Answer:
The answer will have to be A
gabriel created 270 grams of aluminum oxide from 145 grams of aluminum. what was his percent yield?
A. 99.1%
B. 98.6%
C. 97.2%
D.96.5%
( it’s not “D” because I got it wrong lol) pls help tho
Answer:
% yield = 200%
Explanation:
By using 145 gram of aluminium
Using 26.982 g/mol of Al, 101.96 g/mol of Aluminium oxide is produced
Using 145 grams of aluminium, the yield of Aluminium oxide would have been = (101.96 g/mol/26.982 g/mol)/145 grams
= 547.9282485 gram
Now % yield = actual yield /theoretical yield * 100
Substituting the given values, we get -
% yield = (547.928/270) *100
% yield = 200%
balance this equation plz
SO2+O2+H2O------->H2SO4
Answer: The balanced equation is [tex]2SO_{2} + O_{2} + 2H_{2}O \rightarrow 2H_{2}SO_{4}[/tex].
Explanation:
A chemical equation which contains same number of atoms on both reactant and product side is called a balanced chemical equation.
For example, [tex]SO_{2} + O_{2} + H_{2}O \rightarrow H_{2}SO_{4}[/tex]
Here, number of atoms present on reactant side are as follows.
S = 1O = 5H = 2Number of atoms present on product side are as follows.
S = 1O = 4H = 2To balance this equation, multiply [tex]SO_{2}[/tex] by 2 and [tex]H_{2}O[/tex] by 2 on reactant side. Also, multiply [tex]H_{2}SO_{4}[/tex] by 2 on product side.
Hence, the equation can be re-written as follows.
[tex]2SO_{2} + O_{2} + 2H_{2}O \rightarrow 2H_{2}SO_{4}[/tex]
Now, the number of atoms present on reactant side are as follows.
S = 2O = 8H = 4Number of atoms present on product side are as follows.
S = 2O = 8H = 4Since, the atoms present on both reactant and product side are equal. Hence, the equation is now balanced.
Thus, we can conclude that the balanced equation is [tex]2SO_{2} + O_{2} + 2H_{2}O \rightarrow 2H_{2}SO_{4}[/tex].
You calculate that 0.000345 m is the answer to a problem. You are asked to write
your answer in scientific notation. Which answer is correct? *
A~ 34.5 x 10^-5m
B~ 345 x 10^6m
C~ 3.45 x 10^-5 m
D~ 3.45 x 10^-4 m
g An ionic bond involves ____ a. molecules that gain or lose an atom to develop a bonding charge b. molecules that bond together through a weak force c. atoms that either lose or gain an electron in order to bond d. atoms that share an electron to tightly bond
Answer:
a. molecules that gain or lose an atom to develop a bonding charge
Explanation:
PLS HELP THESE ARE RHE ONLY QUESTIONS I HAVE LEFT DUE SOON
Explanation:
Magnesium reacts with dilute hydrochloric acid in a conical flask which is connected to an inverted measuring cylinder in a trough of water. The volume of hydrogen gas produced is measured over a few minutes, and the results are used to plot a graph
This is intended as a class practical. It is best if the students work in pairs because setting up and starting the experiment requires more than one pair of hands. One student can add the magnesium ribbon to the acid and stopper the flask, while the other starts the stopclock. During the experiment, one student can take the readings while the other records them. The experiment itself takes only a few minutes. But allow at least 30 minutes to give students time to set up, take readings and draw graph.
please mark as brainliest
One gram of a compound requires the following quantities of solvent to dissolve: 47 mL of water, 8.1 mL of chloroform, 370 mL of diethyl ether, or 86 mL of benzene. Calculate the solubility of the compound in these four solvents (as g/100 mL). Estimate the partition coefficient of the compound between chloroform and water, ethyl ether and water, and benzene and water. Which solvent would you choose to extract the compound from an aqueous solution
Answer:
Chloroform.
