Gregory knows that ABC is reflected onto A'B'C. Which statement about the figures is true? Olf Gregory draws the segment with endpoints A and A', then the midpoint will lie on the line of reflection O If Gregory draws the segment with endpoints B and C', then the midpoint will be on the line of reflection O Points A and B are equidistant from the line of reflection O AB will be perpendicular to the line of reflection​

Answers

Answer 1

The true statement about the reflection is (a) If Gregory draws the segment with endpoints A and A’, then the midpoint will lie on the line of reflection.

When a shape is reflected, it must be reflected across a line (called the line of reflection)

The line of reflection is always located at a point equidistant to the image and the pre-image of the shape that is being reflected

Hence, the true statement is (a) If Gregory draws the segment with endpoints A and A’, then the midpoint will lie on the line of reflection.

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Answer 2

Answer:

a

Step-by-step explanation:

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Related Questions

how can u stand applying math to every thing doesn't it make every thing repetitive and why does every thing need a pattern doesn't that just make every thing worthless cause what's the point if every thing repeats and no this is not about history

Answers

Because math sucks like really really sucks

The roots of [tex]10x^2-14x+k[/tex] are sin a and cos a for some real value of a. Compute k.

Answers

Answer:

10

Step-by-step explanation:

10x²-14x+k = 0

x1 = sin a

x2= cos a

x1+x2 ≤ 2

x1. x2 ≤ 1 => k/10 ≤ 1

k ≤ 10

so the value of k should be 10

In your biology class, your final grade is based on several things: a lab score, scores on two major tests, and your score on the final exam. There are 100 points available for each score. However, the lab score is worth 21% of your total grade, each major test is worth 23%, and the final exam is worth 33%. Compute the weighted average for the following scores: 70 on the lab, 99 on the first major test, 91 on the second major test, and 90 on the final exam

Answers

70(0.21) + 99(0.23) + 91(0.23) + 90(0.33)
= 14.7 + 22.77 + 20.93 + 29.7
= 88.1%

What is the value of Y if x=1

Answers

Answer:

y=6

the first equation:

3(1)+y=9

3+y=9

y=6

the second equation:

y= -4(1)+10

y= -4+10

y=6

I hope this helped! :)

how far does the train travel if it is doing 65km/h during a time of 95 minutes ? give your answer in kilometers and then in meters​

Answers

9514 1404 393

Answer:

  102 11/12 km ≈ 102.917 km

  102,916 2/3 m ≈ 102,917 m

Step-by-step explanation:

1 minute is 1/60 of an hour, so 95 minutes is 95/60 hours = 19/12 hours.

Distance is the product of speed and time, so ...

  distance = (65 km/h)(19/12 h) = 1235/12 km = 102 11/12 km ≈ 102.917 km

__

Each kilometer is 1000 meters, so this distance is ...

  (102.917 km) × (1000 m/km) = 102,917 m

Following a strategy of product differentiation, Westwood Corporation (W) makes a high-end kitchen range hood, KE8. W’s data for 2012 and 2013 follow on the next slide.In 2013, W produced no defective units and reduced direct materials usage per unit of KE8. Conversion costs in each year are tied to manufacturing capacity. Selling and customer service costs are related to the number of customers that the functions are designed to support. W has 23 customers (wholesalers) in 2012 and 25 customers in 2013.

Units of KE8 produced and sold 40,000 42,000
Selling Price $100 $110
Direct Materials (sq ft) 120,000 123,000
DM cost per sq ft $10 $11
Manufacturing capacity for KE 850,000units 50,000units
Conversion Costs $1,000,000 $1,100,000
CC per unit $20 $22
Selling & Customer Service capacity 30customers 29customers
Selling & Customer Service Costs$720,000 $725,000
Cost per customer$24,000 $25,000
Required:
(1) Describe elements you would expect to see in W’s BSC.
(2)Calculate the growth, price recovery and productivity components that explain the change in the 2012 to 2013 income. Can you use the worksheet to get the variances?(3) Suppose during 2013, the market size for high-end rangehoods grew 3% and all increases in market share are due to W’s product differentiation strategy. How much of the change in OI is due to the industry market size factor, cost leadership and product differentiation?
(4) How successful was the strategy implementation?

