Answer:
$10 a g
Explanation:
Answer:
As The mass of the beach ball is having lowest magnitude when compared with the other balls given so when apply the same magnitude of force to all the balls then the beach ball due to its lighternessand also its inertia of rest would not resist the force so much so when you apply the force to this ball it would starts to roll and covers the maximum diatance whwn compared with the other ball only in the condition when same magnitude of force applied.Thats this ball would do more work than the other ball.The mass also influences the velocity carried by the body and also the kinetic energy possessed by the body. More the force applied more the distance it would cover
Hope it helps
38. Joey set a school record for running the 200 m race. He completed the distance in
20.6s. What was his average speed?
Answer:
9.7 miles per second
Explanation:
divide 200 by 20.6
A spring extends by 10cm when a mass of 100g is attached to it. What is the spring constant?
Answer:
10N/m
Explanation:
Using F=kx
F=mg
k=mg/x
k=0.1*10/0.1 (kg*m/s^2)/m
10N/m
If 175 kJ of heat caused a chunk of ice at 0°C to melt to liquid water at 0°C, how many moles were in the ice? How many grams of ice? (Note: molar mass of ice/water is 18.02 g/mol)
Answer is 29.1 mol or 525 g
Explanation:
[tex]what \: is \: light \: {?} [/tex]
Light is a form of electromagnetic radiation with a wavelength which can be detected by the human eye. It is a small part of the electromagnetic spectrum and radiation given off by stars like the sun. Animals can also see light. The study of light, known as optics, is an important research area in modern physics.
Answer:
Light is a form of energy which produces the sensation of sight .hope it is helpful to you
what happens to the piece of plastic?
Answer:
it reheated and use form another
The apparent depth of an object at the bottom of a tank filled with a liquid of refractive index 1.3 is 7.7 cm. What is the actual depth of the liquid in the tank?
[tex] \orange{\underline{\huge{\bold{\textit{\green{\bf{QUESTION}}}}}}}[/tex]
The apparent depth of an object at the bottom of a tank filled with a liquid of refractive index 1.3 is 7.7 cm. What is the actual depth of the liquid in the tank?
[tex]{\bold{\blue{GIVEN}}}[/tex]
REFRACTIVE INDEX = 1.3
APPARENT DEPTH = 7.7 cm
[tex]{ \bold{\green{To \: Find}}}[/tex]
REAL DEPTH OF THE OBJECT.
[tex]{\red{FORMULA \: \: USED }}[/tex]
[tex]Reflective \: Index = \frac{Real \: Depth}{Apparent \: Depth } [/tex]
[tex] \huge\mathbb{\red A \pink{N}\purple{S} \blue{W} \orange{ER}}[/tex]
Refractive Index = 1.3
Apparent Depth = 7.7 cm
Putting the values in the formula:-
[tex]Reflective \: Index = \frac{Real \: Depth}{Apparent \: Depth } \\ \\ 1.3 = \frac{Real \: Depth}{7.7 \: cm} \\ \\ 1.3 \times 7.7 = Real \: Depth \\ \\ 10.01 \: \: cm = Real \: Depth[/tex]
The energy stored by any pair of positive charges is inversely proportional to the distance between them, and directly proportional to their charges. Three identical point charges start at the vertices of an equilateral triangle, and this configuration stores 15 Joules of energy. How much more energy, in Joules, would be stored if one of these charges was moved to the midpoint of the opposite side
Answer:
U = 25 J
Explanation:
The energy in a set of charges is given by
U = [tex]k \sum \frac{q_i}{r_i}[/tex]
in this case we have three charges of equal magnitude
q = q₁ = q₂ = q₃
with the configuration of an equilateral triangle all distances are worth
d = a
U = k ( [tex]\frac{q_1q_2}{ r_1_2 } + \frac{q_1q_3}{r_1_3} + \frac{q_2q_3}{r_2_3}[/tex] )
we substitute
15 = k q² (3 / a)
k q² /a = 5
For the second configuration a load is moved to the measured point of the other two
d₁₃ = a
The distance to charge 2 that is at the midpoint of the other two is
d₁₂ = d₂₃ = a / 2
U = k (\frac{q_1q_2}{ r_1_2 } + \frac{q_1q_3}{r_1_3} + \frac{q_2q_3}{r_2_3})
U = k q² ( [tex]\frac{2}{a} + \frac{1}{a} + \frac{2}{a}[/tex] )
U = (kq² /a) 5
substituting
U = 5 5
U = 25 J
Determine la inercia rotacional de una varilla de 4 m de largo y 2 Kg de mesa si su eje de rotación esta situado a la mitad de la varilla.
Answer:
I = 2.667 kg m²
Explanation:
The moment of inertia of a body can be calculated by the expression
I = ∫ L² dm
For high symmetry bodies the expressions of the moment of inertia are tabulated, for a rod with its axis of rotation at its midpoint it is
I = [tex]\frac{1}{12}[/tex] m L²
let's calculate
I = [tex]\frac{1}{12}[/tex] 2 4²
I = 2.667 kg m²
Alisa, a skateboarder, is riding down a hill. If Alisa and the skateboard are considered a single object, what forces are acting on her? Check all that apply.
Answer: gravity
normal force
friction
Explanation:
A force is refered to as the interaction which when unopposed, will lead to a change in an objects motion. The velocity of an object will be changed when force is applied.
Since Alisa s riding down a hill and she and the skateboard are considered to be a single object, then the forces that are acting on her include gravity, normal force and friction.
