The conversion of thermal energy into mechanical energy requires
a thermometer.
D. Beat engine
C vaporizer.
d thermostat.
A car starting from rest has a constant acceleration of 4 meters per second per second. How fast will it be going in 5 seconds?
Answer:
18 m
Explanation:
Given : vo = 0 m/s ; t = 3 s; a = 4 m/s^2 ; d = ? m ; average velocity = ? m/s ; fonal velocity = ? m/s
solving for the final velocity, v
v = a * t
v = 4 m/s^2 * 3 s
v = 12 m / s
Solving for the average velocity. avg v
avg v = (vo + v) / 2
avg v = (0 m / s + 12 m/s) / 2
avg v = 6 m / s
Solving for the distance traveled after 3 s
d = avg v * t
d = 6 m / s * 3 s
d = 18 meters
In the first 3s the car travels 18 meters.
If a car starting from rest has a constant acceleration of 4 meters per second per second, then it would be going at a speed of 20 m / s.
What are the three equations of motion?There are three equations of motion given by Newton,
v = u + at
S = ut + 1/2 × a × t²
v² - u² = 2 × a × s
As given in the problem, a car starting from rest has a constant acceleration of 4 meters per second per second,
By using the first equation of the motion,
v = u + at
v = 0 + 4 × 5
v = 20 m / s
Thus,If a car starting from rest has a constant acceleration of 4 meters per second per second, then it would be going at a speed of 20 m / s.
To learn more about equations of motion here, refer to the link given below ;
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Long Shore Drift is the ...
A. landforms along the shoreline of an ocean or sea
B. submerged or partly exposed ridge of sand along an ocean front
C. accumulation of sand grains along a beach front
D. movement of material along a coast by waves that approach at an angle to the shore.
Answer: D. movement of material along a coast by waves that approach at an angle to the shore.
Explanation:
Longshore drift is also referred to as the littoral druft and it means the sediment that is moved by the longshore current.
Longshore drift is the movement of material along a coast by waves which approach at an angle to the shore but then recede down the beach.
Therefore, the correct option is D.
An electric eel develops a potential difference of 470 V , driving a current of 0.85 A for a 1.0 ms pulse. Part A Find the power of this pulse.
Answer:
399.5 Watts.
Explanation:
From the question given above, the following data were obtained:
Potential difference (V) = 470 V
Current (I) = 0.85 A
Time (t) = 1 ms
Power (P) =?
Electrical power is defined by the following equation:
Power (P) = potential difference (V) × current (I)
P = IV
Using the above formula, the power can be obtained as follow:
Potential difference (V) = 470 V
Current (I) = 0.85 A
Power (P) =?
P = IV
P = 470 × 0.85
P = 399.5 Watts
Therefore, the power is 399.5 Watts.
Which of the following statements best describes energy conservation in heat engines?
A. The heat engine's energy is exhausted to the outside system.
B. The sum of the heat placed into the hot reservoir and the work collected equals the energy transferred from the cold reservoir.
C. A volume of heat is discharged to the cold body where some waste energy is in a form of heat in this engine.
D. The work derived from the heat engine is equal to the energy placed into the hot reservoir.
A car is traveling at a constant speed of 33 m/s on a highway. At the instant this car passes an entrance ramp, a second car enters the highway from the ramp. The second car starts from rest and has a constant acceleration. What acceleration must it maintain, so that the two cars meet for the first time at the next exit, which is 2.5 km away
Answer:
0.8712 m/s²
Explanation:
We are given;
Velocity of first car; v1 = 33 m/s
Distance; d = 2.5 km = 2500 m
Acceleration of first car; a1 = 0 m/s² (constant acceleration)
Velocity of second car; v2 = 0 m/s (since the second car starts from rest)
From Newton's equation of motion, we know that;
d = ut + ½at²
Thus,for first car, we have;
d = v1•t + ½(a1)t²
Plugging in the relevant values, we have;
d = 33t + 0
d = 33t
For second car, we have;
d = v2•t + ½(a2)•t²
Plugging in the relevant values, we have;
d = 0 + ½(a2)t²
d = ½(a2)t²
Since they meet at the next exit, then;
33t = ½(a2)t²
simplifying to get;
33 = ½(a2)t
Now, we also know that;
t = distance/speed = d/v1 = 2500/33
Thus;
33 = ½ × (a2) × (2500/33)
Rearranging, we have;
a2 = (33 × 33 × 2)/2500
a2 = 0.8712 m/s²
Describe the relationship between the period of a pendulum and the length of the pendulum?
