Answer:
Granite
Explanation:
The specific heat capacity of a substance, which is denoted by "c", is the amount of heat required to raise the temperature of a particular mass of that substance by 1°C. It is calculated as follows:
c = Q ÷ m∆T
Where;
c = specific heat capacity
Q = amount of heat (J)
m = mass of substance
∆T = change in temperature.
According to this equation and explanation above, a low specific heat capacity means that the rate at which the temperature is raised is slow and vice versa. Hence, from this question, GRANITE with specific capacity of 0.790 J/gK will raise temperature the slowest.
A balloon filled with air has a volume of 4.24 liters at 23.00°C. If the balloon is cooled at a constant pressure to 5.00°C, what is the new volume?
Identify the components of tourism and hospitality and discuss?
Answer: he basic components or 4'A' s of tourism are as follows:
ATTRACTION: It is the most important element & object that attract people to travel. ...
ACCESSIBILITY: It is important key factor for the development of tourism. ...
ACCOMMODATION: -It includes food & lodging facilities to the guest. ...
AMENITIES:
What are the components of tourism and hospitality?
Accommodations and.
Lodging.
Recreation and.
Entertainment.
Travel Services.
Food and Beverage Services.
Conventions and Event.
Management.
Explanation:
NOT MY WORDS! I HOPE ThIS HELPS!
A sample of gas of unknown pressure occupies 0.766 L at a temperature of 298 K. The same sample of gas is then tested under known conditions and has a pressure of 32.6 kPa and occupies 0.644 L at 303 K. What was the original pressure of the gas
Answer:
26.96 kPa
Explanation:
Applying,
PV/T = P'V'/T'............... Equation 1
Where P = Initial pressure, V = Initial volume, T = Initial temperature, P' = Final pressure, V' = Final volume, T' = Final temperature.
make P the subject of the equation
P = P'V'T/VT'.............. Equation 2
From the question,
Given: V = 0.766 L, T = 298 K, P' = 32.6 kPa, V' = 0.644 L, T' = 303 K
Substitute these values into equation 2
P = (32.6×0.644×298)/(0.766×303)
P = 26.96 kPa
Density is an example of a
Solution A is yellow when alizarin yellow is added and blue when thymol
blue is added. Which of the following correctly identifies Solution A?
A. 3.2 x 10-4 mol/L HCI
B. 3.2 x 10-4 mol/L NaOH
C. 6.3 x 10-5 mol/L HCI
D. 6.3 x 105 mol/L NaOH
Answer:
D. 6.3 x 10-5 mol/L NaOH
Explanation:
Alizarin yellow is an indicator that is yellow when pH < 10.1. In the same way, thymol blue is blue when pH > 9
That means the pH of the solution is between 9 - 10.1
Any acid as HCl could have a pH of these.
The solution of 3.2x10⁻⁴M NaOH has a pH of:
pOH = -log[OH-] = 3.49
pH = 14-pOH = 10.51. The pH of the solution is not 10.5
Now, the solution of 6.3x10⁻⁵M NaOH has a pH:
pOH = -log[OH-] = 4.2
pH = 14-pOH = 9.8
The pH of the solution could be 9.8. Right option is:
D. 6.3 x 10-5 mol/L NaOHHow many atoms are present in 44.89 moles of Be?
Answer:
I hope that helps. I did not round the answer at the end. Maybe you want the final answer in a specific decimal place.
An ideal gas at 2.0 atm pressure and 298 K temperature has a volume of 12.0 L. If the volume is decreased to 4.0 L and the temperature is held constant, what is the new pressure of the the gas in atm
Answer:
[tex]P_2=6.0atm[/tex]
Explanation:
Hello there!
In this case, according to the given information, it turns out possible for us to solve this problem by using the Boyle's law, since the temperature is constant and both volume and pressure change:
[tex]P_2V_2=P_1V_1[/tex]
Thus, we solve for the final pressure, P2, to obtain:
[tex]P_2=\frac{P_1V_1}{V_2}[/tex]
And plug in the given data to get:
[tex]P_2=\frac{2.0atm*12.0L}{4.0L}\\\\P_2=6.0atm[/tex]
Regards!
