Step-by-step explanation:
This is your answer for the question
HELPPP MEEEE PLEASEEE I DONT WANNA FAIL SUMMER SCHOOL NO FILES OR LINKS WOULD BE DEEPLY APPRECIATED
it wouldnt let me type the answer-
Help! Possess I will give brainiest!!!!!!!!!!!!!!!!!!!!!!!
Answer:
[tex]\frac{2}{9}[/tex]
Step-by-step explanation:
Since both fractions have a different denominator, we need to look for a common denominator.
[tex]\frac{1}{3}=\frac{3}{9}[/tex] Multiply 3 in both numerator and denominator
[tex]\frac{5}{9} -\frac{3}{9} =\frac{2}{9}[/tex]
Hence, 2/9 is the answer
if the coordinates are ( -1 , 5) and moved 9 units to the left what is the final answer?
Answer:
Directions: Write the new coordinates for each point or figure.
Sample Question:
Point F has the coordinates (-9,6). What are the coordinates of its image point after the translation of six units down and three units to the left?
Answer:
The coordinates of its image point after the translation are (-12, 0).
Explanation: When you look at an ordered pair the x number comes first, followed by the y number (x,y). Moving a point left or right changes the x number. Moving a point up or down changes the y number. Left and down require subtraction, while right and up require addition. In the sample, we had to go 3 units to the left, -9 - 3 = -12. We also had to go 6 units down, so 6 - 6 = 0.
Point Q has the coordinates (9,5). What are the coordinates of its image point after a translation of six units up and three units to the right?
Point P has the coordinates (3,4). What are the coordinates of its image point after a translation of 8 units down and 5 units to the left?
Point Z has the coordinates (10,7). What are the coordinates of its image point after a translation of six units down and three units to the right?
Point Y has the coordinates (0,-4). What are the coordinates of its image point after a translation of 10 units up and 3 units to the left?
Point X has the coordinates (3,-8). What are the coordinates of its image points after a translation of 11 units down and 10 units to the right?
Answer:
(-10,5)
Step-by-step explanation:
Does anyone know how to solve this equation?
9514 1404 393
Answer:
$80
Step-by-step explanation:
You are given the formula ...
P = I/(rt)
and the values I = 20, r = 0.05, t = 5.
Put the numbers in place of the corresponding variables and do the arithmetic.
P = 20/(0.05·5) = 20/0.25 = 80
The amount $80 will generate $20 in interest over 5 years at 5% per year.
Determine the distance between the points (2,7) and (-4,15)
Answer:
option C
Step-by-step explanation:
[tex]distance = \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2}[/tex]
[tex]=\sqrt{(-4-2)^2+(15-7)^2} \\\\=\sqrt{(-6)^2 + 8^2}\\\\=\sqrt{36 + 64 }\\\\= \sqrt{100} \\\\= 10[/tex]
What is the answer to this
Answer:
A
Step-by-step explanation:
Answer:
[tex]x < - 2[/tex]
Step-by-step explanation:
Hope it is helpful...
PLEASEEEEEE I NEEED HELLPPPPP IM BEGGGINGGGG SOMONE PLEASEEEEE HELPPPPPPPPPPPP
Answer:
2nd option:
8x+2y=32
x+y=7
Step-by-step explanation:
Answer:
It is in fact the second one.
Step-by-step explanation:
It says that he bought a total of 7 tickets and it cost $32.
x represents the number of adult tickets and y represents the number of chid tickets.
So:
x + y = 7 because the adding the number of adult and child tickets should equal the total number bought.
and
8x + 2y = 32 because each adult ticket was 8 dollars and each child was 2 and the total should add up to 32
Can someone please help me with this?? I will like your comment!
Answer:
[tex]A_{\Delta ABP}=\sin \theta[/tex]
Step-by-step explanation:
Let the center of the circle be O.
Recall that the area of a triangle can be given by:
[tex]\displaystyle A=\frac{1}{2} ab\sin C[/tex]
Where C is the angle between the two sides.
ΔABP is equal to the sum of ΔAPO and ΔBOP.
Let a = OP and b = OB. Since this is the unit circle and PO and BO are radii, they both equal one. C will be θ. Hence, the area of ΔBOP is:
[tex]\displaystyle A_{\Delta BOP}=\frac{1}{2}(1)(1)\sin \theta=\frac{1}{2}\sin\theta[/tex]
For ΔAPO, we can use the two sides OP and OA. Again, they are the radii of the unit circle, so they equal one. The angle in this case will be π - θ radians. Hence:
[tex]\displaystyle A_{\Delta APO}=\frac{1}{2}(1)(1)\sin\left(\pi -\theta\right)=\frac{1}{2}\sin\left(\pi -\theta\right)[/tex]
However, note that sin(π - θ) = sin(θ). Hence:
[tex]\displaystyle A_{\Delta APO}=\frac{1}{2}\sin\left(\theta\right)[/tex]
Hence, the area of ΔABP is:
[tex]\displaystyle A_{\Delta ABP}=\frac{1}{2}\sin \theta+\frac{1}{2}\sin\theta =\sin \theta[/tex]
If right get brainly!! 20 points!!
