Answer:
The correct answer is 5.61 × 10⁻⁵.
Explanation:
Based on the given information, let us consider the experimentally determined value of K as 0.000717, with the value of T₁ as 45 degree C, the value of T₁ in Kelvin would be,
T₁ = 273 +45 = 318 K
The value of T₂ is 25 degree C, or (25+273) = 298 K
Based on Arrhenius equation:
ln(K₂/K₁) = -Ea/R(1/T₂ - 1/T₁)
Now putting the values in the equation we get,
ln(K₂/0.000717) = -12070 (1/298 - 1/318)
ln(K₂/0.000717) = -2.54738
K₂/0.000717 = e^-2.54738 = 0.078286
K₂ = 0.078286 × 0.000717
K₂ = 5.61 × 10⁻⁵
SCIENCE
11. farmers tend to clear and bum a patch of forest area
Answer:
n8ce question and answer is time taken
[1] Mass of salt (g) 2.005 1.993 [2] Volume of DI water (mL) 49.8 50.0 Mass of DI water (g) [3] Temperature of DI water (°C) 23.4 23.5 [4] Temperature of mixture after dissolution (°C) 20.4 30.9 Temperature difference (°C) -3 7.4 [5] Total mass in reaction (g) 2.1 2.0 Total moles reacted (mol) .026 Total heat of the reaction (cal) [6] Enthalpy of solution ΔHsolution (cal/mol)
The reaction between hydrogen ion and hydroxide ion will be as follows.
so, ratio between hydrogen and hydroxide ions is 1 : 1.
Therefore, moles of = volume × concentration of
=
= 0.06 mol
Similarly, moles of = volume × concentration of
=
= 0.1 mol
Therefore, ratio of moles of hydrogen and hydroxide ions is as follows.
0.06 : 0.1
= 0.6 : 1
As, hydroxide ions are present in excess so, hydrogen ions are the limiting reagent.
Hence, moles of water formed = moles of ions = 0.06 mol.
So, heat released = moles of
= 0.062 × 62.0 kJ/mol
= 3.72 kJ
= 3.72 × 1000 J
= 3720 J
Let T is the initial temperature. So,
Heat released = Heat absorbed by the solution
=
3720 J =
T =
Thus, we can conclude that initial temperature is .
What is the concentration of a solution that has a volume of 2.5 L and contains 660 g of calcium phosphate? (molar mass of calcium phosphate = 310.18 g/mol)
Answer:
0.85 M
Explanation:
Step 1: Given data
Mass of calcium phosphate (m): 660 gVolume of solution: 2.5 LMolar mass of calcium phosphate (M): 310.18 g/molStep 2: Calculate the moles (n) corresponding to 660 g of calcium phosphate (solute)
We will use the following expression.
n = m/M
n = 660 g/(310.18 g/mol) = 2.13 mol
Step 3: Calculate the molar concentration (molarity) of the solution
Molarity is equal to the moles of solute divided by the liters of solution.
M = 2.13 mol/2.5 L = 0.85 M
Which sentence best describes why MnSO4→MnO+SO3 is not a synthesis reaction?
The equation is not balanced.
The reaction has more than one product.
Oxygen is not a reactant in this reaction.
Energy is not a product in this reaction.
Answer:
The reaction has more than one product.
Explanation:
Answer:
The reaction has more than one product.
Explanation:
how do I name cycloalkanes?
Answer:
[tex]{ \tt{aromatic \: alkanes}} \\ \\ { \underline{ \blue{ \tt{becker⚜jnr}}}}[/tex]
1. Determine the number of sides of the cyclic compound.
2. Use IUPAC theory, determine the functional group and its position.
A pattern of stars that has been named is called a constellation. Late at night, Carolyn saw the constellation named Leo, the lion, in the eastern part of the sky. A drawing of Leo is shown below.
Leo
Early the next morning before sunrise, Carolyn saw the same constellation in the western part of the sky. How could she see the same constellation in a different part of the sky?
A.
The stars revolve around the Earth once each month.
B.
The stars appear to move because the Earth rotates on its axis.
C.
There is more than one set of stars in the same pattern as Leo.
D.
The stars move in different directions every night.
Answer:
The correct answers are B. Constellations can be used for navigational purposes, D. Constellations are used by astronomers to locate objects in the night sky., and E. Constellations are used by astronomers to locate objects in the night sky.
Explanation:
1. Make ___________________
Observe an event. State only what we can
________ or ____________.
2. Ask ___________________
Ask a question that helps us find out _______ and _______ the event happened. We must be
able to answer the question with ________, or ________. We may need to __________ our question several times before it is__________.
