If a swimming pool contains 2850 kg liters of water how many gallons of water does it contain

Answers

Answer 1
Your answer would be 753,000 gallons of water

Related Questions

Walking on sand with your bare feet demonstrate what kind of heat transfer

Answers

Answer:

It would be conduction.

Conduction Explanation:Its the answer

formula for dicyanoargentate (I) ion​

Answers

Answer:

Potassium dicyanoargentate(I) | C2AgKN2 - PubChem.

Synonyms: Potassium dicyanoargentate(I)pota...

Molecular Formula: C2AgKN2

Explanation:

How many moles of oxygen atom are there in 0.5 moles of Ca(ClO3) 2?

Answers

Answer:

Do a quick conversion: 1 moles Ca(ClO3)2 = 206.9804 gram using the molecular weight calculator and the molar mass of Ca(ClO3)2. ... How many moles Ca(ClO3 )2 in 1 grams? ... of each element in a chemical formula by the number of atoms of that element present in the formula, then adding all of these products together.

Explanation:

(jayaanilanmol's answer)

Which of the following describes the products of a chemical reaction?
A. The atoms that make up the compounds
B. The substances that are formed
O C. The starting substances
D. The substances that are not changed during the reaction

Answers

Answer:

B. The substances that are formed

Explanation:

a chemical reaction is a reaction that there's a formation of a new compound or substance.

can i have brainliest? and btw, let me know if you get it right! hope i helped <3

. A 60.0 g piece of Zn at 20.0 o C is dropped into 200.0 g of water at 100.0 o C. Determine the final temperature reached by the Zn and water, knowing that the specific heat capacity of Zn and water are 0.389 J/(g.o C) and 4.184 J/(g.o C), respectively.

Answers

Answer:

97.8 C

Explanation:

Recall the equation for specific heat:

q = mcΔT

There are several things to know in order to answer this question:

1. Whatever heat energy one object gains is the same as the heat energy the other has lost (conservation of energy).

2. Since one substance loses heat and the other gains heat, you need to multiply one side by -1 to account for the opposite direction of heat transfer.

3. The final temperature of both substance will be the same (zeroth law of thermodynamics)

Below, the left side of the equation represents water and the right side represents zinc.

-1 x 200 x 4.184 x (T - 100) = 60 x 0.389 x (T - 20)

Solve this equation and you get T = 97.8.

how many grams of oxygen are required to reach with 0.125 moles of zinc sulfide?

Answers

Answer:

6 g of O₂

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

2ZnS + 3O₂ —> 2ZnO + 2SO₂

From the balanced equation above,

2 moles of ZnS reacted with 3 moles of O₂.

Next, we shall determine the number of mole of O₂ required to react with 0.125 mole of ZnS. This can be obtained as follow:

From the balanced equation above,

2 moles of ZnS reacted with 3 moles of O₂.

Therefore, 0.125 mole of ZnS will react with = (0.125 × 3)/2 = 0.1875 mole of O₂.

Thus, 0.1875 mole of O₂ is needed for the reaction.

Finally, we shall determine the mass of 0.1875 mole of O₂. This can be obtained as follow:

Mole of O₂ = 0.1875 mole

Molar mass of O₂ = 2 × 16 = 32 g/mol

Mass of O₂ =?

Mass = mole × molar mass

Mass of O₂ = 0.1875 × 32

Mass of O₂ = 6 g

Therefore, 6 g of O₂ is required for the reaction.

In its aqueous solution, 99.9% of a substance dissociates to release hydronium ions. Which of the following is true for the substance? (3 points)

a
It is a weak acid.

b
It is a weak base.

c
It is a strong acid.

d
It is a strong base.

Answers

The answer is C. It’s a strong acid

The true statement about a substance in which 99.9% of it dissociates to release hydronium ions in its aqueous solution is that: C. It is a strong acid.

What is a strong acid?

A strong acid can be defined as a type of acid that completely dissociates (splits or ionizes) in an aqueous solution, usually by loosing a proton such as hydronium ions.

This ultimately implies that, a strong acid is a substance in which 99.9% of it dissociates in its aqueous solution to release hydronium ions.

In conclusion, some examples of a strong acid include the following;

Perchloric acidSulfuric acidHydrochloric acidHydrobromic acidNitric acid

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Suppose one was doing this experiment in the real world and the stockroom ran out of NaCl solutions. Which other solutions of similar concentration could be used in place of NaCl(aq)

Answers

Answer:

Polyethylene glycol

Explanation:

Because of the corrosive nature of Brine solution (solution of NaCl) , we can use organic liquid polyethylene glycol .  

