oxford dictionary, viscosity refers to ''a quantity expressing the magnitude of internal friction in a fluid, as measured by the force per unit area resisting uniform flow.''

The higher the molecular weight of a substance, the greater its viscosity. This is because, the long chains in the viscous substance become entangled thereby increasing the internal friction in the liquid.

Motor oil is a heavier hydrocarbon than gasoline hence it is more viscous than gasoline.

Answer:

Motor oil

Heat it

Water

Explanation:

Answer:

7.9 × 10⁻⁹ M

Explanation:

Step 1: Given data

pH of the ocean: 8.1

Step 2: Calculate the concentration of hydronium ions

We will use the definition of pH.

pH = -log [H⁺] = -log [H₃O⁺]

[H₃O⁺] = [H⁺] = antilog -pH

[H₃O⁺] = antilog -8.1 = 7.9 × 10⁻⁹ M

Since [H₃O⁺] < 10⁻⁷ M, the solution is basic.

I am not sure abt the ans

molar mass= 88

1 molecule = 6.022×10^23

4.44 moles = 6.022×10^23×4.44/88

= 26.73768 × 10^23/88

= 0.3038372727 ×10^23

Answer:

KCl + AgNO₃ —> AgCl + KNO₃

Explanation:

To answer the question correctly, we must understand the definition of a double displacement reaction.

A double displacement reaction is a reaction in which the ions of the two reacting compounds exchange to form new compounds different from the two reacting compounds. Example is given below:

XY + AB —> XB + AY

Considering the options given in the question above, only the equation:

KCl + AgNO₃ —> AgCl + KNO₃

Satisfy the definition of a double displacement reaction.

Answer:

You answered your own question

The solubility of a substance is the amount of the substance that can be dissolved in a given amount of solvent at a specified temperature. Hence, option A is correct.

Solubility of a substance can be defined as the fraction of concentration of the substance which can be dissolved in a particular amount of a solvent at a specified temperature.

Solubility of a substance depends on the bond type, temperature, pressure and presence of impurities if any. If the bond strength is greater, less will be the solubility because, greater energy is needed to weaken the bonds in the salt.

Similarly, for most of the salts, as the temperature increases, solubility increases, but some salt's solubility is independent of the temperature such as for NaCl. Therefore, the correct definition of solubility is option A.

Find more on solubility ;

https://brainly.com/question/28170449

#SPJ2

Answer:

H 4so8 is the answer of balance the reaction

Answer:

Concentration and reaction rate is directly proportional

Explanation:

Basically, concentration is directly proportional to the concentration, so the higher the concentration, the higher the reaction rate.

Once the concentration is increased, more chemical will be added hence the reaction rate will increase

Answer:

because they were thought in college

Explanation:

hope that helps

The element whose atom may likely make a -3 ion is P.

Elements in the periodic table are classified into groups and periods. The elements in the same group have similar physical and chemical properties.

Phosphorus (P) is a member of group 15 in the periodic table. The most common ion formed by the members of this group is the -3 ion.

It is formed by accepting three electrons to complete their octet since they have five electrons on their outermost shell.

Hence P is most likely to form a -3 ion.

Learn more: https://brainly.com/question/11155928

Answer: pH = 1.066

Explanation: HCl is strong acid and it protolyzes totally:

HCl + H2O  ⇒ H3O+ + Cl-

Concentrations are same:  [H3O+] = c(HCl)

pH = - log[H3O+] = - log(0.086) = 1.0655

Answer:

CARBON 14 INCLUDES:

-six protons

-eight neutrons in the nucleus

CARBON 12 INCLUDES:

-six protons

-Six neutrons

Answer: The number of cations are [tex]3.24 \times 10^{22}[/tex] and number of anions are  [tex]3.24 \times 10^{22}[/tex] in 6.42 g of KBr.

Explanation:

The molar mass of KBr is (39.10 + 79.90) g/mol = 119.00 g/mol

Now, the dissociation equation for KBr is as follows.

[tex]KBr \rightarrow K^{+} + Br^{-}[/tex]

This means that 1 mole of KBr is forming 1 mole of [tex]K^{+}[/tex] (cation) and 1 mole of [tex]Br^{-}[/tex] (anion).

According to mole concept, 1 mole of every substance contains [tex]6.022 \times 10^{23}[/tex] atoms. Hence, number of cations present in 6.42 g KBr is calculated as follows.

[tex]No. of cations = Moles \times 6.022 \times 10^{23}\\= \frac{mass}{molar mass} \times 6.022 \times 10^{23}\\= \frac{6.42 g}{119.00 g/mol} \times 6.022 \times 10^{23}\\= 3.24 \times 10^{22}[/tex]

As according to the equation, there are equal number of moles of both cation and anions.

This means that the number of anions are also [tex]3.24 \times 10^{22}[/tex].

Thus, we can conclude that the number of cations are [tex]3.24 \times 10^{22}[/tex] and number of anions are  [tex]3.24 \times 10^{22}[/tex] in 6.42 g of KBr.

The number of cations and anions present in potassium bromide is 3.24 × 10²².

In one mole of any substance 6.022 × 10²³ atoms of that substance is present and this is known as Avogadro's number.

KBr is a strong electrolyte means it fully dissociates into their constitute ions. So, the number of moles of produced ions is equal to the moles of KBr and dissociation is represented as:

KBr → K⁺ + Br⁻

From this it is clear that 1 mole of cation and 1 mole of anion is produced from 1 mole of KBr. Moles of KBr will be calculated as:

n = W/M, where

W = given mass = 6.42g

M = molar mass = 119

n = 6.42 / 119 = 0.053 moles

No. of cations and anions present in 0.053 moles = 0.053 × 6.022 × 10²³ = 3.24 × 10²².