Explanation:
Given,
Solvent requires 1g of compound per 100 mL
For water,
= 1g/47ml
= 2.1
For Chloroform,
= 1 g/8.1 mL
= 12.345679
For Diethyl ether,
= 1 g/370 mL
= 0.27
For Benzene,
= 1 g/86 mL
= 1.2
Partition coefficients:
Water = -
chloroform = 5.9
Diethyl = .13
Benzene = .57
The solvent chloroform would be chosen for drawing out the compound out of an aqueous solution as it has the maximum solubility.
Someone pls help me ::/:/
How much energy must be added to 250.0 g of ice at 0.00 °C to raise the
temperature of the water to 50.0 °C? The heat of fusion for water is 334
J/g. The specific heat of water is 4.184 J/g.K.
Answer:
136 KJ
Explanation:
We'll begin by calculating the heat required to melt the ice. This can be obtained as follow:
Mass (M) = 250 g
Heat of fusion (Hբ) = 334 J/gºC
Heat (Q₁) required to melt the ice =?
Q₁ = MHբ
Q₁ = 250 × 334
Q₁ = 83500 J
Next, we shall determine the heat required to change the temperature. This can be obtained as follow:
Mass (M) = 250 g
Initial temperature (T₁) = 0 °C
Final temperature (T₂) = 50 °C
Specific heat capacity (C) = 4.184 J/gºC
Heat (Q₂) required to change the temperature =?
Q₂ = MC(T₂ – T₁)
Q₂ = 250 × 4.184 (50 – 0)
Q₂ = 1046 × 50
Q₂ = 52300 J
Next, we shall determine the total heat required.
Heat (Q₁) required to melt the ice = 83500 J
Heat (Q₂) required to change the temperature = 52300 J
Total heat (Qₜ) required =?
Qₜ = Q₁ + Q₂
Qₜ = 83500 + 52300
Qₜ = 135800 J
Finally, we shall convert 135800 J to KJ. This can be obtained as follow:
1000 J = 1 KJ
Therefore,
135800 J = 135800 J × 1 KJ / 1000 J
135800 J ≈ 136 KJ
Thus, the total heat required is 136 KJ.
A 59.0 mL portion of a 1.80 M solution is diluted to a total volume of 258 mL. A 129 mL portion of that solution is diluted by adding 183 mL of water. What is the final concentration
Answer:
0.170 M
Explanation:
As this is a series of dilutions, we can continuosly use the C₁V₁=C₂V₂ formula to solve this problem:
For the first step:
59.0 mL * 1.80 M = 258 mL * C₂C₂ = 0.412 MThen for when 129 mL of that 0.412 M are diluted by adding 183 mL of water:
V₂ = 129 mL + 183 mL = 312 mLUsing C₁V₁=C₂V₂:
129 mL * 0.412 M = 312 mL * C₂C₂ = 0.170 M1. An ion has a net charge of - 3, and 12 electrons, what is its atomic number? What element has that atomic number?
2. An ion of Celsius has a net charge of -5, how many electrons does it have?
3. Some atom has an atomic number of 46, how many electrons does it have if it has a net charge of +2?
4. How many neutrons are in an atom of Helium, and what is its mass number?
5. There are 3 neutrons in an isotope of Helium, what is its mass number?
6. n isotope has 83 neutrons and a mass number of 167, what is its atomic number? What element is defined by that atomic number?
7. What element has 54 neutrons and a mass number of 112?
8. What element has 10 electrons, a net charge of -2?
Answer:
19 because it gained 3 electron so 12-3=9 beryllium
2
3 is 46-2=44
4 is 2
5 is 5
6 84 polonium
7
8 oxygen
Explanation:
plz let me know if they are right or wrong:)
How many grams of 02 are present in 7.49 L of oxygen gas?
Answer:
10.70grams
Explanation:
Density of a substance = mass/volume
At STP of a gas (standard temperature and pressure), the density of oxygen gas is 1.429 g/L
Hence, according to this question, in 7.49 L of oxygen gas, there would be:
Using D = m/V
1.429 = m/7.49
m = 1.429g/L × 7.49L
m = 10.70g
A solution has a pH of 2.5. what is the H+
Answer: The concentration of [tex]H^+[/tex] in the solution is [tex]3.16\times 10^{-3}M[/tex]
Explanation:
pH is defined as the negative logarithm of hydrogen ion concentration present in the solution.
