Explanation:
Butanol (С4Н9OH)
Structural formula is :-
CH3-CH2-CH2-CH2-OH
When Ethyl Acetoacetate is treated with 1,3-Dibromopropane and 2 moles of Sodium Ethoxide in Ethanol, a compound is produced that has the formula C9H14O3. This compound has an infrared spectrum that shows only one carbonyl adsorption and no OH bond stretch. Suggest a structure for this compound, and provide a mechanism for its formation.
Answer:
The reaction of ethyl acetoacetate with 1,3-Dibromopropane and 2 moles of Sodium Ethoxide in Ethanol.
Explanation:
The structure of ethyl acetoacetate is shown below:
The structure of 1,3-dibromopropane is shown below:
Ethyl acetoacetate on reaction with sodium ethoxide in ethanol forms a carbanion intermediate and the formation of carbanion takes place twice and form a cyclic ring.
The entire reaction is shown below:
The structure of C9H14O3 is shown in the chemical reaction that is shown below:
Which of the following is NOT a property of alkanes?
a)
The boiling point increases as the number of carbons in the compound
increases
b) They are unreactive under standard conditions
C) They have weak intermolecular attractions
d) They are soluble in water
Answer:
D
Explanation:
because alkanes don't dissolve in water. They are insoluble.
cetic acid (HC2H3O2) is an important component of vinegar. A 10.00-mL sample of vinegar is titrated with 0.5052 M NaOH, and 16.88 mL are required to neutralize the acetic acid that is present. Write a balanced equation for this neutralization reaction. What is the molarity of the acetic acid in this vinegar
Answer:
The molarity of the acetic acid in this vinegar is 0.853 M
Explanation:
Step 1: Data given
Volume of vinegar sample = 10.00 mL
Concentration of NaOH = 0.5052 M
16.88 mL are required to neutralize the acetic acid
Step 2: The reaction
HC2H3O2(aq) + NaOH(aq) ⇔ NaC2H3O2(aq) + H2O(l)
Step 3: Calculate molarity of cetic acid (HC2H3O2)
C1*V1 = C2*V2
⇒with C1 = the molarity ofHC2H3O2= TO BE DETERMINED
⇒with V1 = the volume of HC2H3O2 = 10.00 mL = 0.01 L
⇒with C2 = the molarity of NaOH = 0.5052 M
⇒with V2 = the volume of NaOH = 16.88 mL = 0.01688L
C1 = (C2*V2)V1
C1 = (0.5052 * 0.01688 ) / 0.01
C1 = 0.853 M
The molarity of the acetic acid in this vinegar is 0.853 M
If the distance between a point charge and a neutral atom and is multiplied by a factor of 5, by what factor does the force on the neutral atom by the point charge change
Given :
The distance between a point charge and a neutral atom and is multiplied by a factor of 5.
To Find :
By what factor does the force on the neutral atom by the point charge change.
Solution :
We know, electrostatic force between two object is directly proportional to product of charge and inversely proportional to distance between them.
Now, charge in neutral atom is 0 C.
So, the electrostatic force between two of them is also 0 N.
Therefore, by changing distance between the charge the forces did no change ( it remains zero).
Possible interaction between oxygen molecule and water is ______________.
Answer:
Hydrogen Bonds
Explanation:
Opposite charges attract one another. The slight positive charges on the hydrogen atoms in a water molecule attract the slight negative charges on the oxygen atoms of other water molecules. This tiny force of attraction is called a hydrogen bond.
how to find the group number of f block elements
Answer:
I hope you understand please follow me please
Using dimensional analysis convert 238.0 cm3 to L
Answer:
= 0.238 L
Explanation:
From the given information:
To convert cm³ to L(liter), we utilize the advent of a unit fraction that comprises a liter in the upper part of the fraction(numerator) and a cubic centimeter in the lower part of the fraction(denominator)
Recall that:
1000 cm³ = 1 liter
∴
238.0 cm³ = [tex]\dfrac{238.0 \ cm^3}{1} \times \dfrac{1 \ L}{1000 \ cm^3}[/tex]
= 0.238 L
How many moles of I2 are there in 5.34 x 1025molecules of I2 ?