A monoprotic weak acid when dissolved in water is 0.66% dissociated and produces a solution with a pH of 3.04. Calculate the Ka of the acid. g
Answer:
Ka = 6.02x10⁻⁶
Explanation:
The equilibrium that takes place is:
HA ⇄ H⁺ + A⁻Ka = [H⁺][A⁻]/[HA]We calculate [H⁺] from the pH:
pH = -log[H⁺][H⁺] = [tex]10^{-pH}[/tex][H⁺] = 9.12x10⁻⁴ MKeep in mind that [H⁺]=[A⁻].
As for [HA], we know the acid is 0.66% dissociated, in other words:
[HA] * 0.66/100 = [H⁺]We calculate [HA]:
[HA] = 0.138 MFinally we calculate the Ka:
Ka = [tex]\frac{[9.12x10^{-4}]*[9.12x10^{-4}]}{[0.138]}[/tex] = 6.02x10⁻⁶PLEASE HELP!
is the element lithium mostly found in the atmosphere, lithosphere, or the hydrosphere?
Answer:
lithosphere
Explanation:
its found in the earth :)))
Answer:
yes
Explanation:
which of the following can cause muscle fatigue ?
A.A build up of lactic acid
b.an inadequate supply of oxygen
C.an inadequate supply of glycogen
D.all of the above
Answer:
The correct answer is -all of the above.
Explanation:
Muscle fatigue is a reduced ability in work capacity caused by work itself. It is known that altering oxygen is contracting skeletal muscle affects performance. Reduced O2 supply increases the rate of muscle fatigue.
The lactic acid is accumulated as it forms rapidly but the breaking of the lactic acid is slow down, which causes muscle fatigue. Less ATP and glycogen in muscle results in fatigue as the muscle is not able to generate energy to power contractions and therefore contributes to muscle fatigue.
PLZ Answer ASAP
I need help with this thank you if you get it right
Answer:
A) -277.6 KJ/mol
Explanation:
The enthalpy data for first equation is not given but it should be somewhere around ΔH = –1367 kJ/mol.
So, Basically you want to rearrange the given three equations to match the equation they want you to have. To get the final equation, reverse reaction first reaction (turn its value into positive), multiply second equation by 2, multiply third equation by 3 and you add em all up:
You get 1367 + (2* -393.5) + (3 * -285.8) ~ -277.6 KJ/mol
What mass of ethane (CH3CH3) is contained in 50.0 mL of a 13.9% by mass solution of ethane in hexane? The density of the solution is 0.611 m.
A. 8.49 g
B. 2.35 g
C. 11.8 g
D. 4.25 g
E. 6.95 g
Answer:
in a solution with mass 30.55 grams, 4.25 grams is ethane
Option D is correct
Explanation:
Step 1: Data given
Volume of the solution = 50.0 mL = 0.05 L
Density of the solution = 0.611 m (g/mL)
mass % of the solution = 13.9 %
This means for every 100 grams of solution we have 13.9 grams of solute
Step 2: Calculate the mass of the solution
Density = mass/ volume
0.611 g/mL = mass of solution / 50.0 mL
Mass of the solution = 0.611 g/mL * 50.0 mL
Mass of the solution = 30.55 grams
Step 3: Calculate mass of ethane
Since the mass % = 13.9 % this means that there is 13.9 grams solute (ethane) for every 100 grams of solution
For a solution with mass 30.55 grams the mass of the solute (ethane) is:
(30.55/100)* 13.9 = 4.25 grams
This means that in a solution with mass 30.55 grams, 4.25 grams is ethane
Option D is correct
calculate the mass in grams for 3.01 x 10^23 of Sulfur
You heat a 5.05 g piece of titanium to 98.2 oC and place it into 20.00 mL of room temperature water (24.8 oC ). The temperature of the water rises to 27.3 oC. The specific heat of water is 4.184 J/goC. The density of water is 0.997 g/mL. A. How much heat is absorbed by the water (in units of J)
Answer: The heat absorbed by the water is 52.823 J.
Explanation:
Given: Mass of metal = 5.05 g
Specific heat of water = 4.184 [tex]J/g^{o}C[/tex]
Initial temperature = [tex]24.8^{o}C[/tex]
Final temperature = [tex]27.3^{o}C[/tex]
Formula used to calculate heat absorbed is as follows.