3. Construct a_____________________
State the answer we think we’ll get when we ask
our question. This is called a
_________________. It’s based on our best
understanding of the event.
4. Test the hypothesis with an
_______________________
Test whether the hypothesis is ___________.
During the investigation, we collect _______ that
answers the testable question we asked.
Answer:
Explanation:
ANCHOR ANCHOR ANCHOR ANCHOR
Metallic Bond
When nitrogen shares electrons with oxygen, what kind of bond is made?
Answer: covalent bonds
Explanation:
The solubility of CaSO4 in pure water at 0oC is 1.09 gram(s) per liter. The value of the solubility product is g
Answer: See image attached!
Good luck with your future exams!
The value of the solubility of product for CaSO₄ in pure water at 0 °C is 1.1881
What is solubility of product?The solubility of product (Ksp) is defined as the concentration of products raised to their coefficient coefficients. This is illustrated below:
mA <=> nC + eD
Ksp = [C]^n × [D]^e
With the above information in mind, we can obtain the solubility of the product. This is illustrated below:
Dissociation equationCaSO₄(aq) → Ca²⁺(aq) + SO₄²⁻(aq)
From the balanced equation above,
1 mole of CaSO₄ contains 1 mole of Ca²⁺ and 1 mole of SO₄²⁻
How to determine the concentration of Ca²⁺ and SO₄²⁻From the balanced equation above,
1 mole of CaSO₄ contains 1 mole of Ca²⁺ and 1 mole of SO₄²⁻
Therefore,
1.09 g/L of CaSO₄ will also contain
1.09 g/L of Ca²⁺1.09 g/L of SO₄²⁻ How to determine the solubility of product Concentration of Ca²⁺ = 1.09 g/L Concentration of SO₄²⁻ = 1.09 g/L Solubility of product (Ksp) =?CaSO₄(aq) → Ca²⁺(aq) + SO₄²⁻(aq)
Ksp = [Ca²⁺] × [SO₄²⁻]
Ksp = 1.09 × 1.09
Ksp = 1.1881
Learn more about solubility of product:
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A chemistry student needs of carbon tetrachloride for an experiment. By consulting the CRC Handbook of Chemistry and Physics, the student discovers that the density of carbon tetrachloride is . Calculate the volume of carbon tetrachloride the student should pour out. Be sure your answer has the correct number of significant digits.
Answer:
34.6 cm³
Explanation:
A chemistry student needs 55.0 g of carbon tetrachloride for an experiment. By consulting the CRC Handbook of Chemistry and Physics, the student discovers that the density of carbon tetrachloride is 1.59 g/cm³. Calculate the volume of carbon tetrachloride the student should pour out. Be sure your answer has the correct number of significant digits.
Step 1: Given data
Mass of carbon tetrachloride (m): 55.0 gDensity of carbon tetrachloride (ρ): 1.59 g/cm³Step 2: Calculate the required volume of carbon tetrachloride
Density is an intrinsic property of matter. It can be calculated as the quotient between the mass of the sample and its volume.
ρ = m/V
V = m/ρ
V = 55.0 g/(1.59 g/cm³)
V = 34.6 cm³
The chemistry student should pour 34.6 cm³ of carbon tetrachloride.
If a small amount of a strong base is added to buffer made up of a weak acid, HA, and the sodium salt of its conjugate base, NaA, the pH of the buffer solution does not change appreciably because:__________
a. the K, of HA is changed.
b. No reaction occurs.
c. the strong base reacts with A to give HA, which is a weak acid.
d. the strong base reacts with HA to give AOH and H'.
e. the strong base reacts with HA to give A, which is a weak base,
Answer:
e. the strong base reacts with HA to give A, which is a weak base
Explanation:
Let's consider a buffer made up of a weak acid, HA, and the sodium salt of its conjugate base, NaA. The function is a buffer system is to muffle the change in the pH when an acid or a base is added.
Let's suppose a strong base is added. Then, OH⁻ would be more available. OH⁻ ions react with the acid component of the buffer and its effect is reduced. The corresponding reaction is:
OH⁻ + HA ⇄ A⁻ + H₂O
As we can see, the strong base reacts with HA to give A, which is a weak base.