Answer:
The period of the pendulum is directly proportional to the square root of the length of the pendulum
We can also notice that the period of a pendulum does not depend on its mass.
Explanation:
write the chemical equation of rust
ANSWER
4Fe+ 3O2 → 2Fe2O.
EXPLANATION
iron (Fe) combines with oxygen (O2) to form rust, or iron oxide (Fe2O3). The equation for this reaction is: 4Fe+ 3O2 → 2Fe2O.
Is an object on the surface of Earth sitting still relative to outer space?
Answer:
The object is not still as it observe from the outer space.
Explanation:
Our earth is not stationary.
It rotates about its own axis with the period of 24 hours and it revolves around the sun with the period of 1 year.
An object is said to be at rest if the position of the object with respect to time changes.
An object is said to be in motion when the position of the object changes with respect to time.
Both the terms rest and motion are relative to each other.
If an observer observe an object on the earth from the outer space, he observe that the object s not still it is also moving as the earth is moving.
So, the object is not still as it observe from the outer space.
FORCE AND DISPLACEMENT AT AN ANGLE A sailor pulls a boat a distance of 30.0 m along a dock using a rope that makes a 25.0° angle with the horizontal. How much work does the rope do on the boat if its tension is 255 N?
Answer: 6117.58 J
Explanation:
We know that W=Fd*cos(theta) where theta is the angle between the displacement and the force.
In this case, we are given that F=225 N, d=30 m, and theta=25 degrees.
Plugging all this in we get
W=225*30*cos(25)=6117.58 J
Work done by the rope when sailor pulls the boat in the dock is 6930.9 J
What is work ?The work is defined by the product of force and displacement. Its standard formula is,
[tex]W = F.d.Cos\alpha[/tex]
Here F is force, d is displacement and α is angle subtended by force from horizontal.
As given in the question,F = 255N, d = 30m, α = 30°
On putting in the above formulaW = 255×30×Cos30°
=7650×0.906
= 6930.9 J
To learn more about work here
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Select the correct answer.
A force of 100 newtons is applied to a box at an angle
acceleration of the box?
36° with the horizontal. If the mass of the box is 25 kilograms, what is the horizontal
OA
1.52 meters/second2
3.24 meters/second
C.
5.48 meters/second
Ο Ο Ο Ο
6.87 meters/seconda
7.15 meters/second
Answer:
3
Explanation:
first you find the original component of the force be a cause in 36 degrees then with ka sin 36 find the average interforce by multiplying it with hundred Newton then divide the original force by the mass 25 Kg is equals tto ma
Answer:
See image
Explanation:
Plato
Thiết kế mạch điện tử sử dụng chân ngõ ra (I/O) của arduino UNO để lái relay 12VDC/500mA sao cho chân Arduino xuất ra tín hiệu 5V thì relay đóng, ngược lại chân I/O arduino xuất tín hiệu 0V thì relay hở. Mạch lái dùng BJT
Answer:
Mình cũng không biết làm bạn ơi =)))
Explanation:
5
What is back-lash error and how it is avoided
Answer:
The correct answer is - it is an error in the observation.
Explanation:
Backlash error is the error in the motion that takes place during shifting the direction of gears. A backlash error is an error in the observation which occurs due to the wear and tear of threads of the screw observed that takes place at the time of reversing the direction of rotation of the thimble where the tip of the screw does not move in the opposite direction but remains stationary for a part of the rotation.