Answer please a boy is jumping on a trampoline identify the action and reaction force

Answers

Answer:

kinetic energy

Explanation:

this might help..

17. A 55-gram egg is placed in a pot. After the egg is boiled, which is most likely the mass of
the egg?

A. 50g

B. 55g

C. 110g

D. 100g

Answers

Answer:

B. 55g

Explanation:

When an egg is boiled, its albumin (the main component of its yolk) is denaturalized due to the high temperatures, making it apt for human consumption.

This is only a physical change and no mass is lost nor gained during this process.

That's why the correct answer is the original mass of the egg, in this case, option B.

g Calculate the pH when (a) 24.9 mL and (b) 25.1 mL of 0.100 M HNO3 have been added to 25.0 mL of 0.100 M KOH solution.

Answers

Answer:

Following are the responses to the given choices:

Explanation:

For point a:

Using the acid and base which are strong so,

moles of [tex]H^+[/tex] (from[tex]HNO_3[/tex])

[tex]= 24.9\ mL \times 0.100\ M \\\\= \frac{24.9}{1000\ L} \times 0.100\ M \\\\= 2.49 \times 10^{-3} \ mol[/tex]

moles of [tex]OH^{-}[/tex] (from [tex]KOH[/tex])

[tex]= 25.0\ mL \times 0.100\ M \\\\= \frac{25.0}{1000 \ L} \times 0.100 \ M \\\\\= 2.50 \times 10^{-3}\ mol[/tex]  

[tex]1\ mol H^{+} \ neutralizes\ 1\ mol\ of\ OH^{-}[/tex]

So,  [tex](2.50 \times 10^{-3} mol - 2.49 \times 10^{-3} mol)[/tex] i.e. [tex]1 \times 10^{-5}[/tex] mol of [tex]OH^-[/tex] in excess in total volume [tex](24.9+25.0) \ mL = 49.9 \ mL[/tex] i.e. concentration of [tex]OH^- = 2 \times 10^{-4}\ M[/tex]

[tex]p[OH^{-}] = -\log [OH^{-}] = -\log [2 \times 10^{-4}\ mol] = 3.70[/tex]

Since, [tex]pH + pOH = 14,[/tex]

so,

[tex]\to pH = 14- pOH = 14- 3.70 = 10.30[/tex]  

For point b:

moles of [tex]OH^-[/tex] = from point a [tex]= 2.50 \times 10^{-3} \ mol[/tex]

moles of [tex]H^+[/tex](from[tex]HNO_3[/tex]):

[tex]= 25.1 mL \times 0.100 M\\\\ = \frac{25.1}{1000}\ L \times 0.100 \ M\\\\ = 2.51\times 10^{-3} \ mol[/tex]

1 mol [tex]H^+[/tex] neutralizes 1 mol of [tex]OH^-[/tex]

So, [tex](2.51 \times 10^{-3}\ mol - 2.50 \times 10^{-3}\ mol)[/tex] i.e. [tex]1 \times 10^{-5} \ mol \ of\ H^+[/tex] in excess in the total volume of [tex](25.1+25.0) \ mL = 50.1\ mL[/tex] i.e. concentration of[tex]H^+ = 2 \times 10^{-4}\ M[/tex]

Hence, [tex]pH = -\log [H^+] = -\log[2 \times 10^{-4}] = 3.70[/tex]

Reaction 1:

CuO(s)→Cu(s)+12O2(g)ΔG°=155kJ/molrxn


A chemist wants to produce Cu(s) from a sample of pure CuO(s) according to reaction 1, represented by the equation above.


(a) Using the data in the following table, calculate the value of the standard entropy change, ΔS°, for the reaction.


Substance Absolute Entropy at298 K (JK−1mol−1)

Cu(s) 33

O2(g) 205

CuO(s) 43


(b) Given that ΔG° for reaction 1 is positive (155kJ/molrxn), what must be true about the sign of ΔH° for the reaction? Justify your answer.


The decomposition of CuO(s) into Cu(s) and O2(g) is not a thermodynamically favored reaction. However, to produce Cu(s) from CuO(s), the chemist decides to pass H2(g) gas over the CuO(s) as it is heated strongly, as represented below.


Reaction 2:

CuO(s)+H2(g)−----heat→ Cu(s)+H2O(g)


(c) Reaction 2 is what type of chemical reaction? Justify your answer.


A third chemical reaction is represented below.


Reaction 3:

H2(g)+12O2(g)→H2O(g)ΔG°=−229kJ/molrxn


(d) Show how a combination of reaction 1 and reaction 3 can be used to produce reaction 2.