Explanation:
pls the question is not clear to me
Write the empirical formula of at least four binary ionic compounds that could be formed from the following ions: Ca^2 , Al^3 ,I^-,S^2-
Answer:
Write the empirical formula of at least four binary ionic compounds that could be formed from the following ions: Ca^2 , Al^3 ,I^-,S^2-
Explanation:
1)Formula of calcium iodide:
The compound of Ca^2+ and I^-1:
[tex]CaI_2[/tex]
2) Formula of calcium sulfide:
[tex]CaS[/tex]
3) Formula of aluminum iodide:
[tex]AlI_3[/tex]
4) Formul aluminum sulfide:
[tex]Al_2S_3[/tex]
These are the four ionic compounds that are formed.
PLEASE HELP ME WITH THESE TWO QUESTIONS I WILL MARK U AS BRAINLIEST!!
Answer:
See Explanation
Explanation:
From the parameters given here in this question;
n= 1.46 moles
P= 0.982 miles
T= 13°C + 273 = 286 K
R= 0.0821 L.atm/mol.K
We are to find the volume using the ideal gas equation which states that;
PV=nRT
V= nRT/P
V= 1.46 × 0.0821 × 286/0.982
V= 34.9 L
b) Boyle's law can be proven from the kinetic theory of gases. Boyle's law states the relationship between the volume and pressure of an ideal gas. Boyle's law states that the pressure of a given mass of ideal gas is inversely proportional to it's volume at constant temperature and pressure. This is the only correct statement among the options listed in the question.
What is the oxidation state of P in Ca3(PO4)2?
A. -5
B. +3
C. +5
D. -3
The oxidation state of P in [tex]Ca_3(PO_4)_2[/tex] is +5. In the compound [tex]Ca_3(PO_4)_2[/tex], there are 3 Ca ions, each with an oxidation state of +2, and 2 [tex]PO_4[/tex] ions. The correct answer is option C.
To find the oxidation state of P, we need to use the fact that the compound has a neutral overall charge and the oxidation states of all the atoms in the compound must add up to zero. Since the oxidation state of Ca is +2, the total positive charge from the Ca ions is +6. Therefore, the total negative charge from the PO4 ions must be -6. Each [tex]PO_4[/tex] ion has a charge of -3, so the total charge from the two [tex]PO_4[/tex] ions is -6. In [tex]PO_4[/tex], the oxidation state of O is -2. Let the oxidation state of P be x. Since there is 4 O atoms per [tex]PO_4[/tex] ion, the total negative charge from the O atoms is -12. Using the fact that the overall charge is zero, we can set up the following equation: 2x + (-12) = -6 Simplifying, we get 2x = +6 - (-12) = +18 Solving for x, we get x = +9/2 = +4.5. However, the oxidation state of P must be a whole number, so we round to the nearest integer and get: +5. Therefore, the oxidation state of P in [tex]Ca_3(PO_4)_2[/tex] is +5 and the correct answer is option C.For more questions on the oxidation state
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3. 78 mL of 2.5 M phosphoric acid is neutralized with 500 mL of potassium hydroxide. What is the
concentration of the base?
(BRAINLIEST AWARD!! LAST QUESTION!!) Jean-Baptiste Lamarck's theory of evolution stated that an organism could pass on to its offspring all characteristics it had acquired in its lifetime. Which of these statements best explains why this theory is considered invalid at present? (1 point)
Modern scientists accept only new scientific theories.
Most of the scientists worldwide do not accept this theory.
All old theories change into new theories over a period of time.
Newspapers and science magazines do not publish this theory any more.
Answer:
Most of the scientists worldwide do not accept this theory.
