A 59.0 mL portion of a 1.80 M solution is diluted to a total volume of 258 mL. A 129 mL portion of that solution is diluted by adding 183 mL of water. What is the final concentration
Answer:
0.170 M
Explanation:
As this is a series of dilutions, we can continuosly use the C₁V₁=C₂V₂ formula to solve this problem:
For the first step:
59.0 mL * 1.80 M = 258 mL * C₂C₂ = 0.412 MThen for when 129 mL of that 0.412 M are diluted by adding 183 mL of water:
V₂ = 129 mL + 183 mL = 312 mLUsing C₁V₁=C₂V₂:
129 mL * 0.412 M = 312 mL * C₂C₂ = 0.170 M1. An ion has a net charge of - 3, and 12 electrons, what is its atomic number? What element has that atomic number?
2. An ion of Celsius has a net charge of -5, how many electrons does it have?
3. Some atom has an atomic number of 46, how many electrons does it have if it has a net charge of +2?
4. How many neutrons are in an atom of Helium, and what is its mass number?
5. There are 3 neutrons in an isotope of Helium, what is its mass number?
6. n isotope has 83 neutrons and a mass number of 167, what is its atomic number? What element is defined by that atomic number?
7. What element has 54 neutrons and a mass number of 112?
8. What element has 10 electrons, a net charge of -2?
Answer:
19 because it gained 3 electron so 12-3=9 beryllium
2
3 is 46-2=44
4 is 2
5 is 5
6 84 polonium
7
8 oxygen
Explanation:
plz let me know if they are right or wrong:)
. Which is instinctive behavior? A. A puppy cuddling its human owner.C. A young child learned how to read. B. A duckling swimming after its mother.D. A kitten learning to use a litter box.
Answer:
A duckling swimming after its own mother
Explanation:
How many grams of 02 are present in 7.49 L of oxygen gas?
Answer:
10.70grams
Explanation:
Density of a substance = mass/volume
At STP of a gas (standard temperature and pressure), the density of oxygen gas is 1.429 g/L
Hence, according to this question, in 7.49 L of oxygen gas, there would be:
Using D = m/V
1.429 = m/7.49
m = 1.429g/L × 7.49L
m = 10.70g
A 100.0 mL sample of natural water was titrated with NaOH. The titration required 14.53 mL of 0.1031 M NaOH solution to reach a light pink phenolphthalein end point.
Calculate the number of millimoles of NaOH required for the titration.
Answer:
The correct answer is 1.498.
Explanation:
Based on the given information, the volume of NaOH needed for the titration is 14.53 ml, and the concentration of NaOH given is 0.1031 M.
The volume of NaOH, that is, 14.53 ml can also be written as 14.53 × 10⁻³ L.
The concentration of NaOH, that is, 0.1031 M can also be written as 0.1031 moles/Litre.
Molarity (M) is determined as,
M = No of moles/Volume in litres
No of moles = Molarity × Litres
No of moles = 0.1031 moles/Litres × 14.53 × 10⁻³ L
No of moles = 1.498 × 10⁻³ L
Now, number of millimoles = 1.498 × 10⁻³ L × 1000 (millimoles = moles × 1000)
Number of millimoles = 1.498
The number of millimoles of NaOH required for the titration is 1.50 mmol
From the question,
We are to determine the number of millimoles of NaOH required for the titration
From the given information
The titration required 14.53 mL of 0.1031 M NaOH solution
From the formula
Number of moles = Concentration × Volume
Concentration of the NaOH = 0.1031 M
Volume of the NaOH = 14.53 mL
∴ Number of millimoles of NaOH required = 0.1031 × 14.53
Number of millimoles of NaOH required = 1.498043 mmol
Number of millimoles of NaOH required ≅ 1.50 mmol
Hence, the number of millimoles of NaOH required for the titration is 1.50 mmol
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A solution has a pH of 2.5. what is the H+
Answer: The concentration of [tex]H^+[/tex] in the solution is [tex]3.16\times 10^{-3}M[/tex]
Explanation:
pH is defined as the negative logarithm of hydrogen ion concentration present in the solution.