Answers

A I seen it on the test

please answer thank you ​

Answers

Answer:

6.

sin 26=opposite/hypotenuse

sin26=22/x

x=22/sin26

x=50.19

x=50.2

Standard form 6,000,000+900,000+80,000+9,000+500+80+2

Answers

Answer:

6.989582×10^-6

Step-by-step explanation:

6,000,000+900,000+80,000+9,000+500+80+2

=6989582

=6.989582×10^-6

Please help a homie out

Answers

Answer:

TUW=VUW

Step-by-step explanation:

Answer:

Option 3: Angle TUV = angle VUW

Step-by-step explanation:

Graph the inequality 7≤ y -3x < 11

Answers

Answer:

1

Step-by-step explanation:

9 x (-3) + (-15) ÷ 3

Answers

Answer:

-32

Step-by-step explanation:

9(-3) + (-15) ÷ 3 =

-27 + -5 = -32

If my answer is incorrect, pls correct me!

If you like my answer and explanation, mark me as brainliest!

-Chetan K

Answer:-32

Step-by-step explanation:

solve the following
2x+6 = 7x-14

Answers

Answer:

x=4 :)))))))))

Step-by-step explanation:

"-+_$-5_(#-3(

Answer:

x = 4

Step-by-step explanation:

2x + 6 = 7x - 14

2x + 6 - 2x + 14 = 7x - 14 - 2x + 14 ----> To put the variables on one side and the numbers on the other side

20 = 5x --> Simplifying

x = 20/5 --> Flipping the equation and then dividing 5 on both sides

x = 4 --> Simplifying

Hope this helps explain! <3

Evaluate: 2^-4=
A1/8
B-16
C1/16
D-8

Answers

Answer:

C) 1/16

Step-by-step explanation:

2*2*2*2=16

Therefore, 2^(-4)=1/16.

Answer:

C) [tex]\frac{1}{16}[/tex]

Step-by-step explanation:

2⁻⁴

2⁴ = 2 × 2 × 2 × 2 = 16

[tex]\frac{1}{16}[/tex]



Work out the following calculations and give your answers to the nearest 1000
a) 251 x 638

Answers

It’s 160,130 nearest 100 is 160,200

Answer:

160,000

Step-by-step explanation:

                   251

                × 638

     _______________

                2008

                753

    +       1506

__________________

            160138

Product to the  nearest thousand = 160,000            

Which angle is NOT coterminal with 110 degrees
-250degrees
480degrees
-110 degrees
830 degrees

Answers

830 degrees for sureee

3. Suppose college faculty members with the rank of professor at two-year institutions earn an average of $52,500 per year with a standard deviation of $4,000. In an attempt to verify this salary level, a random sample of 60 professors was selected from a personnel database for all two-year institutions in the United States. A. What are the mean and standard deviation of the sampling distribution for n

Answers

Answer:

The right answer is "516.3978".

Step-by-step explanation:

Given:

Sample mean,

[tex]\mu=52500[/tex]

Standard deviation,

[tex]\sigma=4000[/tex]

Random sample,

[tex]n = 60[/tex]

We can say that, the sample mean will be equivalent to the population mean.

So,

⇒  [tex]\mu_\bar x=\mu[/tex]

        [tex]=52500[/tex]

hence,

The standard deviation will be:

⇒ [tex]\sigma_\bar x[/tex] = [tex]\frac{\sigma}{\sqrt{n} }[/tex]

        [tex]=\frac{4000}{\sqrt{60} }[/tex]

        [tex]=516.3978[/tex]

 

From a population of 200 elements, the standard deviation is known to be 14. A sample of 49 elements is selected. It is determined that the sample mean is 56. The standard error of the mean is _____. a. 2 b. greater than 2 c. 3 d. less than 2

Answers

Answer:

a. 2

Step-by-step explanation:

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean [tex]\mu = p[/tex] and standard deviation [tex]s = \sqrt{\frac{p(1-p)}{n}}[/tex]

Standard deviation is known to be 14.

This means that [tex]\sigma = 14[/tex]

Sample of 49

This means that [tex]n = 49[/tex]

The standard error of the mean is

[tex]s = \frac{\sigma}{\sqrt{n}} = \frac{14}{\sqrt{49}} = \frac{14}{7} = 2[/tex]

So the correct answer is given by option a.

Which represents the value of s in s + 12 = 100?

Answers

Answer:

S = 88

Step-by-step explanation:

s + 12 = 100

     -12    -12

s = 88

The value of s in s + 12 = 100 is 88

How to determine the value of s?

