Remains the same
Explanation:
According to Gauss's law, the electric flux through a closed surface is proportional to the charge enclosed by the surface. So no matter how big or small we make the surface that encloses the charge, the electric flux remains the same because it only depends on the enclosed charge, not surface area.
1. What did you observe about the magnitudes of the forces on the two charges? Were they the same or different? Does your answer depend on whether the charges were of the same magnitude or different? How does this relate to Newton’s 3rd law?
Answer:
Following are the solution to the given question:
Explanation:
Its strength from both charges is equivalent or identical. The power is equal. And it is passed down
[tex]F=\frac{kq_1q_2}{r^2}[/tex]
Therefore, the extent doesn't rely on the fact that charges are the same or different. Newton's third law complies with Electrostatic Charges due to a couple of charges. They are similar in magnitude, and they're in the other way.
[tex]|F_{12}| = |F_{21}|[/tex]
An object travels down a ramp at a constant acceleration. The object experiences a force of friction and a gravitational force. Which of the following could be true about the motion of the object?
a. The force of friction acts in the same direction as the object travels.
b. The force of friction between the surface and the object is less than the component of the gravitational force that is parallel to the ramp.
c. If the object increased in mass, the object's acceleration would change.
d. If the object increased in mass, the normal force exerted on the object would remain the same.
Answer:
Option (b) is correct.
Explanation:
An object travels down a ramp at a constant acceleration.
Friction force and the gravitational force is there.
(a). It is false. As the friction acts in the opposite direction of motion of the object.
(b). It is true. As the object moves down the ramp so the force of friction is less the component of gravitational force along the ramp.
(c). It is false. the acceleration does not depends on the mass.
a = g sin A - u g cos A
where, A is the angle of inclination and u is the coefficient of friction.
(d). It is false. The normal force is given by
N = m g cos A
so it depends on the mass.
With the frequency set at the mid-point of the slider and the amplitude set at the mid-point of the slider, approximately how many grid marks is the wavelength of the wave (use the pause button and step button as you need to in order to get a good measure, and round to the nearest whole grid mark)?
If the amplitude is increased the wavelength:___________.
a. decreases
b. stays the same
c. increases
Answer:
correct answer is b
Explanation:
The frequency of a wave depends on the properties of medium density and the elasticity properties change the amplitude depends on the energy carried by the wave, that is, the amplitude is proportional to the height of the wave (oscillation).
Consequently the amplitude of independent of the frequency because it depends on different factors.
Therefore when changing the amplitude the wavelength remains constant
the correct answer is b
A particle of mass M moves along a straight line with initial speed vi. A force of magnitude F pushes the particle a distance D along the direction of its motion.
Required:
By what multiplicative factor RK does the initial kinetic energy increase, and by what multiplicative factor RWdoes the work done by the force increase (with respect to the case when the particle had a mass M)?
Solution :
From the Newton's second law of motion :
F = ma
[tex]a=\frac{F}{m}[/tex]
[tex]$\frac{dv}{dt}=\frac{F}{m}$[/tex]
[tex]$\left(\frac{dv}{ds} \times \frac{ds}{dt}\right)=\frac{F}{m}$[/tex]
[tex]$v \frac{dv}{ds} = \frac{F}{m}$[/tex]
[tex]$v dv =\frac{F}{m}\ ds$[/tex]
Integrating above the expression by applying the limits :
[tex]$\int_{v_i}^{v_f} v \ dv= \frac{F}{m} \int_0^s ds$[/tex]
Here the diameter is s= D
[tex]$\frac{v_f^2 - v_i^2}{2}=\frac{FD}{m}$[/tex]
The final speed of the particle after travelling distance D is
[tex]$v_f = \sqrt{v_i^2 + \frac{2FD}{m}}$[/tex]
The kinetic energy of the particle of mass M is :
[tex]$K_1=\frac{1}{2}Mv^2$[/tex]
For M = 3M
[tex]$K_2=\frac{1}{2}(3M)v^2$[/tex]
[tex]$=3(K_1)$[/tex]
Thus the kinetic energy increases by a factor of 3.
The work done depends on the factor and the displacement of the body. Thus, the work done remains same even though the mass increases. Hence the work down increases by factor 1.
