Q. Find the missing side

Answer:

Slope = 4/9

Step-by-step explanation:

x1(-4,2)

x2(5,6)

Slope,

m = (y2-y1)/(x2-x1)

= (6-2)/(5--4)

=4/9

Answer:1

Step-by-step explanation:

twice a number minus a second number is -1. Twice the second number added to three times the first number is 9. find the two numbers. System of Equations is how we are supposed to solve this word problem.

Answer:

cone a is the correct answer

the third choice is the cirrect answer.

the cone with a 4.5 cm height and a 8cm diameter

hope this helps :)

Answer:

A = 20.25 sq units

Step-by-step explanation:

to find the area of a square you only need to know the measure of one side -- all other sides will be equal to it

it appears the segment is 4.5 units so you would square that to get the area

A = 4.5²

A = 20.25

Answer:

[tex] - 15[/tex]

Step-by-step explanation:

We know that,

[tex]( - ) \times ( + ) = (- )[/tex]

So,

[tex] (- 3) \times ( + 5) = - 15[/tex]

hope this helps you.

Have a nice day!

Answer:

-15

Step-by-step explanation:

(-3)*(+5) = -15

the noun press itself is already a noun. though the word can also be expressed as a verb, (for example: he pressed his face against the glass) it can also be a noun (for example: the incident was not reported to the press).

hope this helps. :)

have a great day! stay safe, happy, and healthy!

1.4 feet

let me know if you get it right hope i helped!

Answer:

14

Step-by-step explanation:

a2+(48)2=

 502\,\,50^{2}502

Use the Pythagorean Theorem.

a2+2304=a^{2}+2304=a2+2304=

 2500\,\,25002500

Simplify.

−2304-2304\phantom{=}−2304=

 −2304\,\,-2304−2304

Subtract 2304 from both sides.

a2=a^{2}=a2=

 196\,\,196196

a2=\sqrt{a^{2}}=a2

​=

 ±196\,\,\pm\sqrt{196}±196

​

Square root both sides.

a=a=a=

 14\,\,1414

Simplify. Ignore negative root, as length must be positive.

Step-by-step explanation:

3×‐9×-5y-2y =0-7

-6x-7y =-7

Answer:

[tex]x = \frac{9}{13} \ , \ y = - \frac{5}{13}[/tex]

Step-by-step explanation:

                         3x - 5y = 4 ----------- ( 1 )

                         9x - 2y = 7 -----------( 2 )

                 ______________________

( 1 ) x 9  =>       27x - 45y = 36   ----------------- ( 3 )

( 2) x 3 =>        27x - 6y = 21     -------------------( 4 )

                  _____________________

( 3 )  =>          27x - 45y = 36

- ( 4 ) =>         -27x + 6y = - 21

                   ____________________

( 3 ) - ( 4 ) =>     0x - 39y = 15

                            -39y = 15

                                [tex]y = \frac{15}{-39} = -\frac{5}{13}[/tex]

Substitute y in ( 1 ) :

                     [tex]3x - 5y = 4\\\\3x - ( 5 \times -\frac{5}{13}) = 4\\\\3x + \frac{25}{13} = 4\\\\3x = 4 - \frac{25}{13}\\\\3x = \frac{52 - 25}{13}\\\\3x = \frac{27}{13}\\\\x = \frac{27}{13 \times 3}\\\\x= \frac{9}{13}[/tex]                        

Answer:

not a function because -3 maps to two different values 5 and 6

Step-by-step explanation:

Answer:

its a function something to remember is if anything on the y line (up and down) touches its not a function otherwise it is

Step-by-step explanation:

Answer:

B) 3^-5 (1 / 243) and D) 2^5 x 6^-5 (1 / 243)

Step-by-step explanation:

3 to the negative 5th power as a fraction is

1 / 243.

2 to the power of 5 multiplied by 6 to the power of negative 5 also equals 1 / 243.

Both expressions are equivalent to 2^5 / 6^5 because they equal the same thing (1 / 243).

Answer:

an = 80. 2^(n-5)

Step-by-step explanation:

r = a6/a5 =160/80 = 2

an = a5. r^(n-5)

= 80. 2^(n-5)

Answer:

The amplitude is 3 and the period is 10π/9.

Step-by-step explanation:

The standard cosine function is in the form:

[tex]y=a\cos(b(x-c))+d[/tex]

Where |a| is the amplitude, 2π/b is the period, c is the phase shift, and d is the vertical shift.

We have the function:

[tex]f(x)=\displaystyle 3\cos\frac{9}{5}t[/tex]

We can rewrite this as:

[tex]\displaystyle f(x)=(3)\cos\left(\frac{9}{5}\left(t-0\right)\right)-(0)[/tex]

Therefore, a = 3, b = 9/5, c = 0, and d  = 0.

Hence, our amplitude is |3| = 3.

Our period will be:

[tex]\displaystyle \text{Period}=\frac{2\pi}{9/5}=2\pi \cdot \frac{5}{9}=\frac{10\pi}{9}[/tex]