Avoid backlash error:
While taking measurements, the screw should be rotated in one direction only.
Describe how the human ear hears sound.
Answer:
sound waves enter the outer ear and travel through a narrow passageway called the ear canal, which leads to the eardrum. The eardrum vibrates from the incoming sound waves and sends these vibrations to three tiny bones in the middle ear.
Explanation:
As part of an exercise program, a woman walks south at a speed of 2.8 m/s for 46 minutes. She then turns around and walks north a distance 3,132 m in 54 minutes . What is the woman's average speed in m/s during her entire motion
Answer:
[tex]A_[avg}=1.81m/s[/tex]
Explanation:
From the question we are told that:
North Movement
Velocity[tex]V=2.8[/tex]
Time [tex]t=46 minuites[/tex]
South movement
Distance [tex]d=3,132[/tex]
Time [tex]t'= 54 minutes[/tex]
Generally the equation for Average Velocity is mathematically given by
[tex]A_[avg}\]frac{Total distance}{Total time}[/tex]
Where
Total distance d_t
[tex]d_t=Souther\ distance\ traveled\ +Northern\ distance\ traveled[/tex]
[tex]d_t=(2.8*46*60)+(3132)[/tex]
[tex]d_t=10860[/tex]
An
Total Time
[tex]T=(46+54)60[/tex]
[tex]T=6000[/tex]
Therefore
[tex]A_[avg}=\frac{d_t}{T}[/tex]
[tex]A_[avg}=\frac{10860}{6000}[/tex]
[tex]A_[avg}=1.81m/s[/tex]
a given mass of an ideal gas law occupies a volume V of a temperature T under a pleasure p, if the pressure is increased to 2 p and temperature 1/2 T what is the percentage change in the volume of the gas
Answer:
75%
Explanation:
We'll begin by calculating the final volume of the gas. This can be obtained as follow:
Initial volume (V₁) = V
Initial temperature (T₁) = T
Initial pressure (P₁) = P
Final pressure (P₂) = 2P
Final temperature (T₂) = ½T
Final volume (V₂) =?
P₁V₁/T₁ = P₂V₂/T₂
PV/T = 2P × V₂ / ½T
Cross multiply
T × 2P × V₂ = PV × ½T
T × 2P × V₂ = PV × ½T
Divide both side by T × 2P
V₂ = (PV × ½T) / T × 2P
V₂ = ¼V
Next, we shall determine the absolute change in the volume of the gas. This can be obtained as follow:
Initial volume (V₁) = V
Final volume (V₂) = ¼V
Absolute change in volume |ΔV| =?
|ΔV| = |V₂ – V₁|
|ΔV| = |¼V – V|
|ΔV| = |0.25V – V|
|ΔV| = 0.75V
Finally, we shall determine percentage change in the volume of the gas. This can be obtained as follow:
Initial volume (V₁) = V
Absolute change in volume |ΔV| = 0.75V
Percentage change =?
Percentage change = |ΔV| / V × 100
Percentage change = 0.75V / V × 100
Percentage change = 0.75 × 100
Percentage change = 75%
Thus, the percentage change in the volume of the gas is 75%
A trumpet player hears 5 beats per second when she plays a note and simultaneously sounds a 440 Hz tuning fork. After pulling her tuning valve out to slightly increase the length of her trumpet, she hears 3 beats per second against the tuning fork. Was her initial frequency 435 Hz or 445 Hz? Explain.
Answer:
her initial frequency is 445 Hz
Explanation:
Given;
initial beat frequency, [tex]F_B[/tex] = 5
observed frequency, F = 440 Hz
let the initial frequency = F₁
F₁ = F ± 5 Hz
F₁ = 440 Hz ± 5 Hz
F₁ = 435 or 445 Hz
This result obtained shows that her initial frequency can either be 435 Hz or 445 Hz
The last beat frequency will be used to determine the actual initial frequency.
