Answer:
d. All of the above is the correct answer
Match each date to the correct description.
1. autumnal equinox
June 21
2. vernal equinox
September 22
3. longest day in Northern Hemisphere
December 22
4. longest day in Southern Hemisphere
March 21
June 21: longest day in Northern Hemisphere
December 22: longest day in Southern Hemisphere
September 22: autumnal equinox
march 21: vernal equinox
Answer:
Autumnal Equinox: September 22nd
Vernal Equinox: March 21st
Longest day in the Northern Hemisphere: June 21st
Longest day in the Southern Hemisphere: December 22nd
Explanation:
I hope this helps! <3
¿Es posible que un objeto se mueva en
una dirección distinta de la dirección de la fuerza neta
que actúa sobre el objeto?
Answer:
translate it to English plss
A bullet has a mass of 0.0042kg. The muzzle velocity of the bullet coming
out of the barrel of the rifle is 993m/s. What is the KE of the bullet as it
exits the gun barrel?
Answer:
KE= 1/2mv^2= 1/2*0.0042kg*993m/s= 2.0853joule
The conversion of thermal energy into mechanical energy requires
a thermometer.
D. Beat engine
C vaporizer.
d thermostat.
A car starting from rest has a constant acceleration of 4 meters per second per second. How fast will it be going in 5 seconds?
Answer:
18 m
Explanation:
Given : vo = 0 m/s ; t = 3 s; a = 4 m/s^2 ; d = ? m ; average velocity = ? m/s ; fonal velocity = ? m/s
solving for the final velocity, v
v = a * t
v = 4 m/s^2 * 3 s
v = 12 m / s
Solving for the average velocity. avg v
avg v = (vo + v) / 2
avg v = (0 m / s + 12 m/s) / 2
avg v = 6 m / s
Solving for the distance traveled after 3 s
d = avg v * t
d = 6 m / s * 3 s
d = 18 meters
In the first 3s the car travels 18 meters.
If a car starting from rest has a constant acceleration of 4 meters per second per second, then it would be going at a speed of 20 m / s.
What are the three equations of motion?There are three equations of motion given by Newton,
v = u + at
S = ut + 1/2 × a × t²
v² - u² = 2 × a × s
As given in the problem, a car starting from rest has a constant acceleration of 4 meters per second per second,
By using the first equation of the motion,
v = u + at
v = 0 + 4 × 5
v = 20 m / s
Thus,If a car starting from rest has a constant acceleration of 4 meters per second per second, then it would be going at a speed of 20 m / s.
To learn more about equations of motion here, refer to the link given below ;
brainly.com/question/5955789
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A rubber ball is shot straight up from the ground with a speed of 12 m/s. Simultaneously, a second identical rubber ball is dropped from rest exactly 7 m directly above the first ball. At what height (in m) do the two balls collide?
Answer:
6.17 m
Explanation:
We are given that
Initial speed of rubber ball, u=12 m/s
Total height, h=7 m
Initial speed of second ball, u'=0
We have to find the height at which the two balls collide.
Let first rubber ball and second ball strikes after t time.
For first ball
Distance traveled by first ball in time t
[tex]S=ut-\frac{1}{2}gt^2[/tex]
Substitute the value
[tex]S=12t-\frac{1}{2}(9.8)t^2[/tex]
[tex]S=12t-4.9t^2[/tex] ...(1)
Distance traveled by second ball in time t
[tex]7-S=\frac{1}{2}(9.8)t^2[/tex]
[tex]7-S=4.9t^2[/tex] .....(2)
Using equation (2) in equation (1) we get
[tex]S=12t-(7-S)[/tex]
[tex]S=12t-7+S[/tex]
[tex]\implies 12t=7[/tex]
[tex]t=\frac{12}{7}[/tex]sec
Now, using the value of t
[tex]S=12(\frac{12}{7})-4.9(\frac{12}{7})^2[/tex]
S=6.17 m
Hence, at height 6.17 m the two balls collide .
Long Shore Drift is the ...
