Perimeter of 30 ft in an area of 14 ft what is the length and the width

Answer:

ok

Step-by-step explanation:

please mark me brainleast

Answer:

See Explaination

Step-by-step explanation:

According To Question

(Diagram, Please Find In Attachment)

Question 38 . Cos ∅ = 12/13   ∅ in Quadrant-4(Where only Cos & Sec are Positive all other Functions Are Negative in this Quadrant)

Now ∅ Represent a Right Angle Triangle with Base=12 Perpendicular=5 & Hypothenese=13

Sin∅ = -5/13 , Cosec∅=-13/5 , Tan∅=-5/12 , Cot∅=-12/5 & Sec∅=13/12

Question 39 . SinX=-3/4   X Lies in Quadrant-3(Where only Tan & Cot are Positive all other Functions Are Negative in this Quadrant)

Find By Using Basic Formulas

[tex]SinX^{2}+CosX^{2}=1[/tex] ↔ Put Value of Sin∅=-3/4

We get CosX= ±[tex]\frac{\sqrt{5} }{4}[/tex] (but X Lies in Quadrant-3 Where Cosine Is Negative , So Neglect CosX= +[tex]\frac{\sqrt{5} }{4}[/tex])

So CosX= -[tex]\frac{\sqrt{5} }{4}[/tex] ...... now you get the point . All Questions Will Solve like This .

Answer:

22.5

Step-by-step explanation:

Inscribed Angle =1/2 Intercepted Arc

F = 1/2 (45)

<F = 22.5

[tex]0.375[/tex] ✅

Step-by-step explanation:

[tex] - 1 \frac{7}{8} + 2 \frac{1}{4} \\ = - \frac{15}{8} + \frac{9}{4} \\ = - \frac{15}{8} + \frac{9 \times 2}{4 \times 2} \\ = \frac{ - 15 + 18}{8} \\ = \frac{3}{8} \\ = 0.375[/tex]

[tex]\large\mathfrak{{\pmb{\underline{\orange{Happy\:learning }}{\orange{!}}}}}[/tex]

Answer:

01:04

Step-by-step explanation:

add 7 minutes to 22:57 to get 23:04. then add 2 hours to get to 01:04.

Answer:

1

Step-by-step explanation:

Answer:

She didn't put the sign's in the proper place, it should be ( x + 3 ) ( x - 7 )

Step-by-step explanation:

( x - 3 ) ( x + 7 ) = x² + 7x - 3x - 21 = x² + 4x - 21

( x + 3 ) ( x - 7 ) = x² - 7x + 3x - 21 = x² - 4x - 21

Answer:

See Below.

Step-by-step explanation:

Problem A)

We have:

[tex]\displaystyle \csc^2\theta \tan^2\theta -1=\tan^2\theta[/tex]

When in doubt, convert all reciprocal trig functions and tangent into terms of sine and cosine.

So, let cscθ = 1/sinθ and tanθ = sinθ/cosθ. Hence:

[tex]\displaystyle \left(\frac{1}{\sin^2\theta}\right)\left(\frac{\sin^2\theta}{\cos^2\theta}\right)-1=\tan^2\theta[/tex]

Cancel:

[tex]\displaystyle \frac{1}{\cos^2\theta}-1=\tan^2\theta[/tex]

Let 1/cosθ = secθ:

[tex]\sec^2\theta -1=\tan^2\theta[/tex]

From the Pythagorean Identity, we know that tan²θ + 1 = sec²θ. Hence, sec²θ - 1 = tan²θ:

[tex]\tan^2\theta =\tan^2\theta[/tex]

Problem B)

We have:

[tex]\sin^3x=\sin x-\sin x \cos^2 x[/tex]

Factor out a sine:

[tex]\sin x(\sin^2 x)=\sin x-\sin x\cos^2 x[/tex]

From the Pythagorean Identity, sin²θ + cos²θ = 1. Hence, sin²θ = 1 - cos²θ:

[tex]\sin x(1-\cos^2 x)=\sin x-\sin x\cos^2x[/tex]

Distribute:

[tex]\sin x- \sin x \cos^2 x=\sin x-\sin x\cos^2 x[/tex]

Problem C)

We have:

[tex]\displaystyle \frac{\cos 2x+1}{\sin 2x}=\cot x[/tex]

Recall that cos2θ = cos²θ - sin²θ and that sin2θ = 2sinθcosθ. Hence:

[tex]\displaystyle \frac{\cos^2 x-\sin^2 x+1}{2\sin x\cos x}=\cot x[/tex]

