Answer:
5Step-by-step explanation:
X * 3^2 +2 = 47
X * 9 + 2 = 47
9X = 47 - 2
9x = 45
x = 45 : 9
X = 5
Jen factored x² - 4x - 21 as (x - 3)(x + 7) What did she do wrong?
Answer:
She didn't put the sign's in the proper place, it should be ( x + 3 ) ( x - 7 )
Step-by-step explanation:
( x - 3 ) ( x + 7 ) = x² + 7x - 3x - 21 = x² + 4x - 21
( x + 3 ) ( x - 7 ) = x² - 7x + 3x - 21 = x² - 4x - 21
Marinas bill for dinner totals $38.65, including tax. She leaves a 20% tip. How much is Marinas total? (pls hurry i’m in summer school rn and i need the answer)
9514 1404 393
Answer:
$46.38
Step-by-step explanation:
When a 20% tip is added to the bill, the result is the bill being multiplied by a factor of (1 + 20%) = 1.20.
1.20 × 38.65 = 46.38
Marina's total with the tip is $46.38.
Let U = {1, 2, 3, 4, 5, 6, 7), A = {2, 4, 6, 7), and B = {1, 4, 7}. Find the set (A U B)'.
Step-by-step explanation:
(A U B) = {1,2, 4, 6, 7}
(A U B)'= U- (A U B) = { 3,5}<------- Answer
If you do this for me I will mark you as brainless
Answer:
π and f. 125
Step-by-step explanation:
for the circle its π or 3.1415926535....
for the triangle its f. 125
[Pre-Calc] Please Help! I don’t know where to start. How do I do this?
Answer:
See Below.
Step-by-step explanation:
Problem A)
We have:
[tex]\displaystyle \csc^2\theta \tan^2\theta -1=\tan^2\theta[/tex]
When in doubt, convert all reciprocal trig functions and tangent into terms of sine and cosine.
So, let cscθ = 1/sinθ and tanθ = sinθ/cosθ. Hence:
[tex]\displaystyle \left(\frac{1}{\sin^2\theta}\right)\left(\frac{\sin^2\theta}{\cos^2\theta}\right)-1=\tan^2\theta[/tex]
Cancel:
[tex]\displaystyle \frac{1}{\cos^2\theta}-1=\tan^2\theta[/tex]
Let 1/cosθ = secθ:
[tex]\sec^2\theta -1=\tan^2\theta[/tex]
From the Pythagorean Identity, we know that tan²θ + 1 = sec²θ. Hence, sec²θ - 1 = tan²θ:
[tex]\tan^2\theta =\tan^2\theta[/tex]
Problem B)
We have:
[tex]\sin^3x=\sin x-\sin x \cos^2 x[/tex]
Factor out a sine:
[tex]\sin x(\sin^2 x)=\sin x-\sin x\cos^2 x[/tex]
From the Pythagorean Identity, sin²θ + cos²θ = 1. Hence, sin²θ = 1 - cos²θ:
[tex]\sin x(1-\cos^2 x)=\sin x-\sin x\cos^2x[/tex]
Distribute:
[tex]\sin x- \sin x \cos^2 x=\sin x-\sin x\cos^2 x[/tex]
Problem C)
We have:
[tex]\displaystyle \frac{\cos 2x+1}{\sin 2x}=\cot x[/tex]
Recall that cos2θ = cos²θ - sin²θ and that sin2θ = 2sinθcosθ. Hence:
[tex]\displaystyle \frac{\cos^2 x-\sin^2 x+1}{2\sin x\cos x}=\cot x[/tex]
From the Pythagorean Identity, sin²θ + cos²θ = 1 so cos²θ = 1 - sin²θ:
[tex]\displaystyle \frac{2\cos^2 x}{2\sin x\cos x}=\cot x[/tex]
Cancel:
[tex]\displaystyle \frac{\cos x}{\sin x}=\cot x[/tex]
By definition:
[tex]\cot x = \cot x[/tex]
Solve the equation by factoring. 3x^2-5x-12=0
Answer:
x = 3
[tex]x=-1\frac{1}{3}[/tex] or [tex]x=-\frac{4}{3}[/tex]
Step-by-step explanation:
3x² - 5x - 12 = 0
Method 1: Factoring
3x² + 4x - 9x - 12 = 0
(3x² + 4x) + (- 9x - 12) = 0
x(3x + 4) - 3(3x + 4) = 0
(x - 3)(3x + 4) = 0
Two separate equations
x - 3 = 0
3x + 4 = 0
x - 3 = 0
x - 3 + 3 = 0 + 3
3x + 4 = 0
3x + 4 - 4 = 0 - 4
3x = - 4
[tex]\frac{3x}{3} :-\frac{4}{3}[/tex]
[tex]x=-1\frac{1}{3}[/tex]
Method 2: Quadratic Formula
Ignore the A before the ±, it wouldn't let me type it correctly.