A weight stretches a spring 1.5 inches in equilibrium. The weight is initially displaced 8 inches above equilibrium and given a downward velocity of 4 ft/s. Find its displacement for t > 0
Answer:
x = 0.667 cos 10.69 t + 0.383)
Explanation:
This is a simple harmonic movement exercise, the general solution is
x = A cos (wt + Ф)
w² = k / m
In this exercise, the initial displacement is that it corresponds to the amplitude of the movement.
A = 8 in. (1 ft. 12 in.) = ⅔ ft. = 0.6667 ft.
x = 1.5 in = 0.125 ft
We look for the constant k with Hooke's law
F = -kx
the force applied is the weight of the body F = W = mg
-mg = - k x
k = m g / x
we substitute
k = m 32.16 / 0.125
k = 257.28 m
we substitute
w = √257.28
w = 16.04 rad / s
we substitute in the expression of the position
x = 0.667 cos (16.04 t + Ф)
to find the constant fi we look for the velocity
v = dx / dt
v = - 0.667 16.04 sin (16.04 t +Ф)
indicate the values of v = 4 ft / s for t = 0
- 4 = -10.6934 sin Ф
remember angles are in radians
Ф = sin⁻¹ (4/106934)
Ф = 0.383
we substitute
x = 0.667 cos 10.69 t + 0.383)
which equation describes the sum of the vectors plotted below
Answer:
i think it could be d
Explanation:
I'm not sure
The sum of the vectors plotted below describes by 2x i + 4y j. Hence, option (B) is correct.
What is vector?Physical quantities that exhibit both magnitude and direction are referred to as vector quantities. As an illustration, consider displacement, force, torque, momentum, acceleration, and velocity.
It is more complicated to add vectors than it is to add scalars. It is impossible to simply add two vectors together to get their sum since vectors include both magnitude and direction. The Triangle law is used to calculate the vector addition.
According to the figure:
the sum of the vectors is position vector of second vector, that is, r = 2x i + 4y j.
Learn more about vector here:
https://brainly.com/question/29740341
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which wave characteristic is the same for all electromagnetic waves traveling through a vacuum?
Answer:
All waves travel at the same speed c.
How much power is required to light a lightbulb at 100V of voltage when the lightbulb has a resistance of 500 Ohms?
Answer:
20 Watt
Explanation:
Applying
P = V²/R................... Equation 1
Where V = Voltage, P = Power, R = resistance
From the question,
Given: V = 100V, R = 500 ohms
Substitute these values into equation 1
P = (100²)/500
P = 10000/500
P = 20 Watt.
Hence the power required to light the bulb is 20 W
What is the vibrating source that creates sound waves?
Answer:
Sound is produced when an object vibrates, creating a pressure wave. This pressure wave causes particles in the surrounding medium (air, water, or solid) to have vibrational motion. As the particles vibrate, they move nearby particles, transmitting the sound further through the medium.
in a Mercury thermometer the level of Mercury Rises when its bulb comes in contact with a hot object what is the reason for this rise in the level of Mercury
Answer:
because thermometric liquid readily expands on heating or contracts on cooling even for a small difference in the temperature of the body.
Find the acceleration due to gravity on the surface of a planet with a mass of 3.5 * 10^24 kg and an average radius of 4.5 * 10^6 m.
g A car with a mass of 1,120.0 kg accelerates from 0 to 80.0 km/h in 10.0 s. The driver applies the brakes when the car is moving at 80.0 km/h, and the car comes to rest after traveling 44.0 m. What is the net force (in N) on the car during its deceleration
Answer:
8761.5 N
Explanation: Given that a car with a mass of 1,120.0 kg accelerates from 0 to 80.0 km/h in 10.0 s. The driver applies the brakes when the car is moving at 80.0 km/h, and the car comes to rest after traveling 44.0 m. What is the net force (in N) on the car during its deceleration
Mass m = 1120kg
First change km/h to m/s
(80 × 1000) ÷ 3600
Velocity = 22.2 m/s
Acceleration = ( 22.2 - 0 ) ÷ 10
Acceleration = 2.2 m/s^2
Force F1 = mass × acceleration
Substitutes all the parameters into the formula
F1 = 1120 × 2.2
F1 = 2489 N
For the car to come to rest, it will be decelerating.
Using 3rd law of motion
V^2 = U^2 + 2as
V = 0 since it is coming to rest.