A. landforms along the shoreline of an ocean or sea
B. submerged or partly exposed ridge of sand along an ocean front
C. accumulation of sand grains along a beach front
D. movement of material along a coast by waves that approach at an angle to the shore.
Answer: D. movement of material along a coast by waves that approach at an angle to the shore.
Explanation:
Longshore drift is also referred to as the littoral druft and it means the sediment that is moved by the longshore current.
Longshore drift is the movement of material along a coast by waves which approach at an angle to the shore but then recede down the beach.
Therefore, the correct option is D.
What are moana's hobbies
An electric eel develops a potential difference of 470 V , driving a current of 0.85 A for a 1.0 ms pulse. Part A Find the power of this pulse.
Answer:
399.5 Watts.
Explanation:
From the question given above, the following data were obtained:
Potential difference (V) = 470 V
Current (I) = 0.85 A
Time (t) = 1 ms
Power (P) =?
Electrical power is defined by the following equation:
Power (P) = potential difference (V) × current (I)
P = IV
Using the above formula, the power can be obtained as follow:
Potential difference (V) = 470 V
Current (I) = 0.85 A
Power (P) =?
P = IV
P = 470 × 0.85
P = 399.5 Watts
Therefore, the power is 399.5 Watts.
Which of the following statements best describes energy conservation in heat engines?
A. The heat engine's energy is exhausted to the outside system.
B. The sum of the heat placed into the hot reservoir and the work collected equals the energy transferred from the cold reservoir.
C. A volume of heat is discharged to the cold body where some waste energy is in a form of heat in this engine.
D. The work derived from the heat engine is equal to the energy placed into the hot reservoir.
The work function of titanium metal is 6.93 x 10-19 J. Calculate the kinetic energy of the ejected electrons if light of frequency 2.50 X 1015 s-1 is used to irradiate the metal.
Answer:
g m t o k liye cbbhhhf to be be free and ear is not a short time to be a short of a week and I am a short kat key and ear to be free and ear is not a short time and ear buds and duster for a short of a week of the action is not by the action is not a short time to make sure to be free and duster and not by the way to
Explanation:
ahhhhhhh to be be free and ear is nothing to be be free and ear is not a short time to be be free and ear is not by the class is not a a short time to be be free and
In movies, there are explosions in space with fire and smoke but there is no oxygen in space. What is wrong? What would really happen ?
Answer:
For an explosion with fire to occur, there must be a combustion of oxygen, and there is no oxygen in space, so that would be the mistake.
So it is NOT possible to say that in space there can be explosions. And what really happened would be the non-existence of this phenomenon in that place.
Calculate the coefficient of linear expansion of aluminum and the percent error. (the known value is 16.7×10^(-6)/℃)
Answer:
sorry I don't know
Explanation:
in really sorry
It is late and Carlos is sliding down a rope from his third-floor window to meet his friend Juan. As he slides down the rope faster and faster, he becomes frightened and grabs harder on the rope, increasing the tension in the rope. As soon as the upward tension in the rope becomes equal to his weight:
Answer:
It would help Carlos stop sliding down and he would stay in his place in the air.
Explanation:
According to Newton's 1st Law of Motion, a body is said to be at rest or uniform motion when no net force is acting on it. This explains that when the tension in the rope becomes equal to Carlos' weight, the net force becomes zero which means the body (Carlos), is at rest and remains in the air instead of sliding down the rope.