[tex]x=\frac{-b±\sqrt{b^{2} -4ac} }{2a}[/tex]
3x² - 5x - 12 = 0
a = 3
b = - 5
c = - 12
[tex]x=\frac{-(-5)±\sqrt{(-5)^{2} -4((3)(-12))} }{2(3)}[/tex]
[tex]x=\frac{-(-5)±\sqrt{25 -4((3)(-12))} }{2(3)}[/tex]
[tex]x=\frac{-(-5)±\sqrt{25 +144} }{2(3)}[/tex]
[tex]x=\frac{-(-5)±\sqrt{169} }{2(3)}[/tex]
[tex]x=\frac{-(-5)±13}{2(3)}[/tex]
[tex]x=\frac{5±13}{6}[/tex]
Two separate equations
One must have a + (positive) and the other will have a - (negative).
[tex]x=\frac{5+13}{6}[/tex]
[tex]x=\frac{18}{6}[/tex]
x = 18 ÷ 6
x = 3
[tex]x=\frac{5-13}{6}[/tex]
[tex]x=\frac{-8}{6}[/tex]
x = - 8 ÷ 6
[tex]x=-1\frac{1}{3}[/tex]
Steps for: 6-2x+5+4x
Answer:
6-2x+5+4x
2x+11
hope this helps
have a good day :)
Step-by-step explanation:
The only step you need to do is add like terms
help pls ill give u brainlest
Step-by-step explanation:
πr²= Area of a circle
In this case:
π16²
16²= 256265×π= 804.2 (1dp)So therefore, the answer is A
Hope this helped!
hey this is my first post, does anyone know how to do this and find V?
Answer:
16
Step-by-step explanation:
8/1/2
8 divided by 1/2
8 x 2/1 = 16
Answer:
Step-by-step explanation:
P=8/V
1/2=8/V
do cross multiplication
2*8=V*1
16=V
How many feet are in 24 yards? 27 feet 72 feet 240 feet 288 feet
Answer:
72
Step-by-step explanation:
Suppose the probability of failure in a binomial experiment is 0.25. What is
the probability of success?
A. 0.65
B. 0.85
C. 0.75
D. 0.35
Answer:
C: .75
Step-by-step explanation:
I really just subtracted
6. The quotient of 5 and a number y, minus 10.
Answer:
5/y - 10
Step-by-step explanation:
I doubt the completeness of your question, however
the answer is
5/y - 10
HELP PLZZZ !!
3. Solve the equation by factoring.
C^2 - 4c = 0
Answer:
0,4
Step-by-step explanation:
See image below:)
In ΔXYZ, ∠Y is a right angle and sin X = 12/25 Find sec X, tan X, and cos Z in fraction and in decimal form. Round to the nearest hundredth, if necessary.
Answer:
In ΔXYZ
∠Y is a right angle ∠X and ∠Z are complementary anglessin X = 12/25-------------
sec X = 1/cos X = [tex]1/\sqrt{1- sin^2X} = 1/\sqrt{1 - 12^2/25^2} = 1/\sqrt{481}/25 = 25/\sqrt{481}[/tex]tan X = sin X / cos X = [tex]12/{25 : {\sqrt{481} }/25 = 12/{\sqrt{481} }[/tex]cos Z = sin X = 12/25The equation for line r can be written as y=-1/4x+3. Line s which is parallel to lone r includes the point (-4,3). What is the equation of line s?
Answer:
[tex]y=-\frac{1}{4}x+2[/tex]
Step-by-step explanation:
Hi there!
