The ideal gas law is PV = nRT.
Use 8.31 for R. (8.31 Lx kPa / Kx mol)
What is the temperature of 3.0 moles of a gas that is in a closed container of
volume 9L, and has a pressure of 85kPa?


1. 3.4 kelvin
2. 0.03 kelvin
3. 30.7 kelvin
4. 28.6 kelvin

Answers

Answer 1

Answer: 30.66945 kelvin

Explanation:


Related Questions

In what kind of orbitals do the lone-pair electrons on the singly bonded oxygen of methyl acetate reside, and are they in the same plane as the group

Answers

Answer:

Both lone pairs reside in sp3 orbitals; they are co-planar with the CH3 group.

Explanation:

In the compound, methyl acetate, the  lone-pair of electrons on the singly bonded oxygen atom is accommodated in sp3 hybridized orbitals.

If we look at the compound, we will notice the both lone pair of electrons on oxygen are accommodated in sp3 orbitals which are co-planar with the  CH3 group  in the molecule.

Use the following balanced equation to answer the questions below.

Answers

Answer:

A. 4.5 mol Mg(OH)₂

B. 6 mol NaOH

Explanation:

Let's consider the following balanced equation.

Mg(NO₃)₂ + 2 NaOH ⇒ Mg(OH)₂ + 2 NaNO₃

PART A

The molar ratio of NaOH to Mg(OH)₂ is 2:1. The moles of Mg(OH)₂ produced from 9 moles of NaOH are:

9 mol NaOH × 1 mol Mg(OH)₂/2 mol NaOH = 4.5 mol Mg(OH)₂

PART B

The molar ratio of NaOH to NaNO₃ is 2:2. The moles of NaOH needed to produce 6 moles of NaNO₃ are:

6 mol NaNO₃ × 2 mol NaOH/2 mol NaNO₃ = 6 mol NaOH

If A Reaction Takes 10s To Go To Completion At 0°C, How Long Will It Take To Go At 100°C?

Answers

Answer:

1,000s

Explanation:

i just multiply it

If a reaction takes 10s to go to completion at 0°C,then 1000s will It take to go at 100°C.

What is reaction ?

A chemical reaction is a procedure that causes one group of chemical components to change chemically into another.

Combination, decomposition, single-replacement, double-replacement, and combustion are the five fundamental types of chemical reactions. You can classify a reaction into one of these groups by looking at the reactants and products. Several categories will apply to some reactions.

When atoms establish or break chemical bonds, chemical processes take place. Reactants are the substances that begin a chemical reaction, while products are the compounds that are created as a result of the reaction.

Thus,If a reaction takes 10s to go to completion at 0°C,then 1000s will It take to go at 100°C.

To learn more about reaction, follow the link;

https://brainly.com/question/3664113

#SPJ2

paano pakalmahin ang leon

15 points po​

Answers

Answer:

lo siento señor, yo no hablo taka taka

Explanation:

5 puntos gratis pa

Determain the number of moles in 2.24l of ch4 at stp

Answers

Answer:

0.1 mole of CH₄

Explanation:

From the question given above, the following data were obtained:

Volume of CH₄ = 2.24 L

Number of mole of CH₄ =?

The number of mole of CH₄ can be obtained as follow:

Recall:

1 mole of a gas occupy 22.4 L at stp. This implies that 1 mole of CH₄ occupies 22.4 L at stp.

22.4 L = 1 mole of CH₄

Therefore,

2.24 L = 2.24 × 1 mole of CH₄ / 22.4

2.24 L = 0.1 mole of CH₄.

HELP WITH QUESTION 3,4 and 5 PLEASE

Answers

Answer:

I have no idea never get this in class before.

3 enzimas presentes en nuestro organismo e indique en que procesos actúan

Answers

Answer:

ATP asa, Helicasa, Proteasa, ARN polimerasa

Explanation:

Las enzimas son un tipo de biomoleculas que se corresponden con las proteinas.

Al momento de referirse a ellas, se utiliza la terminación asa.

ATPasa → Sintetizando ATP para el funcionamiento celular

Helicasa → Abre las hebras de ADN permitiendo el paso de la horquilla para el proceso de replicación de ADN.

Proteasas → Enzimas que degradan proteinas mal plegadas, rompen los enlaces peptídicos.

