predict the major and minor products of the reaction. name the products using systematic names. ch3ch=ch2+h2o-->h+
Answer:
major will be propan-2-ol
minor will be propan-1-ol
Select all the true statements.
a. Ionic bonding is more prevalent for the higher oxidation states and covalent bonding is more prevalent for the lower states.
b. The highest oxidation state of elements in Groups 3A through 7B is +3.
c. In the transition series, atomic size across a period decreases at first but then remains relatively constant.
d. The transition elements in a period show a steady increase in electronegativity.
Answer:
In the transition series, atomic size across a period decreases at first but then remains relatively constant.
The transition elements in a period show a steady increase in electronegativity.
Explanation:
In considering the transition series, we observe that atomic sizes of the elements decreases first and subsequently remain constant. The reason for the initial decrease in atomic size is the increase in nuclear charge across the period. After the first few elements in the period, the atomic size remains relatively constant due to shielding effect of the inner d electrons which opposes the increase in effective nuclear charge.
It is also observed that electro negativity increases smoothly across the period for the transition series. Consequently, the transition series become less electro positive across the period.
Sodium hydrogen carbonate, also called baking soda, is an active ingredient in some antacids used for the relief of indigestion. Determine the percent of carbon in sodium hydrogen carbonate.
Answer:
14.30%
Explanation:
Step 1: Given data
Chemical formula of sodium hydrogen carbonate: NaHCO₃
Step 2: Determine the mass of C in 1 mole of NaHCO₃
The is 1 atom of C in 1 molecule of NaHCO₃ and the molar mass of C is 12.01 g/mol. Then, there are 12.01 g of C in 1 mole of NaHCO₃.
Step 3: Determine the mnolar mass of NaHCO₃
M(NaHCO₃) = 1 × M(Na) + 1 × M(H) + 1 × M(C) + 3 × M(O)
M(NaHCO₃) = 1 × 22.98 g/mol + 1 × 1.01 g/mol + 1 × 12.01 g/mol + 3 × 16.00 g/mol = 84.00 g/mol
Step 4: Determine the mass percent of C in NaHCO₃
We will use the following expression.
%C = mC / mNaHCO₃ × 100%
%C = 12.01 g / 84.00 g × 100% = 14.30%
How to convert chloroform to chloretone
1.00 mL of 12.0 M HCl is added to 1.00 L of a buffer that contains 0.110 M HNO2 and 0.170 M NaNO2. How many moles of HNO2 and NaNO2 remain in solution after addition of the HCl
Answer:
Moles of NaNO2 = 0.158
Moles of HNO2 final = 0.098
Explanation:
Given
Moles of HCl = 12
Moles of HNO2 = 0.11
Moles of NaNO2 = 0.170
HCl +NaNO2 --> HNO2 + NaCl
1 mole of HCl react with one mole of NaNO2 to produce 1 mole of NaCl and 1 mole of HNO2
Moles of NaNO2 = 0.17 - 0.012 = 0.158
Moles of HNO2 final = 0.11 - 0.012 = 0.098
The acid-base reaction between HCl and NaOH produces a solution with a pH of 7 at the equivalence point (NaCl H2O). Why does an acid-base indicator that changes color at pH 5 or 9 work just as well for this reaction as one that changes color at pH 7
Answer:
Answer is in the explanation.
Explanation:
Before the equivalence point, the pH of the solution of HCl that is titrated with NaOH has a pH <<< 7. When you are adding more NaOH nearing, thus, to the equivalence point the change in pH occurs quickly, and, with 1 drop of excess of NaOH after equivalence, the pH of the solution change to a pH >>> 7
That means the volume added at pH 5 or pH 9 is, almost, the same doing the indicator work just as well as an indicator with change color at pH 7
52.1 mL of aqueous 0.255 M Pb(NO3)2 is mixed with 38.5 mL of 0.415 M NaCl. The equation for the precipitate reaction is: Pb(NO3)2 (aq) 2 NaCl (aq) --> PbCl2 (s) 2 NaNO3 (aq) The concentration of Pb2 ion in the solution is _____ M after the reaction is complete.
