To produce a neutral solution, both the anion and the cation of a salt must be neutral.

a. True
b. False

Answers

Answer 1
A. True
To produce a neutral solution both the anion and the cation of a salt must be neural.

Related Questions

What is the molarity of 20.2 g of potassium nitrate, KNO3, in enough water to make 250.0 mL of solution

Answers

Answer:

0.8M

Explanation:

CM=n/V

The molarity is an important method which is used to determine the concentration of a solution. The molarity of potassium nitrate is 0.796 M.

What is molarity?

The molarity of a solution is defined as the number of moles of the solute present per litre of the solution. It is generally expressed in mol / L. The equation used to calculate the molarity is given as:

Molarity = Number of moles of the solute / Volume of the solution in litres

The number of moles is the ratio of the given mass to the molar mass. Here the mass of potassium nitrate is 20.2 g and its molar mass is 101.10 g/mol. Then the number of moles is:

n = 20.2 g / 101.10 g/mol = 0.199 mol

1 L = 1000 mL

250.0 mL = 250.0 / 1000 = 0.25 L

Molarity = 0.199 / 0.25 = 0.796 M

Thus the molarity is 0.796 M.

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CAN YOU HELP ME PLZ AND THANKS

Answers

Answer:

Question 7 the answer is B

Explanation:

In every nuclear reaction there is always formation of products either by nuclei bombardment or by the elements breaking into two elements of the same mass

Question 8

The answer is A

Nuclear reactions release a huge amount of energy than chemical reactions

One atom of chromium (Cr) has a mass of 52.00 amu. How many chromium atoms does it take to equal a mass of 52.00 g?

Answers

1 chromium atom

Explanation:

number of (Cr) atom =

[tex] \frac{mass \: of \: cr}{molar \: mass \: (amu)} [/tex]

n = m/M

n = 52/52

n= 1g

Which of the following hydrocarbons will be the most acidic?
Pentane
Propylene
Isobutane
Ethene
Acetylene

Answers

Answer:

its answer is (Acetylene)

Using dimensional analysis convert 238.0 cm3 to L

Answers

Answer:

=  0.238 L

Explanation:

From the given information:

To convert cm³ to L(liter), we utilize the advent of a unit fraction that comprises a liter in the upper part of the fraction(numerator) and a cubic centimeter in the lower part of the fraction(denominator)

Recall that:

1000 cm³ = 1 liter

238.0 cm³ = [tex]\dfrac{238.0 \ cm^3}{1} \times \dfrac{1 \ L}{1000 \ cm^3}[/tex]

=  0.238 L

What is the oxidation state of P in Ca3(PO4)2?
A. -5
B. +3
C. +5
D. -3

Answers

The oxidation state of P in [tex]Ca_3(PO_4)_2[/tex] is +5. In the compound [tex]Ca_3(PO_4)_2[/tex], there are 3 Ca ions, each with an oxidation state of +2, and 2 [tex]PO_4[/tex] ions. The correct answer is option C.

To find the oxidation state of P, we need to use the fact that the compound has a neutral overall charge and the oxidation states of all the atoms in the compound must add up to zero. Since the oxidation state of Ca is +2, the total positive charge from the Ca ions is +6. Therefore, the total negative charge from the PO4 ions must be -6. Each [tex]PO_4[/tex] ion has a charge of -3, so the total charge from the two [tex]PO_4[/tex] ions is -6. In [tex]PO_4[/tex], the oxidation state of O is -2. Let the oxidation state of P be x. Since there is 4 O atoms per [tex]PO_4[/tex] ion, the total negative charge from the O atoms is -12. Using the fact that the overall charge is zero, we can set up the following equation: 2x + (-12) = -6 Simplifying, we get 2x = +6 - (-12) = +18 Solving for x, we get x = +9/2 = +4.5. However, the oxidation state of P must be a whole number, so we round to the nearest integer and get: +5. Therefore, the oxidation state of P in [tex]Ca_3(PO_4)_2[/tex] is +5 and the correct answer is option C.

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3. 78 mL of 2.5 M phosphoric acid is neutralized with 500 mL of potassium hydroxide. What is the
concentration of the base?

Answers


Hence, concentration of base is 1.17 M

A pure copper cube has an edge length of 1.76 cm. How many copper atoms does it contain? (volume of a cube = (edge length)^3; density of copper = 8.96 g/cm^3 )

Answers

I havent learnt this yet sry

how many grams of zinc sulfide are used to produce 1.28 grams of zinc oxide?

Answers

Answer:

0.012288122055459

Explanation:

i might be wrong

How many grams are in 3.7 moles of Na2O?