ARN polimerasa → Sintesis de ARN mensajero a partir de ADN en el proceso de la Transcripción. Se la puede conocer a veces, como primasa.

Which of the metals would reduce an iron ion
F
Fe
Cr
Cu
Ag
Sn

Answers

Answer:

Cu

Explanation:

Copper since it is more reactive than Iron. Hence, it can easily displace ions in an iron based compound.

Please help
Calculate the sodium ion (Na+) concentration for a 0.812 M Na3PO4 solution.
[Na+]=____M

Answers

Explanation:

Correct option is

B

0.750 M

Na3PO4 dissociates as:

Na3PO4⇌3Na++PO43−

∴ conc. of Na+ would be =3×0.250=

hope help

PLS HELP ME WITH THESE QUESTIONS ITS DUE TOMORROW I WILL MARK U AS BRAINLIEST

Answers

Answer:

See Explanation

Explanation:

1 mole of Cl2 gas occupies 22.4 L

x moles of Cl2 gas occupies 5.24 L

x= 1 × 5.24/22.4

x= 0.23 moles of Cl2

According to the kinetic theory of gases, the particles of a gas are in constant random motion and collide with each other and the walls of the container. Collision between gas particles are perfectly elastic.

Hence the statement that particles must not be able to move in any fixed or open container is false according to the kinetic theory of gases.

predict the major and minor products of the reaction. name the products using systematic names. ch3ch=ch2+h2o-->h+​

Answers

Answer:

major will be propan-2-ol

minor will be propan-1-ol

Select all the true statements.
a. Ionic bonding is more prevalent for the higher oxidation states and covalent bonding is more prevalent for the lower states.
b. The highest oxidation state of elements in Groups 3A through 7B is +3.
c. In the transition series, atomic size across a period decreases at first but then remains relatively constant.
d. The transition elements in a period show a steady increase in electronegativity.

Answers

Answer:

In the transition series, atomic size across a period decreases at first but then remains relatively constant.

The transition elements in a period show a steady increase in electronegativity.

Explanation:

In considering the transition series, we observe that atomic sizes of the elements decreases first and subsequently remain constant. The reason for the initial decrease in atomic size is the increase in nuclear charge across the period. After the first few elements in the period, the atomic size remains relatively constant due to shielding effect of the inner d electrons which opposes the increase in effective nuclear charge.

It is also observed that electro negativity increases smoothly across the period for the transition series. Consequently, the transition series become less electro positive across the period.

2. A student was asked to make up a 10% w/w solution of sodium carbonate. Calculate the amount of solute and solvent required to prepare that solution?
please explain step by step

Answers

Answer:

The amount of the solute and solvent can be calculated by the molality. The equation for the molality is as following:

Molality= (mass of solute*1000)/(molar mass*mass of solvent)

it is given that, 10% of Na2CO3 is made,

It means 100gram solution contains 10gram Na2CO3

So, the Mass of solute = 10 gram

then,

Mass of solvent= 100–10 = 90 gram

And, the molar mass of the Na2CO3 = 106 gram

from, now with the help of formula, we can calculate the amount of solute and solvent.

Sodium hydrogen carbonate, also called baking soda, is an active ingredient in some antacids used for the relief of indigestion. Determine the percent of carbon in sodium hydrogen carbonate.

Answers

Answer:

14.30%

Explanation:

Step 1: Given data

Chemical formula of sodium hydrogen carbonate: NaHCO₃

Step 2: Determine the mass of C in 1 mole of NaHCO₃

The is 1 atom of C in 1 molecule of NaHCO₃ and the molar mass of C is 12.01 g/mol. Then, there are 12.01 g of C in 1 mole of NaHCO₃.

Step 3: Determine the mnolar mass of NaHCO₃

M(NaHCO₃) = 1 × M(Na) + 1 × M(H) + 1 × M(C) + 3 × M(O)

M(NaHCO₃) = 1 × 22.98 g/mol + 1 × 1.01 g/mol + 1 × 12.01 g/mol + 3 × 16.00 g/mol = 84.00 g/mol

Step 4: Determine the mass percent of C in NaHCO₃

We will use the following expression.

%C = mC / mNaHCO₃ × 100%

%C = 12.01 g / 84.00 g × 100% = 14.30%

How to convert chloroform to chloretone​

Answers

Chloroform combines with acetone in the presence of potassium hydroxide to give chloretone, which is used as a sleep producing (hypnotic) drug.

1.00 mL of 12.0 M HCl is added to 1.00 L of a buffer that contains 0.110 M HNO2 and 0.170 M NaNO2. How many moles of HNO2 and NaNO2 remain in solution after addition of the HCl

Answers

Answer:

Moles of NaNO2 = 0.158

Moles of HNO2 final = 0.098

Explanation:

Given

Moles of HCl = 12

Moles of HNO2 = 0.11

Moles of NaNO2 = 0.170

HCl +NaNO2 --> HNO2  + NaCl

1 mole of HCl react with one mole of NaNO2 to produce 1 mole of NaCl and 1 mole of HNO2

Moles of NaNO2 = 0.17 - 0.012 = 0.158

Moles of HNO2 final = 0.11 - 0.012 = 0.098

The acid-base reaction between HCl and NaOH produces a solution with a pH of 7 at the equivalence point (NaCl H2O). Why does an acid-base indicator that changes color at pH 5 or 9 work just as well for this reaction as one that changes color at pH 7

Answers

Answer:

Answer is in the explanation.

Explanation:

Before the equivalence point, the pH of the solution of HCl that is titrated with NaOH has a pH <<< 7. When you are adding more NaOH nearing, thus, to the equivalence point the change in pH occurs quickly, and, with 1 drop of excess of NaOH after equivalence, the pH of the solution change to a pH >>> 7

That means the volume added at pH 5 or pH 9 is, almost, the same doing the indicator work just as well as an indicator with change color at pH 7

52.1 mL of aqueous 0.255 M Pb(NO3)2 is mixed with 38.5 mL of 0.415 M NaCl. The equation for the precipitate reaction is: Pb(NO3)2 (aq) 2 NaCl (aq) --> PbCl2 (s) 2 NaNO3 (aq) The concentration of Pb2 ion in the solution is _____ M after the reaction is complete.

Answers

Answer:

0.0585 M

Explanation:

Pb(NO₃)₂ (aq) + 2NaCl (aq) → PbCl₂ (s) + 2NaNO₃ (aq)

First we calculate the inital number of moles of each reagent, using the given volumes and concentrations:

0.255 M Pb(NO₃)₂ * 52.1 mL = 13.3 mmol Pb(NO₃)₂ 0.415 M NaCl * 38.5 mL = 16.0 mmol NaCl

Then we calculate how many Pb(NO₃)₂ moles reacted with 16.0 mmoles of NaCl, using the stoichiometric coefficients of the reaction:

16.0 mmol NaCl * [tex]\frac{1mmolPb(NO_3)_2}{2mmolNaCl}[/tex] = 8.00 mmol Pb(NO₃)₂

Now we calculate the remaining number of Pb(NO₃)₂ moles after the reaction:

13.3 mmol - 8.00 mmol = 5.30 mmol Pb(NO₃)₂

Finally we divide the number of moles by the final volume to calculate the concentration:

5.30 mmol / (52.1 mL + 38.5 mL) = 0.0585 M

How many moles of oxygen atom are there in 0.5 moles of Ca(ClO3) 2?

Answers

Answer:

Do a quick conversion: 1 moles Ca(ClO3)2 = 206.9804 gram using the molecular weight calculator and the molar mass of Ca(ClO3)2. ... How many moles Ca(ClO3 )2 in 1 grams? ... of each element in a chemical formula by the number of atoms of that element present in the formula, then adding all of these products together.

Explanation:

(jayaanilanmol's answer)

g Calculate the pH when (a) 24.9 mL and (b) 25.1 mL of 0.100 M HNO3 have been added to 25.0 mL of 0.100 M KOH solution.

Answers

Answer:

Following are the responses to the given choices:

Explanation:

For point a:

Using the acid and base which are strong so,

moles of [tex]H^+[/tex] (from[tex]HNO_3[/tex])

[tex]= 24.9\ mL \times 0.100\ M \\\\= \frac{24.9}{1000\ L} \times 0.100\ M \\\\= 2.49 \times 10^{-3} \ mol[/tex]

moles of [tex]OH^{-}[/tex] (from [tex]KOH[/tex])

[tex]= 25.0\ mL \times 0.100\ M \\\\= \frac{25.0}{1000 \ L} \times 0.100 \ M \\\\\= 2.50 \times 10^{-3}\ mol[/tex]  