What we need to know:
Linear equations are typically organized in slope-intercept form:[tex]y=mx+b[/tex] where m is the slope and b is the y-intercept (the value of y when x is 0)Parallel lines always have the same slope1) Determine the slope of line S using line R (m)
[tex]y=-\frac{1}{4} x+3[/tex]
We can identify clearly that the slope of the line is [tex]-\frac{1}{4}[/tex], as it is in the place of m. Because parallel lines always have the same slope, the slope of line S would also be [tex]-\frac{1}{4}[/tex]. Plug this into [tex]y=mx+b[/tex]:
[tex]y=-\frac{1}{4}x+b[/tex]
2) Determine the y-intercept of line S (b)
[tex]y=-\frac{1}{4}x+b[/tex]
Plug in the given point (-4,3) and solve for b
[tex]3=-\frac{1}{4}(-4)+b\\3=1+b[/tex]
Subtract 1 from both sides to isolate b
[tex]3-1=1+b-1\\2=b[/tex]
Therefore, the y-intercept is 2. Plug this back into [tex]y=-\frac{1}{4}x+b[/tex]:
[tex]y=-\frac{1}{4}x+2[/tex]
I hope this helps!
Help me pls I do not know
Sqrt 15(3+5) = Sqrt3+ sqrt 5
Answer:
False
Step-by-step explanation:
Assuming a and b are 2 different terms,
Sqrt a + Sqrt b is not equal to Sqrt (a * b).
The only way to obtain Sqrt (a * b) is by doing the following:
Sqrt (a * b) = Sqrt (a) * Sqrt (b)
calculate the circumference of a circle with a radius of 7.5. show or explain your reasoning.
what is the slope of a line perpendicular to 3x+2y = 7?
Answer:
2/3
Step-by-step explanation:
First find the slope of the line
3x+2y = 7
Subtract 3x
2y = -3x+7
Divide by 2
y = -3/2x +7/2
This is in slope intercept form y = mx+b where m is the slope
The slope is -3/2
A line perpendicular is the negative reciprocal
-1/(-3/2)
2/3
The slope of the perpendicular line is 2/3
Answer:
Slope of the line perpendicular to the given line = 2/3
Step-by-step explanation:
The product of the slopes of lines perpendicular to each other is - 1
That is,
[tex]slope_{1} \times slope _ 2 = - 1\\[/tex]
Given equation of the line :
3x + 2y = 7
2y = - 3x + 7
[tex]y = -\frac{3}{2}x + \frac{7}{2}[/tex]
[tex]Therefore, \ slope \ of \ the \ given \ line \ , slope _1 = \ -\frac{3}{2}[/tex]
Find slope of the line perpendicular to the given line:
[tex]\frac{-3}{2} \times slope_2 = - 1\\\\slope_2 = - 1 \times \frac{2}{-3} = \frac{2}{3}[/tex]
How many different codes of 6 digits are possible if the first digit must be 3, 4, 5, or 6 and if the code may not end in 0? Hint: think of positions.
Answer:
360000 possible codes
Step-by-step explanation:
The first digit can only be one of four things and the last digit can't be zero.
4*10*10*10*10*9=360000
Determine if the type of sequence of the following terms.
2, 5, 10, 17, 26, 37,
...
O Arithmetic
O Polynomial
O Neither
O Geometric
Question
Answer:
B: polynomial
Step-by-step explanation:
The sequence given is;
2, 5, 10, 17, 26, 37,...
From this sequence, the first difference between consecutive terms is respectively;
3, 5, 7, 9, 11...
We can see that the differences gotten are not constant.
Now, let's find the second difference between the consecutive first differences respectively;
2, 2, 2, 2...
This second difference is constant and thus we can say that the terms form a quadratic sequence of the form;
f(x) = an² + bx + c
Where the quadratic coefficient is two times the second difference.
Thus;
2a = 2
a = 1
And where c is the 0th term.
Thus, this is a quadratic sequence. Since quadratic functions are 2nd degree polynomials, then this is said to be a polynomial sequence.
which of the following is the horizontal asymptote for the graph below?
A. x = 0
B. y = 0
C. y= -7
D. x = -7
The horizontal asymptote for the graph at y = -7.