F = v/λ
Frequency (F) is inversely proportional to wavelength. That is an increase in length will cause a proportional decrease in frequency.
This shows that the final frequency is smaller than the initial frequency because of the increase in length.
Initial frequency - frequency of tuning fork = 5 beat frequency
Reduced initial frequency - frequency of tuning fork = 3 beat frequency
Initial frequency = 5Hz + 440 Hz = 445 Hz
Final frequency (Reduced initial frequency) = 440 + 3 = 443 Hz
Check: 445 Hz - 440 Hz = 5 Hz
443 Hz - 440 Hz = 3 Hz
What kind of force are you using when you squish a marshmallow?
The answer is compression because when you are squishing a marshmello you are compressing it.
After landing on an unfamiliar planet, a space explorer constructs a simple pendulum of length 55.0 cm . She finds that the pendulum makes 100 complete swings in a time of 130 s . What is the value of g on this planet?
Explanation:
Given:
l = 55.0 cm = 0.550 m
T = (130 s)/100 = 1.30 s
g = ?
The period of a pendulum is given by
[tex]T=2 \pi \sqrt{ \dfrac{l}{g}}[/tex]
Solving for T, we get
[tex]\dfrac{T^2}{4 \pi^2}=\dfrac{l}{g}[/tex]
Solving for g, we get
[tex]g=\dfrac{4 \pi^2l}{T^2}=\dfrac{4 \pi^2(0.550 m)}{(1.30\:s)^2}=12.8\:\dfrac{m}{s^2}[/tex]
The table shows caolums that brenda uses for her notes on the properties of elements her notes state that some elements can react to from basic compounds where should brenda place this property in her table
Answer:
The table shows caolums that brenda uses for her notes on the properties of elements her notes state that some elements can react to from basic compounds where should brenda place this property in her table
Explanation:
Imagine an alternate universe where all of the quantum number rules were identical to ours except m_{s} had three allowed values (rather than two as it does in our universe). If this were the case, and the Pauli Exclusion Principle still applies, how many electrons would be allowed in each orbital
Answer:
so in a given orbital there can be 3 electrons.
Explanation:
The Pauli exclusion principle states that all the quantum numbers of an electron cannot be equal, if the spatial part of the wave function is the same, the spin part of the wave function determines how many electrons fit in each orbital.
In the case of having two values, two electrons change. In the case of three allowed values, one electron fits for each value, so in a given orbital there can be 3 electrons.
(A) State the relation between acceleration and momentum (10 marks).
(B) Two small steel balls A and B have mass 0.6 kg and 0.2 kg respectively. They are moving towards each other in opposite directions on a smooth horizontal table when they collide directly. Immediately before the collision, the speed of A is 8 m/s and the speed of B is 2 m/s. Immediately after the collision, the direction of motion of A is unchanged and the speed of B is twice the speed of A. Find : a. The speed of A immediately after the collision (10 marks), b. The magnitude of the impulse exerted on B in the collision (10 marks).
Answer:
momentum is directly proportional to acceleration
A single 1,000 kg train car moving at 3.0 m/s collides with the back of two 1,000 kg train cars linked together. It latches onto the car it strikes as the two parts of the coupled cars exert forces on each other. What is the speed of the cars immediately afterward?
1.0 m/s
1.5 m/s
3.0 m/s
0.0 m/s
Answer:
Its 1.0 m/s
Explanation:
I checked to quiz
What is the voltage drop across an alarm clock that is connected to a circuit with a current of 1.10A and a resistance of 90Ω?
