HCl(aq) and KOH(aq) Express your answer as a balanced chemical equation. Identify all of the phases in your answer.

Answer:

Question 7 the answer is B

Explanation:

In every nuclear reaction there is always formation of products either by nuclei bombardment or by the elements breaking into two elements of the same mass

Question 8

The answer is A

Nuclear reactions release a huge amount of energy than chemical reactions

Answer:

See explanation and image attached

Explanation:

Fischer esterification is a type of reaction used  to convert carboxylic acids to ester in the presence of excess alcohol and a strong acid which acts as a catalyst. Another final product formed in the reaction is water.

The mechanism for the fischer esterification of Benzoic acid and  C H 3 O H in the presence of HCl as the catalyst is shown in the image attached to this answer.

The final products of the reaction are methyl benzoate, water and H^+ as shown in the image attached.

The methyl ester, water, and the acid catalyst (HCl) are byproducts of the Fischer esterification process, which involves protonation, nucleophilic attack, elimination, and deprotonation processes.

Carbonyl oxygen protonation: The carbonyl oxygen of the carboxylic acid (benzoic acid) is protonated by the acid catalyst (HCl) in the first step. The protonation of the carbonyl carbon increases its electrophilicity and promotes the alcohol's nucleophilic assault. Attack by the alcohol's nucleophilic oxygen (methanol, CH3OH) on the protonated carboxylic acid's carbonyl carbon results in the formation of a tetrahedral intermediate. The acid catalyst also helps with this phase. Elimination of water: In the following step, the water molecule must be removed from the tetrahedral intermediate. The hydroxyl group (-OH) from the carboxylic acid and a hydrogen from the hydroxyl group of the alcohol are removed to create this water molecule. Deprotonation: A deprotonation occurs after the removal of water.

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Answer:

Both lone pairs reside in sp3 orbitals; they are co-planar with the CH3 group.

Explanation:

In the compound, methyl acetate, the  lone-pair of electrons on the singly bonded oxygen atom is accommodated in sp3 hybridized orbitals.

If we look at the compound, we will notice the both lone pair of electrons on oxygen are accommodated in sp3 orbitals which are co-planar with the  CH3 group  in the molecule.

Answer:

0.1 mole of CH₄

Explanation:

From the question given above, the following data were obtained:

Volume of CH₄ = 2.24 L

Number of mole of CH₄ =?

The number of mole of CH₄ can be obtained as follow:

Recall:

1 mole of a gas occupy 22.4 L at stp. This implies that 1 mole of CH₄ occupies 22.4 L at stp.

22.4 L = 1 mole of CH₄

Therefore,

2.24 L = 2.24 × 1 mole of CH₄ / 22.4

2.24 L = 0.1 mole of CH₄.

Answer:

ATP asa, Helicasa, Proteasa, ARN polimerasa

Explanation:

Las enzimas son un tipo de biomoleculas que se corresponden con las proteinas.

Al momento de referirse a ellas, se utiliza la terminación asa.

ATPasa → Sintetizando ATP para el funcionamiento celular

Helicasa → Abre las hebras de ADN permitiendo el paso de la horquilla para el proceso de replicación de ADN.

Proteasas → Enzimas que degradan proteinas mal plegadas, rompen los enlaces peptídicos.

ARN polimerasa → Sintesis de ARN mensajero a partir de ADN en el proceso de la Transcripción. Se la puede conocer a veces, como primasa.

Answer:

major will be propan-2-ol

minor will be propan-1-ol

Answer:

In the transition series, atomic size across a period decreases at first but then remains relatively constant.

The transition elements in a period show a steady increase in electronegativity.

Explanation:

In considering the transition series, we observe that atomic sizes of the elements decreases first and subsequently remain constant. The reason for the initial decrease in atomic size is the increase in nuclear charge across the period. After the first few elements in the period, the atomic size remains relatively constant due to shielding effect of the inner d electrons which opposes the increase in effective nuclear charge.

It is also observed that electro negativity increases smoothly across the period for the transition series. Consequently, the transition series become less electro positive across the period.