[tex]pH=-\log [H^+][/tex] .....(1)
We are given:
pH of solution = 2.5
Putting values in equation 1, we get:
[tex]2.5=-\log [H^+][/tex]
[tex][H^+]=10^{-2.5}[/tex]
[tex][H^+]=3.16\times 10^{-3}M[/tex]
Hence, the concentration of [tex]H^+[/tex] in the solution is [tex]3.16\times 10^{-3}M[/tex]
When aqueous solutions of AgNO3 and MgCl2 are mixed, a precipitate forms. What is the correct formula for the precipitate
Answer:
AgCl
Explanation:
The reaction that takes place is:
2AgNO₃ (aq) + MgCl₂ (aq) → Mg(NO₃) (aq) + 2AgCl (s)The precipitate (meaning a solid substance) formed is silver chloride, AgCl.
All salts formed with silver and a halogen (F, Cl, Br, I) are insoluble in water, meaning that when working with aqueous solutions they will be precipitates.
Provide the IUPAC names for
the following structures
CH2CH3
w
CH2CH:
(b) H-C-N
CH.CH
H-EN
N
H
(c)
OCH2CH3
Answer:
For a: The IUPAC name of the compound is N-ethylethaneamide.
For b: The IUPAC name of the compound is N,N-diethylmethaneamide.
For c: The IUPAC name of the compound is ethyl pentanoate
Explanation:
To name a compound, first look for the longest possible carbon chain.
For a:Amide group is a type of functional group where an amine group is attached to a carbonyl group. The general formula of amide is [tex]R-CO-NH_2[/tex], where R is an alkyl or aryl group.
In part (a), the alkyl group has 2 carbon atoms and thus, the prefix used is 'eth-'
Also, an ethyl substituent is directly attached to N-atom. It is an alkane structured hydrocarbon thus, the suffix used will be '-ane'
Hence, the IUPAC name of the compound is N-ethylethaneamide.
For b:Amide group is a type of functional group where an amine group is attached to a carbonyl group. The general formula of amide is [tex]R-CO-NH_2[/tex], where R is an alkyl or aryl group.
In part (b), the alkyl group has 1 carbon atoms and thus, the prefix used is 'meth-'
Also, two ethyl substituents are directly attached to N-atom. It is an alkane structured hydrocarbon thus, the suffix used will be '-ane'
Hence, the IUPAC name of the compound is N,N-diethylmethaneamide.
For c:Esters are a kind of organic molecules having functional groups, [tex]R-COO-R'[/tex] where R and R' are the alkyl or aryl groups. They are formed by the combination of alcohol and carboxylic acid.
These functional group compounds are named in two words which is alkyl alkanoates, where alkyl refers to the alcoholic part and alkanoate refers to the carboxylic acid part of the molecule. The numbering of the parent chain in esters is done from the carboxylic carbon. The alkyl part is not given any numbers.
In part (c), there are 5 carbon atoms present in a straight chain and thus, the prefix used is 'pent-'
Also, an ethyl group forms the alcoholic part.
Hence, the IUPAC name of the compound is ethyl pentanoate
How many molecules are in 4.44 mol of CF4? 4.44 mol CF4 =
I am not sure abt the ans
molar mass= 88
1 molecule = 6.022×10^23
4.44 moles = 6.022×10^23×4.44/88
= 26.73768 × 10^23/88
= 0.3038372727 ×10^23
Which example shows a double replacement reaction?
Answer:
KCl + AgNO₃ —> AgCl + KNO₃
Explanation:
To answer the question correctly, we must understand the definition of a double displacement reaction.