Substitute all the parameters into the formula
0 = 22.2^2 - 2 × a × 44
88a = 492.84
a = 492.84/88
a = 5.6 m/s^2
The force F2 = 1120 × 5.6
F2 = 6272.5N
Net force = 6272.5 + 2489
Net force = 8761.5 N
Therefore, the net force is 8761.5 N
A crate falling from a plane is part of a closed system that has 24,450 J of
mechanical energy. If the kinetic energy of the crate increases from 10,000 J
to 15,000 J, what happens to the gravitational potential energy of the system?
The electric field strength between the plates of a simple air capacitor is equal to the voltage across the plates divided by the distance between them. When a voltage of is put across the plates of such a capacitor an electric field strength of
Answer:
The formula for the separation between the plates, d = V/E and d = 1.02 mm
Explanation:
Here is the complete question
The electric field strength between the plates of a simple air Capacitor is equal to the voltage across the plates divided by the distance between them When a voltage of 112. V is put across the plates of such a capacitor an electric field strength of 1.1 kV/cm is measured. Write an equation that will let you calculate the distance d between the plates. Your equation should contain only symbols. Be sure you define each symbol
Solution
The electric field strength between the plates of a simple air capacitor is given by E = V/d where V = electric potential between the plates and d = separation between the plates.
Making d the separation between the plates subject of the formula, we have
d = V/E
Since V = 112 V and E = 1.1 kV/cm = 1100 V/cm
Substituting the values of the variables into the equation, we have
d = V/E
d = 112 V/1100 V/cm
d = 0.102 cm
d = 1.02 mm
So, the formula for the separation between the plates, d = V/E and d = 1.02 mm.
A truck is driving over a scale at a weight station. When the front wheels drive over the scale, the scale reads 5800 N. When the rear wheels drive over the scale, it reads 6500 N. The distance between the front and rear wheels is 3.20 m Determine the distance between the front wheels and the truck's center of gravity.
Answer:
[tex]x_2=1.60m[/tex]
Explanation:
From the Question We are told that
Initial Force [tex]F_1=5800N[/tex]
Final Force [tex]F_2=6500N[/tex]
Distance between the front and rear wheels \triangle x=3.20 m
Since
[tex]\triangle x=3.20 m[/tex]
Therefore
[tex]x_1+x_2=3.20[/tex]
[tex]x_1=3.20-x_2[/tex]
Generally the equation for The center of mass is at x_2 is mathematically
given by
[tex]x_2 =\frac{(F_1x_1+F_2x_2)}{(F_1+F_2)}[/tex]
[tex]x_2=3.20F_1-\frac{x_2F_1+F_2x_2}{(F_1+F_2)}[/tex]
[tex]2*F_1*x_2 =3.20F_1[/tex]
[tex]x_2=1.60m[/tex]
Center of gravity of a body is the sum of its moments divided by the overall weight of the object. The distance between the front wheels and the truck's center of gravity is 1.6 meters.
Given-
Scale reading value when the front wheels drive over the scale [tex]m_{1}[/tex] is 5800 N.
Scale reading value when the rear wheels drive over the scale [tex]m_{2}[/tex] is 6500 N
Distance between the front and rear wheel [tex]\bigtriangleup x[/tex] is 3.20 meters.
Let, the distance between the front wheels and the truck's center of gravity is [tex]x_{2}[/tex].
Since sum of the distance between front wheel to truck's center of gravity [tex]x_{1}[/tex], and rear wheel to truck's center of gravity [tex]x_{2}[/tex], is equal to the distance between the front and rear wheel [tex]\bigtriangleup x[/tex]. Therefore,
[tex]\bigtriangleup x=x_{1} +x_{2}[/tex]
[tex]3.20=x_{1} +x_{2}[/tex]
[tex]x_{1} =3.20-x_{2}[/tex]
For the distance between the front wheels and the truck's center of gravity is the formula of center of gravity can be written as,
[tex]x_{2} =\dfrac{m_{1}x_{1}+m_{2} x_{2} }{m_{1} +m_{2} }[/tex]
[tex]x_{2} =\dfrac{5800\times (3.20- x_{2})+6500\times x_{2} }{5800 +6500 }[/tex]
[tex]1230 x_{2} ={18560-5800 x_{2}+6500 x_{2} }[/tex]
[tex]x_{2}= 1.6[/tex]
Hence, the distance between the front wheels and the truck's center of gravity is 1.6 meters.
For more about the center of gravity, follow the link below-
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150 0.0000
2. Use the distance from the previous problem to calculate how long it takes for light to travel from the
Sun to Earth.
300,000,000X 15000,000,
Answer:
t = 5 10² s
Explanation:
Light is an electromagnetic wave that travels at a constant speed of 3 10⁸ m/s in vacuum.
The distance from the Sun to the Earth is 150 10⁶ km
Let's reduce the distance to the SI system
x = 150 10⁶ km (10³ m / 1 km) = 150 10⁹ m
Since the velocity is constant, we can use the uniform motion relations
v = x / t
t = x / v
let's calculate
t = 150 10⁹ / 3 10⁸
t = 5 10² s
(a) Which force is involved in kicking a ball?
i. frictional force
ii.gravity
iii. pushing force
iv. centrifugal force
An ideal spring is used to stop blocks as they slide along a table without friction. A 0.80 kg block traveling at a speed of 2.2 m/s can be stopped over a distance of 0.11 m once it makes contact with the spring.
A rectangular block on a level surface moves at velocity v to the right towards a spring that rests on the surface and is attached to a fixed mount on the right.
What distance would a 1.40 kg block travel after making contact with the spring if the block is traveling at a speed of 3.0 m/s before it makes contact with the spring?
Use the work-energy theorem: the total work done on the 0.80 kg block by the spring to make it come to a stop is equal to the change in the block's kinetic energy.
If we take the block's initial direction of motion to be positive, then the spring does negative work on the block, and
-1/2 k (0.11 m)² = 0 - 1/2 (0.80 kg) (2.2 m/s)²
Solve for the spring constant k :
k = (1/2 (0.80 kg) (2.2 m/s)²) / (1/2 (0.11 m)²) = 320 N/m
We can use the same equation as above to find the distance the 1.40 kg block would travel as it is slowed down by the same spring:
-1/2 (320 N/m) x ² = 0 - 1/2 (1.40 kg) (3.0 m/s)²
Solve for the displacement x :
x = √((1/2 (1.40 kg) (3.0 m/s)²) / (1/2 (320 N/m))) ≈ 0.20 m
You are on a train that is traveling at 3.0 m/s along a level straight track. Very near and parallel to the track is a wall that slopes upward at a 12 angle with the horizontal. As you face the window (0.90 m high, 2.0 m wide) in your compartment, the train is moving to the left, as the drawing indicates. The top edge of the wall first appears at window corner A and eventually disappears at window corner B. How much time passes between appearance and disappearance of the upper edge of the wall
Questions Diagram is attached below
Answer:
[tex]T=2.08s[/tex]
Explanation:
From the question we are told that:
Speed of Train [tex]V=3.0m.s[/tex]
Angle [tex]\theta=12\textdegree[/tex]
Height of window [tex]h_w=0.90m[/tex]
Width of window [tex]w_w=2.0m[/tex]
The Horizontal distance between B and A from Trigonometric Laws is mathematically given by
[tex]b=\frac{0.9}{tan12}[/tex]
[tex]b=4.23[/tex]
Therefore
Distance from A-A
[tex]d_a=2.0+4.23[/tex]
[tex]d_a=6.23[/tex]
Therefore
Time Required to travel trough d is mathematically given as
[tex]T=\frac{d_a}{v}[/tex]
[tex]T=\frac{6.23}{3}[/tex]
[tex]T=2.08s[/tex]
Which statement describe. good hypothesis ? Check all that apply
How do we get heat on Earth? Does thermal energy travel directly from the sun?
A wave with a frequency of 60 hertz would generate 60 wave crests every
Answer:
A wave with a frequency of 60 hertz will have 60 successive wave crests occurring every second
Explanation:
A crest is the highest point the medium rises to in a wave. That means that the crest is a point on the wave where the displacement is at a maximum.
Frequency is the number of oscillations of a wave in one second. Hence, frequency of a wave is the number of successive crests occurring in a second.
Therefore a wave with a frequency of 60 hertz will have 60 successive wave crests occurring every second.
What do we call air in the motion
Answer:
carbon d
Explanation:
Research indicates that social isolation tends to decrease aggressive behaviors.