Explanation:
Lamarck's theory states that acquired traits can be passed on from parents to offspring. This theory can not be sufficiently substantiated by indisputable scientific evidences hence it is not accepted by majority of scientists worldwide.
Since science is empirical and the theory is mostly based on vague speculations rather than concrete evidence, it was long rejected by many biologists.
This theory suggests that all life forms will gradually evolve from simple to complex organisms while the simple organisms gradually disappear. This is not the case.
A pure copper cube has an edge length of 1.76 cm. How many copper atoms does it contain? (volume of a cube = (edge length)^3; density of copper = 8.96 g/cm^3 )
Draw and upload the structures
of the following derivatives of
the carboxylic acids
a. Ethyl 2-hydroxypropanoate
b. Butyl 3,3-dimethyhexanoate
c. N-Ethyl-N-methylbenzamide
d. 2,3-Dibromohexanamide
Answer:
Draw and upload the structures
of the following derivatives of
the carboxylic acids:
a. Ethyl 2-hydroxypropanoate
b. Butyl 3,3-dimethyhexanoate
c. N-Ethyl-N-methylbenzamide
d. 2,3-Dibromohexanamide
Explanation:
a. Ethyl 2-hydroxypropanoate
indicates that the given molecule has -oate suffix that means it has an ester(R-COO-R') functional group.
Prop- indicates that the main carbon chain has three carbon atoms.
Ethyl group at the second position is the substituent.
b. In this molecule has also -oate functional group which means it has an ester functional group.
The rootword hex-indicates that the main carbon chain has six carbons.
Butyl-3,3-dimethyl group is the substituent.
c. N-ethyl-N-methylbenzamide
In this molecule, the aimde group indicates the presence of -CONH2 group.
N-methyl group prefix indicates that the methyl group is attached to N-atom.
N-ethyl prefix indicates the presence of ethyl group to N-atom.
d. 2,3-dibromohexanamide indicates the presence of amide functional group and two bromo groups as substituents at the second and third carbons.
The structures of all the compounds are shown below:
Answer: The structures of all the acid derivatives are attached below.
Explanation:
Some of the acid derivatives are:
EstersAmidesAcid anhydridesAcid halidesTo name a compound, first look for the longest possible carbon chain.
Amide group is a type of functional group where an amine group is attached to a carbonyl group. The general formula of amide is [tex]R-CO-NH_2[/tex], where R is an alkyl or aryl group.
Esters are a kind of organic molecules having functional groups, where R and R' are the alkyl or aryl groups. They are formed by the combination of alcohol and carboxylic acid.
These functional group compounds are named in two words which is alkyl alkanoates, where alkyl refers to the alcoholic part and alkanoate refers to the carboxylic acid part of the molecule. The numbering of the parent chain in esters is done from the carboxylic carbon. The alkyl part is not given any numbers.
For (a): Ethyl 2-hydroxypropanoate
The longest possible carbon chain has 3 carbon atoms and prefix used will be 'prop-'.
A hydroxy (-OH) group is attached to the 2nd position.
The structure is attached in the image below.
For (b): Butyl 3,3-dimethyhexanoate
The longest possible carbon chain has 6 carbon atoms and prefix used will be 'hex-'.
2 methyl groups are attached at the 3rd position
The structure is attached in the image below.
For (c): N-Ethyl-N-methylbenzamide
The longest possible carbon chain is a benzene ring
1 methyl and 1 ethyl groups are attached directly to the N-atom
The structure is attached in the image below.
For (d): 2,3-Dibromohexanamide
The longest possible carbon chain has 6 carbon atoms and prefix used will be 'hex-'.
2 bromo groups are attached at the 2nd and 3rd position
The structure is attached in the image below.
if The difference in height of mercury in the two arms is 435 mm. What is the pressure of the nitrogen gas in kPa?