TR (N)*2
or in other words triangle number of N times 2
Answer:
NEDD POITS SERY
Step-by-step explanation:
Challenge: Solve x+3y=-6 for x. Then use your value for x to solve for y.
X=
Y=
Answer:
X = -6 - 3y
Y = -1
Step-by-step explanation: Solve for X first using basic algebra. Plug in X vaalue to original equation and solve. -6 - 3y + 3y = -6. Solve by adding 6 to both sides of the equation and dividing -3y by 3y.
the rectangle prism below has a volume of 464 3/4 cubic meters. a- write an equation that could be used to find the length of the prism b- find the length, show your work.
PLEASE HELP!!
Answer:
ok
Step-by-step explanation:
please mark me brainleast
I'm kinda lost here, what do I do when the quadrant is given? CanI have some of these solved at least with steps?
Answer:
See Explaination
Step-by-step explanation:
According To Question
In Quadrant-1 (0* to 90*) ( All the Trignometry Functions are Positive )In Quadrant-2 (90* to 180*) (Only Sine & Cosecant are Positive)In Quadrant-3 (180* to 270*) (Only Tangent & Cotangent Are Positive)In Quadrant-4 (270* to 360*) ( Only Cosine & Secant Are Positive)(Diagram, Please Find In Attachment)
Question 38 . Cos ∅ = 12/13 ∅ in Quadrant-4(Where only Cos & Sec are Positive all other Functions Are Negative in this Quadrant)
Now ∅ Represent a Right Angle Triangle with Base=12 Perpendicular=5 & Hypothenese=13
other Five Trignometry Functions Are as FollowSin∅ = -5/13 , Cosec∅=-13/5 , Tan∅=-5/12 , Cot∅=-12/5 & Sec∅=13/12
Question 39 . SinX=-3/4 X Lies in Quadrant-3(Where only Tan & Cot are Positive all other Functions Are Negative in this Quadrant)
Now For Other Trignometry FunctionsFind By Using Basic Formulas
[tex]SinX^{2}+CosX^{2}=1[/tex] ↔ Put Value of Sin∅=-3/4
We get CosX= ±[tex]\frac{\sqrt{5} }{4}[/tex] (but X Lies in Quadrant-3 Where Cosine Is Negative , So Neglect CosX= +[tex]\frac{\sqrt{5} }{4}[/tex])
So CosX= -[tex]\frac{\sqrt{5} }{4}[/tex] ...... now you get the point . All Questions Will Solve like This .
identify EFG
Answer Options:
= 45
= 35
= 22.5
=27.5
Answer:
22.5
Step-by-step explanation:
Inscribed Angle =1/2 Intercepted Arc
F = 1/2 (45)
<F = 22.5
252k is a perfect square. Find any two possible values of k.
f(x)=−2x
2
+8x−10
\text{Find }f(-4)
Find f(−4)
Answer:
-74
Step-by-step explanation:
f(x) = -2x^2 +8x -10
Let x = -4
f(-4) = -2 ( -4)^2 +8(-4) -10
= -2(16) -32-10
= -32 -32-10
= -74
A wave with a frequency of 60 hertz would generate 60 wave crests every
- 1 7/8 + 2 1/4
Plz help im confused
[tex]0.375[/tex] ✅
Step-by-step explanation:
[tex] - 1 \frac{7}{8} + 2 \frac{1}{4} \\ = - \frac{15}{8} + \frac{9}{4} \\ = - \frac{15}{8} + \frac{9 \times 2}{4 \times 2} \\ = \frac{ - 15 + 18}{8} \\ = \frac{3}{8} \\ = 0.375[/tex]
[tex]\large\mathfrak{{\pmb{\underline{\orange{Happy\:learning }}{\orange{!}}}}}[/tex]
Determine the time 2 hours and 7 minutes after 22:57
Answer:
01:04
Step-by-step explanation:
add 7 minutes to 22:57 to get 23:04. then add 2 hours to get to 01:04.
Graph the inequality. y ≥ |x + 5| - 3
Answer:
1
Step-by-step explanation:
Rewrite each side with a common base and solve. Round your answer to two decimal places.
3^4x=1/27
Jen factored x² - 4x - 21 as (x - 3)(x + 7) What did she do wrong?
Answer:
She didn't put the sign's in the proper place, it should be ( x + 3 ) ( x - 7 )
Step-by-step explanation:
( x - 3 ) ( x + 7 ) = x² + 7x - 3x - 21 = x² + 4x - 21
( x + 3 ) ( x - 7 ) = x² - 7x + 3x - 21 = x² - 4x - 21
[Pre-Calc] Please Help! I don’t know where to start. How do I do this?
Answer:
See Below.
Step-by-step explanation:
Problem A)
We have:
[tex]\displaystyle \csc^2\theta \tan^2\theta -1=\tan^2\theta[/tex]
When in doubt, convert all reciprocal trig functions and tangent into terms of sine and cosine.