Hence, 3.24 × 10²² is the no. of cations and anions.

To know more about Avogadro's number,  visit the below link:
https://brainly.com/question/10614569

Answer and Explanation:

If we remember from school, we should know that the equation for finding the volume of a box (rectangular) is length times width times height.

Since we know the volume, we can divide the two sides given from the volume to find the remaining side.

0.310 ÷ 0.7120 ÷ 0.52458 = 0.83

The answer is 0.83 for the remaining side measurement.

#teamtrees #PAW (Plant And Water)

Answer:

The answer is: 0.82998448

Explanation:

If you multiply 0.7120 × 0.52458, it will equal: 0.37350096.

if you divide 0.310 ÷ 0.37350096, you will get 0.82998448.

Hope it helps!!

(also, i don't want to be "that" person, but brainliest would be apreciated!)

Answer:

(a): Precipitate of calcium carbonate will form.

(b): Precipitate of barium sulfate will form.

(c): Precipitate of silver iodide will form.

(d): Precipitate of sodium chromate will form.

Explanation:

Complete ionic equation is defined as the equation in which all the substances that are strong electrolytes present in an aqueous state and are represented in the form of ions.

Net ionic equation is defined as the equations in which spectator ions are not included.

Spectator ions are the ones that are present equally on the reactant and product sides. They do not participate in the reaction.

(a):

The balanced molecular equation is:

[tex]CaCl_2(aq)+K_2CO_3(aq)\rightarrow 2KCl(aq)+CaCO_3(s)[/tex]

The complete ionic equation follows:

[tex]Ca^{2+}(aq)+2Cl^-(aq)+2K^+(aq)+CO_3^{2-}(aq)\rightarrow 2K^+(aq)+2Cl^-(aq)+CaCO_3(s)[/tex]

As potassium and chloride ions are present on both sides of the reaction. Thus, they are considered spectator ions.

The net ionic equation follows:

[tex]Ca^{2+}(aq)+CO_3^{2-}(aq)\rightarrow CaCO_3(s)[/tex]

Precipitate of calcium carbonate will form.

(b)

The balanced molecular equation is:

[tex]BaCl_2(aq)+MgSO_4(aq)\rightarrow MgCl_2(aq)+BaSO_4(s)[/tex]

The complete ionic equation follows:

[tex]Ba^{2+}(aq)+2Cl^-(aq)+Mg^{2+}(aq)+SO_4^{2-}(aq)\rightarrow Mg^{2+}(aq)+2Cl^-(aq)+BaSO_4(s)[/tex]

As magnesium and chloride ions are present on both sides of the reaction. Thus, they are considered spectator ions.

The net ionic equation follows:

[tex]Ba^{2+}(aq)+SO_4^{2-}(aq)\rightarrow BaSO_4(s)[/tex]

Precipitate of barium sulfate will form.

(c):

The balanced molecular equation is:

[tex]AgNO_3(aq)+KI(aq)\rightarrow KNO_3(aq)+AgI(s)[/tex]

The complete ionic equation follows:

[tex]Ag^{+}(aq)+NO_3^-(aq)+K^+(aq)+I^{-}(aq)\rightarrow K^+(aq)+NO_3^-(aq)+AgI(s)[/tex]

As potassium and nitrate ions are present on both sides of the reaction. Thus, they are considered spectator ions.

The net ionic equation follows:

[tex]Ag^{+}(aq)+I^{-}(aq)\rightarrow AgI(s)[/tex]

Precipitate of silver iodide will form.

(d):

The balanced molecular equation is:

[tex]2NaCl(aq)+(NH_4)_2CrO_4(aq)\rightarrow 2NH_4Cl(aq)+Na_2CrO_4(s)[/tex]

The complete ionic equation follows:

[tex]2Na^{+}(aq)+2Cl^-(aq)+2NH_4^+(aq)+CrO_4^{2-}(aq)\rightarrow 2NH_4^+(aq)+2Cl^-(aq)+Na_2CrO_4(s)[/tex]

As ammonium and chloride ions are present on both sides of the reaction. Thus, they are considered spectator ions.

The net ionic equation follows:

[tex]2Na^{+}(aq)+CrO_4^{2-}(aq)\rightarrow Na_2CrO_4(s)[/tex]

Precipitate of sodium chromate will form.

Answer:

[tex]{ \boxed{ \bf{newtons \: law \: of \: gravitation}}} [/tex]

It states that the product of masses of bodies ( planets and satellites and asteroids ) in space is inversely proportional to square of their separation mean distance

[tex]{ \tt{formular : F = \frac{GMm}{ {r}^{2} } }}[/tex]

Answer:

D.) When HX adds to an asymmetrical alkene, the halogen attaches to the least substituted sp² carbon.

Explanation:

Which of the following statements is NOT true?

A.) When HX adds to an asymmetrical alkene, the sp² carbon bonded to the most H atoms is protonated. TRUE. This is known as Markovnikov's rule.

B.) When HX adds to an asymmetrical alkene, protonation leads to the most stable carbocation intermediate. TRUE. The order of stability of carbocations is tertiary > secondary > primary.

C.) When HX adds to a symmetrical alkene, either of the sp² carbons can be protonated. TRUE. Since the alkene is symmetrical, either carbon can be protonated.

D.) When HX adds to an asymmetrical alkene, the halogen attaches to the least substituted sp² carbon. FALSE. The halogen attaches to the most substituted sp² carbon.