[tex]q = m \times C \times (T_{2} - T_{1})[/tex]
where,
q = heat
m = mass of substance
[tex]T_{1}[/tex] = initial temperature
[tex]T_{2}[/tex] = final temperature
Substitute the values into above formula as follows.
[tex]q = m \times C \times (T_{2} - T_{1})\\= 5.05 g \times 4.184 J/g^{o}C \times (27.3 - 24.8)^{o}C\\= 52.823 J[/tex]
Thus, we can conclude that heat absorbed by the water is 52.823 J.
B. Directions: Identify the factors affecting the different seasons in the Philippines.
1. Areas with less rainfall, has a pronounced dry
season. When it always rain, that place has wet season most of the year.
2. The higher the particular place, the cooler its
temperature.
3. Climate near in coastal areas is cooler because
water does not absorb heat as fast as land area.
4. . When large amount of warm air cool, if gives off
lots of rain over the land
5. Philippines lies near the equator, has warm climate
during certain times of the year.
Answer:
The correct answer is -
1. Latitude
2. Altitude
3. Bodies of water
4. Wind system
5. Amount of rainfall
Explanation:
Lattitude is the angle from the earth's equator towards the north or south to the poles. This is one of the important factors that lead to different seasons and define the temperature of the area.
Altitude is the elevation from the sea that also helps in affecting the seasons as the higher the altitude cooler the temperature. Water bodies like the sea affect the wind and climate as they are not able to absorb heat faster in comparison to the land.
Wind also affects the seasons and climate of the area as a large amount of warm air cools, it gives off lots of rain over the land. Precipitation or rainfall determines and influences the climate.
2Al + 6HCl → 2AlCl3 + 3H2
You want to make 10 moles of AlCl3. How many moles of HCl does that require?
Answer: If you want to make 10 moles of [tex]AlCl_{3}[/tex] then 30 moles of HCl are required in the given reaction.
Explanation:
The given reaction equation is as follows.
[tex]2Al + 6HCl \rightarrow 2AlCl_{3} + 3H_{2}[/tex]
Here, 6 moles of HCl reacts with 2 moles of [tex]AlCl_{3}[/tex]. This means that 1 mole of [tex]AlCl_{3}[/tex] is obtained as follows.
[tex]\frac{6}{2} HCl\\= 3 HCl[/tex]
Hence, 3 moles of HCl will give 1 mole of [tex]AlCl_3[/tex]. So, moles of HCl required to react with 10 moles of [tex]AlCl_{3}[/tex] is as follows.
[tex]1 mol AlCl_3 = 3 mol HCl\\10 mol AlCl_{3} = 3 \times 10 mol HCl\\= 30 mol HCl[/tex]
Thus, we can conclude that if you want to make 10 moles of [tex]AlCl_{3}[/tex] then 30 moles of HCl are required in the given reaction.
How does the neutron number in each compare
Answer:
Neutrons are all identical to each other, just as protons are. Atoms of a particular element must have the same number of protons but can have different numbers of neutrons.
Explanation:
Since the vast majority of an atom's mass is found its protons and neutrons, subtracting the number of protons (i.e. the atomic number) from the atomic mass will give you the calculated number of neutrons in the atom. In our example, this is: 14 (atomic mass) – 6 (number of protons) = 8 (number of neutrons).
A solution has a [H3O+] 1 x 10^-3 what is the [OH-] of the solution
Answer:
OH- is 1x 10^ + 3
Explanation:
- and - = +
Write the Ka expression for an aqueous solution of hypochlorous acid: (Note that either the numerator or denominator may contain more than one chemical species. Enter the complete numerator in the top box and the complete denominator in the bottom box. Remember to write the hydronium ion out as , and not as )
Answer: The Ka expression for an aqueous solution of hypochlorous acid is [tex]K_{a} = \frac{[H_{3}O^{+}][OCl^{-}]}{[HClO]}[/tex].
Explanation:
The chemical formula of hypochlorous acid is HClO. So, when it is added to water (solvent) then its dissociation is as follows.
