Look at the graph and extrapolate how many baskets were made by the team at 8.5 minutes.


A.
3
B.
1
C.
23
D.
24

Use the work-energy theorem: the total work done on the 0.80 kg block by the spring to make it come to a stop is equal to the change in the block's kinetic energy.

If we take the block's initial direction of motion to be positive, then the spring does negative work on the block, and

-1/2 k (0.11 m)² = 0 - 1/2 (0.80 kg) (2.2 m/s)²

Solve for the spring constant k :

k = (1/2 (0.80 kg) (2.2 m/s)²) / (1/2 (0.11 m)²) = 320 N/m

We can use the same equation as above to find the distance the 1.40 kg block would travel as it is slowed down by the same spring:

-1/2 (320 N/m) x ² = 0 - 1/2 (1.40 kg) (3.0 m/s)²

Solve for the displacement x :

x = √((1/2 (1.40 kg) (3.0 m/s)²) / (1/2 (320 N/m))) ≈ 0.20 m

Answer:

A wave with a frequency of 60 hertz will have 60 successive wave crests occurring every second

Explanation:

A crest is the highest point the medium rises to in a wave. That means that the crest is a point on the wave where the displacement is at a maximum.

Frequency is the number of oscillations of a wave in one second. Hence, frequency of a wave is the number of successive crests occurring in a second.

Therefore a wave with a frequency of 60 hertz will have 60 successive wave crests occurring every second.

Answer:

carbon d

Explanation:

Answer:

False

Explanation:

Just took the quiz

Answer:

false

Explanation:

Answer: See explanation

Explanation:

Climate change, is also referred to as global warming, and it simply means the rise in Earth's average surface temperature.

Effects of climate change include rising sea levels, heat waves, drought, storms, etc.

Extreme heat events is dangerous to the health of both animals and humans. For human beings, it can bring about increase in heat- related illness, weakness, heat stroke and excessive water consumption.

For animals, it can lead to struggling of the animals in losing their excess body heat by evaporation. Other effects include panting, loss of appetite, increased drinking, difficulty breathing, anxious behaviour, and weakness.

Answer:

the inductive reactance of the coil is 1335.35 Ω

Explanation:

Given;

inductance of the coil, L = 250 mH = 0.25 H

effective current through the coil, I = 5 mA

frequency of the coil, f = 850 Hz

The inductive reactance of the coil is calculated as;

[tex]X_l = \omega L = 2\pi f L\\\\X_l = 2\pi \times 850 \times 0.25\\\\X_l = 1335.35 \ ohms[/tex]

Therefore, the inductive reactance of the coil is 1335.35 Ω

Answer:

The right solution is "165.8 nm".

Explanation:

Given:

Index of refraction,

n = 1.81

Wavelength,

λ = 600 nm

We know that,

⇒ [tex]t=\frac{\lambda}{2\times n}[/tex]

By putting the values, we get

      [tex]=\frac{600}{2\times 1.81}[/tex]

      [tex]=165.8 \ nm[/tex]

Answer:

The pond's water level will fall.

Explanation:

Archimedes principle explains that a floating body will displace the amount of water that weighs the same as it, whereas a body resting on the bottom of the water displaces the amount of water that is equal to the body's volume.

When the anchor is in the boat it is in the category of floating body and when it is on the bottom of the pond it is in the second category.

Since anchors are naturally heavy and denser than water, the amount of water displaced when the anchor is in the boat is greater than the amount of water displaced when the anchor is on the bottom of the pond since the way anchors are doesn't make for them to have considerable volume.

When the anchor is dropped to the bottom of the pond, the water level will therefore fall. If the anchor doesn't reach the bottom it is still in the floating object category and there will be no difference to the water level, but once it touches the bottom of the pond, the water level of the pond drops.

Answer:

B) is perpendicular to the magnetic field

Answer:

B.

Explanation:

Gravitational Potential Energy to Kinetic Energy

Answer:

the sound intensity at the position of the microphone is 7.4 × 10⁻⁴ W/m²

Explanation:

Given the data in the question;

Sound power P = 26.0 W

Area of microphone A = 1.00 cm²

Radius r = 53.0 m

sound intensity at the position of the microphone = ?

Now, intensity at the position of the microphone can be determined using the following expression;

[tex]I[/tex] = P / 4πr²

We substitute

[tex]I[/tex] = 26.0 / ( 4 × π × (53.0 )² )

[tex]I[/tex] = 26.0 / ( 4 × π × 2809 )

[tex]I[/tex] = 26.0 / 35298.935

[tex]I[/tex] = 26.0 / ( 4 × π × (53.0 )² )

[tex]I[/tex] = 0.000736566

[tex]I[/tex] = 7.4 × 10⁻⁴ W/m²

Therefore, the sound intensity at the position of the microphone is 7.4 × 10⁻⁴ W/m²

Question: Find acceleration of a refrigerator 30s after a person begins pushing it at a force of 400 N, If the mass of the refrigerator is 10 kg.

Answer:

40 m/s²

Explanation:

Applying,

F = ma................Equation 1

Where F = Force applied to the refrigerator, m = mass of the refrigerator, a = acceleration of the refrigerator.

make a the subject of the equation

a = F/m............ Equation 2

From the question,

Given: F = 400 N, m = 10 kg

Substitute these values into equation 2

a = 400/10

a = 40 m/s²

Answer:

0 J

Explanation:

Since work done W = PΔV where P = pressure and ΔV = change in volume.

Since the volume is constant, ΔV = 0

So, Work done, W = PΔV = P × 0 = 0 J

So, the work done is 0 J.

Answer:

Put the 2 light bulbs in series.

Explanation:

The resistance will be the greatest if you hook up the light bulb in series, and since resistance and current are inversely proportional, the current will be the least as well.

Answer:

The correct answer is "8 V".

Explanation:

Given:

Potential difference across battery,

= 20 V

Potential difference across R1,

= 12 V

Now,

On applying the Kirchorff loop, we get

⇒ [tex]E-I_1R_1-I_2R_2=0[/tex]

⇒ [tex]E-V_1-V_2=0[/tex]

⇒ [tex]V_2=E-V_1[/tex]

On putting values, we get

⇒      [tex]=20-12[/tex]

⇒      [tex]= 8 \ V[/tex]  

The potential difference across the resistance R2 will be "8 Volts.

According to the kirchoff's law in a loop of a circuit when there are number of the resistances so the sum of all the potential differences will be zero.

It is given that:

Potential difference across battery,= 20 V

Potential difference across R1,= 12 V

Now,

On applying the Kirchorff loop, we get

⇒ [tex]\rm E-I_1R_1-I_2R_2=0[/tex]

⇒ [tex]\rm E-V_1-V_2=0[/tex]

⇒ [tex]\rm V_2=E-V_1[/tex]

On putting values, we get

⇒ [tex]V_2=20-12=8\ volt[/tex]

Hence the potential difference across the resistance R2 will be "8 Volts.      

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Answer:

Uniform Circular Motion is the Movement or Rotation of an Object along a circular Path at constant speed.

OPTION C IS YOUR ANSWER!.

Answer:

Option A. The speed of sound through water is 4.3 times faster than sound through air.

Explanation:

To answer the question correctly, we shall determine the speed of the wave in both cases. This is illustrated below:

For Air:

Frequency (fₐ) = 195 Hz

Wavelength (λₐ) = 1.76 m

Velocity (vₐ) =?

vₐ = λₐfₐ

vₐ = 1.76 × 195

vₐ = 343.2 m/s

For Water:

Frequency (fᵥᵥ) = 195 Hz

Wavelength (λᵥᵥ) = 7.6 m

Velocity (vᵥᵥ) =?

vᵥᵥ = λᵥᵥfᵥᵥ

vᵥᵥ = 7.6 × 195

vᵥᵥ = 1482 m/s

Finally, we shall compare the speed in water to that of air. This can be obtained as follow:

Velocity in air (vₐ) = 343.2 m/s

Velocity in water (vᵥᵥ) = 1482 m/s

Water : Air

vᵥᵥ : vₐ =>

vᵥᵥ / vₐ = 1482 / 343.2

vᵥᵥ / vₐ = 4.3

Cross multiply

vᵥᵥ = 4.3 × vₐ

Thus, the speed in water is 4.3 times the speed in air.

Option A gives the correct answer to the question.

Solution :

We know, resistance is given by :

[tex]R = \dfrac{\rho l}{A}[/tex]

[tex]A = \dfrac{\rho l }{R}\\\\A = \dfrac{1.72\times 10^{-8} \times 3.5 }{0.125}\\\\A = 4.816 \times 10^{-7} \ m^2[/tex]

Now, we know mass of wire is given by :

[tex]Mass = Density \times Volume\\\\\M = 8.9 \times 10^3 \times 4.816 \times 10^{-7} \times 3.5 kg\\\\M = 0.01500\ kg\\\\M = 15.00\ gram[/tex]

Hence, this is the required solution.