V = 99 volts
Explanation:
The voltage drop can be calculated using Ohm's law:
V = IR
= (1.10 A)(90 Ω)
= 99 volts
g A circular swimming pool has a diameter of 10 m, the sides are 4 m high, and the depth of the water is 3 m. How much work (in Joules) is required to pump all of the water over the side
Answer:
[tex]W=2.69*10^{6}J[/tex]
Explanation:
Generally the equation for momentum is mathematically given by
Diameter [tex]d=10m[/tex]
Radius [tex]r =\frac{d}{2}=>5m[/tex]
Height [tex]h=4m[/tex]
Depth [tex]d=3m[/tex]
Generally the equation for Area of the circle is mathematically given by
[tex]A=\pi r^2[/tex]
[tex]A=\pi 5^2[/tex]
[tex]A=78.5m^2[/tex]
Generally the equation for Work done is mathematically given by
[tex]d_w=d_f*x[/tex]
Where
[tex]d_f=(\rho*d_v)*g[/tex]
Therefore
[tex]d_w=((\rho*d_v)*g)*x[/tex]
[tex]d_w=((1000*78.5)*9.8)*x dx[/tex]
[tex]d_w=769300x dx[/tex]
[tex]W=\int dw[/tex]
[tex]\int dw=769300 \int^4_{3}x dx[/tex]
[tex]W=(769300\2)*7[/tex]
[tex]W=2.69*10^{6}J[/tex]
A 50-ohm resistor in a 0.5 Amp circuit produces how much voltage drop?
25 volts
Explanation:
Use Ohm's law to find the potential drop:
V = IR
= (0.5 A)(50 ohms)
= 25 volts
An astronaut weighing 248 lbs on Earth is on a mission to the Moon and Mars. (a) What would he weigh in newtons when he is on the Moon
Answer:
[tex]W_m=183.495N[/tex]
Explanation:
From the question we are told that:
Weight [tex]W=248Ibs[/tex]
Mass of Weight [tex]m= 248*0.453[/tex]
[tex]m=112.344kg[/tex]
Generally the acceleration due to gravity on the Moon is one-sixth that on Earth.
Therefore
The equation for Weight on Moon is given as
[tex]W_m=m*g/6[/tex]
[tex]W_m=122.344*\frac{9.8}{6}[/tex]
[tex]W_m=183.495N[/tex]
Answer:
F ’= 40.9 lb
Explanation:
The weight of a body is the attraction of the Earth on the body
F = [tex]G \frac{m M_e}{R_e^2}[/tex]
F = mg
m = F / g
m = 248/32
m = 7.75 slug
The weight of the body on the moon is the attraction of the body for the satellite
F ’= [tex]G \frac{mM}{R^2}[/tex]
from the tables the mass and radius of the moon are M = 7.34 10²² kg and R = 1.74 10⁶ m
let's reduce the mass to the SI system
m = 7.75 slug (14.59 kg / 1 slug) = 113 kg
F ’= 6.67 10⁻¹¹ 113 7.34 10²² / (1.74 10⁶) ²
F ’= 1.82 10² N
F ’= 1.82 10² N (0.2248 lb / 1 N)
F ’= 40.9 lb
A position vector in the first quadrant has an x-component of 6 m and a magnitude of 10 m. What is the value of its y-component
Answer:
8m
Explanation:
The magnitude m of a vector (x, y) is given by
m = [tex]\sqrt{x^2 + y^2}[/tex] -------------------------(i)
where;
x and y are the x- and y- components of the vector.
From the question;
m = 10m
x = 6m
Substitute these values into equation (i) as follows;
10 = [tex]\sqrt{6^2 + y^2}[/tex]
Solve for y;
Find the square of both sides
10² = 6² + y²
100 = 36 + y²
y² = 100 - 36
y² = 64
y = √64
y = 8
Therefore, the y-component of the position vector is 8m
convert 37 microgram to Gigagram
Answer:
3.7e-14
Explanation:
mark me brainliest!!
Ftension = 120 N
10 kg
Fg
What is the weight (not mass) of the box?
O 10 kg
0 19 N
98 N
O 98 kg
PLZ HELP
Answer:
98N
Explanation:
El peso se mide en kg y la fuerza no afecta