Answer:
0.0585 M
Explanation:
Pb(NO₃)₂ (aq) + 2NaCl (aq) → PbCl₂ (s) + 2NaNO₃ (aq)First we calculate the inital number of moles of each reagent, using the given volumes and concentrations:
0.255 M Pb(NO₃)₂ * 52.1 mL = 13.3 mmol Pb(NO₃)₂ 0.415 M NaCl * 38.5 mL = 16.0 mmol NaClThen we calculate how many Pb(NO₃)₂ moles reacted with 16.0 mmoles of NaCl, using the stoichiometric coefficients of the reaction:
16.0 mmol NaCl * [tex]\frac{1mmolPb(NO_3)_2}{2mmolNaCl}[/tex] = 8.00 mmol Pb(NO₃)₂Now we calculate the remaining number of Pb(NO₃)₂ moles after the reaction:
13.3 mmol - 8.00 mmol = 5.30 mmol Pb(NO₃)₂Finally we divide the number of moles by the final volume to calculate the concentration:
5.30 mmol / (52.1 mL + 38.5 mL) = 0.0585 MHow many moles of oxygen atom are there in 0.5 moles of Ca(ClO3) 2?
Answer:
Do a quick conversion: 1 moles Ca(ClO3)2 = 206.9804 gram using the molecular weight calculator and the molar mass of Ca(ClO3)2. ... How many moles Ca(ClO3 )2 in 1 grams? ... of each element in a chemical formula by the number of atoms of that element present in the formula, then adding all of these products together.
Explanation:
(jayaanilanmol's answer)
Some glucose produced by gluconeogenesis is stored in the body as glycogen. Order the steps of glycogen synthesis.
a. Pyrophosphatase converts PPi and water into two Pi
b. Glycogen synthase adds a glucose unit from UDP-glucose to glycogen, producing a larger glycogen molecule and UDP
c. Glvcogen synthase removes a glucose unit from a glycogen molecule producing a smaller glycogen molecule and IJDP
d. ADP-glucose pyrophosphorylase catalyzes the reaction of glucose-I -phosphate and ATP to ADP-glucose and PPi
e. UDP-glucose pyrophosphorylase catalyzes the reaction of glucose-I-phosphate and UTP to UDP-glucose and PPi
Answer:
e. UDP-glucose pyrophosphorylase catalyzes the reaction of glucose-I-phosphate and UTP to UDP-glucose and PPi
a. Pyrophosphatase converts PPi and water into two Pi
b. Glycogen synthase adds a glucose unit from UDP-glucose to glycogen, producing a larger glycogen molecule and UDP
Explanation:
Glycogen synthesis or glycogenesis is the process of synthesis of glycogen molecules from glucose molecules in living organisms. Glycogen is a polysaccharide storage form of glucose and helps to store excess glucose in the body form use when required by the body.
The synthesis of glycogen involves sugar nucleotides. Sugar nucleotides are compounds in which a sugar molecule is attached to a nucleotide through phosphate ester bond, resulting in the activation of the sugar molecule. The sugar nucleotides then are used as substrates for the polymerization of the monosaccharide sugars into disaccharides, oligosaccharides and polysaccharides.
In the synthesis of glycogen, glucose-6-phosphate from phosphorylation of free glucose by hexokinase is first isomerized to glucose-1-phosphate by phosphoglucomutase.
Glucose-1-phosphate is then converted to UDP-glucose by its reaction with UTP catalyse by UDP-glucose pyrophosphorylase. The reaction is favoured by the rapid hydrolysis of PPi produced to two molecules of inorganic phosphate by the enzyme pyrophosphatase.
Glycogen synthase then adds a glucose unit from UDP-glucose to a growing chain of glycogen, producing a larger glycogen molecule and free UDP.
What characteristic of a light wave in a medium determines the index of refraction of that
medium?
Answer:
The refractive index can be seen as the factor by which the speed and the wavelength of the radiation are reduced with respect to their vacuum values: the speed of light in a medium is v = c/n, and similarly the wavelength in that medium is λ = λ0/n, where λ0 is the wavelength of that light in vacuum.
Explanation:
How many milliliters of 0.350 M H2SO4 are required to neutralize 60.0 mL of 0.300 M NaOH?
Answer:
25.7 mL of H₂SO₄
Explanation:
We'll begin by writing the balanced equation for the reaction. This is illustrated below:
H₂SO₄ + 2NaOH —> Na₂SO₄ + 2H₂O
From the balanced equation above,
The mole ratio of acid, H₂SO₄ (nₐ) = 1
The mole ratio of base, NaOH (n₆) = 2
Finally, we shall determine the volume of H₂SO₄ needed for the reaction. This can be obtained as shown below:
Molarity of acid, H₂SO₄ (Mₐ) = 0.350 M
Volume of base, NaOH (V₆) = 60 mL
Molarity of base, NaOH (M₆) = 0.300 M
Volume of acid, H₂SO₄ (Vₐ) = ?