(e) Determine the value of ΔG° for reaction 2.


The chemist takes the Cu(s) produced from reaction 2 and uses it to make an electrode in a galvanic cell, as shown in the following diagram.


The figure presents a diagram of a galvanic cell consisting of two solutions in beakers, two metal electrodes, a salt bridge, and a wire. The half-cell on the left shows a copper electrode partially submerged in a solution of 1.0 molar copper sulfate. The half-cell on the right shows a silver electrode partially submerged in a solution of 1.0 molar silver nitrate. A salt bridge connects the two solutions. A wire connects the copper electrode and the silver electrode, and an arrow indicates that the electron flow through the wire is from the copper to the silver.


(f) Using the reduction half-reactions in the table below, write a balanced net-ionic equation representing the overall reaction that takes place as the cell operates.


Half-Reaction E° (volts)

Cu2+(aq)+2e−→Cu(s) 0.337

Ag+(aq)+e−→Ag(s) 0.800


(g) Determine the value of E° for the cell.

(h) Determine the value of ΔG° for the cell reaction.

Answers

a. ΔS°, for the reaction

= 3252-1032

= 2220 K (JK−1mol−1).

b. ΔG= ΔH- TΔS

155x10^3 = ΔH- 222ox 298

= ΔH= 816.56 KJ.

c. CuO(s)+H2(g)−----heat→ Cu(s)+H2O(g)

balance eqn -  2CuO(s)+2H2(g)−----heat→ 2Cu(s)+2H2O(g)

It is displacement reaction.

H2(g)+12O2(g)→H2O(g)ΔG°=−229kJ/molrxn

d. Adding 1 and 3 eqn to get 2 eqn.

CuO(s)→Cu(s)+12O2(g)----Cu(s)+12O2(g)+ H2O(g)

e. ΔG = ΔG reaction 1 - ΔG reaction 3

= 155-229

= - 74 KJ/mol.

f. Overall cell reaction :

2Ag +Cu ⇒ 2Ag +Cu(s)2+

There will be greater reduction potential so Ag will have reduction potential while Cu will have oxidation.

g. E= -0.337 + 0.8

= 0.463 V

h.  ΔG° = -89.359 kJ.

What is entropy ?

It is the amount of energy unavailable to do work in a system.

Thus it is well explained.

To learn more about the Entropy  refer to link ;

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What is the general trend in electro negativity as you move from left to right across the periodic table

Answers

Answer:

On the periodic table, electronegativity generally increases as you move from left to right across a period and decreases as you go down a group. As a result, the most electronegative elements are found on the top right of the periodic table, while the least electronegative elements are found on the bottom left.

Explanation:

Answer:

The Electronegativity increases

Explanation:

;)

what is the NGOs location in Nigeria​

Answers

Answer:

9E , Badagry road , off marine road , apapa , Lagos State

Explanation

Neap tides happen when ?

Answers

When uh yeah that’s what I’m saying dog
it happens when the sun and moon are at right angles to each other

find the sum of angles x° and y° from the given figure​

Answers

Answer:

where is the figure . u can simply add them

(c) If the student mixed 10 mL of distilled water with 10 mL of the sample, would this diluted solution have anabsorbance greater than, less than or equal to the absorbance of the original solution? Justify your answer.

Answers

Answer:

The diluted solution have an absorbance less than the original solution

Explanation:

As you can see in the graph, the absorbance of a substance is directly proportional to the concentration of the substance (Lambert-Beer law). That means a solution more concentrated than another will have an absorbannce greater than the more diluted solution.

In the problem, you are diluting the original sample by the addition of 10mL of distilled water, that means,

The diluted solution have an absorbance less than the original solution

A 15.00 L sample of Helium gas has a mass of .002 kg. What is the
density of this sample? Your answer should be expressed in proper
scientific notation. Please show your work to receive credit.

Answers

Answer:

[tex]d=1.33x10^{-4}kg/L[/tex]

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to calculate the required density by knowing it is calculated by dividing mass over volume:

[tex]d=m/V[/tex]

Therefore, we plug in the given kilograms and liters to obtain:

[tex]d=\frac{0.002kg}{15.00L}\\\\d=1.33x10^{-4}kg/L[/tex]

Which shows the proper scientific notation.

Regards!