[tex]pH=-\log [H^+][/tex] .....(1)
We are given:
pH of solution = 2.5
Putting values in equation 1, we get:
[tex]2.5=-\log [H^+][/tex]
[tex][H^+]=10^{-2.5}[/tex]
[tex][H^+]=3.16\times 10^{-3}M[/tex]
Hence, the concentration of [tex]H^+[/tex] in the solution is [tex]3.16\times 10^{-3}M[/tex]
What mass of sodium hydroxide is needed to make 12.5 L of a 0.150M solution?
a) 1.88g
b) 40.0g
c) 75.0g
d) 83.0g
Answer:
75g
Explanation:
n=Cmxv
=0,15x12,5
=1,875 mol
m=nxM
=1,875x40
=75g
When aqueous solutions of AgNO3 and MgCl2 are mixed, a precipitate forms. What is the correct formula for the precipitate
Answer:
AgCl
Explanation:
The reaction that takes place is:
2AgNO₃ (aq) + MgCl₂ (aq) → Mg(NO₃) (aq) + 2AgCl (s)The precipitate (meaning a solid substance) formed is silver chloride, AgCl.
All salts formed with silver and a halogen (F, Cl, Br, I) are insoluble in water, meaning that when working with aqueous solutions they will be precipitates.
Provide the IUPAC names for
the following structures
CH2CH3
w
CH2CH:
(b) H-C-N
CH.CH
H-EN
N
H
(c)
OCH2CH3
Answer:
For a: The IUPAC name of the compound is N-ethylethaneamide.
For b: The IUPAC name of the compound is N,N-diethylmethaneamide.
For c: The IUPAC name of the compound is ethyl pentanoate
Explanation:
To name a compound, first look for the longest possible carbon chain.
For a:Amide group is a type of functional group where an amine group is attached to a carbonyl group. The general formula of amide is [tex]R-CO-NH_2[/tex], where R is an alkyl or aryl group.
In part (a), the alkyl group has 2 carbon atoms and thus, the prefix used is 'eth-'
Also, an ethyl substituent is directly attached to N-atom. It is an alkane structured hydrocarbon thus, the suffix used will be '-ane'
Hence, the IUPAC name of the compound is N-ethylethaneamide.
For b:Amide group is a type of functional group where an amine group is attached to a carbonyl group. The general formula of amide is [tex]R-CO-NH_2[/tex], where R is an alkyl or aryl group.
In part (b), the alkyl group has 1 carbon atoms and thus, the prefix used is 'meth-'
Also, two ethyl substituents are directly attached to N-atom. It is an alkane structured hydrocarbon thus, the suffix used will be '-ane'
Hence, the IUPAC name of the compound is N,N-diethylmethaneamide.
For c:Esters are a kind of organic molecules having functional groups, [tex]R-COO-R'[/tex] where R and R' are the alkyl or aryl groups. They are formed by the combination of alcohol and carboxylic acid.
These functional group compounds are named in two words which is alkyl alkanoates, where alkyl refers to the alcoholic part and alkanoate refers to the carboxylic acid part of the molecule. The numbering of the parent chain in esters is done from the carboxylic carbon. The alkyl part is not given any numbers.
In part (c), there are 5 carbon atoms present in a straight chain and thus, the prefix used is 'pent-'
Also, an ethyl group forms the alcoholic part.
Hence, the IUPAC name of the compound is ethyl pentanoate
Given that vat contains 9600 kg of milk, what is the mass of mg of the milk that vat contains?
Answer:
9.6x10⁹ mg
Explanation:
In order to solve this problem we need to convert 9600 kg into mg.
First we convert 9600 kg into g, keeping in mind that 1 kg = 1000 g:
9600 kg * [tex]\frac{1000g}{1kg}[/tex] = 9.6x10⁶ g
Then we convert 9.6x10⁶ g into mg, keeping in mind that 1 g = 1000 mg:
9.6x10⁶ g * [tex]\frac{1000mg}{1g}[/tex] = 9.6x10⁹ mg
The mass of milk miligrams is 9.6x10⁹.
Gasoline and motor oil are chemically similar. They are both mixtures of nonpolar hydrocarbons
containing carbon and hydrogen atoms. However, motor oil is much more viscous than gasoline. Which
substance probably has the higher average molar mass?
Answer:
motor oil
Explanation:
According to Oxford dictionary, viscosity refers to ''a quantity expressing the magnitude of internal friction in a fluid, as measured by the force per unit area resisting uniform flow.''
The higher the molecular weight of a substance, the greater its viscosity. This is because, the long chains in the viscous substance become entangled thereby increasing the internal friction in the liquid.
Motor oil is a heavier hydrocarbon than gasoline hence it is more viscous than gasoline.
Answer:
Motor oil
Heat it
Water
Explanation:
The pH of the ocean is 8.1. What is the concentration of hydronium ions?