[tex]HClO + H_{2}O \rightarrow H_{3}O^{+} + Cl^{-}[/tex]
When we write the equilibrium constant for this reaction then it is called acid acid dissociated constant.
Hence, the expression for acid dissociation constant of this reaction is as follows.
[tex]K_{a} = \frac{[H_{3}O^{+}][OCl^{-}]}{[HClO]}[/tex]
Thus, we can conclude that the Ka expression for an aqueous solution of hypochlorous acid is [tex]K_{a} = \frac{[H_{3}O^{+}][OCl^{-}]}{[HClO]}[/tex].
the first liquid that comes out of a woman's breast after delivery is called?
The first liquid (milk) that comes out of a woman's breast after delivery is called [tex]\sf\purple{colostrum}[/tex].
[tex]\large\mathfrak{{\pmb{\underline{\orange{Happy\:learning }}{\orange{!}}}}}[/tex]
gabriel created 270 grams of aluminum oxide from 145 grams of aluminum. what was his percent yield?
A. 99.1%
B. 98.6%
C. 97.2%
D.96.5%
( it’s not “D” because I got it wrong lol) pls help tho
Answer:
% yield = 200%
Explanation:
By using 145 gram of aluminium
Using 26.982 g/mol of Al, 101.96 g/mol of Aluminium oxide is produced
Using 145 grams of aluminium, the yield of Aluminium oxide would have been = (101.96 g/mol/26.982 g/mol)/145 grams
= 547.9282485 gram
Now % yield = actual yield /theoretical yield * 100
Substituting the given values, we get -
% yield = (547.928/270) *100
% yield = 200%
balance this equation plz
SO2+O2+H2O------->H2SO4
Answer: The balanced equation is [tex]2SO_{2} + O_{2} + 2H_{2}O \rightarrow 2H_{2}SO_{4}[/tex].
Explanation:
A chemical equation which contains same number of atoms on both reactant and product side is called a balanced chemical equation.
For example, [tex]SO_{2} + O_{2} + H_{2}O \rightarrow H_{2}SO_{4}[/tex]
Here, number of atoms present on reactant side are as follows.
S = 1O = 5H = 2Number of atoms present on product side are as follows.
S = 1O = 4H = 2To balance this equation, multiply [tex]SO_{2}[/tex] by 2 and [tex]H_{2}O[/tex] by 2 on reactant side. Also, multiply [tex]H_{2}SO_{4}[/tex] by 2 on product side.
Hence, the equation can be re-written as follows.
[tex]2SO_{2} + O_{2} + 2H_{2}O \rightarrow 2H_{2}SO_{4}[/tex]
Now, the number of atoms present on reactant side are as follows.
S = 2O = 8H = 4Number of atoms present on product side are as follows.
S = 2O = 8H = 4Since, the atoms present on both reactant and product side are equal. Hence, the equation is now balanced.
Thus, we can conclude that the balanced equation is [tex]2SO_{2} + O_{2} + 2H_{2}O \rightarrow 2H_{2}SO_{4}[/tex].
10. What could the pH of a solution be if a cyanidin indicator turned blue? What is used to determine the endpoint of a titration? (Choose all that apply)
D 4
5
06
07
Answer:
The cyanidin indicator turns blue within a pH range of 5 - 7. The pH of the solution could be 5, 6 or 7.
An indicator is used to determine the endpoint of a titration.
Explanation:
Cyanidin indicator changes colour with each change in pH. In acidic solutions (pH < 7) cyanidin indicator will turn red, through to purple and blue, while in basic solutions (pH > 7), cyanidin indicator will change colour from aquamarine through to green and yellow. The cyanidin indicator turns blue within a pH range of 5 - 7.
Titration is a technique used in analytical chemistry to determine the unknown concentration of a solution. A solution of known concentration is added from a burette to the solution of unknown concentration until the reaction between the two solutions is complete. This known as the endpoint of the experiment. The endpoint of a titration is determined using an indicator which is added to reaction mixture. A colour charge is produced by the indicator at the endpoint of the reaction.
Note: An indicator is a dye of weak organic acids or bases which changes colour with changes in the pH of a solution. Some common indicators are methyl orange, methyl red, phenolphthalein, etc. These indicators are used to monitor the changes in the pH of solutions during a reaction.