Answer:
Therefore, Pnitrogen=97.5kpa
Explanation:
100.0-2.49
=97.5
435= i don't know
Hydrolysis of the compound B5H9 forms boric acid, H3BO3. Fusion of boric acid with sodium oxide forms a borate salt, Na2B4O7. Part A Without writing complete equations, find the mass (in grams) of B5H9 required to form 148 g of the borate salt by this reaction sequence.
Answer:
37.09 g of B₅H₉ is required to form 148 g of borate salt( Na₂B₄O₇ )
Explanation:
Given the data in the question;
B₅H₉ → H₃BO₃ → Na₂B₄O₇
find the mass (in grams) of B5H9 required to form 148 g of the borate salt by this reaction sequence.
S M.W
B₅H₉ 63
H₃BO₃ 62
Na₂B₄O₇ 201
So, moles of Na₂B₄O₇ = 148 / 201 = 0.736
Since Boron will be conserved,
Moles of Boron atoms in Na₂B₄O₇ will be;
⇒ 4 × 0.736 = 2.944
Now, Moles of Boron in Na₂B₄O₇ = Moles of Boron in H₃BO₃ = Moles of Boron in B₅H₉
Hence,
Moles of Boron in B₅H₉ = 2.944
Moles of B₅H₉ = 2.944 / 5 = 0.5888
Mass of B₅H₉ = 0.5888 × 63 = 37.09 g
Therefore, 37.09 g of B₅H₉ is required to form 148 g of borate salt( Na₂B₄O₇ )
If a certain gas occupies a volume of 12 LL when the applied pressure is 6.0 atmatm , find the pressure when the gas occupies a volume of 3.0 LL . Express your answer to two significant figures, and include the appropriate units. View Available Hint(s)
Given :
If a certain gas occupies a volume of 12 LL when the applied pressure is 6.0 atm.
To Find :
The pressure when the gas occupies a volume of 3.0 LL .
Solution :
Since, their is no information of temperature, let us assume it is constant throughout the process.
We know, by ideal gas equation at constant temperature :
[tex]\alpha P_1V_1 = P_2V_2\\\\6 \times 12 = P_2 \times 3\\\\P_2 = 24\ atm[/tex]
Therefore, the pressure when the gas occupies a volume of 3.0 LL is 24 atm.
HELP AS SOON AS POSSIBLE PLEASE……Which of the following equations is balanced? (5 points)
1) 2H2 + O2 + 4H20
2) 4Na + O2 -2Na20
3) Fe2O3 + H2 - 2Fe + 3H20
4) CH4 + O2 - CO2 + H20
Answer:
Number 2 is the balanced equation
Explanation:
There is
4 Na on both sides
2 O on both sides
4Na + O2 -2Na2O is a balanced equation.
What is Balanced equation?An equation for a chemical reaction is said to be balanced if both the reactants and the products have the same number of atoms and total charge for each component of the reaction.
The law of conservation of mass states that when a chemical reaction takes place, the mass of the reactants and products should be equal.
The chemical equation that depicts the chemical reaction must be balanced as a result. When the total number of atoms in the reactants and products sides of a chemical equation equals one, the equation is said to be balanced.
An unbalanced chemical equation lists the reactants and products in a chemical reaction but doesn't state the amounts required to satisfy the conservation of mass.
Therefore, 4Na + O2 -2Na2O is a balanced equation.
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The movement of the liquid in a thermometer shows changes in temperature. An increase in temperature
indicates the molecules in the liquid
Answer:
When heated, the molecules of the liquid in the thermometer move faster, causing them to get a little further apart. This results in movement up the thermometer. When cooled, the molecules of the liquid in the thermometer move slower, causing them to get a little closer together.
Explanation:
I hope it can help
An increase in temperature indicates the molecules in the liquid are moving faster and the temperature is rising in the thermometer.
What are the uses of mercury Thermometer ?Mercury thermometer are useful in measuring body , liquid and vapor temperature.