Answer:
7.9 × 10⁻⁹ M
Explanation:
Step 1: Given data
pH of the ocean: 8.1
Step 2: Calculate the concentration of hydronium ions
We will use the definition of pH.
pH = -log [H⁺] = -log [H₃O⁺]
[H₃O⁺] = [H⁺] = antilog -pH
[H₃O⁺] = antilog -8.1 = 7.9 × 10⁻⁹ M
Since [H₃O⁺] < 10⁻⁷ M, the solution is basic.
How many molecules are in 4.44 mol of CF4? 4.44 mol CF4 =
I am not sure abt the ans
molar mass= 88
1 molecule = 6.022×10^23
4.44 moles = 6.022×10^23×4.44/88
= 26.73768 × 10^23/88
= 0.3038372727 ×10^23
Which example shows a double replacement reaction?
Answer:
KCl + AgNO₃ —> AgCl + KNO₃
Explanation:
To answer the question correctly, we must understand the definition of a double displacement reaction.
A double displacement reaction is a reaction in which the ions of the two reacting compounds exchange to form new compounds different from the two reacting compounds. Example is given below:
XY + AB —> XB + AY
Considering the options given in the question above, only the equation:
KCl + AgNO₃ —> AgCl + KNO₃
Satisfy the definition of a double displacement reaction.
Define solubility. the amount of a substance that will dissolve in a given amount of solvent a solid mixed with another solid a liquid that does not dissolve in another liquid the amount of a substance that will dissolve in a given amount of solute a solid that does not dissolve in a gas
Answer:
You answered your own question
The solubility of a substance is the amount of the substance that can be dissolved in a given amount of solvent at a specified temperature. Hence, option A is correct.
What is solubility ?Solubility of a substance can be defined as the fraction of concentration of the substance which can be dissolved in a particular amount of a solvent at a specified temperature.
Solubility of a substance depends on the bond type, temperature, pressure and presence of impurities if any. If the bond strength is greater, less will be the solubility because, greater energy is needed to weaken the bonds in the salt.
Similarly, for most of the salts, as the temperature increases, solubility increases, but some salt's solubility is independent of the temperature such as for NaCl. Therefore, the correct definition of solubility is option A.
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Which additional product balances the reaction h2so4+2naoh>na2so4
Answer:
H 4so8 is the answer of balance the reaction
what will happen to the initial rate of the reaction if the concentration of iron(III) chloride is tripled
Answer:
Concentration and reaction rate is directly proportional
Explanation:
Basically, concentration is directly proportional to the concentration, so the higher the concentration, the higher the reaction rate.
Once the concentration is increased, more chemical will be added hence the reaction rate will increase
g Draw the most stable chair conformation for each of the following compounds (a) Cis-1-ethyl-2-methyl cyclohexane (b) Trans-1-ethyl-2-methyl cyclohexane (c) Which one is more stable, a or b
Answer:
See explanation
Explanation:
Image 1 is the chair conformation of trans-1-ethyl-2-methyl cyclohexane while image 2 is the chair conformation of Cis-1-ethyl-2-methyl cyclohexane.
Now let us look at the two structures closely. In the chair conformation, the more stable structure is the structure that has the bulky groups placed in the equatorial position.
Clearly, in trans-1-ethyl-2-methylcyclohexane, the ethyl and methyl groups are found to be in equatorial positions. Hence, trans-1-ethyl-2-methylcyclohexane is more stable in the chair conformation than cis-1-ethyl-2-methyl cyclohexane which has its methyl and ethyl groups in axial position.
Why should a science teacher know how to prepare stock solution
Answer:
because they were thought in college
Explanation:
hope that helps
Which of the following is most likely to make a -3 ion?
Bі
P
Se
Be
All
The element whose atom may likely make a -3 ion is P.
Elements in the periodic table are classified into groups and periods. The elements in the same group have similar physical and chemical properties.
Phosphorus (P) is a member of group 15 in the periodic table. The most common ion formed by the members of this group is the -3 ion.
It is formed by accepting three electrons to complete their octet since they have five electrons on their outermost shell.
Hence P is most likely to form a -3 ion.
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What is the pH of a 0.086 M HCl solution?
Answer: pH = 1.066
Explanation: HCl is strong acid and it protolyzes totally:
HCl + H2O ⇒ H3O+ + Cl-
Concentrations are same: [H3O+] = c(HCl)
pH = - log[H3O+] = - log(0.086) = 1.0655
grams of sodium 9.5g in NaCl
Answer:
3.68 grams.
Explanation:
First we convert 9.5 g of NaCl into moles of NaCl, using its molar mass:
9.5 g ÷ 58.44 g/mol = 0.16 mol NaCl
In 0.16 moles of NaCl there are 0.16 moles of sodium as well.