A car is traveling at a constant speed of 33 m/s on a highway. At the instant this car passes an entrance ramp, a second car enters the highway from the ramp. The second car starts from rest and has a constant acceleration. What acceleration must it maintain, so that the two cars meet for the first time at the next exit, which is 2.5 km away
Answer:
0.8712 m/s²
Explanation:
We are given;
Velocity of first car; v1 = 33 m/s
Distance; d = 2.5 km = 2500 m
Acceleration of first car; a1 = 0 m/s² (constant acceleration)
Velocity of second car; v2 = 0 m/s (since the second car starts from rest)
From Newton's equation of motion, we know that;
d = ut + ½at²
Thus,for first car, we have;
d = v1•t + ½(a1)t²
Plugging in the relevant values, we have;
d = 33t + 0
d = 33t
For second car, we have;
d = v2•t + ½(a2)•t²
Plugging in the relevant values, we have;
d = 0 + ½(a2)t²
d = ½(a2)t²
Since they meet at the next exit, then;
33t = ½(a2)t²
simplifying to get;
33 = ½(a2)t
Now, we also know that;
t = distance/speed = d/v1 = 2500/33
Thus;
33 = ½ × (a2) × (2500/33)
Rearranging, we have;
a2 = (33 × 33 × 2)/2500
a2 = 0.8712 m/s²
Describe the relationship between the period of a pendulum and the length of the pendulum?
Answer:
The period of the pendulum is directly proportional to the square root of the length of the pendulum
We can also notice that the period of a pendulum does not depend on its mass.
Explanation:
write the chemical equation of rust
ANSWER
4Fe+ 3O2 → 2Fe2O.
EXPLANATION
iron (Fe) combines with oxygen (O2) to form rust, or iron oxide (Fe2O3). The equation for this reaction is: 4Fe+ 3O2 → 2Fe2O.
Is an object on the surface of Earth sitting still relative to outer space?
Answer:
The object is not still as it observe from the outer space.
Explanation:
Our earth is not stationary.
It rotates about its own axis with the period of 24 hours and it revolves around the sun with the period of 1 year.
An object is said to be at rest if the position of the object with respect to time changes.
An object is said to be in motion when the position of the object changes with respect to time.
Both the terms rest and motion are relative to each other.
If an observer observe an object on the earth from the outer space, he observe that the object s not still it is also moving as the earth is moving.
So, the object is not still as it observe from the outer space.
A 2800-lbm car climbs a 1160 ft. long uphill road which is inclined at 15o (to the horizontal) and covers the distance in 12 sec. Determine the power required if the car covers the distance (a) at constant velocity, (b) from an initial velocity, at the bottom of the hill, of 10 mph to a final velocity of 50 mph at the top of the hill and (c) from an initial velocity of 45 mph to a final velocity of 15 mph. Neglect the effects of friction and wind resistance.
Answer:
a) P = 70054.3 W, b) P = 18820 W, c) P = 14116.7 W
Explanation:
Power is defined as work per unit of time
P = W / t = F x / t
P = F v
a) in this case the velocity is constant, let's use the equilibrium relation to find the force.
Let's set a reference system with the x axis parallel to the plane
F - Wₓ = 0
F = Wₓ
with trigonometry let's decompose the weight
sin θ = Wₓ / W
Wₓ = W sin θ
F = W sin 15
F = 2800 sin 15
F = 724.7 lb
we look for the speed, as it rises with constant speed we can use the relations of uniform motion
v = x / t
v = 1160/12
v = 96.67 ft / s
we calculate the power
P = 724.7 96.67
P = 70054.3 W
b) In this case, the speed of the vehicle changes during the ascent, so we use the relationship between work and the change in kinetic energy
W = ΔK
W = ½ m v_f² - ½ m v₀²
let's reduce to the SI system
v₀ = 10 mph (5280 ft / 1 mile) (1h / 3600 s = 14.67 ft / s
v_f = 50 mph (5280 ft / 1 mile) (1 h / 3600s) = 73.33 ft.s
mass : m = w / g
W = ½ 2800/32 (73.33² - 14.67²)
W = 225841 J
we calculate the average power
P = W / t
P = 225841/12
P = 18820 W
c) we repeat the previous procedure
v₀ = 45 mph = 66 ft / s
v_f = 15 mph = 22 ft / s
W = ½ 2800/32 (22² - 66²)
W = -169400 J
P = W / t
P = 169400/12
P = 14116.7 W
A good-quality measuring tape can be off by 0.58 cm over a distance of 22 m. What is its percent uncertainty
Answer:
22 m = 2200 cm
.58 / 2200 = .00026 = .026 %
Percent error = +_ .026
FORCE AND DISPLACEMENT AT AN ANGLE A sailor pulls a boat a distance of 30.0 m along a dock using a rope that makes a 25.0° angle with the horizontal. How much work does the rope do on the boat if its tension is 255 N?