A double displacement reaction is a reaction in which the ions of the two reacting compounds exchange to form new compounds different from the two reacting compounds. Example is given below:
XY + AB —> XB + AY
Considering the options given in the question above, only the equation:
KCl + AgNO₃ —> AgCl + KNO₃
Satisfy the definition of a double displacement reaction.
Define solubility. the amount of a substance that will dissolve in a given amount of solvent a solid mixed with another solid a liquid that does not dissolve in another liquid the amount of a substance that will dissolve in a given amount of solute a solid that does not dissolve in a gas
Answer:
You answered your own question
The solubility of a substance is the amount of the substance that can be dissolved in a given amount of solvent at a specified temperature. Hence, option A is correct.
What is solubility ?Solubility of a substance can be defined as the fraction of concentration of the substance which can be dissolved in a particular amount of a solvent at a specified temperature.
Solubility of a substance depends on the bond type, temperature, pressure and presence of impurities if any. If the bond strength is greater, less will be the solubility because, greater energy is needed to weaken the bonds in the salt.
Similarly, for most of the salts, as the temperature increases, solubility increases, but some salt's solubility is independent of the temperature such as for NaCl. Therefore, the correct definition of solubility is option A.
Find more on solubility ;
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Which additional product balances the reaction h2so4+2naoh>na2so4
Answer:
H 4so8 is the answer of balance the reaction
what will happen to the initial rate of the reaction if the concentration of iron(III) chloride is tripled
Answer:
Concentration and reaction rate is directly proportional
Explanation:
Basically, concentration is directly proportional to the concentration, so the higher the concentration, the higher the reaction rate.
Once the concentration is increased, more chemical will be added hence the reaction rate will increase
Why should a science teacher know how to prepare stock solution
Answer:
because they were thought in college
Explanation:
hope that helps
Which of the following is most likely to make a -3 ion?
Bі
P
Se
Be
All
The element whose atom may likely make a -3 ion is P.
Elements in the periodic table are classified into groups and periods. The elements in the same group have similar physical and chemical properties.
Phosphorus (P) is a member of group 15 in the periodic table. The most common ion formed by the members of this group is the -3 ion.
It is formed by accepting three electrons to complete their octet since they have five electrons on their outermost shell.
Hence P is most likely to form a -3 ion.
Learn more: https://brainly.com/question/11155928
What is the pH of a 0.086 M HCl solution?
Answer: pH = 1.066
Explanation: HCl is strong acid and it protolyzes totally:
HCl + H2O ⇒ H3O+ + Cl-
Concentrations are same: [H3O+] = c(HCl)
pH = - log[H3O+] = - log(0.086) = 1.0655
Calculate the number of cations and anions in each of the following compounds. Enter your answers in scientific notation. (a) 6.42 g of KBr:
Answer: The number of cations are [tex]3.24 \times 10^{22}[/tex] and number of anions are [tex]3.24 \times 10^{22}[/tex] in 6.42 g of KBr.
Explanation:
The molar mass of KBr is (39.10 + 79.90) g/mol = 119.00 g/mol
Now, the dissociation equation for KBr is as follows.
[tex]KBr \rightarrow K^{+} + Br^{-}[/tex]
This means that 1 mole of KBr is forming 1 mole of [tex]K^{+}[/tex] (cation) and 1 mole of [tex]Br^{-}[/tex] (anion).
According to mole concept, 1 mole of every substance contains [tex]6.022 \times 10^{23}[/tex] atoms. Hence, number of cations present in 6.42 g KBr is calculated as follows.
[tex]No. of cations = Moles \times 6.022 \times 10^{23}\\= \frac{mass}{molar mass} \times 6.022 \times 10^{23}\\= \frac{6.42 g}{119.00 g/mol} \times 6.022 \times 10^{23}\\= 3.24 \times 10^{22}[/tex]
As according to the equation, there are equal number of moles of both cation and anions.
This means that the number of anions are also [tex]3.24 \times 10^{22}[/tex].
Thus, we can conclude that the number of cations are [tex]3.24 \times 10^{22}[/tex] and number of anions are [tex]3.24 \times 10^{22}[/tex] in 6.42 g of KBr.