Some glucose produced by gluconeogenesis is stored in the body as glycogen. Order the steps of glycogen synthesis.

a. Pyrophosphatase converts PPi and water into two Pi
b. Glycogen synthase adds a glucose unit from UDP-glucose to glycogen, producing a larger glycogen molecule and UDP
c. Glvcogen synthase removes a glucose unit from a glycogen molecule producing a smaller glycogen molecule and IJDP
d. ADP-glucose pyrophosphorylase catalyzes the reaction of glucose-I -phosphate and ATP to ADP-glucose and PPi
e. UDP-glucose pyrophosphorylase catalyzes the reaction of glucose-I-phosphate and UTP to UDP-glucose and PPi

Answers

Answer:

e. UDP-glucose pyrophosphorylase catalyzes the reaction of glucose-I-phosphate and UTP to UDP-glucose and PPi

a. Pyrophosphatase converts PPi and water into two Pi

b. Glycogen synthase adds a glucose unit from UDP-glucose to glycogen, producing a larger glycogen molecule and UDP

Explanation:

Glycogen synthesis or glycogenesis is the process of synthesis of glycogen molecules from glucose molecules in living organisms. Glycogen is a polysaccharide storage form of glucose and helps to store excess glucose in the body form use when required by the body.

The synthesis of glycogen involves sugar nucleotides. Sugar nucleotides are compounds in which a sugar molecule is attached to a nucleotide through phosphate ester bond, resulting in the activation of the sugar molecule. The sugar nucleotides then are used as substrates for the polymerization of the monosaccharide sugars into disaccharides, oligosaccharides and polysaccharides.

In the synthesis of glycogen, glucose-6-phosphate from phosphorylation of free glucose by hexokinase is first isomerized to glucose-1-phosphate by phosphoglucomutase.

Glucose-1-phosphate is then converted to UDP-glucose by its reaction with UTP catalyse by UDP-glucose pyrophosphorylase. The reaction is favoured by the rapid hydrolysis of PPi produced to two molecules of inorganic phosphate by the enzyme pyrophosphatase.

Glycogen synthase then adds a glucose unit from UDP-glucose to a growing chain of glycogen, producing a larger glycogen molecule and free UDP.

What characteristic of a light wave in a medium determines the index of refraction of that
medium?

Answers

Answer:

The refractive index can be seen as the factor by which the speed and the wavelength of the radiation are reduced with respect to their vacuum values: the speed of light in a medium is v = c/n, and similarly the wavelength in that medium is λ = λ0/n, where λ0 is the wavelength of that light in vacuum.

Explanation:

Refractive index

Explanation: i need points

A student in CEM143 was doing a fractional distillation when she noticed that the temperature suddenly started to drop. What could have caused the decrease in the temperature

Answers

Explanation:

A process where two or more number of miscible liquids present in different fractions are separated by boiling at different temperatures is called fractional distillation.

The sudden decrease in temperature is because the compounds having lower boiling point have completed the distillation before vapor of the higher boiling point can actually fill the distillation head.

How many milliliters of 0.350 M H2SO4 are required to neutralize 60.0 mL of 0.300 M NaOH?

Answers

Answer:

25.7 mL of H₂SO₄

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

H₂SO₄ + 2NaOH —> Na₂SO₄ + 2H₂O

From the balanced equation above,

The mole ratio of acid, H₂SO₄ (nₐ) = 1

The mole ratio of base, NaOH (n₆) = 2

Finally, we shall determine the volume of H₂SO₄ needed for the reaction. This can be obtained as shown below:

Molarity of acid, H₂SO₄ (Mₐ) = 0.350 M

Volume of base, NaOH (V₆) = 60 mL

Molarity of base, NaOH (M₆) = 0.300 M

Volume of acid, H₂SO₄ (Vₐ) = ?

MₐVₐ / M₆V₆ = nₐ/n₆

0.350 × Vₐ / 0.3 × 60 = 1/2

0.350 × Vₐ / 18 = 1/2

Cross multiply

0.350 × 2 × Vₐ = 18

0.7 × Vₐ = 18

Divide both side by 0.7

Vₐ = 18 / 0.7

Vₐ = 25.7 mL

Thus, 25.7 mL of H₂SO₄ is needed for the reaction.

2Al + 6HCl → 2AlCl3 + 3H2

If 12 moles of Al completely react, how many moles of H2 are produced?

Answers

Answer:

18 moles of H₂.

Explanation:

The balanced equation for the reaction is given below:

2Al + 6HCl –> 2AlCl₃ + 3H₂

From the balanced equation above,

2 moles of Al reacted to produce 3 moles of H₂.

Finally, we shall determine the number of mole of H₂ produced by the reaction of 12 moles of Al. This can be obtained as follow:

From the balanced equation above,

2 moles of Al reacted to produce 3 moles of H₂.