We now convert 0.16 moles of sodium into grams, using sodium's molar mass:
0.16 mol * 23 g/mol = 3.68 g
Carbon 14 and carbon 12 are both isotopes of the element carbon check all answers that are true about them
Answer:
CARBON 14 INCLUDES:
-six protons
-eight neutrons in the nucleus
CARBON 12 INCLUDES:
-six protons
-Six neutrons
Calculate the number of cations and anions in each of the following compounds. Enter your answers in scientific notation. (a) 6.42 g of KBr:
Answer: The number of cations are [tex]3.24 \times 10^{22}[/tex] and number of anions are [tex]3.24 \times 10^{22}[/tex] in 6.42 g of KBr.
Explanation:
The molar mass of KBr is (39.10 + 79.90) g/mol = 119.00 g/mol
Now, the dissociation equation for KBr is as follows.
[tex]KBr \rightarrow K^{+} + Br^{-}[/tex]
This means that 1 mole of KBr is forming 1 mole of [tex]K^{+}[/tex] (cation) and 1 mole of [tex]Br^{-}[/tex] (anion).
According to mole concept, 1 mole of every substance contains [tex]6.022 \times 10^{23}[/tex] atoms. Hence, number of cations present in 6.42 g KBr is calculated as follows.
[tex]No. of cations = Moles \times 6.022 \times 10^{23}\\= \frac{mass}{molar mass} \times 6.022 \times 10^{23}\\= \frac{6.42 g}{119.00 g/mol} \times 6.022 \times 10^{23}\\= 3.24 \times 10^{22}[/tex]
As according to the equation, there are equal number of moles of both cation and anions.
This means that the number of anions are also [tex]3.24 \times 10^{22}[/tex].
Thus, we can conclude that the number of cations are [tex]3.24 \times 10^{22}[/tex] and number of anions are [tex]3.24 \times 10^{22}[/tex] in 6.42 g of KBr.
The number of cations and anions present in potassium bromide is 3.24 × 10²².
How we calculate atoms from moles?In one mole of any substance 6.022 × 10²³ atoms of that substance is present and this is known as Avogadro's number.
KBr is a strong electrolyte means it fully dissociates into their constitute ions. So, the number of moles of produced ions is equal to the moles of KBr and dissociation is represented as:
KBr → K⁺ + Br⁻
From this it is clear that 1 mole of cation and 1 mole of anion is produced from 1 mole of KBr. Moles of KBr will be calculated as:
n = W/M, where
W = given mass = 6.42g
M = molar mass = 119
n = 6.42 / 119 = 0.053 moles
No. of cations and anions present in 0.053 moles = 0.053 × 6.022 × 10²³ = 3.24 × 10²².
Hence, 3.24 × 10²² is the no. of cations and anions.
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You are working on a project where you need the volume of a box. You take the length, height, and width measurements and then multiply the values together to find the volume. You re- port the volume of the box as 0.310 ml. If two of your mea- surements were 0.7120 m and 0.52458 m, what was the other measurement?
Answer and Explanation:
If we remember from school, we should know that the equation for finding the volume of a box (rectangular) is length times width times height.
Since we know the volume, we can divide the two sides given from the volume to find the remaining side.
0.310 ÷ 0.7120 ÷ 0.52458 = 0.83
The answer is 0.83 for the remaining side measurement.
#teamtrees #PAW (Plant And Water)
Answer:
The answer is: 0.82998448
Explanation:
If you multiply 0.7120 × 0.52458, it will equal: 0.37350096.
if you divide 0.310 ÷ 0.37350096, you will get 0.82998448.
Hope it helps!!
(also, i don't want to be "that" person, but brainliest would be apreciated!)
how do i convert 145.6grams of Iron sulphide into iron and sulfur
A diamond can make permanent marks on glass. It can also cut glass. Most other materſals cannot do this.Which property of a diamond allows it to make cuts or marks on glass? a. Hardness b. Heaviness c. Roughness d. transparency
Calculate the pH of a buffer solution prepared by mixing 75.0 mL of 1.25 M lactic acid and 40.0 mL of 0.75 M sodium lactate. (The pKa for lactic acid is 3.86. The molar mass for lactic acid is 90.1 g/mol and the molar mass for sodium lactate is 112.1 g/mol.)
Answer:
pH = 3.37
Explanation:
A weak acid as lactic acid in a solution with sodium lactate (Its conjugate base) produce a buffer. The pH of this buffer is obtained using H-H equation:
pH = pKa + log [A-] / [HA]
Where pH is the pH of the buffer,
pKa is 3.86
And [] could be taken as the moles of A- = Sodium lactate and HA = Lactic acid.