From the Pythagorean Identity, sin²θ + cos²θ = 1 so cos²θ = 1 - sin²θ:

[tex]\displaystyle \frac{2\cos^2 x}{2\sin x\cos x}=\cot x[/tex]

Cancel:

[tex]\displaystyle \frac{\cos x}{\sin x}=\cot x[/tex]

By definition:

[tex]\cot x = \cot x[/tex]

Answer:

16

Step-by-step explanation:

8/1/2

8 divided by 1/2

8 x 2/1 = 16

Answer:

Step-by-step explanation:

P=8/V

1/2=8/V

do cross multiplication

2*8=V*1

16=V

Answer:

C: .75

Step-by-step explanation:

I really just subtracted

Answer:

0,4

Step-by-step explanation:

See image below:)

Answer:

[tex]x = 70^o[/tex]

Step-by-step explanation:

Given

See attachment for triangle

Required

Find x

To solve for x, we make use of:

[tex]x + 50^o + 60^o = 180^o[/tex] --- angles in a triangle

[tex]x + 110^o = 180^o[/tex]

Collect like terms

[tex]x = 180^o-110^o[/tex]

[tex]x = 70^o[/tex]

Step-by-step explanation:

P(red) = 12/(12+10+5+4+29)

= 12/60

= 1/5

= 0.2

= 20%

Answer:

[tex] \cos(x) = \frac{24}{30} [/tex]

OPTION C

Answer:

The probability that less than 3 road construction projects are currently taking place in this city is 0.06197

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

[tex]P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}[/tex]

In which

x is the number of sucesses

e = 2.71828 is the Euler number

[tex]\mu[/tex] is the mean in the given interval.

Poisson distribution with a mean of 6.

This means that [tex]\mu = 6[/tex]

Find the probability that less than 3 road construction projects are currently taking place in this city.

This is:

[tex]P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2)[/tex]

So

[tex]P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}[/tex]

[tex]P(X = 0) = \frac{e^{-6}*6^{0}}{(0)!} = 0.00248[/tex]

[tex]P(X = 1) = \frac{e^{-6}*6^{1}}{(1)!} = 0.01487[/tex]

[tex]P(X = 2) = \frac{e^{-6}*6^{2}}{(2)!} = 0.04462[/tex]

[tex]P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2) = 0.00248 + 0.01487 + 0.04462 = 0.06197[/tex]

The probability that less than 3 road construction projects are currently taking place in this city is 0.06197

Answer:    [tex]2\sqrt{7}[/tex]

When writing this on a keyboard, you would say 2*sqrt(7)

========================================================

Explanation:

The formula we'll use is

A = 0.5*p*q*sin(R)

where R is the angle between sides p and q.

The diagram shows that p = x+4 is opposite angle P, and q = x is opposite angle Q. Convention usually has the uppercase letters be angles, and the lowercase letters as the sides.

Plug in the given values and simplify to get the following

A = 0.5*p*q*sin(R)

A = 0.5*(x+4)*x*sin(60)

A = 0.5*(x+4)*x*sqrt(3)/2 ..... use the unit circle

A = 0.25*(x^2+4x)*sqrt(3)

A = (0.25x^2+x)*sqrt(3)

Set this equal to the given area of A = sqrt(27) and solve for x

A = (0.25x^2+x)*sqrt(3)

(0.25x^2+x)*sqrt(3) = A

(0.25x^2+x)*sqrt(3) = sqrt(27)

(0.25x^2+x)*sqrt(3) = 3*sqrt(3) .... see note1 at the very bottom

0.25x^2+x = 3

(1/4)x^2+x = 3

x^2+4x = 12 .... see note2 at the very bottom

x^2+4x-12 = 0

(x+6)(x-2) = 0

x+6 = 0 or x-2 = 0

x = -6 or x = 2

A negative side length doesn't make sense, so we ignore x = -6. The only solution here is x = 2.

Since x = 2, this means we have the following side lengths so far

Now apply the law of cosines to find the missing side.

r^2 = p^2 + q^2 - 2*p*q*cos(R)

r^2 = 6^2 + 2^2 - 2*6*2*cos(60)

r^2 = 36 + 4 - 24*1/2

r^2 = 40 - 12

r^2 = 28

r = sqrt(28)

r = sqrt(4*7)

r = 2*sqrt(7)

Side PQ is exactly 2*sqrt(7) units long

This approximates to 2*sqrt(7) = 5.2915

------------------------------------

Footnotes:

Answer:

132/100 or 1.32

Step-by-step explanation:

13/10=130/100

130/100+2/100=132/100

Answer:

132

Step-by-step explanation:

13/10+2/100=?/100

Get a common denominator of 100 for the first term

13/10  * (10/10)  +2/100=?/100

130/100 + 2/100 = ?/100

132/100   = ? /100

Answer:

C)  3(x+7)²

Step-by-step explanation:

Answer:

A) (3x + 21)(x + 7)

Step-by-step explanation:

If we look at the equation we can see that it is a quadratic equation, therefore we can factor it in the following way...