[tex]1\ mol H^{+} \ neutralizes\ 1\ mol\ of\ OH^{-}[/tex]

So,  [tex](2.50 \times 10^{-3} mol - 2.49 \times 10^{-3} mol)[/tex] i.e. [tex]1 \times 10^{-5}[/tex] mol of [tex]OH^-[/tex] in excess in total volume [tex](24.9+25.0) \ mL = 49.9 \ mL[/tex] i.e. concentration of [tex]OH^- = 2 \times 10^{-4}\ M[/tex]

[tex]p[OH^{-}] = -\log [OH^{-}] = -\log [2 \times 10^{-4}\ mol] = 3.70[/tex]

Since, [tex]pH + pOH = 14,[/tex]

so,

[tex]\to pH = 14- pOH = 14- 3.70 = 10.30[/tex]  

For point b:

moles of [tex]OH^-[/tex] = from point a [tex]= 2.50 \times 10^{-3} \ mol[/tex]

moles of [tex]H^+[/tex](from[tex]HNO_3[/tex]):

[tex]= 25.1 mL \times 0.100 M\\\\ = \frac{25.1}{1000}\ L \times 0.100 \ M\\\\ = 2.51\times 10^{-3} \ mol[/tex]

1 mol [tex]H^+[/tex] neutralizes 1 mol of [tex]OH^-[/tex]

So, [tex](2.51 \times 10^{-3}\ mol - 2.50 \times 10^{-3}\ mol)[/tex] i.e. [tex]1 \times 10^{-5} \ mol \ of\ H^+[/tex] in excess in the total volume of [tex](25.1+25.0) \ mL = 50.1\ mL[/tex] i.e. concentration of[tex]H^+ = 2 \times 10^{-4}\ M[/tex]

Hence, [tex]pH = -\log [H^+] = -\log[2 \times 10^{-4}] = 3.70[/tex]

Neap tides happen when ?

Answers

When uh yeah that’s what I’m saying dog
it happens when the sun and moon are at right angles to each other

Some glucose produced by gluconeogenesis is stored in the body as glycogen. Order the steps of glycogen synthesis.

a. Pyrophosphatase converts PPi and water into two Pi
b. Glycogen synthase adds a glucose unit from UDP-glucose to glycogen, producing a larger glycogen molecule and UDP
c. Glvcogen synthase removes a glucose unit from a glycogen molecule producing a smaller glycogen molecule and IJDP
d. ADP-glucose pyrophosphorylase catalyzes the reaction of glucose-I -phosphate and ATP to ADP-glucose and PPi
e. UDP-glucose pyrophosphorylase catalyzes the reaction of glucose-I-phosphate and UTP to UDP-glucose and PPi

Answers

Answer:

e. UDP-glucose pyrophosphorylase catalyzes the reaction of glucose-I-phosphate and UTP to UDP-glucose and PPi

a. Pyrophosphatase converts PPi and water into two Pi

b. Glycogen synthase adds a glucose unit from UDP-glucose to glycogen, producing a larger glycogen molecule and UDP

Explanation:

Glycogen synthesis or glycogenesis is the process of synthesis of glycogen molecules from glucose molecules in living organisms. Glycogen is a polysaccharide storage form of glucose and helps to store excess glucose in the body form use when required by the body.

The synthesis of glycogen involves sugar nucleotides. Sugar nucleotides are compounds in which a sugar molecule is attached to a nucleotide through phosphate ester bond, resulting in the activation of the sugar molecule. The sugar nucleotides then are used as substrates for the polymerization of the monosaccharide sugars into disaccharides, oligosaccharides and polysaccharides.

In the synthesis of glycogen, glucose-6-phosphate from phosphorylation of free glucose by hexokinase is first isomerized to glucose-1-phosphate by phosphoglucomutase.

Glucose-1-phosphate is then converted to UDP-glucose by its reaction with UTP catalyse by UDP-glucose pyrophosphorylase. The reaction is favoured by the rapid hydrolysis of PPi produced to two molecules of inorganic phosphate by the enzyme pyrophosphatase.

Glycogen synthase then adds a glucose unit from UDP-glucose to a growing chain of glycogen, producing a larger glycogen molecule and free UDP.

What characteristic of a light wave in a medium determines the index of refraction of that
medium?