Write balanced equations and solubility product expressions for the following compounds
a. CuBr
b. ZnC2O4
c. Ag2CrO4
d. Hg2Cl2
e. AlCl3
f. Mn3(PO4)3
Explanation:
Solubility product is defined as the product of the concentrations or solubilities of the ions each raised to the power their stoichiometric coefficients present in the solution. It is expressed as [tex]K_{sp}[/tex].
(a): CuBr
The chemical equation for the dissociation of CuBr into its ions follows:
[tex]CuBr\rightleftharpoons Cu^++Br^-[/tex]
The expression of [tex]K_{sp}[/tex] for CuBr follows:
[tex]K_{sp}=[Cu^+][Br^-][/tex]
(b): [tex]ZnC_2O_4[/tex]
The chemical equation for the dissociation of [tex]ZnC_2O_4[/tex] into its ions follows:
[tex]ZnC_2O_4\rightleftharpoons Zn^{2+}+C_2O_4^{2-}[/tex]
The expression of [tex]K_{sp}[/tex] for [tex]ZnC_2O_4[/tex] follows:
[tex]K_{sp}=[Zn^{2+}][C_2O_4^{2-}][/tex]
(c): [tex]Ag_2CrO_4[/tex]
The chemical equation for the dissociation of [tex]Ag_2CrO_4[/tex] into its ions follows:
[tex]Ag_2CrO_4\rightleftharpoons 2Ag^{+}+CrO_4^{2-}[/tex]
The expression of [tex]K_{sp}[/tex] for [tex]Ag_2CrO_4[/tex] follows:
[tex]K_{sp}=[Ag^{+}]^2[CrO_4^{2-}][/tex]
(d): [tex]ZnC_2O_4[/tex]
The chemical equation for the dissociation of [tex]Hg_2Cl_2[/tex] into its ions follows:
[tex]Hg_2Cl_2\rightleftharpoons 2Hg^{+}+2Cl^{-}[/tex]
The expression of [tex]K_{sp}[/tex] for [tex]Hg_2Cl_2[/tex] follows:
[tex]K_{sp}=[Hg^{+}]^2[Cl^{-}]^2[/tex]
(e): [tex]AlCl_3[/tex]
The chemical equation for the dissociation of [tex]AlCl_3[/tex] into its ions follows:
[tex]AlCl_3\rightleftharpoons Al^{3+}+3Cl^{-}[/tex]
The expression of [tex]K_{sp}[/tex] for [tex]AlCl_3[/tex] follows:
[tex]K_{sp}=[Al^{3+}][Cl^{-}]^3[/tex]
(f): [tex]ZnC_2O_4[/tex]
The chemical equation for the dissociation of [tex]Mn_3(PO_4)_2[/tex] into its ions follows:
[tex]Mn_3(PO_4)_2\rightleftharpoons 3Mn^{2+}+2PO_4^{3-}[/tex]
The expression of [tex]K_{sp}[/tex] for [tex]Mn_3(PO_4)_2[/tex] follows:
[tex]K_{sp}=[Mn^{2+}]^3[PO_4^{3-}]^2[/tex]
he specific heat capacity of a pure substance can be found by dividing the heat needed to change the temperature of a sample of the substance by the mass of the sample and by the change in temperature. The heat capacity of a certain substance has been measured to be
Complete question is;
The specific heat capacity of a pure substance can be found by dividing the heat needed to change the temperature of a sample of the substance by the mass of the sample and by the change in temperature. The specific heat capacity of a certain substance has been measured to be 3.52 J/g°C. Suppose 420.0 g of the substance is heated until the temperature of the sample has changed by 43.8 °C.
Write an equation that will let you calculate the last Q that was needed for this temperature change. Your equation should contain only symbols. Be sure to define each symbol.
Answer:
Q = m•c•Δt
Q = 64753.92 J
Explanation:
We are given;
Mass (m) = 420 g
Change in temperature; (Δt) = 43.8 °C
Specific heat capacity (c) = 3.52 J/g °C
The last Q is simply the heat energy that caused that temperature change.
This is given by the formula;
Q = m•c•Δt
Plugging in the relevant values;
Q = 420 × 3.52 × 43.8
Q = 64753.92 J
Given the following information, calculate the density in g/mL of an irregular solid.
Mass of weighing vessel 1.005g
Mass of solid + weighing vessel 9.441g
Volume of liquid in graduated cylinder 3.45 mL
Volume of liquid in graduated cylinder + volume of solid 5.45 mL
Answer:
4.22 g/mL
Explanation:
First we calculate the mass of the solid via mass difference:
Mass of solid = 9.441 g - 1.005 g = 8.436 gThen we calculate the volume of the solid, once again by difference:
Volume of solid = 5.45 mL - 3.45 mL = 2.00 mLFinally we calculate the density in g/mL:
Density = 8.436 g / 2.00 mL = 4.22 g/mLThe density of an irregular solid will be "4.96 g/mL".