[tex]3x^{2} + 42x + 147 = 3x^{2} + 21x + 21x + 147 = 3x(x + 7) + 21(x + 7) = (3x + 21)(x + 7)[/tex]

Therefore the answer is A)

Answer:

Since R32,210 is greater than R30,000; it simply means that Mr X would get greater return on investment

Step-by-step explanation:

a) Mr X Return

We have the compound interest formula as;

V = P(1 + r)^t

V is the value yielded after some certain amount t

Where P is the amount invested = R20,000

r is the yearly interest rate = 10/100 = 0.1

t = 5 years

so we have;

V = 20,000(1 + 0.1)^5 = R32,210.2

b) Mrs X return

We use the simple interest formula here;

A = P + I

I = PRT/100

where P, the principal is the amount invested = R20,000

R = 10%

T = 5 years

I = (20,000 * 10 * 5)/100

I = R10,000

A = R20,000 + R10,000

A = R30,000

Since R32,210 is greater than R30,000; it simply means that Mr X would get greater return on investment

Answer:

it's 4488 Wich would make 187

Step-by-step explanation:

missing where ?

I guess you mean that there is one element missing between 51 and 33 (based on the readable answer options).

if that is true, then the missing element is 42.

the difference between 60 and 51 is 9.

the difference between 51 and 33 is 18.

if there is an engender missing in between 51 and 33, then it is logical to put it in the middle cutting the interval of 18 in half to 2 times 9. which is also supported by the first interval between 60 and 51 (9).

so, it would be 51 -9 = 42

Answers:

These values are approximate

=============================================================

Explanation:

The circumference formula is

C = 2*pi*r

which rearranges to

r = C/(2pi)

when solving for r.

Plug in the given circumference to find that

r = C/(2pi)

r = (39,750)/(2pi)

r = 6,326.40898790283

For the sake of the most accuracy possible, I'm using my calculator's stored version of pi (and not something like pi = 3.14); if your teacher requires you to use pi = 3.14 then follow those instructions of course.

The radius is roughly 6326 km when rounded to the nearest integer.

Keep in mind that the earth isn't a perfect sphere, but rather a slightly squished one. This means the earth is slightly fatter than it is tall. However, for the sake of this problem, we'll assume it's a sphere.

------------------------

Once you determine the circumference, aka distance around the circle, we can figure out the next problem: determining the distance from the north pole to the equator. This distance runs along a line of longitude, so it's a north-south distance.

Again, imagine the earth is a perfect sphere. This means that the equator circumference is the same as the circumference as a full longitude line when we travel the globe only along that line. In other words, start at the north pole, travel along that specific longitude only until you reach the south pole. Then staying on that line, travel back to the north pole going around the backend of the earth.

That full circular path we traveled will get cut into 1/4 because 1/2 the circumference is the portion from north to south pole, and then we cut that distance in half when going from north pole to the equator.

(1/4)*(6,326.40898790283) = 1,581.6022469757

That rounds to 1582 km

------------------------

Side notes:

Answer:

boxers get injured but it is good to have some security on your fist and for those who do do boxing it's nice to have some security

Answer:

So, if we say Jiri's age is j (we can pick any letter), then Pamela's age is 2j, right?

j + 2j = 72

j is the same as 1j, but we wouldn't call you 1James, just James.

3j = 72

To isolate j, we do the opposite operation to both sides.

3j/3 = 72/3

j/j = 1, so that cancels out. 72/3 = 24.

j = 24

Jiri is 24 years old.

Answer:

Jiri is 7 years old.

explanation:

3j + j = 28

4j = 28

4j/4 = 28/4

j = 7

this can be proven:

Pamela's age: 3×7 = 21

the sum of their ages = 28

7 + 21 = 28

Answer:

(-0.5, -1)

Step-by-step explanation:

A turning point is a point of the graph where the graph changes from increasing to decreasing (rising to falling) or decreasing to increasing (falling to rising)

Answer:

O A. 3.1

Step-by-step explanation:

it's correct if I'm rwong (*´ω｀*)

Answer: The answer is C. 6.9

Step-by-step explanation: