A publishing house is selling subscriptions to magazines for 10% off the original price.
If a subscription to Time Magazine usually costs $50, how much will it cost on sale?
A) $5
B) $45
C) $42
D) $55.56

Answer:

21 cm²

21 square centimeters

Step-by-step explanation:

A = bh

A = 3 × 7

A = 21

Answer:

you swim 20inches and then you walk 50

Step-by-step explanation:

just because

Answer:  T=1700

Step-by-step explanation:

Answer:

4.6

Step-by-step explanation:

yes

Answer:

She must take a sample of 56.

Step-by-step explanation:

We have that to find our [tex]\alpha[/tex] level, that is the subtraction of 1 by the confidence interval divided by 2. So:

[tex]\alpha = \frac{1 - 0.95}{2} = 0.025[/tex]

Now, we have to find z in the Z-table as such z has a p-value of [tex]1 - \alpha[/tex].

That is z with a pvalue of [tex]1 - 0.025 = 0.975[/tex], so Z = 1.96.

Now, find the margin of error M as such

[tex]M = z\frac{\sigma}{\sqrt{n}}[/tex]

In which [tex]\sigma[/tex] is the standard deviation of the population and n is the size of the sample.

Standard deviation estimate of 1.90

This means that [tex]\sigma = 1.9[/tex]

Wow large a sample must she take if she wants the margin of error to be under 0.5 inch?

This is n for which M = 0.5. So

[tex]M = z\frac{\sigma}{\sqrt{n}}[/tex]

[tex]0.5 = 1.96\frac{1.9}{\sqrt{n}}[/tex]

[tex]0.5\sqrt{n} = 1.96*1.9[/tex]

[tex]\sqrt{n} = \frac{1.96*1.9}{0.5}[/tex]

[tex](\sqrt{n})^2 = (\frac{1.96*1.9}{0.5})^2[/tex]

[tex]n = 55.5[/tex]

Rounding up:

She must take a sample of 56.

Answer:48.013

Step-by-step explanation: just found it

Answer:

24

Step-by-step explanation:

betty age = 41 - 17

= 24

Answer:

160 units²

Step-by-step explanation:

Surface area of the square pyramid = a² + 2al

Where,

a = side length of the square = 8

l = slant height of the triangular face = 6

Plug in the values

Surface area of the square pyramid = 8² + 2*8*6

= 64 + 96

= 160 units²

Answer:

Factorizing 4x2 - 9y2, we get

(2x)2 - (3y)2, by using the identities of a2 - b2.

= (2x + 3y) (2x - 3y)

Step-by-step explanation:

=====================================================

Explanation:

We have n = 5 sides. This means the interior angles sum up to...

S = 180(n-2)

S = 180(5-2)

S = 180(3)

S = 540

All five interior angles of this pentagon add up to 540 degrees.

Answer:

-27

Hope this helped in anyway

Answer:

the answer to this is -27.

the answer is [tex]x^{2} \sqrt{x} \leq \geq \lim_{n \to \infty} a_n \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \pi x^{2} \sqrt{x} \frac{x}{y} \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \left \{ {{y=2} \atop {x=2}} \right.[/tex]random but marter than einstein

Answer:

32 Years, 7 Months, 2 Days old

Step-by-step explanation:

Answer:

2590.33

Step-by-step explanation:

...............

it wouldnt let me type the answer-

Answer:

Directions: Write the new coordinates for each point or figure.

Sample Question:

Point F has the coordinates (-9,6). What are the coordinates of its image point after the translation of six units down and three units to the left?

Answer:

The coordinates of its image point after the translation are (-12, 0).

Explanation: When you look at an ordered pair the x number comes first, followed by the y number (x,y). Moving a point left or right changes the x number. Moving a point up or down changes the y number. Left and down require subtraction, while right and up require addition. In the sample, we had to go 3 units to the left, -9 - 3 = -12. We also had to go 6 units down, so 6 - 6 = 0.

Point Q has the coordinates (9,5). What are the coordinates of its image point after a translation of six units up and three units to the right?

Point P has the coordinates (3,4). What are the coordinates of its image point after a translation of 8 units down and 5 units to the left?

Point Z has the coordinates (10,7). What are the coordinates of its image point after a translation of six units down and three units to the right?

Point Y has the coordinates (0,-4). What are the coordinates of its image point after a translation of 10 units up and 3 units to the left?

Point X has the coordinates (3,-8). What are the coordinates of its image points after a translation of 11 units down and 10 units to the right?

Answer:

(-10,5)

Step-by-step explanation:

9514 1404 393

Answer:

  $80

Step-by-step explanation:

You are given the formula ...

  P = I/(rt)

and the values I = 20, r = 0.05, t = 5.

Put the numbers in place of the corresponding variables and do the arithmetic.

  P = 20/(0.05·5) = 20/0.25 = 80

The amount $80 will generate $20 in interest over 5 years at 5% per year.

Answer:

option C

Step-by-step explanation:

[tex]distance = \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2}[/tex]

              [tex]=\sqrt{(-4-2)^2+(15-7)^2} \\\\=\sqrt{(-6)^2 + 8^2}\\\\=\sqrt{36 + 64 }\\\\= \sqrt{100} \\\\= 10[/tex]

Answer:

2nd option:

8x+2y=32

x+y=7

Step-by-step explanation:

Answer:

It is in fact the second one.