Answer:

14.30%

Explanation:

Step 1: Given data

Chemical formula of sodium hydrogen carbonate: NaHCO₃

Step 2: Determine the mass of C in 1 mole of NaHCO₃

The is 1 atom of C in 1 molecule of NaHCO₃ and the molar mass of C is 12.01 g/mol. Then, there are 12.01 g of C in 1 mole of NaHCO₃.

Step 3: Determine the mnolar mass of NaHCO₃

M(NaHCO₃) = 1 × M(Na) + 1 × M(H) + 1 × M(C) + 3 × M(O)

M(NaHCO₃) = 1 × 22.98 g/mol + 1 × 1.01 g/mol + 1 × 12.01 g/mol + 3 × 16.00 g/mol = 84.00 g/mol

Step 4: Determine the mass percent of C in NaHCO₃

We will use the following expression.

%C = mC / mNaHCO₃ × 100%

%C = 12.01 g / 84.00 g × 100% = 14.30%

Answer:

Answer is in the explanation.

Explanation:

Before the equivalence point, the pH of the solution of HCl that is titrated with NaOH has a pH <<< 7. When you are adding more NaOH nearing, thus, to the equivalence point the change in pH occurs quickly, and, with 1 drop of excess of NaOH after equivalence, the pH of the solution change to a pH >>> 7

That means the volume added at pH 5 or pH 9 is, almost, the same doing the indicator work just as well as an indicator with change color at pH 7

Answer:

e. UDP-glucose pyrophosphorylase catalyzes the reaction of glucose-I-phosphate and UTP to UDP-glucose and PPi

a. Pyrophosphatase converts PPi and water into two Pi

b. Glycogen synthase adds a glucose unit from UDP-glucose to glycogen, producing a larger glycogen molecule and UDP

Explanation:

Glycogen synthesis or glycogenesis is the process of synthesis of glycogen molecules from glucose molecules in living organisms. Glycogen is a polysaccharide storage form of glucose and helps to store excess glucose in the body form use when required by the body.

The synthesis of glycogen involves sugar nucleotides. Sugar nucleotides are compounds in which a sugar molecule is attached to a nucleotide through phosphate ester bond, resulting in the activation of the sugar molecule. The sugar nucleotides then are used as substrates for the polymerization of the monosaccharide sugars into disaccharides, oligosaccharides and polysaccharides.

In the synthesis of glycogen, glucose-6-phosphate from phosphorylation of free glucose by hexokinase is first isomerized to glucose-1-phosphate by phosphoglucomutase.

Glucose-1-phosphate is then converted to UDP-glucose by its reaction with UTP catalyse by UDP-glucose pyrophosphorylase. The reaction is favoured by the rapid hydrolysis of PPi produced to two molecules of inorganic phosphate by the enzyme pyrophosphatase.

Glycogen synthase then adds a glucose unit from UDP-glucose to a growing chain of glycogen, producing a larger glycogen molecule and free UDP.

Answer: 98.08 g/mol

Explanation:

i just took this test and got it right

Answer:

A

Explanation:

Answer:

[tex]V'=1040ml[/tex]

Explanation:

From the question we are told that:

Initial Volume [tex]V_1=10.5mL[/tex]

Initial Aciditity of [tex]HN0_3 pH_1=2.0g[/tex]

Finial Aciditity of [tex]HN0_3 pH_2=4.0g[/tex]

Generally the equation for Acidity &Volume Relationship is mathematically given by

[tex]N_1V_1=N_2V_2[/tex]

Therefore

[tex]V_2=\frac{N_1V_2}{N_2}[/tex]

[tex]V_2=\frac{10^{-2}*10.5}{10^{-4}}V_2=1050ml[/tex]

Therefore

Change in Water volume is

[tex]V'=V_2-V_1[/tex]

[tex]V'=1050ml-10ml[/tex]

[tex]V'=1040ml[/tex]

Answer:

tungstun

Explanation:

Answer:

tungsten

Explanation:

strongest out of any natural metal (142,000 psi).

Answer:

60ug

Explanation:

If it has experienced two half lives, that means it has been halved twice. in that case, to undo it, just multiply it by two twice. 0.15ug * 2 = 0.30ug. 0.30ug * 2 = 0.60ug. Hope this helps.