According to the question,
→ The Mass of solid will be:
= [tex][(Mass \ of \ solid+ Weighing \ vessel)-(Mass \ of \ weighing)][/tex]
By substituting the values, we get
= [tex]9.441-1.005[/tex]
= [tex]8.436 \ g[/tex]
→ The Volume of solid will be:
= [tex][(Volume \ of \ liquid \ in \ grad. \ cylinder+Solid)-(Volume \ of \ grad. \ cylinder)][/tex]
= [tex]5.15 - 3.45[/tex]
= [tex]1.70 \ mL[/tex]
hence,
→ The density of irregular solid will be:
= [tex]\frac{Mass}{Volume}[/tex]
= [tex]\frac{8.436}{1.70}[/tex]
= [tex]4.96 \ mL[/tex]
Thus the above is the correct answer.
Learn more:
https://brainly.com/question/1150199
Draw the structure of the major organic product isolated from the reaction of 3-hexyne with hydrogen (1 mol), Lindlar palladium.
Answer:
See explanation and image attached
Explanation:
When 1 mole of hydrogen is added to 3-hexyne, the addition occurs on the same face or side of the triple bond to yield cis-2-hexene in the presence of lindlar catalyst which prevents further hydrogenation. This is known as syn addition.
The syn addition is achieved because the hydrogen molecule is first adsorbed on the surface of the palladium metal and is subsequently attached to the same face of the triple bond in 3-hexyne as shown in the image attached to this answer.
Element X contains 4 electrons in its outer shell and 125 neutrons in its nucleus. what is element X? (beryllium/carbon/tin/lead)
Answer:
lead
Explanation:
As it is in group 4 so 4 electron In its outer shell
and you can find number of neutrons by taking
mass number - atomic number
207.2-82=124.2=125
hope it make sense:)
34. Which type of reaction is represented by the
equation?
CH. + Biz - CH.Br + HB,
A suhstitution
C. esterification
D. polymerization
Answer:
Option A. Substitution
Explanation:
To know which option is correct, let us define each option. This is illustrated below:
A substitution reaction is a reaction in which an halogen replaces hydrogen in a hydrocarbon to produce alkyl halide and the corresponding acid. For example:
RH + X₂ –> RX + HX
NOTE:
R => is an alkyl group
X => is an halogen (F₂, Cl₂, Br₂ or I₂)
Addition reaction is a reaction in which two reactants combined to form a new compound without any loss of the reactants. This reaction is peculiar to only unsaturated hydrocarbon. For example:
CₓHᵧ + A₂ —> ACₓHᵧA
NOTE:
CₓHᵧ => unsaturated hydrocarbon (alkene, alkyne)
A₂ => halogen (F₂, Cl₂, Br₂ or I₂) or HBr, HCl etc
Esterification is a reaction involving carbonxylic and alcohol to produce ester and water. For example:
RCOOH + HOR —> RCOOR + H₂O
NOTE:
R => is an alkyl group
Polymerization is a process of reacting smaller molecules called monomers to form a larger molecule called polymer.
With the information provided above, we can see that the reaction:
CH₄ + Br₂ —> CH₃Br + HBr
Is a substitution reaction since Br replaces H in CH₄ to produce CH₃Br and the corresponding acid i.e HBr
Helppppp
What is the mass of 4.09 x 10^22 molecules of oxygen gas?
1.09 grams
7.69 x 1044 grams
2.17 grams
0.0679 gram
Answer:
[tex]2.17gO_2[/tex]
Explanation:
Hello there!
In this case, according to the given information, it turns out possible for us to calculate the mass of 4.09 x 10^22 molecules of oxygen gas by firstly keeping in mind that that 1 mole of it has a mass of 32.0 g and secondly that 1 mole of any substance contains 6.022x10^23 representative units, in this case, molecules of O2, and thus, the appropriate setup to perform this conversion is shown below:
[tex]4.09x10^{22}molecules \ O_2*\frac{1molO_2}{6.022x10^{23}molecules \ O_2}*\frac{32.0gO_2}{1molO_2} \\\\2.17gO_2[/tex]
Regards!
What’s the correct answer
Answer:
I think it's 2-methylhept-2-ene
Explanation:
Hope this will help and correct me if I'm wrong.