Answer: 6117.58 J
Explanation:
We know that W=Fd*cos(theta) where theta is the angle between the displacement and the force.
In this case, we are given that F=225 N, d=30 m, and theta=25 degrees.
Plugging all this in we get
W=225*30*cos(25)=6117.58 J
Work done by the rope when sailor pulls the boat in the dock is 6930.9 J
What is work ?The work is defined by the product of force and displacement. Its standard formula is,
[tex]W = F.d.Cos\alpha[/tex]
Here F is force, d is displacement and α is angle subtended by force from horizontal.
As given in the question,F = 255N, d = 30m, α = 30°
On putting in the above formulaW = 255×30×Cos30°
=7650×0.906
= 6930.9 J
To learn more about work here
https://brainly.com/question/4095205
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Select the correct answer.
A force of 100 newtons is applied to a box at an angle
acceleration of the box?
36° with the horizontal. If the mass of the box is 25 kilograms, what is the horizontal
OA
1.52 meters/second2
3.24 meters/second
C.
5.48 meters/second
Ο Ο Ο Ο
6.87 meters/seconda
7.15 meters/second
Answer:
3
Explanation:
first you find the original component of the force be a cause in 36 degrees then with ka sin 36 find the average interforce by multiplying it with hundred Newton then divide the original force by the mass 25 Kg is equals tto ma
Answer:
See image
Explanation:
Plato
Thiết kế mạch điện tử sử dụng chân ngõ ra (I/O) của arduino UNO để lái relay 12VDC/500mA sao cho chân Arduino xuất ra tín hiệu 5V thì relay đóng, ngược lại chân I/O arduino xuất tín hiệu 0V thì relay hở. Mạch lái dùng BJT
Answer:
Mình cũng không biết làm bạn ơi =)))
Explanation:
5
What is back-lash error and how it is avoided
Answer:
The correct answer is - it is an error in the observation.
Explanation:
Backlash error is the error in the motion that takes place during shifting the direction of gears. A backlash error is an error in the observation which occurs due to the wear and tear of threads of the screw observed that takes place at the time of reversing the direction of rotation of the thimble where the tip of the screw does not move in the opposite direction but remains stationary for a part of the rotation.
Avoid backlash error:
While taking measurements, the screw should be rotated in one direction only.
Describe how the human ear hears sound.
Answer:
sound waves enter the outer ear and travel through a narrow passageway called the ear canal, which leads to the eardrum. The eardrum vibrates from the incoming sound waves and sends these vibrations to three tiny bones in the middle ear.
Explanation:
As part of an exercise program, a woman walks south at a speed of 2.8 m/s for 46 minutes. She then turns around and walks north a distance 3,132 m in 54 minutes . What is the woman's average speed in m/s during her entire motion
Answer:
[tex]A_[avg}=1.81m/s[/tex]
Explanation:
From the question we are told that:
North Movement
Velocity[tex]V=2.8[/tex]
Time [tex]t=46 minuites[/tex]
South movement
Distance [tex]d=3,132[/tex]
Time [tex]t'= 54 minutes[/tex]
Generally the equation for Average Velocity is mathematically given by
[tex]A_[avg}\]frac{Total distance}{Total time}[/tex]
Where
Total distance d_t
[tex]d_t=Souther\ distance\ traveled\ +Northern\ distance\ traveled[/tex]
[tex]d_t=(2.8*46*60)+(3132)[/tex]
[tex]d_t=10860[/tex]
An
Total Time
[tex]T=(46+54)60[/tex]
[tex]T=6000[/tex]
Therefore
[tex]A_[avg}=\frac{d_t}{T}[/tex]
[tex]A_[avg}=\frac{10860}{6000}[/tex]
[tex]A_[avg}=1.81m/s[/tex]
a given mass of an ideal gas law occupies a volume V of a temperature T under a pleasure p, if the pressure is increased to 2 p and temperature 1/2 T what is the percentage change in the volume of the gas
Answer:
75%
Explanation:
We'll begin by calculating the final volume of the gas. This can be obtained as follow:
Initial volume (V₁) = V
Initial temperature (T₁) = T
Initial pressure (P₁) = P
Final pressure (P₂) = 2P
Final temperature (T₂) = ½T
Final volume (V₂) =?