What is a horizontal asymptote?A horizontal asymptote exists as a horizontal line that exists not in the region of a graph of a function while directing it for x-values. “far” to the right and/or “far” to the left. The graph may cross it but ultimately, for big adequately or small.
By definition, when we say asymptote, this exists a line that the graph of a function comes but never connects. A horizontal asymptote exists the y-value on a graph which a function approaches but never connects. Horizontal asymptotes exist approached by the curve of a function as x proceeds towards infinity.
Therefore, the correct answer is option C. y = -7
To learn more about the graph refer to:
https://brainly.com/question/2288165
#SPJ2
Find the value of unknown angles.
Х
50
Answer:
[tex]x = 70^o[/tex]
Step-by-step explanation:
Given
See attachment for triangle
Required
Find x
To solve for x, we make use of:
[tex]x + 50^o + 60^o = 180^o[/tex] --- angles in a triangle
[tex]x + 110^o = 180^o[/tex]
Collect like terms
[tex]x = 180^o-110^o[/tex]
[tex]x = 70^o[/tex]
You choose a marble at random from a bag contains 12 red 10 blue 5 green 4 yellow and 29 black marbles. The marble is red.
Step-by-step explanation:
P(red) = 12/(12+10+5+4+29)
= 12/60
= 1/5
= 0.2
= 20%
Which equation can be used to solve for x?
A. sin (x) =
30
18
B. cos (x)
30
24
C. cos (x)
24
30
D.
tan (x)
24
18
NÉED HELP ASAP PLEASE check the picture
Answer:
[tex] \cos(x) = \frac{24}{30} [/tex]
OPTION C
The number of road construction projects that take place at any one time in a certain city follows a Poisson distribution with a mean of 6. Find the probability that less than 3 road construction projects are currently taking place in this city.a) 0.050409b) 0.089235c) 0.301168d) 0.014936
Answer:
The probability that less than 3 road construction projects are currently taking place in this city is 0.06197
Step-by-step explanation:
In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:
[tex]P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}[/tex]
In which
x is the number of sucesses
e = 2.71828 is the Euler number
[tex]\mu[/tex] is the mean in the given interval.
Poisson distribution with a mean of 6.
This means that [tex]\mu = 6[/tex]
Find the probability that less than 3 road construction projects are currently taking place in this city.
This is:
[tex]P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2)[/tex]
So
[tex]P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}[/tex]
[tex]P(X = 0) = \frac{e^{-6}*6^{0}}{(0)!} = 0.00248[/tex]
[tex]P(X = 1) = \frac{e^{-6}*6^{1}}{(1)!} = 0.01487[/tex]
[tex]P(X = 2) = \frac{e^{-6}*6^{2}}{(2)!} = 0.04462[/tex]
[tex]P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2) = 0.00248 + 0.01487 + 0.04462 = 0.06197[/tex]
The probability that less than 3 road construction projects are currently taking place in this city is 0.06197
Find the perimeter of the figure below, in meters.
2.7 m
2.7 m
*4m
Answer:
31.8 m
Step-by-step explanation: 6 5 17 26
add up all the lengths to find the perimeter
or sum the multiplication of the common lengths
P = 6 × 4.4 m + 2 × 2.7 m
= 26.4 m + 5.4 m
= 31.8 m
PLEASE HELP ASAP !!!!!!!!
Answer:
[tex] \large{ \tt{❃ \: EXPLANATION }}: [/tex]
We're provided - m [tex] \angle[/tex] FBD = ( 2x + 3 ) ° & m [tex] \angle[/tex] EBC = ( 9x - 11 ) ° and We're asked to find m [tex] \angle[/tex] EBC .Do you know what vertically opposite angles are ? - When two lines intersect , the angles formed opposite to each other are called vertically opposite angles. Vertically opposite angles [ VOA ] are always equal to each other.