MₐVₐ / M₆V₆ = nₐ/n₆
0.350 × Vₐ / 0.3 × 60 = 1/2
0.350 × Vₐ / 18 = 1/2
Cross multiply
0.350 × 2 × Vₐ = 18
0.7 × Vₐ = 18
Divide both side by 0.7
Vₐ = 18 / 0.7
Vₐ = 25.7 mL
Thus, 25.7 mL of H₂SO₄ is needed for the reaction.
What is the molar mass of H2SO4?
(Molar mass of H = 1.0079 g/mol; S = 32.065 g/mol; O = 15.999 g/mol)
Answer: 98.08 g/mol
Explanation:
i just took this test and got it right
Answer:
A
Explanation:
What volume of water must be added to 10.5 mL of a pH 2.0 solution of HNO3 in order to change the pH to 4.0 g
Answer:
[tex]V'=1040ml[/tex]
Explanation:
From the question we are told that:
Initial Volume [tex]V_1=10.5mL[/tex]
Initial Aciditity of [tex]HN0_3 pH_1=2.0g[/tex]
Finial Aciditity of [tex]HN0_3 pH_2=4.0g[/tex]
Generally the equation for Acidity &Volume Relationship is mathematically given by
[tex]N_1V_1=N_2V_2[/tex]
Therefore
[tex]V_2=\frac{N_1V_2}{N_2}[/tex]
[tex]V_2=\frac{10^{-2}*10.5}{10^{-4}}V_2=1050ml[/tex]
Therefore
Change in Water volume is
[tex]V'=V_2-V_1[/tex]
[tex]V'=1050ml-10ml[/tex]
[tex]V'=1040ml[/tex]
Complete and balance equation KI(aq)+BaS(aq)→
The balanced reaction equation is; 2KI(aq)+BaS(aq)→ K2S(aq) + BaI2(aq)
What is equation?A chemical equation shows the conversion of reactants into products. Recall that in a chemical reactions, reactans interact with each other to yield products.
For the reaction we have in the question,the complete reaction equation is; 2KI(aq)+BaS(aq)→ K2S(aq) + BaI2(aq)
Learn more about reaction equation; https://brainly.com/question/16921139
This kind of bond is formed when an atom with low electronegativity donates electrons to an
atom with high electronegativity.
Answer:
Ionic Bond
Explanation:
The atom with the higher electronegativity wants to fill its valence electron shell (meaning it wants 8 electrons in this shell). The atom with lower electronegativity will want to empty or donate an electron so that it can have an empty valence shell.
STRONGEST METALL ON EARTH
Answer:
tungstun
Explanation:
Answer:
tungsten
Explanation:
strongest out of any natural metal (142,000 psi).
When does a redox reaction produce electricity?
A. Only when an electrical device is attached
B. Whenever electrons are transferred between atoms
C. When electrons are transfered, and a pathway for electrons is provided
D. Whenever a pathway for electrons is provided
Based on a specific example of titration method. How do titration methods play a role in agriculture industry?
Answer:
Titration is an analytical technique that is widely used in the food industry. It allows food manufacturers to determine the quantity of a reactant in a sample. For example, it can be used to discover the amount of salt or sugar in a product or the concentration of vitamin C or E, which has an effect on product colour.
Answer:
How is titration used in the industry?
Titration is an analytical technique that is widely used in the food industry. It allows food manufacturers to determine the quantity of a reactant in a sample. For example, it can be used to discover the amount of salt or sugar in a product or the concentration of vitamin C or E, which has an effect on product colour.
help i’ll give u points
Answer:
60ug
Explanation:
If it has experienced two half lives, that means it has been halved twice. in that case, to undo it, just multiply it by two twice. 0.15ug * 2 = 0.30ug. 0.30ug * 2 = 0.60ug. Hope this helps.
12. Which of the following metals is NOT obtained by commercial
electrolytic process?
B) AI
C) Cu
A) Ag
D) Na
An ideal gas at 2.0 atm pressure and 298 K temperature has a volume of 12.0 L. If the volume is decreased to 4.0 L and the temperature is held constant, what is the new pressure of the the gas in atm
Answer:
[tex]P_2=6.0atm[/tex]
Explanation:
Hello there!
