The complete question is as follows: Which statement describes the way in which energy moves between a system reacting substances in the surroundings.
A) molecule Collisions transfer thermal energy between the system and its surroundings
B) The thermal energy of the system and it’s surroundings increase
C) The potential energy of the system and it’s surroundings increases
D) molecular collisions create energy that is then released into the surroundings
Answer: The statement, molecule Collisions transfer thermal energy between the system and its surroundings describes the way in which energy moves between a system reacting substances in the surroundings.
Explanation:
When there will occur an increase in kinetic energy of molecules then there will occur more number of collisions.
When kinetic energy between these molecules tends to decrease then they will release heat energy into their surroundings.
As a result, it means that molecule collisions transfer thermal energy between the system and its surroundings.
Thus, we can conclude that the statement molecule Collisions transfer thermal energy between the system and its surroundings describes the way in which energy moves between a system reacting substances in the surroundings.
What is the molarity of 20.2 g of potassium nitrate, KNO3, in enough water to make 250.0 mL of solution
Answer:
0.8M
Explanation:
CM=n/V
The molarity is an important method which is used to determine the concentration of a solution. The molarity of potassium nitrate is 0.796 M.
What is molarity?The molarity of a solution is defined as the number of moles of the solute present per litre of the solution. It is generally expressed in mol / L. The equation used to calculate the molarity is given as:
Molarity = Number of moles of the solute / Volume of the solution in litres
The number of moles is the ratio of the given mass to the molar mass. Here the mass of potassium nitrate is 20.2 g and its molar mass is 101.10 g/mol. Then the number of moles is:
n = 20.2 g / 101.10 g/mol = 0.199 mol
1 L = 1000 mL
250.0 mL = 250.0 / 1000 = 0.25 L
Molarity = 0.199 / 0.25 = 0.796 M
Thus the molarity is 0.796 M.
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CAN YOU HELP ME PLZ AND THANKS
Answer:
Question 7 the answer is B
Explanation:
In every nuclear reaction there is always formation of products either by nuclei bombardment or by the elements breaking into two elements of the same mass
Question 8
The answer is A
Nuclear reactions release a huge amount of energy than chemical reactions
Which of the following hydrocarbons will be the most acidic?
Pentane
Propylene
Isobutane
Ethene
Acetylene
Answer:
its answer is (Acetylene)
Using dimensional analysis convert 238.0 cm3 to L
Answer:
= 0.238 L
Explanation:
From the given information:
To convert cm³ to L(liter), we utilize the advent of a unit fraction that comprises a liter in the upper part of the fraction(numerator) and a cubic centimeter in the lower part of the fraction(denominator)
Recall that:
1000 cm³ = 1 liter
∴
238.0 cm³ = [tex]\dfrac{238.0 \ cm^3}{1} \times \dfrac{1 \ L}{1000 \ cm^3}[/tex]
= 0.238 L
3. 78 mL of 2.5 M phosphoric acid is neutralized with 500 mL of potassium hydroxide. What is the
concentration of the base?
A pure copper cube has an edge length of 1.76 cm. How many copper atoms does it contain? (volume of a cube = (edge length)^3; density of copper = 8.96 g/cm^3 )
How many grams are in 3.7 moles of Na2O?
Answer:
mass = moles x molar mass
m= 3.7 x (23x2+16)
m= 3.7x62
m= 229.4g
198.4 grams are there is 3.7 moles of Na₂O.
The number of moles is defined as the ratio between given mass and molar mass.
[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}\\\\[/tex]
Given:
Number of moles= 3.7 moles
To find:
Mass=?
Molar mass of Na₂O= 62 g/mol
Thus substituting the values in the given formula
[tex]\text{Given mass}=\text{Number of moles}*\text{Molar mass}\\\\\text{Given mass}= 3.2 \text{moles}*62 \text{g/mol}\\\\\text{Given mass}=198.4 \text{g}[/tex]
Thus, 198.4 grams are there is 3.7 moles of Na₂O.
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The Fischer esterification mechanism is examined in this question. The overall reaction is: Benzoic acid, C H 3 O H and H C l react to form a methyl ester, H 2 O and H C l. Benzoic acid is a carboxylic acid bonded to a benzene ring. Identify the results or mechanism of each step.
Answer:
See explanation and image attached
Explanation:
Fischer esterification is a type of reaction used to convert carboxylic acids to ester in the presence of excess alcohol and a strong acid which acts as a catalyst. Another final product formed in the reaction is water.
The mechanism for the fischer esterification of Benzoic acid and C H 3 O H in the presence of HCl as the catalyst is shown in the image attached to this answer.