Answers

Answer:

mass = moles x molar mass

m= 3.7 x (23x2+16)

m= 3.7x62

m= 229.4g

198.4 grams are there is 3.7 moles of Na₂O.

The number of moles is defined as the ratio between given mass and molar mass.

[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}\\\\[/tex]

Given:

Number of moles= 3.7 moles

To find:

Mass=?

Molar mass of Na₂O= 62 g/mol

Thus substituting the values in the given formula

[tex]\text{Given mass}=\text{Number of moles}*\text{Molar mass}\\\\\text{Given mass}= 3.2 \text{moles}*62 \text{g/mol}\\\\\text{Given mass}=198.4 \text{g}[/tex]

Thus, 198.4 grams are there is 3.7 moles of Na₂O.

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How many grams of oxygen are present in 93.98 g of CO2?

Answers

Answer:

There are about 68.33 grams of oxygen present in 93.98 g of CO2.

The Fischer esterification mechanism is examined in this question. The overall reaction is: Benzoic acid, C H 3 O H and H C l react to form a methyl ester, H 2 O and H C l. Benzoic acid is a carboxylic acid bonded to a benzene ring. Identify the results or mechanism of each step.

Answers

Answer:

See explanation and image attached

Explanation:

Fischer esterification is a type of reaction used  to convert carboxylic acids to ester in the presence of excess alcohol and a strong acid which acts as a catalyst. Another final product formed in the reaction is water.

The mechanism for the fischer esterification of Benzoic acid and  C H 3 O H in the presence of HCl as the catalyst is shown in the image attached to this answer.

The final products of the reaction are methyl benzoate, water and H^+ as shown in the image attached.

The methyl ester, water, and the acid catalyst (HCl) are byproducts of the Fischer esterification process, which involves protonation, nucleophilic attack, elimination, and deprotonation processes.

Carbonyl oxygen protonation: The carbonyl oxygen of the carboxylic acid (benzoic acid) is protonated by the acid catalyst (HCl) in the first step. The protonation of the carbonyl carbon increases its electrophilicity and promotes the alcohol's nucleophilic assault. Attack by the alcohol's nucleophilic oxygen (methanol, CH3OH) on the protonated carboxylic acid's carbonyl carbon results in the formation of a tetrahedral intermediate. The acid catalyst also helps with this phase. Elimination of water: In the following step, the water molecule must be removed from the tetrahedral intermediate. The hydroxyl group (-OH) from the carboxylic acid and a hydrogen from the hydroxyl group of the alcohol are removed to create this water molecule. Deprotonation: A deprotonation occurs after the removal of water.

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In what kind of orbitals do the lone-pair electrons on the singly bonded oxygen of methyl acetate reside, and are they in the same plane as the group

Answers

Answer:

Both lone pairs reside in sp3 orbitals; they are co-planar with the CH3 group.

Explanation:

In the compound, methyl acetate, the  lone-pair of electrons on the singly bonded oxygen atom is accommodated in sp3 hybridized orbitals.

If we look at the compound, we will notice the both lone pair of electrons on oxygen are accommodated in sp3 orbitals which are co-planar with the  CH3 group  in the molecule.

Use the following balanced equation to answer the questions below.

Answers

Answer:

A. 4.5 mol Mg(OH)₂

B. 6 mol NaOH

Explanation:

Let's consider the following balanced equation.

Mg(NO₃)₂ + 2 NaOH ⇒ Mg(OH)₂ + 2 NaNO₃

PART A

The molar ratio of NaOH to Mg(OH)₂ is 2:1. The moles of Mg(OH)₂ produced from 9 moles of NaOH are:

9 mol NaOH × 1 mol Mg(OH)₂/2 mol NaOH = 4.5 mol Mg(OH)₂

PART B

The molar ratio of NaOH to NaNO₃ is 2:2. The moles of NaOH needed to produce 6 moles of NaNO₃ are:

6 mol NaNO₃ × 2 mol NaOH/2 mol NaNO₃ = 6 mol NaOH

If A Reaction Takes 10s To Go To Completion At 0°C, How Long Will It Take To Go At 100°C?

Answers

Answer:

1,000s

Explanation:

i just multiply it

If a reaction takes 10s to go to completion at 0°C,then 1000s will It take to go at 100°C.

What is reaction ?

A chemical reaction is a procedure that causes one group of chemical components to change chemically into another.

Combination, decomposition, single-replacement, double-replacement, and combustion are the five fundamental types of chemical reactions. You can classify a reaction into one of these groups by looking at the reactants and products. Several categories will apply to some reactions.