The number of cations and anions present in potassium bromide is 3.24 × 10²².
How we calculate atoms from moles?In one mole of any substance 6.022 × 10²³ atoms of that substance is present and this is known as Avogadro's number.
KBr is a strong electrolyte means it fully dissociates into their constitute ions. So, the number of moles of produced ions is equal to the moles of KBr and dissociation is represented as:
KBr → K⁺ + Br⁻
From this it is clear that 1 mole of cation and 1 mole of anion is produced from 1 mole of KBr. Moles of KBr will be calculated as:
n = W/M, where
W = given mass = 6.42g
M = molar mass = 119
n = 6.42 / 119 = 0.053 moles
No. of cations and anions present in 0.053 moles = 0.053 × 6.022 × 10²³ = 3.24 × 10²².
Hence, 3.24 × 10²² is the no. of cations and anions.
To know more about Avogadro's number, visit the below link:
https://brainly.com/question/10614569
You are working on a project where you need the volume of a box. You take the length, height, and width measurements and then multiply the values together to find the volume. You re- port the volume of the box as 0.310 ml. If two of your mea- surements were 0.7120 m and 0.52458 m, what was the other measurement?
Answer and Explanation:
If we remember from school, we should know that the equation for finding the volume of a box (rectangular) is length times width times height.
Since we know the volume, we can divide the two sides given from the volume to find the remaining side.
0.310 ÷ 0.7120 ÷ 0.52458 = 0.83
The answer is 0.83 for the remaining side measurement.
#teamtrees #PAW (Plant And Water)
Answer:
The answer is: 0.82998448
Explanation:
If you multiply 0.7120 × 0.52458, it will equal: 0.37350096.
if you divide 0.310 ÷ 0.37350096, you will get 0.82998448.
Hope it helps!!
(also, i don't want to be "that" person, but brainliest would be apreciated!)
how do i convert 145.6grams of Iron sulphide into iron and sulfur
Show the complete ionic equation and net ionic equation for all the equations below, then state whether or not a precipitate (insoluble compound) will form. To receive full credit, you must show ALL your work.
Cacl2(aq) + K2co3(aq) + -------->
Bacl2(aq) + MgSO4(aq) + -------->
AgNO3(aq) + Kl(aq) →
Nacl(aq) + (NH4)2Cro4(aq) →
Answer:
(a): Precipitate of calcium carbonate will form.
(b): Precipitate of barium sulfate will form.
(c): Precipitate of silver iodide will form.
(d): Precipitate of sodium chromate will form.
Explanation:
Complete ionic equation is defined as the equation in which all the substances that are strong electrolytes present in an aqueous state and are represented in the form of ions.
Net ionic equation is defined as the equations in which spectator ions are not included.
Spectator ions are the ones that are present equally on the reactant and product sides. They do not participate in the reaction.
(a):
The balanced molecular equation is:
[tex]CaCl_2(aq)+K_2CO_3(aq)\rightarrow 2KCl(aq)+CaCO_3(s)[/tex]
The complete ionic equation follows:
[tex]Ca^{2+}(aq)+2Cl^-(aq)+2K^+(aq)+CO_3^{2-}(aq)\rightarrow 2K^+(aq)+2Cl^-(aq)+CaCO_3(s)[/tex]
As potassium and chloride ions are present on both sides of the reaction. Thus, they are considered spectator ions.
The net ionic equation follows:
[tex]Ca^{2+}(aq)+CO_3^{2-}(aq)\rightarrow CaCO_3(s)[/tex]
Precipitate of calcium carbonate will form.
(b)
The balanced molecular equation is:
[tex]BaCl_2(aq)+MgSO_4(aq)\rightarrow MgCl_2(aq)+BaSO_4(s)[/tex]
The complete ionic equation follows:
[tex]Ba^{2+}(aq)+2Cl^-(aq)+Mg^{2+}(aq)+SO_4^{2-}(aq)\rightarrow Mg^{2+}(aq)+2Cl^-(aq)+BaSO_4(s)[/tex]
As magnesium and chloride ions are present on both sides of the reaction. Thus, they are considered spectator ions.