The final products of the reaction are methyl benzoate, water and H^+ as shown in the image attached.
The methyl ester, water, and the acid catalyst (HCl) are byproducts of the Fischer esterification process, which involves protonation, nucleophilic attack, elimination, and deprotonation processes.
Carbonyl oxygen protonation: The carbonyl oxygen of the carboxylic acid (benzoic acid) is protonated by the acid catalyst (HCl) in the first step. The protonation of the carbonyl carbon increases its electrophilicity and promotes the alcohol's nucleophilic assault. Attack by the alcohol's nucleophilic oxygen (methanol, CH3OH) on the protonated carboxylic acid's carbonyl carbon results in the formation of a tetrahedral intermediate. The acid catalyst also helps with this phase. Elimination of water: In the following step, the water molecule must be removed from the tetrahedral intermediate. The hydroxyl group (-OH) from the carboxylic acid and a hydrogen from the hydroxyl group of the alcohol are removed to create this water molecule. Deprotonation: A deprotonation occurs after the removal of water.
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In what kind of orbitals do the lone-pair electrons on the singly bonded oxygen of methyl acetate reside, and are they in the same plane as the group
Answer:
Both lone pairs reside in sp3 orbitals; they are co-planar with the CH3 group.
Explanation:
In the compound, methyl acetate, the lone-pair of electrons on the singly bonded oxygen atom is accommodated in sp3 hybridized orbitals.
If we look at the compound, we will notice the both lone pair of electrons on oxygen are accommodated in sp3 orbitals which are co-planar with the CH3 group in the molecule.
Use the following balanced equation to answer the questions below.
Answer:
A. 4.5 mol Mg(OH)₂
B. 6 mol NaOH
Explanation:
Let's consider the following balanced equation.
Mg(NO₃)₂ + 2 NaOH ⇒ Mg(OH)₂ + 2 NaNO₃
PART A
The molar ratio of NaOH to Mg(OH)₂ is 2:1. The moles of Mg(OH)₂ produced from 9 moles of NaOH are:
9 mol NaOH × 1 mol Mg(OH)₂/2 mol NaOH = 4.5 mol Mg(OH)₂
PART B
The molar ratio of NaOH to NaNO₃ is 2:2. The moles of NaOH needed to produce 6 moles of NaNO₃ are:
6 mol NaNO₃ × 2 mol NaOH/2 mol NaNO₃ = 6 mol NaOH
If A Reaction Takes 10s To Go To Completion At 0°C, How Long Will It Take To Go At 100°C?
Answer:
1,000s
Explanation:
i just multiply it
If a reaction takes 10s to go to completion at 0°C,then 1000s will It take to go at 100°C.
What is reaction ?A chemical reaction is a procedure that causes one group of chemical components to change chemically into another.
Combination, decomposition, single-replacement, double-replacement, and combustion are the five fundamental types of chemical reactions. You can classify a reaction into one of these groups by looking at the reactants and products. Several categories will apply to some reactions.
When atoms establish or break chemical bonds, chemical processes take place. Reactants are the substances that begin a chemical reaction, while products are the compounds that are created as a result of the reaction.
Thus,If a reaction takes 10s to go to completion at 0°C,then 1000s will It take to go at 100°C.
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paano pakalmahin ang leon
15 points po
Answer:
lo siento señor, yo no hablo taka taka
Explanation:
5 puntos gratis pa
Determain the number of moles in 2.24l of ch4 at stp
Answer:
0.1 mole of CH₄
Explanation:
From the question given above, the following data were obtained:
Volume of CH₄ = 2.24 L
Number of mole of CH₄ =?
The number of mole of CH₄ can be obtained as follow:
Recall:
1 mole of a gas occupy 22.4 L at stp. This implies that 1 mole of CH₄ occupies 22.4 L at stp.
22.4 L = 1 mole of CH₄
Therefore,
2.24 L = 2.24 × 1 mole of CH₄ / 22.4
2.24 L = 0.1 mole of CH₄.
HELP WITH QUESTION 3,4 and 5 PLEASE
Answer:
I have no idea never get this in class before.
3 enzimas presentes en nuestro organismo e indique en que procesos actúan
Answer:
ATP asa, Helicasa, Proteasa, ARN polimerasa
Explanation:
Las enzimas son un tipo de biomoleculas que se corresponden con las proteinas.
Al momento de referirse a ellas, se utiliza la terminación asa.
ATPasa → Sintetizando ATP para el funcionamiento celular
Helicasa → Abre las hebras de ADN permitiendo el paso de la horquilla para el proceso de replicación de ADN.