When atoms establish or break chemical bonds, chemical processes take place. Reactants are the substances that begin a chemical reaction, while products are the compounds that are created as a result of the reaction.

Thus,If a reaction takes 10s to go to completion at 0°C,then 1000s will It take to go at 100°C.

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paano pakalmahin ang leon

15 points po​

Answers

Answer:

lo siento señor, yo no hablo taka taka

Explanation:

5 puntos gratis pa

Determain the number of moles in 2.24l of ch4 at stp

Answers

Answer:

0.1 mole of CH₄

Explanation:

From the question given above, the following data were obtained:

Volume of CH₄ = 2.24 L

Number of mole of CH₄ =?

The number of mole of CH₄ can be obtained as follow:

Recall:

1 mole of a gas occupy 22.4 L at stp. This implies that 1 mole of CH₄ occupies 22.4 L at stp.

22.4 L = 1 mole of CH₄

Therefore,

2.24 L = 2.24 × 1 mole of CH₄ / 22.4

2.24 L = 0.1 mole of CH₄.

HELP WITH QUESTION 3,4 and 5 PLEASE

Answers

Answer:

I have no idea never get this in class before.

3 enzimas presentes en nuestro organismo e indique en que procesos actúan

Answers

Answer:

ATP asa, Helicasa, Proteasa, ARN polimerasa

Explanation:

Las enzimas son un tipo de biomoleculas que se corresponden con las proteinas.

Al momento de referirse a ellas, se utiliza la terminación asa.

ATPasa → Sintetizando ATP para el funcionamiento celular

Helicasa → Abre las hebras de ADN permitiendo el paso de la horquilla para el proceso de replicación de ADN.

Proteasas → Enzimas que degradan proteinas mal plegadas, rompen los enlaces peptídicos.

ARN polimerasa → Sintesis de ARN mensajero a partir de ADN en el proceso de la Transcripción. Se la puede conocer a veces, como primasa.

Which of the metals would reduce an iron ion
F
Fe
Cr
Cu
Ag
Sn

Answers

Answer:

Cu

Explanation:

Copper since it is more reactive than Iron. Hence, it can easily displace ions in an iron based compound.

Please help
Calculate the sodium ion (Na+) concentration for a 0.812 M Na3PO4 solution.
[Na+]=____M

Answers

Explanation:

Correct option is

B

0.750 M

Na3PO4 dissociates as:

Na3PO4⇌3Na++PO43−

∴ conc. of Na+ would be =3×0.250=

hope help

PLS HELP ME WITH THESE QUESTIONS ITS DUE TOMORROW I WILL MARK U AS BRAINLIEST

Answers

Answer:

See Explanation

Explanation:

1 mole of Cl2 gas occupies 22.4 L

x moles of Cl2 gas occupies 5.24 L

x= 1 × 5.24/22.4

x= 0.23 moles of Cl2

According to the kinetic theory of gases, the particles of a gas are in constant random motion and collide with each other and the walls of the container. Collision between gas particles are perfectly elastic.

Hence the statement that particles must not be able to move in any fixed or open container is false according to the kinetic theory of gases.

predict the major and minor products of the reaction. name the products using systematic names. ch3ch=ch2+h2o-->h+​

Answers

Answer:

major will be propan-2-ol

minor will be propan-1-ol

Select all the true statements.
a. Ionic bonding is more prevalent for the higher oxidation states and covalent bonding is more prevalent for the lower states.
b. The highest oxidation state of elements in Groups 3A through 7B is +3.
c. In the transition series, atomic size across a period decreases at first but then remains relatively constant.
d. The transition elements in a period show a steady increase in electronegativity.

Answers

Answer:

In the transition series, atomic size across a period decreases at first but then remains relatively constant.

The transition elements in a period show a steady increase in electronegativity.

Explanation:

In considering the transition series, we observe that atomic sizes of the elements decreases first and subsequently remain constant. The reason for the initial decrease in atomic size is the increase in nuclear charge across the period. After the first few elements in the period, the atomic size remains relatively constant due to shielding effect of the inner d electrons which opposes the increase in effective nuclear charge.

It is also observed that electro negativity increases smoothly across the period for the transition series. Consequently, the transition series become less electro positive across the period.

2. A student was asked to make up a 10% w/w solution of sodium carbonate. Calculate the amount of solute and solvent required to prepare that solution?
please explain step by step

Answers

Answer:

The amount of the solute and solvent can be calculated by the molality. The equation for the molality is as following:

Molality= (mass of solute*1000)/(molar mass*mass of solvent)

it is given that, 10% of Na2CO3 is made,

It means 100gram solution contains 10gram Na2CO3

So, the Mass of solute = 10 gram

then,

Mass of solvent= 100–10 = 90 gram

And, the molar mass of the Na2CO3 = 106 gram

from, now with the help of formula, we can calculate the amount of solute and solvent.