Given:

The resistance will be:

→ [tex]R = \frac{\rho l}{A}[/tex]

or,

→ [tex]A = \frac{\rho l}{R}[/tex]

By substituting the values, we get

      [tex]= \frac{1.72\times 10^{-8}\times 3.5}{0.125}[/tex]

      [tex]= 4.816\times 10^{-7} \ m^2[/tex]

hence,

The mass will be:

→ [tex]Mass = Density\times Volume[/tex]

             [tex]= 8.9\times 10^3\times 4.816\times 10^{-7}\times 3.5[/tex]

             [tex]= 0.01500 \ kg[/tex]

             [tex]= 15.00 \ g[/tex]

Thus the above answer is right.  

Learn more about mass here:

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Answer:

Appliance A and B can work together without tripping

Explanation:

We will calculate the amount of current consumed by each appliances.

Appliance A

P = VI

I = P/V  

I = 250/120 = 2.08 A

Appliance B

I = 480 /120 = 4 A

Appliance C

I = 1450/120

I = 12.08 A

Hence, appliance C will trip the circuit as it consumes a lot of electricity.

Explanation:

The range R of a projectile is given by

[tex]R = \frac{v_0^2}{g} \sin 2\theta[/tex]

The maximum range [tex]R_{max}[/tex] occurs when [tex]\sin 2\theta = 1\:\text{or}\:\theta = 45°[/tex]. Let [tex]\alpha[/tex] be the angle above or below 45°. Now let's look at the ranges brought about by these angle differences.

Case 1: Angle above 45°

We can write the range as

[tex]R_+ = \dfrac{v_0^2}{g} \sin 2(45° + \alpha)= \dfrac{v_0^2}{g} \sin (90° + 2\alpha)[/tex]

[tex]\:\:\:\:\:\:\:= \dfrac{v_0^2}{g} (\sin 90° \cos 2\alpha + \cos 90° \sin 2\alpha)[/tex]

[tex]\:\:\:\:\:\:\:= \dfrac{v_0^2}{g} \cos 2\alpha\:\:\:\:\:(1)[/tex]

Case 2: Angle below 45°

We can write the range as

[tex]R_- = \dfrac{v_0^2}{g} \sin 2(45° - \alpha)= \dfrac{v_0^2}{g} \sin (90° - 2\alpha)[/tex]

[tex]\:\:\:\:\:\:\:= \dfrac{v_0^2}{g} (\sin 90° \cos 2\alpha - \cos 90° \sin 2\alpha)[/tex]

[tex]\:\:\:\:\:\:\:= \dfrac{v_0^2}{g} \cos 2\alpha\:\:\:\:\:(2)[/tex]

Note that the equations (1) and (2) are identical. Therefore, the ranges are equal if they differ from 45° by the same amount.

Answer:

the maximum vertical height the person in the cart can reach is 18.42 m

Explanation:

Given;

mass of the person, m₁ = 45 kg

mass of the cart, m₂ = 43 kg

velocity of the system, v = 19 m/s

let the maximum vertical height reached = h

Apply the principle of conservation mechanical energy;

[tex]P.E = K.E\\\\mgh_{max} = \frac{1}{2} mv^2_{max}\\\\gh_{max} = \frac{1}{2} v^2_{max}\\\\h_{max} = \frac{v_{max}^2}{2g} \\\\h_{max} = \frac{19^2}{2\times 9.8} \\\\h_{max} = 18.42 \ m[/tex]

Therefore, the maximum vertical height the person in the cart can reach is 18.42 m

Answer: The speed of gymnast at the bottom of the swing is 6.44 m/s.

Explanation:

Given: Distance = 1.06 m

According to the law of conservation of energy, the speed is calculated as follows.

[tex]mgh = - mgh + \frac{1}{2}mv^{2}\\gh = - gh + \frac{1}{2}v^{2}\\v = \sqrt{4gh}[/tex]

where,

g = acceleration due to gravity = 9.8 [tex]m/s^{2}[/tex]

h = distance

v = speed

Substitute the values into above formula as follows.

[tex]v = \sqrt{4gh}\\= \sqrt{4 \times 9.8 m/s^{2} \times 1.06}\\= 6.44 m/s[/tex]

Thus, we can conclude that speed of gymnast at the bottom of the swing is 6.44 m/s.

Answer:

plz mark brainliest again lol :)

Explanation:

When you drop a ball from a greater height, it has more kinetic energy just before it hits the floor and stores more energy during the bounce—it dents farther as it comes to a stop.