P₁V₁/T₁ = P₂V₂/T₂
PV/T = 2P × V₂ / ½T
Cross multiply
T × 2P × V₂ = PV × ½T
T × 2P × V₂ = PV × ½T
Divide both side by T × 2P
V₂ = (PV × ½T) / T × 2P
V₂ = ¼V
Next, we shall determine the absolute change in the volume of the gas. This can be obtained as follow:
Initial volume (V₁) = V
Final volume (V₂) = ¼V
Absolute change in volume |ΔV| =?
|ΔV| = |V₂ – V₁|
|ΔV| = |¼V – V|
|ΔV| = |0.25V – V|
|ΔV| = 0.75V
Finally, we shall determine percentage change in the volume of the gas. This can be obtained as follow:
Initial volume (V₁) = V
Absolute change in volume |ΔV| = 0.75V
Percentage change =?
Percentage change = |ΔV| / V × 100
Percentage change = 0.75V / V × 100
Percentage change = 0.75 × 100
Percentage change = 75%
Thus, the percentage change in the volume of the gas is 75%
A trumpet player hears 5 beats per second when she plays a note and simultaneously sounds a 440 Hz tuning fork. After pulling her tuning valve out to slightly increase the length of her trumpet, she hears 3 beats per second against the tuning fork. Was her initial frequency 435 Hz or 445 Hz? Explain.
Answer:
her initial frequency is 445 Hz
Explanation:
Given;
initial beat frequency, [tex]F_B[/tex] = 5
observed frequency, F = 440 Hz
let the initial frequency = F₁
F₁ = F ± 5 Hz
F₁ = 440 Hz ± 5 Hz
F₁ = 435 or 445 Hz
This result obtained shows that her initial frequency can either be 435 Hz or 445 Hz
The last beat frequency will be used to determine the actual initial frequency.
F = v/λ
Frequency (F) is inversely proportional to wavelength. That is an increase in length will cause a proportional decrease in frequency.
This shows that the final frequency is smaller than the initial frequency because of the increase in length.
Initial frequency - frequency of tuning fork = 5 beat frequency
Reduced initial frequency - frequency of tuning fork = 3 beat frequency
Initial frequency = 5Hz + 440 Hz = 445 Hz
Final frequency (Reduced initial frequency) = 440 + 3 = 443 Hz
Check: 445 Hz - 440 Hz = 5 Hz
443 Hz - 440 Hz = 3 Hz
A combination lock has a 1.1-cmcm-diameter knob that is part of the dial you turn to unlock the lock. To turn that knob, you grip it between your thumb and forefinger with a force of 0.67 NN as you twist your wrist. Suppose the coefficient of static friction between the knob and your fingers is only 0.14 because some oil accidentally got onto the knob.
Required:
What is the most torque you can exert on the knob without having it slip between your fingers?
Answer:
1.0318 × 10⁻³ N m
Explanation:
From the given question;
The torque can be determined by using the formula:
Torque = Force × radius
where;
Force = Normal force(N) × coefficient of friction (μ)
Force = 0.67 N × 0.14
Force = 0.0938 N
Since force is applied to the knob in two directions;
The Torque of the thumb and the finger can be computed as:
[tex]T_{thumb} =0.0938 *0.55 = 0.05159\ N \ cm \\ \\ T_{finger} =0.0938 *0.55 = 0.05159\ N \ cm[/tex]
The total max torque = 0.05159 N cm + 0.05159 N cm
= 0.10318 N cm
= 1.0318 × 10⁻³ N m
What kind of force are you using when you squish a marshmallow?
The answer is compression because when you are squishing a marshmello you are compressing it.