Sodium hydrogen carbonate, also called baking soda, is an active ingredient in some antacids used for the relief of indigestion. Determine the percent of carbon in sodium hydrogen carbonate.

Answers

Answer:

14.30%

Explanation:

Step 1: Given data

Chemical formula of sodium hydrogen carbonate: NaHCO₃

Step 2: Determine the mass of C in 1 mole of NaHCO₃

The is 1 atom of C in 1 molecule of NaHCO₃ and the molar mass of C is 12.01 g/mol. Then, there are 12.01 g of C in 1 mole of NaHCO₃.

Step 3: Determine the mnolar mass of NaHCO₃

M(NaHCO₃) = 1 × M(Na) + 1 × M(H) + 1 × M(C) + 3 × M(O)

M(NaHCO₃) = 1 × 22.98 g/mol + 1 × 1.01 g/mol + 1 × 12.01 g/mol + 3 × 16.00 g/mol = 84.00 g/mol

Step 4: Determine the mass percent of C in NaHCO₃

We will use the following expression.

%C = mC / mNaHCO₃ × 100%

%C = 12.01 g / 84.00 g × 100% = 14.30%

How to convert chloroform to chloretone​

Answers

Chloroform combines with acetone in the presence of potassium hydroxide to give chloretone, which is used as a sleep producing (hypnotic) drug.

1.00 mL of 12.0 M HCl is added to 1.00 L of a buffer that contains 0.110 M HNO2 and 0.170 M NaNO2. How many moles of HNO2 and NaNO2 remain in solution after addition of the HCl

Answers

Answer:

Moles of NaNO2 = 0.158

Moles of HNO2 final = 0.098

Explanation:

Given

Moles of HCl = 12

Moles of HNO2 = 0.11

Moles of NaNO2 = 0.170

HCl +NaNO2 --> HNO2  + NaCl

1 mole of HCl react with one mole of NaNO2 to produce 1 mole of NaCl and 1 mole of HNO2

Moles of NaNO2 = 0.17 - 0.012 = 0.158

Moles of HNO2 final = 0.11 - 0.012 = 0.098

The acid-base reaction between HCl and NaOH produces a solution with a pH of 7 at the equivalence point (NaCl H2O). Why does an acid-base indicator that changes color at pH 5 or 9 work just as well for this reaction as one that changes color at pH 7

Answers

Answer:

Answer is in the explanation.

Explanation:

Before the equivalence point, the pH of the solution of HCl that is titrated with NaOH has a pH <<< 7. When you are adding more NaOH nearing, thus, to the equivalence point the change in pH occurs quickly, and, with 1 drop of excess of NaOH after equivalence, the pH of the solution change to a pH >>> 7

That means the volume added at pH 5 or pH 9 is, almost, the same doing the indicator work just as well as an indicator with change color at pH 7

52.1 mL of aqueous 0.255 M Pb(NO3)2 is mixed with 38.5 mL of 0.415 M NaCl. The equation for the precipitate reaction is: Pb(NO3)2 (aq) 2 NaCl (aq) --> PbCl2 (s) 2 NaNO3 (aq) The concentration of Pb2 ion in the solution is _____ M after the reaction is complete.

Answers

Answer:

0.0585 M

Explanation:

Pb(NO₃)₂ (aq) + 2NaCl (aq) → PbCl₂ (s) + 2NaNO₃ (aq)

First we calculate the inital number of moles of each reagent, using the given volumes and concentrations:

0.255 M Pb(NO₃)₂ * 52.1 mL = 13.3 mmol Pb(NO₃)₂ 0.415 M NaCl * 38.5 mL = 16.0 mmol NaCl

Then we calculate how many Pb(NO₃)₂ moles reacted with 16.0 mmoles of NaCl, using the stoichiometric coefficients of the reaction:

16.0 mmol NaCl * [tex]\frac{1mmolPb(NO_3)_2}{2mmolNaCl}[/tex] = 8.00 mmol Pb(NO₃)₂

Now we calculate the remaining number of Pb(NO₃)₂ moles after the reaction:

13.3 mmol - 8.00 mmol = 5.30 mmol Pb(NO₃)₂

Finally we divide the number of moles by the final volume to calculate the concentration:

5.30 mmol / (52.1 mL + 38.5 mL) = 0.0585 M
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