The equation is given as:

s + 12 = 100

Add -12 to both sides of the equation

s = 100 -12

Evaluate

s = 88

Hence, the value of s in s + 12 = 100 is 88

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PLEASE HELP

h(3) = 5x2^-x , Evaluate the function h (3)

Answers

h (x) = 5 x 2^-x

2^-x is the same as saying 1/2^x .

h (x) = 5 x 1/2^x

h (3) = 5 x 1/2^3
= 5 x 1/8
= 5/8

Therefore h (3) = 5/8

how can u stand applying math to every thing doesn't it make every thing repetitive and why does every thing need a pattern doesn't that just make every thing worthless cause what's the point if every thing repeats and no this is not about history

Answers

Math makes everything easier without math people would be sitting there all day wondering about simple things like money and how many eggs are in a carton

The Environmental Protection Agency records data on the fuel economy of many different makes of cars. Data on the mileage of 20 randomly selected cars are listed below. The values are ordered for convenience.
12 13 15 16 16 17 18 18 19 19
20 20 22 23 24 26 26 27 27 29
What is the interquartile range for the mileage data?
A) 8.5 miles per gallon
B) 16.5 miles per gallon
C) 17 miles per gallon
D) 25 miles per gallon

Answers

Answer:

A) 8.5 miles per gallon

Step-by-step explanation:

Given

[tex]x = \{12\ 13\ 15\ 16\ 16\ 17\ 18\ 18\ 19\ 19\ 20\ 20\ 22\ 23\ 24\ 26\ 26\ 27\ 27\ 29\}[/tex]

[tex]n = 20[/tex]

Required

The IQR

This is calculated as:

[tex]IQR = Q_3 - Q_1[/tex]

Calculate [tex]Q_1[/tex]

[tex]Q_1 = \frac{1}{4}(n + 1)th[/tex]

[tex]Q_1 = \frac{1}{4}(20 + 1)th[/tex]

[tex]Q_1 = \frac{1}{4}(21)th[/tex]

Remove bracket

[tex]Q_1 = 5.25th[/tex]

This means that:

[tex]Q_1[/tex] is the mean of 5th and 6th item

From the given data:

[tex]5th \to 16[/tex]

[tex]6th \to 17[/tex]

So, we have:

[tex]Q_1 = \frac{1}{2}(16 + 17)[/tex]

[tex]Q_1 = \frac{1}{2}(33)[/tex]

[tex]Q_1 = 16.5[/tex]

[tex]Q_1 = 16.25[/tex]

Calculate [tex]Q_3[/tex]

[tex]Q_3 = \frac{3}{4}(n + 1)th[/tex]

[tex]Q_3 = \frac{3}{4}(20 + 1)th[/tex]

[tex]Q_3 = \frac{3}{4}(21)th[/tex]

Remove bracket

[tex]Q_3 = 15.75th[/tex]

This means that:

[tex]Q_3[/tex] is the mean of 15th and 16th item

From the data:

[tex]15th \to 24[/tex]

[tex]16th \to 26[/tex]

So:

[tex]Q_3 = \frac{1}{2}(24 + 26)[/tex]

[tex]Q_3 = \frac{1}{2}(50)[/tex]

[tex]Q_3 = 25[/tex]

Recall that:

[tex]IQR = Q_3 - Q_1[/tex]

[tex]IQR = 25 -16.5[/tex]

[tex]IQR = 8.5[/tex]

The width of rectangle is 6 fr less than the lengthThe area of the rectangle is 247f Find the lengthand with of the rectangle

Answers

Answer:

i don't know 241 I think sorry

answer???
please help

Answers

Answer:

150°

Step-by-step explanation:

M = 58° + 92° (ext angles of a triangle)

M= 150°

Answer:

92+58=1

1=150

measure of angle1 is 150

I WILL GIVE BRAINLIEST
Twelve students were asked, “How old is your oldest guardian?” They gave the following responses: 56, 50, 47, 55, 50, 51, 55, 45, 55, 49, 45, 44. Which answer choice would represent the correct box plot?

Answers

Answer:17 abnd 60

Expiration: I know your not that guy pal your not that guy

Answer:

A

Step-by-step explanation:

56, 50, 47, 55, 50, 51, 55, 45, 55, 49, 45, 44.