The net ionic equation follows:
[tex]Ba^{2+}(aq)+SO_4^{2-}(aq)\rightarrow BaSO_4(s)[/tex]
Precipitate of barium sulfate will form.
(c):
The balanced molecular equation is:
[tex]AgNO_3(aq)+KI(aq)\rightarrow KNO_3(aq)+AgI(s)[/tex]
The complete ionic equation follows:
[tex]Ag^{+}(aq)+NO_3^-(aq)+K^+(aq)+I^{-}(aq)\rightarrow K^+(aq)+NO_3^-(aq)+AgI(s)[/tex]
As potassium and nitrate ions are present on both sides of the reaction. Thus, they are considered spectator ions.
The net ionic equation follows:
[tex]Ag^{+}(aq)+I^{-}(aq)\rightarrow AgI(s)[/tex]
Precipitate of silver iodide will form.
(d):
The balanced molecular equation is:
[tex]2NaCl(aq)+(NH_4)_2CrO_4(aq)\rightarrow 2NH_4Cl(aq)+Na_2CrO_4(s)[/tex]
The complete ionic equation follows:
[tex]2Na^{+}(aq)+2Cl^-(aq)+2NH_4^+(aq)+CrO_4^{2-}(aq)\rightarrow 2NH_4^+(aq)+2Cl^-(aq)+Na_2CrO_4(s)[/tex]
As ammonium and chloride ions are present on both sides of the reaction. Thus, they are considered spectator ions.
The net ionic equation follows:
[tex]2Na^{+}(aq)+CrO_4^{2-}(aq)\rightarrow Na_2CrO_4(s)[/tex]
Precipitate of sodium chromate will form.
What is the law
of universal gravitation?
Answer:
[tex]{ \boxed{ \bf{newtons \: law \: of \: gravitation}}} [/tex]
It states that the product of masses of bodies ( planets and satellites and asteroids ) in space is inversely proportional to square of their separation mean distance
[tex]{ \tt{formular : F = \frac{GMm}{ {r}^{2} } }}[/tex]
Please help me I need help with this questions I’m very confused fused as to what the answer is please
Which of the following statements is NOT true?
A.) When HX adds to an asymetrical alkene, the SP2 carbon bonded to the most H atoms is protonated.
B.) When HX adds to an asymetrical alkene, protonation leads to the most stable carbocation intermediate.
C.) When HX adds to a symetrical alkene, either of the SP2 carbons can be protonated.
D.) When HX adds to an asymetrical alkene, the halogen attaches to the least substituted SP2 carbon.
Answer:
D.) When HX adds to an asymmetrical alkene, the halogen attaches to the least substituted sp² carbon.
Explanation:
Which of the following statements is NOT true?
A.) When HX adds to an asymmetrical alkene, the sp² carbon bonded to the most H atoms is protonated. TRUE. This is known as Markovnikov's rule.
B.) When HX adds to an asymmetrical alkene, protonation leads to the most stable carbocation intermediate. TRUE. The order of stability of carbocations is tertiary > secondary > primary.
C.) When HX adds to a symmetrical alkene, either of the sp² carbons can be protonated. TRUE. Since the alkene is symmetrical, either carbon can be protonated.
D.) When HX adds to an asymmetrical alkene, the halogen attaches to the least substituted sp² carbon. FALSE. The halogen attaches to the most substituted sp² carbon.
Pb(NO3)2 + 2Naci
2NaNO, + PbCI,
Substance
Number of Protons
Number of
Electrons
2.
3
lithium
fluorine
9
10
19
potassium
sulfur
19
18
16
19. Which substance is electrically neutral?
A. lithium
B. fluorine
Β
C. potassium
D. sulfur
20. Which substance has an overall I'charge?
Answer:
lithium 3
Explanation:
This is because lithium has three protons