Answer:

Ka = 6.02x10⁻⁶

Explanation:

The equilibrium that takes place is:

We calculate [H⁺] from the pH:

Keep in mind that [H⁺]=[A⁻].

As for [HA], we know the acid is 0.66% dissociated, in other words:

We calculate [HA]:

Finally we calculate the Ka:

Answer:

Neutrons are all identical to each other, just as protons are. Atoms of a particular element must have the same number of protons but can have different numbers of neutrons.

Explanation:

Since the vast majority of an atom's mass is found its protons and neutrons, subtracting the number of protons (i.e. the atomic number) from the atomic mass will give you the calculated number of neutrons in the atom. In our example, this is: 14 (atomic mass) – 6 (number of protons) = 8 (number of neutrons).

Explanation:

Magnesium reacts with dilute hydrochloric acid in a conical flask which is connected to an inverted measuring cylinder in a trough of water. The volume of hydrogen gas produced is measured over a few minutes, and the results are used to plot a graph

This is intended as a class practical. It is best if the students work in pairs because setting up and starting the experiment requires more than one pair of hands. One student can add the magnesium ribbon to the acid and stopper the flask, while the other starts the stopclock. During the experiment, one student can take the readings while the other records them. The experiment itself takes only a few minutes. But allow at least 30 minutes to give students time to set up, take readings and draw graph.

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Answer:

AgCl

Explanation:

The reaction that takes place is:

The precipitate (meaning a solid substance) formed is silver chloride, AgCl.

All salts formed with silver and a halogen (F, Cl, Br, I) are insoluble in water, meaning that when working with aqueous solutions they will be precipitates.

Answer:

H 4so8 is the answer of balance the reaction

Answer:

Concentration and reaction rate is directly proportional

Explanation:

Basically, concentration is directly proportional to the concentration, so the higher the concentration, the higher the reaction rate.

Once the concentration is increased, more chemical will be added hence the reaction rate will increase

The element whose atom may likely make a -3 ion is P.

Elements in the periodic table are classified into groups and periods. The elements in the same group have similar physical and chemical properties.

Phosphorus (P) is a member of group 15 in the periodic table. The most common ion formed by the members of this group is the -3 ion.

It is formed by accepting three electrons to complete their octet since they have five electrons on their outermost shell.

Hence P is most likely to form a -3 ion.

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Answer: The number of cations are [tex]3.24 \times 10^{22}[/tex] and number of anions are  [tex]3.24 \times 10^{22}[/tex] in 6.42 g of KBr.

Explanation:

The molar mass of KBr is (39.10 + 79.90) g/mol = 119.00 g/mol

Now, the dissociation equation for KBr is as follows.

[tex]KBr \rightarrow K^{+} + Br^{-}[/tex]

This means that 1 mole of KBr is forming 1 mole of [tex]K^{+}[/tex] (cation) and 1 mole of [tex]Br^{-}[/tex] (anion).

According to mole concept, 1 mole of every substance contains [tex]6.022 \times 10^{23}[/tex] atoms. Hence, number of cations present in 6.42 g KBr is calculated as follows.

[tex]No. of cations = Moles \times 6.022 \times 10^{23}\\= \frac{mass}{molar mass} \times 6.022 \times 10^{23}\\= \frac{6.42 g}{119.00 g/mol} \times 6.022 \times 10^{23}\\= 3.24 \times 10^{22}[/tex]

As according to the equation, there are equal number of moles of both cation and anions.

This means that the number of anions are also [tex]3.24 \times 10^{22}[/tex].

Thus, we can conclude that the number of cations are [tex]3.24 \times 10^{22}[/tex] and number of anions are  [tex]3.24 \times 10^{22}[/tex] in 6.42 g of KBr.

The number of cations and anions present in potassium bromide is 3.24 × 10²².

In one mole of any substance 6.022 × 10²³ atoms of that substance is present and this is known as Avogadro's number.