Put in order from smallest to largest

44,45,45,47, 49, 50,  50, 51, 55, 55, 55, 56,

The left side of the box plot is 44,

The right side of the box plot his 56

This eliminates C and D

The median is 12/2 = 6

44,45,45,47, 49, 50,        50, 51, 55, 55, 55, 56,

Take the 6 and the 7th terms and average

(50+50)/2 = 50

This is the line in the middle of the box

This eliminates B

Find the 8th term of the sequence

100, 20, 4, 4/5
__
1/4096

25/16394

25/256

4/3125

Answers

9514 1404 393

Answer:

  (d)  4/3125

Step-by-step explanation:

The first term is 100 and the common ratio is 20/100 = 1/5. The explicit formula for terms of a geometric sequence is ...

  an = a1·r^(n-1)

  an = 100·(1/5)^(n-1)

Then the 8th term is ...

  a8 = 100 ·(1/5)^(8-1) = 100·5^(-7) = 4/3125

Answer:

[tex]d. \: \frac{4}{3125} [/tex]

Step-by-step explanation:

HOPE IT HELPS MUCH UNTO YOU

Helppppp 78 squared to the 3rd

Answers

The answer would be:

Given the Graph, identify the y-intercept​

Answers

Answer:

5

Step-by-step explanation:

5!

This is because the red line intersects with the Y-Axis (Line going up & down) on 5.

Multiply.
(2x+1)(6x2+8x+9)

Answers

16x^2 +50x+21 is the answer to your question.

Answer: 12x^ 3 + 22x^ 2 +26x + 9

Draw and label the circle given by the equation (x - 5 + y + 10 = 6^2​

Answers

Answer:

See attachment for circle

Step-by-step explanation:

Given

[tex](x -5)^2 + (y + 10)^2 = 6^2[/tex]

Required

Draw and label the circle

The equation of a circle is:

[tex](x -a)^2 + (y - b)^2 = r^2[/tex]

Where:

[tex]Center = (a,b)[/tex]

[tex]Radius = r[/tex]

So, we have:

[tex]Center = (5,-10)[/tex]

[tex]Radius = 6[/tex]

See attachment for circle

You have land that you would like to use to create two distinct fenced-in areas in the shape given below. You have 410 meters of fencing materials to use. What values of x and y would result in the maximum area that you can enclose

Answers

Answer:

[tex]x = \frac{205}{3}[/tex]

[tex]y =\frac{195}{4}[/tex]

Step-by-step explanation:

Given

[tex]p = 410[/tex] --- perimeter

See attachment for fence

Required

x and y

The perimeter of the fence is:

[tex]p = 2(x + y +5 + y) +x[/tex]

Open bracket

[tex]p = 2x + 2y +10 + 2y +x[/tex]

Collect like terms

[tex]p = 2x+x + 2y + 2y+10[/tex]

[tex]p = 3x + 4y+10[/tex]

Substitute: [tex]p = 410[/tex]

[tex]3x + 4y+10 =410[/tex]

Make 4y the subject

[tex]4y =410-10-3x[/tex]

[tex]4y =400-3x[/tex]

Make y the subject

[tex]y =\frac{400-3x}{4}[/tex]

The area (A) of the fence is:

[tex]A = (y + y + 5) * x[/tex]

[tex]A = (2y + 5) * x[/tex]

Substitute: [tex]y =\frac{400-3x}{4}[/tex]

[tex]A = (2*\frac{400-3x}{4} + 5) * x[/tex]

[tex]A = (\frac{400-3x}{2} + 5) * x[/tex]

Take LCM

[tex]A = (\frac{400-3x+10}{2}) * x[/tex]

Solve like terms

[tex]A = (\frac{410-3x}{2}) * x[/tex]

Open bracket

[tex]A = \frac{410x-3x^2}{2}[/tex]

Remove fraction

[tex]A = 205x-1.5x^2[/tex]

Differentiate both sides

[tex]A' = 205 - 3x[/tex]

To maximize; set [tex]A' =0[/tex]

[tex]205 - 3x =0[/tex]

Solve for 3x

[tex]3x = 205[/tex]

Solve for x

[tex]x = \frac{205}{3}[/tex]

Recall that: [tex]y =\frac{400-3x}{4}[/tex]

So, we have:

[tex]y =\frac{400-3*205/3}{4}[/tex]

[tex]y =\frac{400-205}{4}[/tex]

[tex]y =\frac{195}{4}[/tex]

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