So, let cscθ = 1/sinθ and tanθ = sinθ/cosθ. Hence:
[tex]\displaystyle \left(\frac{1}{\sin^2\theta}\right)\left(\frac{\sin^2\theta}{\cos^2\theta}\right)-1=\tan^2\theta[/tex]
Cancel:
[tex]\displaystyle \frac{1}{\cos^2\theta}-1=\tan^2\theta[/tex]
Let 1/cosθ = secθ:
[tex]\sec^2\theta -1=\tan^2\theta[/tex]
From the Pythagorean Identity, we know that tan²θ + 1 = sec²θ. Hence, sec²θ - 1 = tan²θ:
[tex]\tan^2\theta =\tan^2\theta[/tex]
Problem B)
We have:
[tex]\sin^3x=\sin x-\sin x \cos^2 x[/tex]
Factor out a sine:
[tex]\sin x(\sin^2 x)=\sin x-\sin x\cos^2 x[/tex]
From the Pythagorean Identity, sin²θ + cos²θ = 1. Hence, sin²θ = 1 - cos²θ:
[tex]\sin x(1-\cos^2 x)=\sin x-\sin x\cos^2x[/tex]
Distribute:
[tex]\sin x- \sin x \cos^2 x=\sin x-\sin x\cos^2 x[/tex]
Problem C)
We have:
[tex]\displaystyle \frac{\cos 2x+1}{\sin 2x}=\cot x[/tex]
Recall that cos2θ = cos²θ - sin²θ and that sin2θ = 2sinθcosθ. Hence:
[tex]\displaystyle \frac{\cos^2 x-\sin^2 x+1}{2\sin x\cos x}=\cot x[/tex]
From the Pythagorean Identity, sin²θ + cos²θ = 1 so cos²θ = 1 - sin²θ:
[tex]\displaystyle \frac{2\cos^2 x}{2\sin x\cos x}=\cot x[/tex]
Cancel:
[tex]\displaystyle \frac{\cos x}{\sin x}=\cot x[/tex]
By definition:
[tex]\cot x = \cot x[/tex]
hey this is my first post, does anyone know how to do this and find V?
Answer:
16
Step-by-step explanation:
8/1/2
8 divided by 1/2
8 x 2/1 = 16
Answer:
Step-by-step explanation:
P=8/V
1/2=8/V
do cross multiplication
2*8=V*1
16=V
Suppose the probability of failure in a binomial experiment is 0.25. What is
the probability of success?
A. 0.65
B. 0.85
C. 0.75
D. 0.35
Answer:
C: .75
Step-by-step explanation:
I really just subtracted
HELP PLZZZ !!
3. Solve the equation by factoring.
C^2 - 4c = 0
Answer:
0,4
Step-by-step explanation:
See image below:)
calculate the circumference of a circle with a radius of 7.5. show or explain your reasoning.
Find the value of unknown angles.
Х
50
Answer:
[tex]x = 70^o[/tex]
Step-by-step explanation:
Given
See attachment for triangle
Required
Find x
To solve for x, we make use of:
[tex]x + 50^o + 60^o = 180^o[/tex] --- angles in a triangle
[tex]x + 110^o = 180^o[/tex]
Collect like terms
[tex]x = 180^o-110^o[/tex]
[tex]x = 70^o[/tex]
You choose a marble at random from a bag contains 12 red 10 blue 5 green 4 yellow and 29 black marbles. The marble is red.
Step-by-step explanation:
P(red) = 12/(12+10+5+4+29)
= 12/60
= 1/5
= 0.2
= 20%
Which equation can be used to solve for x?
A. sin (x) =
30
18
B. cos (x)
30
24
C. cos (x)
24
30
D.
tan (x)
24
18
NÉED HELP ASAP PLEASE check the picture
Answer:
[tex] \cos(x) = \frac{24}{30} [/tex]
OPTION C
The number of road construction projects that take place at any one time in a certain city follows a Poisson distribution with a mean of 6. Find the probability that less than 3 road construction projects are currently taking place in this city.a) 0.050409b) 0.089235c) 0.301168d) 0.014936
Answer:
The probability that less than 3 road construction projects are currently taking place in this city is 0.06197
Step-by-step explanation:
In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:
[tex]P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}[/tex]
In which
x is the number of sucesses
e = 2.71828 is the Euler number
[tex]\mu[/tex] is the mean in the given interval.
Poisson distribution with a mean of 6.
This means that [tex]\mu = 6[/tex]
Find the probability that less than 3 road construction projects are currently taking place in this city.
This is:
[tex]P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2)[/tex]
So
[tex]P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}[/tex]
[tex]P(X = 0) = \frac{e^{-6}*6^{0}}{(0)!} = 0.00248[/tex]
[tex]P(X = 1) = \frac{e^{-6}*6^{1}}{(1)!} = 0.01487[/tex]
[tex]P(X = 2) = \frac{e^{-6}*6^{2}}{(2)!} = 0.04462[/tex]
[tex]P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2) = 0.00248 + 0.01487 + 0.04462 = 0.06197[/tex]
The probability that less than 3 road construction projects are currently taking place in this city is 0.06197