Proteasas → Enzimas que degradan proteinas mal plegadas, rompen los enlaces peptídicos.
ARN polimerasa → Sintesis de ARN mensajero a partir de ADN en el proceso de la Transcripción. Se la puede conocer a veces, como primasa.
Which of the metals would reduce an iron ion
F
Fe
Cr
Cu
Ag
Sn
Answer:
Cu
Explanation:
Copper since it is more reactive than Iron. Hence, it can easily displace ions in an iron based compound.
Please help
Calculate the sodium ion (Na+) concentration for a 0.812 M Na3PO4 solution.
[Na+]=____M
Explanation:
Correct option is
B
0.750 M
Na3PO4 dissociates as:
Na3PO4⇌3Na++PO43−
∴ conc. of Na+ would be =3×0.250=
hope help
PLS HELP ME WITH THESE QUESTIONS ITS DUE TOMORROW I WILL MARK U AS BRAINLIEST
Answer:
See Explanation
Explanation:
1 mole of Cl2 gas occupies 22.4 L
x moles of Cl2 gas occupies 5.24 L
x= 1 × 5.24/22.4
x= 0.23 moles of Cl2
According to the kinetic theory of gases, the particles of a gas are in constant random motion and collide with each other and the walls of the container. Collision between gas particles are perfectly elastic.
Hence the statement that particles must not be able to move in any fixed or open container is false according to the kinetic theory of gases.
predict the major and minor products of the reaction. name the products using systematic names. ch3ch=ch2+h2o-->h+
Answer:
major will be propan-2-ol
minor will be propan-1-ol
Select all the true statements.
a. Ionic bonding is more prevalent for the higher oxidation states and covalent bonding is more prevalent for the lower states.
b. The highest oxidation state of elements in Groups 3A through 7B is +3.
c. In the transition series, atomic size across a period decreases at first but then remains relatively constant.
d. The transition elements in a period show a steady increase in electronegativity.
Answer:
In the transition series, atomic size across a period decreases at first but then remains relatively constant.
The transition elements in a period show a steady increase in electronegativity.
Explanation:
In considering the transition series, we observe that atomic sizes of the elements decreases first and subsequently remain constant. The reason for the initial decrease in atomic size is the increase in nuclear charge across the period. After the first few elements in the period, the atomic size remains relatively constant due to shielding effect of the inner d electrons which opposes the increase in effective nuclear charge.
It is also observed that electro negativity increases smoothly across the period for the transition series. Consequently, the transition series become less electro positive across the period.
Sodium hydrogen carbonate, also called baking soda, is an active ingredient in some antacids used for the relief of indigestion. Determine the percent of carbon in sodium hydrogen carbonate.
Answer:
14.30%
Explanation:
Step 1: Given data
Chemical formula of sodium hydrogen carbonate: NaHCO₃
Step 2: Determine the mass of C in 1 mole of NaHCO₃
The is 1 atom of C in 1 molecule of NaHCO₃ and the molar mass of C is 12.01 g/mol. Then, there are 12.01 g of C in 1 mole of NaHCO₃.
Step 3: Determine the mnolar mass of NaHCO₃
M(NaHCO₃) = 1 × M(Na) + 1 × M(H) + 1 × M(C) + 3 × M(O)
M(NaHCO₃) = 1 × 22.98 g/mol + 1 × 1.01 g/mol + 1 × 12.01 g/mol + 3 × 16.00 g/mol = 84.00 g/mol
Step 4: Determine the mass percent of C in NaHCO₃
We will use the following expression.
%C = mC / mNaHCO₃ × 100%
%C = 12.01 g / 84.00 g × 100% = 14.30%
How to convert chloroform to chloretone
1.00 mL of 12.0 M HCl is added to 1.00 L of a buffer that contains 0.110 M HNO2 and 0.170 M NaNO2. How many moles of HNO2 and NaNO2 remain in solution after addition of the HCl
Answer:
Moles of NaNO2 = 0.158
Moles of HNO2 final = 0.098
Explanation:
Given
Moles of HCl = 12
Moles of HNO2 = 0.11
Moles of NaNO2 = 0.170
HCl +NaNO2 --> HNO2 + NaCl
1 mole of HCl react with one mole of NaNO2 to produce 1 mole of NaCl and 1 mole of HNO2
Moles of NaNO2 = 0.17 - 0.012 = 0.158
Moles of HNO2 final = 0.11 - 0.012 = 0.098
The acid-base reaction between HCl and NaOH produces a solution with a pH of 7 at the equivalence point (NaCl H2O). Why does an acid-base indicator that changes color at pH 5 or 9 work just as well for this reaction as one that changes color at pH 7
Answer:
Answer is in the explanation.