Answer:
5,7,6
Explanation:
Took the quiz! Good luck!
You calculate that 0.000345 m is the answer to a problem. You are asked to write
your answer in scientific notation. Which answer is correct? *
A~ 34.5 x 10^-5m
B~ 345 x 10^6m
C~ 3.45 x 10^-5 m
D~ 3.45 x 10^-4 m
g An ionic bond involves ____ a. molecules that gain or lose an atom to develop a bonding charge b. molecules that bond together through a weak force c. atoms that either lose or gain an electron in order to bond d. atoms that share an electron to tightly bond
Answer:
a. molecules that gain or lose an atom to develop a bonding charge
Explanation:
Draw the structure of the starting material needed to make 2‑methylhept‑3‑yne (or 2‑methyl‑3‑heptyne) using sodium amide in liquid ammonia, followed by 1‑bromopropane.
Answer:
See explanation and image attached
Explanation:
2‑methylhept‑3‑yne can be made by the reaction of the compound shown in the image attached with soidamide in liquid ammonia and 1‑bromopropane.
The first step in the reaction is the deprotonation of the alkyne starting material by the amide ion.
This step is followed a nucleophilic substitution reaction of the alkyne with 1‑bromopropane to yield the 2‑methylhept‑3‑yne product.
Write the balanced COMPLETE ionic equation for the reaction when aqueous NiCl₂ and aqueous Na₂S are mixed in solution to form solid NiS and aqueous NaCl. If no reaction occurs, simply write only NR.
Answer:
Explanation:
The chemical reaction of the well-balanced equation is as follows:
[tex]\mathbf{2NiCl_{2(aq)}+2Na_2S_{(aq)} \to 4NaCl_{(aq)}+2NiS_{s}}[/tex]
The aforementioned reaction's ionic equation is:
[tex]\mathbf{2Ni^{2+}_{(aq)}+4Cl^-_{(aq)}+ 4Na^+_{(aq)}+2S^{2-}_{(aq)} \to 4Na^+_{(aq)}+4Cl^-_{(aq)}+2NiS_{(s)}}[/tex]
From above; Na⁺ and Cl⁻ appear on both sides;
Hence, the net ionic equation is:
[tex]\mathbf{2Ni^{2+}_{(aq)}+2S^{2-}_{(aq)} \to 2NiS_{(s)}}[/tex]
PLS HELP THESE ARE RHE ONLY QUESTIONS I HAVE LEFT DUE SOON
Explanation:
Magnesium reacts with dilute hydrochloric acid in a conical flask which is connected to an inverted measuring cylinder in a trough of water. The volume of hydrogen gas produced is measured over a few minutes, and the results are used to plot a graph
This is intended as a class practical. It is best if the students work in pairs because setting up and starting the experiment requires more than one pair of hands. One student can add the magnesium ribbon to the acid and stopper the flask, while the other starts the stopclock. During the experiment, one student can take the readings while the other records them. The experiment itself takes only a few minutes. But allow at least 30 minutes to give students time to set up, take readings and draw graph.
please mark as brainliest
One mole of Beryllium weighs 9.0122 grams. How many atoms of Beryllium are
there?
A~ 6.022x10^23
B~ 9.0122
C~ 4
D~ 18
One gram of a compound requires the following quantities of solvent to dissolve: 47 mL of water, 8.1 mL of chloroform, 370 mL of diethyl ether, or 86 mL of benzene. Calculate the solubility of the compound in these four solvents (as g/100 mL). Estimate the partition coefficient of the compound between chloroform and water, ethyl ether and water, and benzene and water. Which solvent would you choose to extract the compound from an aqueous solution
Answer:
Chloroform.
Explanation:
Given,
Solvent requires 1g of compound per 100 mL
For water,
= 1g/47ml
= 2.1
For Chloroform,
= 1 g/8.1 mL
= 12.345679
For Diethyl ether,
= 1 g/370 mL
= 0.27
For Benzene,
= 1 g/86 mL
= 1.2
Partition coefficients:
Water = -
chloroform = 5.9
Diethyl = .13
Benzene = .57
The solvent chloroform would be chosen for drawing out the compound out of an aqueous solution as it has the maximum solubility.