Mercury is used in the thermometer , The movement of the liquid in a thermometer shows changes in temperature.
The volume expansion coefficient of Mercury is very high and so by 1 degree rise in temperature there is 0.018 % increase in volume.
An increase in temperature indicates the molecules in the liquid are moving faster and the temperature is rising in the thermometer.
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how many grams of zinc sulfide are used to produce 1.28 grams of zinc oxide?
Answer:
0.012288122055459
Explanation:
i might be wrong
How many grams are in 3.7 moles of Na2O?
Answer:
mass = moles x molar mass
m= 3.7 x (23x2+16)
m= 3.7x62
m= 229.4g
198.4 grams are there is 3.7 moles of Na₂O.
The number of moles is defined as the ratio between given mass and molar mass.
[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}\\\\[/tex]
Given:
Number of moles= 3.7 moles
To find:
Mass=?
Molar mass of Na₂O= 62 g/mol
Thus substituting the values in the given formula
[tex]\text{Given mass}=\text{Number of moles}*\text{Molar mass}\\\\\text{Given mass}= 3.2 \text{moles}*62 \text{g/mol}\\\\\text{Given mass}=198.4 \text{g}[/tex]
Thus, 198.4 grams are there is 3.7 moles of Na₂O.
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HELP!!!! if 3.50 moles of sodium hydroxide reacts with excess lead(II) nitrate, how many moles of Pb(OH)2 are produced?
Answer: 1.5 moles of [tex]Pb(OH)_2[/tex] are produced.
Explanation:
We are given:
Moles of sodium hydroxide = 3.50 moles
The given chemical equation follows:
[tex]Pb(NO_3)_2(aq)+2NaOH(aq)\rightarrow Pb(OH)_2(s)+2NaNO_3(aq)[/tex]
By stoichiometry of the reaction:
If 2 moles of NaOH produces 1 mole of [tex]Pb(OH)_2[/tex]
So, 3 moles of NaOH will produce = [tex]\frac{1}{2}\times 3=1.5mol[/tex] of [tex]Pb(OH)_2[/tex]
Hence, 1.5 moles of [tex]Pb(OH)_2[/tex] are produced.
How many molecules in 8H2(g)+4O2
Rank these transition metal ions in order of decreasing number of unpaired electrons.
a. Fe^3
b. Mn^4+
c. V3+
d. Ni^2+
e. Cu^+
Answer: The given transition metal ions in order of decreasing number of unpaired electrons are as follows.
[tex]Mn^{4+} > V^{3+} = Ni^{2+} > Fe^{3+} > Cu^{+}[/tex]
Explanation:
In atomic orbitals, the distribution of electrons of an atom is called electronic configuration.
The electronic configuration in terms of noble gases for the given elements are as follows.
Atomic number of Fe is 26.[tex]Fe^{3+} - [Ar] 3d^{5}[/tex]
So, there is only 1 unpaired electron present in [tex]Fe^{3+}[/tex].
Atomic number of Mn is 25.[tex]Mn^{4+} - [Ar]3d^{3}[/tex]
So, there are only 3 unpaired electrons present in [tex]Mn^{4+}[/tex].
Atomic number of V is 23.[tex]V^{3+} - [Ar] 3d^{2}[/tex]
So, there are only 2 unpaired electrons present in [tex]V^{3+}[/tex].
Atomic number of Ni is 28.[tex]Ni^{2+} - [Ar] 3d^{8}[/tex]
So, there will be 2 unpaired electrons present in [tex]Ni^{2+}[/tex].
Atomic number of Cu is 29.[tex]Cu^{+} - [Ar] 3d^{10}[/tex]
So, there is no unpaired electron present in [tex]Cu^{+}[/tex].
Therefore, given transition metal ions in order of decreasing number of unpaired electrons are as follows.
[tex]Mn^{4+} > V^{3+} = Ni^{2+} > Fe^{3+} > Cu^{+}[/tex]
Thus, we can conclude that given transition metal ions in order of decreasing number of unpaired electrons are as follows.