Answer:

When you drop a ball from a greater height, there is more potential energy. When you release the ball, the potential energy turns into kinetic energy. When the ball bounces off the ground, the ball go upward and then it has more potential energy. Then when it goes down it has more kinetic energy. The ball keeps doing this until there is not enough potential energy left.

Explanation:

Answer:

378 KWh

Explanation:

We'll begin by converting 1.2×10³ W to KW. This can be obtained as follow:

10³ W = 1 KW

Therefore,

1.2×10³ W = 1.2×10³ W × 1 KW / 10³ W

1.2×10³ W = 1.2 KW

Next, we shall convert 6.3×10² mins to hours (h). This can be obtained as follow:

60 mins = 1 h

Therefore,

6.3×10² mins = 6.3×10² mins × 1 h / 60 mins

6.3×10² mins = 10.5 h

Finally, we shall determine the electrical energy in KWh used for 1 month (i.e 30 days). This can be obtained as follow:

Power (P) = 1.2 KW

Time (t) for 1 month (30 days) = 10.5 h × 30

= 315 h

Energy (E) =?

E = Pt

E = 1.2 × 315

E = 378 KWh

Thus, the electrical energy used for 1 month (i.e 30 days) is 378 KWh.

Answer:

2.0km/h.

Explanation:

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This question is incomplete, the complete question is;

Model a hydrogen atom as a three-dimensional potential well with U₀ = 0 in the region 0 < x < L, 0 < y < L and 0 < z < L, and infinite otherwise, with L = 1.0 × 10⁻¹⁰ m.

Which of the following is NOT one of the lowest three energy levels of an electron in this model?

a. 283 eV

b. 339 eV

c. 113   eV  

d. 226 eV        

Answer:

the lowest three energy are; 113 eV, 225 eV, and 339 eV.

Hence Option a) 283 eV is not among the three lowest energy

Explanation:

Given the data in the question;

Three dimension cube or particle in a cubic box

the energy value is given by;

[tex]E_{nx,ny,nz[/tex] = [tex]( n_x^2 + n_y^2 + n_z^2 )[/tex] × π²h"² / 2ml²

where h" = h/2π and h is Planck's constant ( 6.626 × 10⁻³⁴ m² kg / s )

m is mass of electron ( 9.1 × 10⁻³¹ kg )

l is length of side of box ( 1.0 × 10⁻¹⁰ m )

for ground level ( [tex]n_x = n_y = n_z = 1[/tex] )

so

[tex]( n_x^2 + n_y^2 + n_z^2 )[/tex] ×  π²h"² / 2ml²

since h" = h/2π

[tex]( n_x^2 + n_y^2 + n_z^2 )[/tex] × π²h² / (2π)²2ml²

so we substitute

[tex]E_{111[/tex] = ( 1² + 1² + 1² ) × [ π²( 6.626 × 10⁻³⁴ )² ] / [ (2π)² × 2 × 9.1 × 10⁻³¹ kg × ( 1.0 × 10⁻¹⁰)² ]

[tex]E_{111[/tex] = 3 × [ (4.333188779 × 10⁻⁶⁶) / ( 7.185072 × 10⁻⁴⁹ ) ]    

[tex]E_{111[/tex] = 3 × [ 6.03082165 × 10⁻¹⁸ ]

Now, we know that electric charge = 1.602 x 10⁻¹⁹

so

[tex]E_{111[/tex] = 3 × [ (6.03082165 × 10⁻¹⁸) / (1.602 x 10⁻¹⁹) ]

[tex]E_{111[/tex] = 3 × [ 37.645578 ]

[tex]E_{111[/tex] = 112.9 ≈ 113 eV

[tex]E_{211[/tex] = [tex]( n_x^2 + n_y^2 + n_z^2 )[/tex]  × π²h² / (2π)²2ml²

we substitute

[tex]E_{211[/tex] = ( 1² + 1² + 2² ) × [ 37.645578 ]

[tex]E_{211[/tex] = 6 × [ 37.645578 ]

[tex]E_{211[/tex] = 225.87 ≈ 226 eV

[tex]E_{221[/tex] = [tex]( n_x^2 + n_y^2 + n_z^2 )[/tex]  × π²h² / (2π)²2ml²

we substitute

[tex]E_{221[/tex] = ( 2² + 2² + 1² ) × [ 37.645578 ]

[tex]E_{211[/tex] = 9 × [ 37.645578 ]

[tex]E_{211[/tex] = 338.8 ≈ 339 eV

Therefore, the lowest three energy are; 113 eV, 225 eV, and 339 eV.

Hence Option a) 283 eV is not among the three lowest energy