Write the reaction of maleic acid with Br2
How many moles are in 2.98x10^23 particles?
Answer:
[tex]\boxed {\boxed {\sf 0.495 \ mol}}[/tex]
Explanation:
We are given a number of particles and asked to convert to moles.
1. Convert Particles to Moles1 mole of any substance contains the same number of particles (atoms, molecules, formula units) : 6.022 *10²³ or Avogadro's Number. For this question, the particles are not specified.
So, we know that 1 mole of this substance contains 6.022 *10²³ particles. Let's set up a ratio.
[tex]\frac { 1 \ mol }{6.022*10^{23 } \ particles}}[/tex]
We are converting 2.98*10²³ particles to moles, so we multiply the ratio by that value.
[tex]2.98*10^{23} \ particles *\frac { 1 \ mol }{6.022*10^{23 } \ particles}}[/tex]
The units of particles cancel.
[tex]2.98*10^{23} *\frac { 1 \ mol }{6.022*10^{23 } }}[/tex]
[tex]\frac { 2.98*10^{23}}{6.022*10^{23 } }} \ mol[/tex]
[tex]0.4948522086 \ mol[/tex]
2. RoundThe original measurement of particles (2.98*10²³) has 3 significant figures, so our answer must have the same.
For the number we found, 3 sig figs is the thousandth place.
The 8 in the ten-thousandth place (0.4948522086) tells us to round the 4 up to a 5 in the thousandth place.
[tex]0.495 \ mol[/tex]
2.98*10²³ particles are equal to approximately 0.495 moles.
Which of the following numbers is in scientific notation?
A~ 13.5 x 10^14
B~ 1.35 x 10^14
C~ 1.35 x 9^14
D~ 13.5 x 9^14
If a swimming pool contains 2850 kg liters of water how many gallons of water does it contain
PLS HELP ME WILL MARK YOU AS BRAINLIEST
Answer:
D
Explanation:
If a light beam strikes a shiny object at a 90-degree angle, to what are the angle of incidence and the angle of reflection equal?
Answer:
Angle of incidence = angle of reflection = 0
Explanation:
Given that,
A light beam strikes a shiny object at a 90-degree angle.
The angle made by incident ray and normal to the mirror is called the angle of incidence and the angle made by the reflected ray and the normal is called the angle of reflection.
Here, the beam strikes normally. So, the angle of incidence is 0.
A/c to the law of reflection,
Angle of incidence = angle of reflection
So, the angle of reflection is also equal to 0.
which type of soil is the best for planting? A.Loam B.Clay c.sand
Answer:
A. Loam soil is best for planting
Thank you....
Have a good day....
calculate to e amount of ammonium chloride needed to produce 200L of hydrogen chloride (HCL) gas at 1.22atm and 573k. NH4Cl ➡️NH3+HCl
Answer:
277.8g of NH4Cl are needed
Explanation:
Based on the reaction, 1mol of NH4Cl reacts producing 1 mole of HCl. To solve this question we must find the moles of HCl using ideal gas law. These moles = Moles NH4Cl:
Moles HCl = Moles NH4Cl
PV = nRT; PV/RT = n
Where P is pressure = 1.22atm,
V is volume = 200L,
R is gas constant = 0.082atmL/molK
And T is absolute temperature = 573K
Replacing:
1.22atm*200L/0.082atmL/molK*573K = n
n = 5.193 moles HCl = Moles NH4Cl
Mass NH4Cl -Molar mass: 53.491g/mol-
5.193 moles * (53.491g / mol) =
277.8g of NH4Cl are neededHow many liters of water would you need to add to 4.36 moles of NaCl to create a 9.4 M solution?
Answer:
0.464 L
Explanation:
Molarity (M) = number moles (n) ÷ volume (V)
According to the information given in this question:
number of moles (n) = 4.36 moles
Molarity = 9.4M
Volume = ?
Using M = n/V
9.4 = 4.36/V
9.4V = 4.36
V = 4.36/9.4
V = 0.464 L
Hence, 0.464L of water are needed the volume of water.
what happens to the volume of a gas if the pressure and temperature doubled
Hi there! Answer is below :)
Explanation:
For this question, we apply Boyle's Law and Charles' Law.
When you double the amount of pressure and temperature of a compound or mixture, the volume will decrease by a half. So, if the pressure and temperature are 2, and the volume is 1, and you double, your volume will be 0.5 and your pressure and temperature will be 4.
Best of Luck!
What area is affected by Earth’s gravitational field?