Therefore, 12 moles of Al will react to produce = (12 × 3)/2 = 18 moles of H₂.

Thus, 18 moles of H₂ were obtained from the reaction.

Which of the following combination of elements would result in covalent compound? * W X Y Z Vand X Wand Z Y and Z Wand y​

Answers

Answer:

C. Y & Z

Explanation:

V, W are imaginary metals here because their valence electrons are typically less than 4. X, Y, Z are non-metals and have higher valence electrons. Here, if V or W bind with X, Y, or Z we make ionic bond (because metal + non metal = ionic). But, if X binds with Y or Z or any combinations of any two of the three non-metals results in covalent bond (non metal + non metal = covalent).

Thus, Y and Z make covalent.

What is the concentration of a solution with a volume of 3.3 mL that contains 12 g of ammonium sulfite? (molar mass = 100.154 g/mol)

Answers

Answer:

36.30 M

Explanation:

Given that:

Molar mass of ammonium sulfite (NH₄)₂ SO₃ = 100.154 g/mol

Volume = 3.3 mL

to liters, we have: (3.3/1000)L

= 0.0033 L

mass = 12 grams

The concentration of the solution = [tex]\dfrac{12 \ g}{ 100 .154 \ g/mol}\times \dfrac{1}{0.0033 \ L}[/tex]

= 36.30 M

Which statements correctly describe the relationship between the event and its effect on energy inputs and outputs?

A. The eruption of a volcano increases the concentration of particles in the atmosphere, which decreases the amount of energy that can reach Earth from the Sun in the short term.

B. Burning fossil fuels decreases the concentration of greenhouse gases in the atmosphere, which decreases the amount of heat that reflects back to Earth's surface.

C. Changes in Earth's orbit periodically increase the amount of solar energy reaching Earth from the Sun, which raises temperatures.​

Answers

Answer:

They Are All Very Good Statements But I Will Go With "A"

Explanation:

I go with "A" Because In The statement it has a cause an effect, it has a positive term and a negative term, in other uses it is "A" between energy inputs and outputs, and events.

The statement that correctly describes the relationship between the event and its effect on energy inputs and outputs is Option A .

What is Energy ?

Energy is defined as the capacity to do work .

There are various types of Energy , Light Energy , Sound Energy , Solar Energy , Wind Energy etc .

Volcanic eruptions emit huge amounts of volcanic dust, sulfur compounds and water vapor into the atmosphere .

This reduces the atmospheric transparency and that results into causing hindrance to the solar radiation penetration in the earth's surface ,

This results in short term cooling effect over large areas of earth.

Among all the statements , Option A , The eruption of a volcano increases the concentration of particles in the atmosphere, which decreases the amount of energy that can reach Earth from the Sun in the short term , correctly describe the relationship between the event and its effect on energy inputs and outputs.

To know more about Energy

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The atomic particle with a charge of -1.6 x 10-19 C is

Answers

Explanation:

Proton +1.60 x 10-19 C 1.672 x 10-24 g

Electron -1.60 x 10-19 C 9.05 x 10-28 g

Neutron neutral 1.674 x 10-24 g

What is the molar mass of H2SO4?
(Molar mass of H = 1.0079 g/mol; S = 32.065 g/mol; O = 15.999 g/mol)

Answers

Answer: 98.08 g/mol

Explanation:

i just took this test and got it right

Answer:

A

Explanation:

What volume of water must be added to 10.5 mL of a pH 2.0 solution of HNO3 in order to change the pH to 4.0 g

Answers

Answer:

[tex]V'=1040ml[/tex]

Explanation:

From the question we are told that:

Initial Volume [tex]V_1=10.5mL[/tex]

Initial Aciditity of [tex]HN0_3 pH_1=2.0g[/tex]

Finial Aciditity of [tex]HN0_3 pH_2=4.0g[/tex]

Generally the equation for Acidity &Volume Relationship is mathematically given by

[tex]N_1V_1=N_2V_2[/tex]

Therefore

[tex]V_2=\frac{N_1V_2}{N_2}[/tex]

[tex]V_2=\frac{10^{-2}*10.5}{10^{-4}}V_2=1050ml[/tex]

Therefore

Change in Water volume is

[tex]V'=V_2-V_1[/tex]

[tex]V'=1050ml-10ml[/tex]

[tex]V'=1040ml[/tex]

PLS HELP ME PLZ AND THANKS

Answers

Answer:

q6= third option

q7= third option

Explanation:

kinetic molecular theory deals with temperature

pressure inversely proportional to volume so when volume doubled, pressure halved given that mass and temperature constant

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