Answers

Answer:

The refractive index can be seen as the factor by which the speed and the wavelength of the radiation are reduced with respect to their vacuum values: the speed of light in a medium is v = c/n, and similarly the wavelength in that medium is λ = λ0/n, where λ0 is the wavelength of that light in vacuum.

Explanation:

Refractive index

Explanation: i need points

How many milliliters of 0.350 M H2SO4 are required to neutralize 60.0 mL of 0.300 M NaOH?

Answers

Answer:

25.7 mL of H₂SO₄

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

H₂SO₄ + 2NaOH —> Na₂SO₄ + 2H₂O

From the balanced equation above,

The mole ratio of acid, H₂SO₄ (nₐ) = 1

The mole ratio of base, NaOH (n₆) = 2

Finally, we shall determine the volume of H₂SO₄ needed for the reaction. This can be obtained as shown below:

Molarity of acid, H₂SO₄ (Mₐ) = 0.350 M

Volume of base, NaOH (V₆) = 60 mL

Molarity of base, NaOH (M₆) = 0.300 M

Volume of acid, H₂SO₄ (Vₐ) = ?

MₐVₐ / M₆V₆ = nₐ/n₆

0.350 × Vₐ / 0.3 × 60 = 1/2

0.350 × Vₐ / 18 = 1/2

Cross multiply

0.350 × 2 × Vₐ = 18

0.7 × Vₐ = 18

Divide both side by 0.7

Vₐ = 18 / 0.7

Vₐ = 25.7 mL

Thus, 25.7 mL of H₂SO₄ is needed for the reaction.

What is the molar mass of H2SO4?
(Molar mass of H = 1.0079 g/mol; S = 32.065 g/mol; O = 15.999 g/mol)

Answers

Answer: 98.08 g/mol

Explanation:

i just took this test and got it right

Answer:

A

Explanation:

What volume of water must be added to 10.5 mL of a pH 2.0 solution of HNO3 in order to change the pH to 4.0 g

Answers

Answer:

[tex]V'=1040ml[/tex]

Explanation:

From the question we are told that:

Initial Volume [tex]V_1=10.5mL[/tex]

Initial Aciditity of [tex]HN0_3 pH_1=2.0g[/tex]

Finial Aciditity of [tex]HN0_3 pH_2=4.0g[/tex]

Generally the equation for Acidity &Volume Relationship is mathematically given by

[tex]N_1V_1=N_2V_2[/tex]

Therefore

[tex]V_2=\frac{N_1V_2}{N_2}[/tex]

[tex]V_2=\frac{10^{-2}*10.5}{10^{-4}}V_2=1050ml[/tex]

Therefore

Change in Water volume is

[tex]V'=V_2-V_1[/tex]

[tex]V'=1050ml-10ml[/tex]

[tex]V'=1040ml[/tex]

Complete and balance equation KI(aq)+BaS(aq)→

Answers

The balanced reaction equation is;  2KI(aq)+BaS(aq)→ K2S(aq) + BaI2(aq)

What is equation?

A chemical equation shows the conversion of reactants into products. Recall that in a chemical reactions, reactans interact with each other to yield products.

For the reaction we have in the question,the complete reaction equation is; 2KI(aq)+BaS(aq)→ K2S(aq) + BaI2(aq)

Learn more about reaction equation; https://brainly.com/question/16921139

This kind of bond is formed when an atom with low electronegativity donates electrons to an
atom with high electronegativity.

Answers

Answer:

Ionic Bond

Explanation:

The atom with the higher electronegativity wants to fill its valence electron shell (meaning it wants 8 electrons in this shell). The atom with lower electronegativity will want to empty or donate an electron so that it can have an empty valence shell.

CH4 (g) + O2 (g) -> CO2 (g) + H20 (g)

Answers

Answer:

CH4(g) + 2O2(g) -> CO2 + 2H2O

Explanation:

Im not sure what the question is but this is the balanced equation.

In the beggingin, there were:

1 C on each side

4 H on the reactants and 2 H on the products

2 O on the reactants and 3 O on the products.

Multiplying the H on the products side by 2 evened out the Hs but the Os became 4 on the products side and 2 on the reactants side so Multiply the O on the products side by 2 evens out the reactans and the products resulting in:

1 C on each side

4 H on each side

4 O on each side

STRONGEST METALL ON EARTH

Answers

Answer:

tungstun

Explanation:

Answer:

tungsten

Explanation:

strongest out of any natural metal (142,000 psi).

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