Explanation:
Before the equivalence point, the pH of the solution of HCl that is titrated with NaOH has a pH <<< 7. When you are adding more NaOH nearing, thus, to the equivalence point the change in pH occurs quickly, and, with 1 drop of excess of NaOH after equivalence, the pH of the solution change to a pH >>> 7
That means the volume added at pH 5 or pH 9 is, almost, the same doing the indicator work just as well as an indicator with change color at pH 7
52.1 mL of aqueous 0.255 M Pb(NO3)2 is mixed with 38.5 mL of 0.415 M NaCl. The equation for the precipitate reaction is: Pb(NO3)2 (aq) 2 NaCl (aq) --> PbCl2 (s) 2 NaNO3 (aq) The concentration of Pb2 ion in the solution is _____ M after the reaction is complete.
Answer:
0.0585 M
Explanation:
Pb(NO₃)₂ (aq) + 2NaCl (aq) → PbCl₂ (s) + 2NaNO₃ (aq)First we calculate the inital number of moles of each reagent, using the given volumes and concentrations:
0.255 M Pb(NO₃)₂ * 52.1 mL = 13.3 mmol Pb(NO₃)₂ 0.415 M NaCl * 38.5 mL = 16.0 mmol NaClThen we calculate how many Pb(NO₃)₂ moles reacted with 16.0 mmoles of NaCl, using the stoichiometric coefficients of the reaction:
16.0 mmol NaCl * [tex]\frac{1mmolPb(NO_3)_2}{2mmolNaCl}[/tex] = 8.00 mmol Pb(NO₃)₂Now we calculate the remaining number of Pb(NO₃)₂ moles after the reaction:
13.3 mmol - 8.00 mmol = 5.30 mmol Pb(NO₃)₂Finally we divide the number of moles by the final volume to calculate the concentration:
5.30 mmol / (52.1 mL + 38.5 mL) = 0.0585 MHow many moles of oxygen atom are there in 0.5 moles of Ca(ClO3) 2?
Answer:
Do a quick conversion: 1 moles Ca(ClO3)2 = 206.9804 gram using the molecular weight calculator and the molar mass of Ca(ClO3)2. ... How many moles Ca(ClO3 )2 in 1 grams? ... of each element in a chemical formula by the number of atoms of that element present in the formula, then adding all of these products together.
Explanation:
(jayaanilanmol's answer)
g Calculate the pH when (a) 24.9 mL and (b) 25.1 mL of 0.100 M HNO3 have been added to 25.0 mL of 0.100 M KOH solution.
Answer:
Following are the responses to the given choices:
Explanation:
For point a:
Using the acid and base which are strong so,
moles of [tex]H^+[/tex] (from[tex]HNO_3[/tex])
[tex]= 24.9\ mL \times 0.100\ M \\\\= \frac{24.9}{1000\ L} \times 0.100\ M \\\\= 2.49 \times 10^{-3} \ mol[/tex]
moles of [tex]OH^{-}[/tex] (from [tex]KOH[/tex])
[tex]= 25.0\ mL \times 0.100\ M \\\\= \frac{25.0}{1000 \ L} \times 0.100 \ M \\\\\= 2.50 \times 10^{-3}\ mol[/tex]
[tex]1\ mol H^{+} \ neutralizes\ 1\ mol\ of\ OH^{-}[/tex]
So, [tex](2.50 \times 10^{-3} mol - 2.49 \times 10^{-3} mol)[/tex] i.e. [tex]1 \times 10^{-5}[/tex] mol of [tex]OH^-[/tex] in excess in total volume [tex](24.9+25.0) \ mL = 49.9 \ mL[/tex] i.e. concentration of [tex]OH^- = 2 \times 10^{-4}\ M[/tex]
[tex]p[OH^{-}] = -\log [OH^{-}] = -\log [2 \times 10^{-4}\ mol] = 3.70[/tex]
Since, [tex]pH + pOH = 14,[/tex]
so,
[tex]\to pH = 14- pOH = 14- 3.70 = 10.30[/tex]
For point b:
moles of [tex]OH^-[/tex] = from point a [tex]= 2.50 \times 10^{-3} \ mol[/tex]
moles of [tex]H^+[/tex](from[tex]HNO_3[/tex]):
[tex]= 25.1 mL \times 0.100 M\\\\ = \frac{25.1}{1000}\ L \times 0.100 \ M\\\\ = 2.51\times 10^{-3} \ mol[/tex]
1 mol [tex]H^+[/tex] neutralizes 1 mol of [tex]OH^-[/tex]
So, [tex](2.51 \times 10^{-3}\ mol - 2.50 \times 10^{-3}\ mol)[/tex] i.e. [tex]1 \times 10^{-5} \ mol \ of\ H^+[/tex] in excess in the total volume of [tex](25.1+25.0) \ mL = 50.1\ mL[/tex] i.e. concentration of[tex]H^+ = 2 \times 10^{-4}\ M[/tex]
Hence, [tex]pH = -\log [H^+] = -\log[2 \times 10^{-4}] = 3.70[/tex]
Some glucose produced by gluconeogenesis is stored in the body as glycogen. Order the steps of glycogen synthesis.
a. Pyrophosphatase converts PPi and water into two Pi
b. Glycogen synthase adds a glucose unit from UDP-glucose to glycogen, producing a larger glycogen molecule and UDP
c. Glvcogen synthase removes a glucose unit from a glycogen molecule producing a smaller glycogen molecule and IJDP
d. ADP-glucose pyrophosphorylase catalyzes the reaction of glucose-I -phosphate and ATP to ADP-glucose and PPi
e. UDP-glucose pyrophosphorylase catalyzes the reaction of glucose-I-phosphate and UTP to UDP-glucose and PPi
Answer:
e. UDP-glucose pyrophosphorylase catalyzes the reaction of glucose-I-phosphate and UTP to UDP-glucose and PPi
a. Pyrophosphatase converts PPi and water into two Pi
b. Glycogen synthase adds a glucose unit from UDP-glucose to glycogen, producing a larger glycogen molecule and UDP
Explanation:
Glycogen synthesis or glycogenesis is the process of synthesis of glycogen molecules from glucose molecules in living organisms. Glycogen is a polysaccharide storage form of glucose and helps to store excess glucose in the body form use when required by the body.
The synthesis of glycogen involves sugar nucleotides. Sugar nucleotides are compounds in which a sugar molecule is attached to a nucleotide through phosphate ester bond, resulting in the activation of the sugar molecule. The sugar nucleotides then are used as substrates for the polymerization of the monosaccharide sugars into disaccharides, oligosaccharides and polysaccharides.
In the synthesis of glycogen, glucose-6-phosphate from phosphorylation of free glucose by hexokinase is first isomerized to glucose-1-phosphate by phosphoglucomutase.
Glucose-1-phosphate is then converted to UDP-glucose by its reaction with UTP catalyse by UDP-glucose pyrophosphorylase. The reaction is favoured by the rapid hydrolysis of PPi produced to two molecules of inorganic phosphate by the enzyme pyrophosphatase.
Glycogen synthase then adds a glucose unit from UDP-glucose to a growing chain of glycogen, producing a larger glycogen molecule and free UDP.
What characteristic of a light wave in a medium determines the index of refraction of that
medium?
Answer:
The refractive index can be seen as the factor by which the speed and the wavelength of the radiation are reduced with respect to their vacuum values: the speed of light in a medium is v = c/n, and similarly the wavelength in that medium is λ = λ0/n, where λ0 is the wavelength of that light in vacuum.
Explanation:
How many milliliters of 0.350 M H2SO4 are required to neutralize 60.0 mL of 0.300 M NaOH?
Answer:
25.7 mL of H₂SO₄
Explanation:
We'll begin by writing the balanced equation for the reaction. This is illustrated below:
H₂SO₄ + 2NaOH —> Na₂SO₄ + 2H₂O
From the balanced equation above,
The mole ratio of acid, H₂SO₄ (nₐ) = 1
The mole ratio of base, NaOH (n₆) = 2
Finally, we shall determine the volume of H₂SO₄ needed for the reaction. This can be obtained as shown below:
Molarity of acid, H₂SO₄ (Mₐ) = 0.350 M
Volume of base, NaOH (V₆) = 60 mL
Molarity of base, NaOH (M₆) = 0.300 M
Volume of acid, H₂SO₄ (Vₐ) = ?
MₐVₐ / M₆V₆ = nₐ/n₆
0.350 × Vₐ / 0.3 × 60 = 1/2
0.350 × Vₐ / 18 = 1/2
Cross multiply
0.350 × 2 × Vₐ = 18
0.7 × Vₐ = 18
Divide both side by 0.7
Vₐ = 18 / 0.7
Vₐ = 25.7 mL
Thus, 25.7 mL of H₂SO₄ is needed for the reaction.