[tex]Mn^{4+} > V^{3+} = Ni^{2+} > Fe^{3+} > Cu^{+}[/tex]
How many grams of oxygen are present in 93.98 g of CO2?
Answer:
There are about 68.33 grams of oxygen present in 93.98 g of CO2.
Given a 0.200 M solution of anserine at its isoelectric point and ready access to 0.100 M HCl, 0.100 M NaOH and distilled water, describe the preparation of 1 L of 0.0400 M anserine buffered solution, pH 7.20.
Solution :
Given :
Amount of anserine solution = 0.200 M
pH value is = 7.20
Preparation of 0.04 M solution of anserine from the 0.2 M solution.
0.2 M x [tex]x[/tex] = 0.04 M x 1000 ml
[tex]x[/tex] = 200 ml
So the 200 ml of 0.2 M anserine solution is required to prepare0.04 M of anserine.
0.1 M x [tex]x[/tex] = 0.04 x 1000 ml
[tex]x[/tex] = 400 ml
Therefore, 400 ml of HCl is needed.
2Al + 6HCl → 2AlCl3 + 3H2
If 85.0 grams of HCl react, how many moles of H2 are produced?
Answer:
1.17 mol
Explanation:
Step 1: Write the balanced equation
2 Al + 6 HCl → 2 AlCl₃ + 3 H₂
Step 2: Calculate the moles corresponding to 85.0 g of HCl
The molar mass of HCl is 36.46 g/mol.
85.0 g × 1 mol/36.46 g = 2.33 mol
Step 3: Calculate the number of moles of H₂ produced from 2.33 moles of HCl
The molar ratio of HCl to H₂ is 6:3.
2.33 mol HCl × 3 mol H₂/6 mol H₂ = 1.17 mol H₂
A bear has just had a sandwich that contained the equivalent of 2.70 mol of glucose ΔHo 2810 kJ mol 1 The standard molar entropy ΔSo of reaction is 182 J K 1 mol 1 How much energy in kJ is available for sustaining the bear's muscular and nervous activity assuming a body temperature of 36.1oC Make sure that your answer has the correct number of significant figures
Answer:
no
Explanation:
The Fischer esterification mechanism is examined in this question. The overall reaction is: Benzoic acid, C H 3 O H and H C l react to form a methyl ester, H 2 O and H C l. Benzoic acid is a carboxylic acid bonded to a benzene ring. Identify the results or mechanism of each step.
Answer:
See explanation and image attached
Explanation:
Fischer esterification is a type of reaction used to convert carboxylic acids to ester in the presence of excess alcohol and a strong acid which acts as a catalyst. Another final product formed in the reaction is water.
The mechanism for the fischer esterification of Benzoic acid and C H 3 O H in the presence of HCl as the catalyst is shown in the image attached to this answer.
The final products of the reaction are methyl benzoate, water and H^+ as shown in the image attached.
The methyl ester, water, and the acid catalyst (HCl) are byproducts of the Fischer esterification process, which involves protonation, nucleophilic attack, elimination, and deprotonation processes.
Carbonyl oxygen protonation: The carbonyl oxygen of the carboxylic acid (benzoic acid) is protonated by the acid catalyst (HCl) in the first step. The protonation of the carbonyl carbon increases its electrophilicity and promotes the alcohol's nucleophilic assault. Attack by the alcohol's nucleophilic oxygen (methanol, CH3OH) on the protonated carboxylic acid's carbonyl carbon results in the formation of a tetrahedral intermediate. The acid catalyst also helps with this phase. Elimination of water: In the following step, the water molecule must be removed from the tetrahedral intermediate. The hydroxyl group (-OH) from the carboxylic acid and a hydrogen from the hydroxyl group of the alcohol are removed to create this water molecule. Deprotonation: A deprotonation occurs after the removal of water.
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