Moles A-:
40.0mL = 0.0400L * (0.75mol / L) = 0.030 moles A-
Moles HA:
75.0mL = 0.0750L * (1.25mol / L) = 0.09375 moles HA
Replacing:
pH = 3.86+ log [0.030 moles A-] / [0.09375 moles HA]
pH = 3.37
PLEASE HELP NEED IT ASAP
A solution has a [H3O+] of 1 × 10−3 M. What is the [OH−] of the solution?
11 M
14 M
1 × 10−14 M
1 × 10−11 M
Answer:
1 × 10−11 M
Explanation:
I took the test :) guy above me is right
Show the complete ionic equation and net ionic equation for all the equations below, then state whether or not a precipitate (insoluble compound) will form. To receive full credit, you must show ALL your work.
Cacl2(aq) + K2co3(aq) + -------->
Bacl2(aq) + MgSO4(aq) + -------->
AgNO3(aq) + Kl(aq) →
Nacl(aq) + (NH4)2Cro4(aq) →
Answer:
(a): Precipitate of calcium carbonate will form.
(b): Precipitate of barium sulfate will form.
(c): Precipitate of silver iodide will form.
(d): Precipitate of sodium chromate will form.
Explanation:
Complete ionic equation is defined as the equation in which all the substances that are strong electrolytes present in an aqueous state and are represented in the form of ions.
Net ionic equation is defined as the equations in which spectator ions are not included.
Spectator ions are the ones that are present equally on the reactant and product sides. They do not participate in the reaction.
(a):
The balanced molecular equation is:
[tex]CaCl_2(aq)+K_2CO_3(aq)\rightarrow 2KCl(aq)+CaCO_3(s)[/tex]
The complete ionic equation follows:
[tex]Ca^{2+}(aq)+2Cl^-(aq)+2K^+(aq)+CO_3^{2-}(aq)\rightarrow 2K^+(aq)+2Cl^-(aq)+CaCO_3(s)[/tex]
As potassium and chloride ions are present on both sides of the reaction. Thus, they are considered spectator ions.
The net ionic equation follows:
[tex]Ca^{2+}(aq)+CO_3^{2-}(aq)\rightarrow CaCO_3(s)[/tex]
Precipitate of calcium carbonate will form.
(b)
The balanced molecular equation is:
[tex]BaCl_2(aq)+MgSO_4(aq)\rightarrow MgCl_2(aq)+BaSO_4(s)[/tex]
The complete ionic equation follows:
[tex]Ba^{2+}(aq)+2Cl^-(aq)+Mg^{2+}(aq)+SO_4^{2-}(aq)\rightarrow Mg^{2+}(aq)+2Cl^-(aq)+BaSO_4(s)[/tex]
As magnesium and chloride ions are present on both sides of the reaction. Thus, they are considered spectator ions.
The net ionic equation follows:
[tex]Ba^{2+}(aq)+SO_4^{2-}(aq)\rightarrow BaSO_4(s)[/tex]
Precipitate of barium sulfate will form.
(c):
The balanced molecular equation is:
[tex]AgNO_3(aq)+KI(aq)\rightarrow KNO_3(aq)+AgI(s)[/tex]
The complete ionic equation follows:
[tex]Ag^{+}(aq)+NO_3^-(aq)+K^+(aq)+I^{-}(aq)\rightarrow K^+(aq)+NO_3^-(aq)+AgI(s)[/tex]
As potassium and nitrate ions are present on both sides of the reaction. Thus, they are considered spectator ions.
The net ionic equation follows:
[tex]Ag^{+}(aq)+I^{-}(aq)\rightarrow AgI(s)[/tex]
Precipitate of silver iodide will form.
(d):
The balanced molecular equation is:
[tex]2NaCl(aq)+(NH_4)_2CrO_4(aq)\rightarrow 2NH_4Cl(aq)+Na_2CrO_4(s)[/tex]
The complete ionic equation follows:
[tex]2Na^{+}(aq)+2Cl^-(aq)+2NH_4^+(aq)+CrO_4^{2-}(aq)\rightarrow 2NH_4^+(aq)+2Cl^-(aq)+Na_2CrO_4(s)[/tex]
As ammonium and chloride ions are present on both sides of the reaction. Thus, they are considered spectator ions.
The net ionic equation follows:
[tex]2Na^{+}(aq)+CrO_4^{2-}(aq)\rightarrow Na_2CrO_4(s)[/tex]
Precipitate of sodium chromate will form.