In this case, according to the given information, it turns out possible for us to solve this problem by using the Boyle's law, since the temperature is constant and both volume and pressure change:
[tex]P_2V_2=P_1V_1[/tex]
Thus, we solve for the final pressure, P2, to obtain:
[tex]P_2=\frac{P_1V_1}{V_2}[/tex]
And plug in the given data to get:
[tex]P_2=\frac{2.0atm*12.0L}{4.0L}\\\\P_2=6.0atm[/tex]
Regards!
A monoprotic weak acid when dissolved in water is 0.66% dissociated and produces a solution with a pH of 3.04. Calculate the Ka of the acid. g
Answer:
Ka = 6.02x10⁻⁶
Explanation:
The equilibrium that takes place is:
HA ⇄ H⁺ + A⁻Ka = [H⁺][A⁻]/[HA]We calculate [H⁺] from the pH:
pH = -log[H⁺][H⁺] = [tex]10^{-pH}[/tex][H⁺] = 9.12x10⁻⁴ MKeep in mind that [H⁺]=[A⁻].
As for [HA], we know the acid is 0.66% dissociated, in other words:
[HA] * 0.66/100 = [H⁺]We calculate [HA]:
[HA] = 0.138 MFinally we calculate the Ka:
Ka = [tex]\frac{[9.12x10^{-4}]*[9.12x10^{-4}]}{[0.138]}[/tex] = 6.02x10⁻⁶calculate the mass in grams for 3.01 x 10^23 of Sulfur
You heat a 5.05 g piece of titanium to 98.2 oC and place it into 20.00 mL of room temperature water (24.8 oC ). The temperature of the water rises to 27.3 oC. The specific heat of water is 4.184 J/goC. The density of water is 0.997 g/mL. A. How much heat is absorbed by the water (in units of J)
Answer: The heat absorbed by the water is 52.823 J.
Explanation:
Given: Mass of metal = 5.05 g
Specific heat of water = 4.184 [tex]J/g^{o}C[/tex]
Initial temperature = [tex]24.8^{o}C[/tex]
Final temperature = [tex]27.3^{o}C[/tex]
Formula used to calculate heat absorbed is as follows.
[tex]q = m \times C \times (T_{2} - T_{1})[/tex]
where,
q = heat
m = mass of substance
[tex]T_{1}[/tex] = initial temperature
[tex]T_{2}[/tex] = final temperature
Substitute the values into above formula as follows.
[tex]q = m \times C \times (T_{2} - T_{1})\\= 5.05 g \times 4.184 J/g^{o}C \times (27.3 - 24.8)^{o}C\\= 52.823 J[/tex]
Thus, we can conclude that heat absorbed by the water is 52.823 J.
B. Directions: Identify the factors affecting the different seasons in the Philippines.
1. Areas with less rainfall, has a pronounced dry
season. When it always rain, that place has wet season most of the year.
2. The higher the particular place, the cooler its
temperature.
3. Climate near in coastal areas is cooler because
water does not absorb heat as fast as land area.
4. . When large amount of warm air cool, if gives off
lots of rain over the land
5. Philippines lies near the equator, has warm climate
during certain times of the year.
Answer:
The correct answer is -
1. Latitude
2. Altitude
3. Bodies of water
4. Wind system
5. Amount of rainfall
Explanation:
Lattitude is the angle from the earth's equator towards the north or south to the poles. This is one of the important factors that lead to different seasons and define the temperature of the area.
Altitude is the elevation from the sea that also helps in affecting the seasons as the higher the altitude cooler the temperature. Water bodies like the sea affect the wind and climate as they are not able to absorb heat faster in comparison to the land.
Wind also affects the seasons and climate of the area as a large amount of warm air cools, it gives off lots of rain over the land. Precipitation or rainfall determines and influences the climate.
2Al + 6HCl → 2AlCl3 + 3H2
You want to make 10 moles of AlCl3. How many moles of HCl does that require?
Answer: If you want to make 10 moles of [tex]AlCl_{3}[/tex] then 30 moles of HCl are required in the given reaction.
Explanation:
The given reaction equation is as follows.
[tex]2Al + 6HCl \rightarrow 2AlCl_{3} + 3H_{2}[/tex]
Here, 6 moles of HCl reacts with 2 moles of [tex]AlCl_{3}[/tex]. This means that 1 mole of [tex]AlCl_{3}[/tex] is obtained as follows.