KBr is a strong electrolyte means it fully dissociates into their constitute ions. So, the number of moles of produced ions is equal to the moles of KBr and dissociation is represented as:

KBr → K⁺ + Br⁻

From this it is clear that 1 mole of cation and 1 mole of anion is produced from 1 mole of KBr. Moles of KBr will be calculated as:

n = W/M, where

W = given mass = 6.42g

M = molar mass = 119

n = 6.42 / 119 = 0.053 moles

No. of cations and anions present in 0.053 moles = 0.053 × 6.022 × 10²³ = 3.24 × 10²².

Hence, 3.24 × 10²² is the no. of cations and anions.

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Answer:

(a): Precipitate of calcium carbonate will form.

(b): Precipitate of barium sulfate will form.

(c): Precipitate of silver iodide will form.

(d): Precipitate of sodium chromate will form.

Explanation:

Complete ionic equation is defined as the equation in which all the substances that are strong electrolytes present in an aqueous state and are represented in the form of ions.

Net ionic equation is defined as the equations in which spectator ions are not included.

Spectator ions are the ones that are present equally on the reactant and product sides. They do not participate in the reaction.

(a):

The balanced molecular equation is:

[tex]CaCl_2(aq)+K_2CO_3(aq)\rightarrow 2KCl(aq)+CaCO_3(s)[/tex]

The complete ionic equation follows:

[tex]Ca^{2+}(aq)+2Cl^-(aq)+2K^+(aq)+CO_3^{2-}(aq)\rightarrow 2K^+(aq)+2Cl^-(aq)+CaCO_3(s)[/tex]

As potassium and chloride ions are present on both sides of the reaction. Thus, they are considered spectator ions.

The net ionic equation follows:

[tex]Ca^{2+}(aq)+CO_3^{2-}(aq)\rightarrow CaCO_3(s)[/tex]

Precipitate of calcium carbonate will form.

(b)

The balanced molecular equation is:

[tex]BaCl_2(aq)+MgSO_4(aq)\rightarrow MgCl_2(aq)+BaSO_4(s)[/tex]

The complete ionic equation follows:

[tex]Ba^{2+}(aq)+2Cl^-(aq)+Mg^{2+}(aq)+SO_4^{2-}(aq)\rightarrow Mg^{2+}(aq)+2Cl^-(aq)+BaSO_4(s)[/tex]

As magnesium and chloride ions are present on both sides of the reaction. Thus, they are considered spectator ions.

The net ionic equation follows:

[tex]Ba^{2+}(aq)+SO_4^{2-}(aq)\rightarrow BaSO_4(s)[/tex]

Precipitate of barium sulfate will form.

(c):

The balanced molecular equation is:

[tex]AgNO_3(aq)+KI(aq)\rightarrow KNO_3(aq)+AgI(s)[/tex]

The complete ionic equation follows:

[tex]Ag^{+}(aq)+NO_3^-(aq)+K^+(aq)+I^{-}(aq)\rightarrow K^+(aq)+NO_3^-(aq)+AgI(s)[/tex]

As potassium and nitrate ions are present on both sides of the reaction. Thus, they are considered spectator ions.

The net ionic equation follows:

[tex]Ag^{+}(aq)+I^{-}(aq)\rightarrow AgI(s)[/tex]

Precipitate of silver iodide will form.

(d):

The balanced molecular equation is:

[tex]2NaCl(aq)+(NH_4)_2CrO_4(aq)\rightarrow 2NH_4Cl(aq)+Na_2CrO_4(s)[/tex]

The complete ionic equation follows:

[tex]2Na^{+}(aq)+2Cl^-(aq)+2NH_4^+(aq)+CrO_4^{2-}(aq)\rightarrow 2NH_4^+(aq)+2Cl^-(aq)+Na_2CrO_4(s)[/tex]

As ammonium and chloride ions are present on both sides of the reaction. Thus, they are considered spectator ions.

The net ionic equation follows:

[tex]2Na^{+}(aq)+CrO_4^{2-}(aq)\rightarrow Na_2CrO_4(s)[/tex]

Precipitate of sodium chromate will form.

Answer:

[tex]{ \boxed{ \bf{newtons \: law \: of \: gravitation}}} [/tex]

It states that the product of masses of bodies ( planets and satellites and asteroids ) in space is inversely proportional to square of their separation mean distance

[tex]{ \tt{formular : F = \frac{GMm}{ {r}^{2} } }}[/tex]