[tex] \large{ \tt{❁ \: SOLUTION}} : [/tex]
Set up an equation and solve for x :[tex] \large{ \tt{❈ \: (2x + 3) \degree = (9x - 11) \degree} \: (BEING\: VERTICALLY \: OPPOSITE \: ANGLES)}[/tex]
[tex] \large{ \tt{⟶2x \degree + 3 \degree = 9x \degree - \: 11 \degree}}[/tex]
[tex] \large{ \tt{⟶3 \degree + 11 \degree = 9x \degree - 2x \degree}}[/tex]
[tex] \large{ \tt{⟶14 \degree = 7x \degree}}[/tex]
[tex] \large{ \tt{⟶ \: 7x \degree = 14 \degree}}[/tex]
[tex] \large{ \tt{⟶x = \frac{14 \degree}{7 \degree} }}[/tex]
[tex] \boxed{\large{ \tt{⟶x = 2 \degree}}}[/tex]
The value of x is 2°.[tex] \large{ \tt{☄ \: REPLACING \: VALUE}} : [/tex]
[tex] \large{ \tt{↝ \: m \: \angle \: EBC = (9x - 11) \degree = (9 \times 2 - 11) \degree = \boxed{ \boxed{ \tt{7 \degree}}}}}[/tex]
[tex] \boxed{ \boxed{ \large{ \tt{OUR \: FINAL \: ANSWER : \boxed{ \underline{ \bold{} \tt{7 \degree}}}} }}}[/tex][tex] \tt{✺ \: NOTHING \: CAN \: GIVE \: YOU \: THE \: POWER \: MORE \: THAN \: EDUCATION \: DOES!} \: ♪[/tex]
۵ Hope I helped! ツ
☼Have a wonderful day / evening !☃
# StayInAndExplore ! ☂
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- Mona Allen wants to buy a bed that costs $695. The city sales tax rate is 7%. In a nearby city the sales tax rate is 4%. How much less would the bed cost if Mona bought it in the nearby city?
Answer:
$20.85 less.
Step-by-step explanation:
City sales:
7% tax = 48.65
total bed cost = $743.65
Nearby City:
4% tax = 27.8
total bed cost = $722.8
city sale - nearby city
743.65 - 722.8
=20.85
Help please thank you very much
Answer: [tex]2\sqrt{7}[/tex]
When writing this on a keyboard, you would say 2*sqrt(7)
========================================================
Explanation:
The formula we'll use is
A = 0.5*p*q*sin(R)
where R is the angle between sides p and q.
The diagram shows that p = x+4 is opposite angle P, and q = x is opposite angle Q. Convention usually has the uppercase letters be angles, and the lowercase letters as the sides.
Plug in the given values and simplify to get the following
A = 0.5*p*q*sin(R)
A = 0.5*(x+4)*x*sin(60)
A = 0.5*(x+4)*x*sqrt(3)/2 ..... use the unit circle
A = 0.25*(x^2+4x)*sqrt(3)
A = (0.25x^2+x)*sqrt(3)
Set this equal to the given area of A = sqrt(27) and solve for x
A = (0.25x^2+x)*sqrt(3)
(0.25x^2+x)*sqrt(3) = A
(0.25x^2+x)*sqrt(3) = sqrt(27)
(0.25x^2+x)*sqrt(3) = 3*sqrt(3) .... see note1 at the very bottom
0.25x^2+x = 3
(1/4)x^2+x = 3
x^2+4x = 12 .... see note2 at the very bottom
x^2+4x-12 = 0
(x+6)(x-2) = 0
x+6 = 0 or x-2 = 0
x = -6 or x = 2
A negative side length doesn't make sense, so we ignore x = -6. The only solution here is x = 2.
Since x = 2, this means we have the following side lengths so far
p = RQ = x+4 = 2+4 = 6q = PR = x = 2Now apply the law of cosines to find the missing side.
r^2 = p^2 + q^2 - 2*p*q*cos(R)
r^2 = 6^2 + 2^2 - 2*6*2*cos(60)
r^2 = 36 + 4 - 24*1/2
r^2 = 40 - 12
r^2 = 28
r = sqrt(28)
r = sqrt(4*7)
r = 2*sqrt(7)
Side PQ is exactly 2*sqrt(7) units long
This approximates to 2*sqrt(7) = 5.2915
------------------------------------
Footnotes:
Note1: sqrt(27) = sqrt(9*3) = sqrt(9)*sqrt(3) = 3*sqrt(3)Note2: I multiplied both sides by 4 to clear out the fraction