[tex]\frac{6}{2} HCl\\= 3 HCl[/tex]
Hence, 3 moles of HCl will give 1 mole of [tex]AlCl_3[/tex]. So, moles of HCl required to react with 10 moles of [tex]AlCl_{3}[/tex] is as follows.
[tex]1 mol AlCl_3 = 3 mol HCl\\10 mol AlCl_{3} = 3 \times 10 mol HCl\\= 30 mol HCl[/tex]
Thus, we can conclude that if you want to make 10 moles of [tex]AlCl_{3}[/tex] then 30 moles of HCl are required in the given reaction.
How does the neutron number in each compare
Answer:
Neutrons are all identical to each other, just as protons are. Atoms of a particular element must have the same number of protons but can have different numbers of neutrons.
Explanation:
Since the vast majority of an atom's mass is found its protons and neutrons, subtracting the number of protons (i.e. the atomic number) from the atomic mass will give you the calculated number of neutrons in the atom. In our example, this is: 14 (atomic mass) – 6 (number of protons) = 8 (number of neutrons).
Write the Ka expression for an aqueous solution of hypochlorous acid: (Note that either the numerator or denominator may contain more than one chemical species. Enter the complete numerator in the top box and the complete denominator in the bottom box. Remember to write the hydronium ion out as , and not as )
Answer: The Ka expression for an aqueous solution of hypochlorous acid is [tex]K_{a} = \frac{[H_{3}O^{+}][OCl^{-}]}{[HClO]}[/tex].
Explanation:
The chemical formula of hypochlorous acid is HClO. So, when it is added to water (solvent) then its dissociation is as follows.
[tex]HClO + H_{2}O \rightarrow H_{3}O^{+} + Cl^{-}[/tex]
When we write the equilibrium constant for this reaction then it is called acid acid dissociated constant.
Hence, the expression for acid dissociation constant of this reaction is as follows.
[tex]K_{a} = \frac{[H_{3}O^{+}][OCl^{-}]}{[HClO]}[/tex]
Thus, we can conclude that the Ka expression for an aqueous solution of hypochlorous acid is [tex]K_{a} = \frac{[H_{3}O^{+}][OCl^{-}]}{[HClO]}[/tex].
gabriel created 270 grams of aluminum oxide from 145 grams of aluminum. what was his percent yield?
A. 99.1%
B. 98.6%
C. 97.2%
D.96.5%
( it’s not “D” because I got it wrong lol) pls help tho
Answer:
% yield = 200%
Explanation:
By using 145 gram of aluminium
Using 26.982 g/mol of Al, 101.96 g/mol of Aluminium oxide is produced
Using 145 grams of aluminium, the yield of Aluminium oxide would have been = (101.96 g/mol/26.982 g/mol)/145 grams
= 547.9282485 gram
Now % yield = actual yield /theoretical yield * 100
Substituting the given values, we get -
% yield = (547.928/270) *100
% yield = 200%
balance this equation plz
SO2+O2+H2O------->H2SO4
Answer: The balanced equation is [tex]2SO_{2} + O_{2} + 2H_{2}O \rightarrow 2H_{2}SO_{4}[/tex].
Explanation:
A chemical equation which contains same number of atoms on both reactant and product side is called a balanced chemical equation.
For example, [tex]SO_{2} + O_{2} + H_{2}O \rightarrow H_{2}SO_{4}[/tex]
Here, number of atoms present on reactant side are as follows.
S = 1O = 5H = 2Number of atoms present on product side are as follows.
S = 1O = 4H = 2To balance this equation, multiply [tex]SO_{2}[/tex] by 2 and [tex]H_{2}O[/tex] by 2 on reactant side. Also, multiply [tex]H_{2}SO_{4}[/tex] by 2 on product side.
Hence, the equation can be re-written as follows.
[tex]2SO_{2} + O_{2} + 2H_{2}O \rightarrow 2H_{2}SO_{4}[/tex]
Now, the number of atoms present on reactant side are as follows.
S = 2O = 8H = 4Number of atoms present on product side are as follows.
S = 2O = 8H = 4Since, the atoms present on both reactant and product side are equal. Hence, the equation is now balanced.
Thus, we can conclude that the balanced equation is [tex]2SO_{2} + O_{2} + 2H_{2}O \rightarrow 2H_{2}SO_{4}[/tex].