Step-by-step explanation:

It says that he bought a total of 7 tickets and it cost $32.

x represents the number of adult tickets and y represents the number of chid tickets.

So:

x + y = 7 because the adding the number of adult and child tickets should equal the total number bought.

and

8x + 2y = 32 because each adult ticket was 8 dollars and each child was 2 and the total should add up to 32

Answer:

[tex]A_{\Delta ABP}=\sin \theta[/tex]

Step-by-step explanation:

Let the center of the circle be O.

Recall that the area of a triangle can be given by:

[tex]\displaystyle A=\frac{1}{2} ab\sin C[/tex]

Where C is the angle between the two sides.

ΔABP is equal to the sum of ΔAPO and ΔBOP.

Let a = OP and b = OB. Since this is the unit circle and PO and BO are radii, they both equal one. C will be θ. Hence, the area of ΔBOP is:

[tex]\displaystyle A_{\Delta BOP}=\frac{1}{2}(1)(1)\sin \theta=\frac{1}{2}\sin\theta[/tex]

For ΔAPO, we can use the two sides OP and OA. Again, they are the radii of the unit circle, so they equal one. The angle in this case will be π - θ radians. Hence:

[tex]\displaystyle A_{\Delta APO}=\frac{1}{2}(1)(1)\sin\left(\pi -\theta\right)=\frac{1}{2}\sin\left(\pi -\theta\right)[/tex]

However, note that sin(π - θ) = sin(θ). Hence:

[tex]\displaystyle A_{\Delta APO}=\frac{1}{2}\sin\left(\theta\right)[/tex]

Hence, the area of ΔABP is:

[tex]\displaystyle A_{\Delta ABP}=\frac{1}{2}\sin \theta+\frac{1}{2}\sin\theta =\sin \theta[/tex]

Answer:

X = -6 - 3y

Y = -1

Step-by-step explanation: Solve for X first using basic algebra. Plug in X vaalue to original equation and solve. -6 - 3y + 3y = -6. Solve by adding 6 to both sides of the equation and dividing -3y by 3y.

Answer:

22.5

Step-by-step explanation:

Inscribed Angle =1/2 Intercepted Arc

F = 1/2 (45)

<F = 22.5

Answer:

01:04

Step-by-step explanation:

add 7 minutes to 22:57 to get 23:04. then add 2 hours to get to 01:04.

Answer:

1

Step-by-step explanation:

Answer:

She didn't put the sign's in the proper place, it should be ( x + 3 ) ( x - 7 )

Step-by-step explanation:

( x - 3 ) ( x + 7 ) = x² + 7x - 3x - 21 = x² + 4x - 21

( x + 3 ) ( x - 7 ) = x² - 7x + 3x - 21 = x² - 4x - 21

Answer:

See Below.

Step-by-step explanation:

Problem A)

We have:

[tex]\displaystyle \csc^2\theta \tan^2\theta -1=\tan^2\theta[/tex]

When in doubt, convert all reciprocal trig functions and tangent into terms of sine and cosine.

So, let cscθ = 1/sinθ and tanθ = sinθ/cosθ. Hence:

[tex]\displaystyle \left(\frac{1}{\sin^2\theta}\right)\left(\frac{\sin^2\theta}{\cos^2\theta}\right)-1=\tan^2\theta[/tex]

Cancel:

[tex]\displaystyle \frac{1}{\cos^2\theta}-1=\tan^2\theta[/tex]

Let 1/cosθ = secθ:

[tex]\sec^2\theta -1=\tan^2\theta[/tex]

From the Pythagorean Identity, we know that tan²θ + 1 = sec²θ. Hence, sec²θ - 1 = tan²θ:

[tex]\tan^2\theta =\tan^2\theta[/tex]

Problem B)

We have:

[tex]\sin^3x=\sin x-\sin x \cos^2 x[/tex]

Factor out a sine:

[tex]\sin x(\sin^2 x)=\sin x-\sin x\cos^2 x[/tex]

From the Pythagorean Identity, sin²θ + cos²θ = 1. Hence, sin²θ = 1 - cos²θ:

[tex]\sin x(1-\cos^2 x)=\sin x-\sin x\cos^2x[/tex]

Distribute:

[tex]\sin x- \sin x \cos^2 x=\sin x-\sin x\cos^2 x[/tex]

Problem C)

We have:

[tex]\displaystyle \frac{\cos 2x+1}{\sin 2x}=\cot x[/tex]

Recall that cos2θ = cos²θ - sin²θ and that sin2θ = 2sinθcosθ. Hence:

[tex]\displaystyle \frac{\cos^2 x-\sin^2 x+1}{2\sin x\cos x}=\cot x[/tex]

From the Pythagorean Identity, sin²θ + cos²θ = 1 so cos²θ = 1 - sin²θ:

[tex]\displaystyle \frac{2\cos^2 x}{2\sin x\cos x}=\cot x[/tex]

Cancel:

[tex]\displaystyle \frac{\cos x}{\sin x}=\cot x[/tex]

By definition:

[tex]\cot x = \cot x[/tex]

Answer:

16

Step-by-step explanation:

8/1/2

8 divided by 1/2

8 x 2/1 = 16

Answer:

Step-by-step explanation:

P=8/V

1/2=8/V

do cross multiplication

2*8=V*1

16=V