Please select the best answer from the choices provided
True
False
Answer:
False
Explanation:
Just took the quiz
Answer:
false
Explanation:
How could extreme heat (resulting from Climate Change) affect human and
animal life?
Answer: See explanation
Explanation:
Climate change, is also referred to as global warming, and it simply means the rise in Earth's average surface temperature.
Effects of climate change include rising sea levels, heat waves, drought, storms, etc.
Extreme heat events is dangerous to the health of both animals and humans. For human beings, it can bring about increase in heat- related illness, weakness, heat stroke and excessive water consumption.
For animals, it can lead to struggling of the animals in losing their excess body heat by evaporation. Other effects include panting, loss of appetite, increased drinking, difficulty breathing, anxious behaviour, and weakness.
a 250 mH coil of negligible resistance is connected to an AC circuit in which as effective current of 5 mA is flowing. if the frequency is 850Hz, find the inductive reactance
Answer:
the inductive reactance of the coil is 1335.35 Ω
Explanation:
Given;
inductance of the coil, L = 250 mH = 0.25 H
effective current through the coil, I = 5 mA
frequency of the coil, f = 850 Hz
The inductive reactance of the coil is calculated as;
[tex]X_l = \omega L = 2\pi f L\\\\X_l = 2\pi \times 850 \times 0.25\\\\X_l = 1335.35 \ ohms[/tex]
Therefore, the inductive reactance of the coil is 1335.35 Ω
A car with a mass of 850kg is moving at a speed of 72km/h when colliding with a concrete wall until it stops. After the collision, the car travels 2.0m before stopping. Determine the resultant of the forces acting on the car.
Answer:
Explanation:
The vehicle is experiencing a large force created by the concrete wall.
Equation
vf^2 = vi^2 + 2*a * d
Givens
vf = 0 The car eventually does stop.
vi = 72 km/hr * [ 1000 m/ km] * [1 hour / 3600 seconds]
vi = 20 meters / second
a = ?
m = 850 kg
Solution
vf^2 = vi^2 + 2a*d
0 = 20 m/s + 2* 2 *a
-20 m/s = 4a
-20/4 = a
a = - 5 m/s^2 The minus sign tells you the vehicle is slowing down. It sure should be.
Force = m * a
F = - 850 * (-5)
F = - 4250 N
The car provides a 4250 N force on it going east to west and a 4250 N force going from west to east provided by the concrete wall.
They realize there is a thin film of oil on the surface of the puddle. If the index of refraction of the oil is 1.81, and they observe the reflected light in the air to be orange (wavelength of 600 nm), what is the thickness of the film of oil in nanometers? Give your answer with one decimal place please.
Answer:
The right solution is "165.8 nm".
Explanation:
Given:
Index of refraction,
n = 1.81
Wavelength,
λ = 600 nm
We know that,
⇒ [tex]t=\frac{\lambda}{2\times n}[/tex]
By putting the values, we get
[tex]=\frac{600}{2\times 1.81}[/tex]
[tex]=165.8 \ nm[/tex]
Imagine you are in a small boat on a small pond that has no inflow or outflow. If you take an anchor that was sitting on the floor of the boat and lower it over the side until it sits on the ground at the bottom of the pond, will the water level rise slightly, stay the same, or lower slightly
Answer:
The pond's water level will fall.
Explanation:
Archimedes principle explains that a floating body will displace the amount of water that weighs the same as it, whereas a body resting on the bottom of the water displaces the amount of water that is equal to the body's volume.
When the anchor is in the boat it is in the category of floating body and when it is on the bottom of the pond it is in the second category.
Since anchors are naturally heavy and denser than water, the amount of water displaced when the anchor is in the boat is greater than the amount of water displaced when the anchor is on the bottom of the pond since the way anchors are doesn't make for them to have considerable volume.
When the anchor is dropped to the bottom of the pond, the water level will therefore fall. If the anchor doesn't reach the bottom it is still in the floating object category and there will be no difference to the water level, but once it touches the bottom of the pond, the water level of the pond drops.
14) A magnetic force acts most strongly on a current carrying wire when it
A) carries a very large current.
B) is perpendicular to the magnetic field.
C) either or both of these
D) none of the above
omring wire the wire
Answer:
B) is perpendicular to the magnetic field
