Answer:
C. Endothermic because breaking bonds require energy
Explanation:
The reaction as follows is given in this question:
Cl2(g) → 2Cl(g)
According to this equation, chlorine molecule (Cl2) is broken down into chlorine atoms (2Cl) by breaking the bonds that holds the two atoms in the molecule together. Breaking of chemical bonds require energy input to occur.
An endothermic reaction is a reaction in which energy is absorbed or used up rather than released. Based on this definition, the reaction involving the breaking of bonds in chlorine molecule is an ENDOTHERMIC REACTION because breaking bonds require energy.
How many atoms are present in 44.89 moles of Be?
Answer:
I hope that helps. I did not round the answer at the end. Maybe you want the final answer in a specific decimal place.
An ideal gas at 2.0 atm pressure and 298 K temperature has a volume of 12.0 L. If the volume is decreased to 4.0 L and the temperature is held constant, what is the new pressure of the the gas in atm
Answer:
[tex]P_2=6.0atm[/tex]
Explanation:
Hello there!
In this case, according to the given information, it turns out possible for us to solve this problem by using the Boyle's law, since the temperature is constant and both volume and pressure change:
[tex]P_2V_2=P_1V_1[/tex]
Thus, we solve for the final pressure, P2, to obtain:
[tex]P_2=\frac{P_1V_1}{V_2}[/tex]
And plug in the given data to get:
[tex]P_2=\frac{2.0atm*12.0L}{4.0L}\\\\P_2=6.0atm[/tex]
Regards!
A monoprotic weak acid when dissolved in water is 0.66% dissociated and produces a solution with a pH of 3.04. Calculate the Ka of the acid. g
Answer:
Ka = 6.02x10⁻⁶
Explanation:
The equilibrium that takes place is:
HA ⇄ H⁺ + A⁻Ka = [H⁺][A⁻]/[HA]We calculate [H⁺] from the pH:
pH = -log[H⁺][H⁺] = [tex]10^{-pH}[/tex][H⁺] = 9.12x10⁻⁴ MKeep in mind that [H⁺]=[A⁻].
As for [HA], we know the acid is 0.66% dissociated, in other words:
[HA] * 0.66/100 = [H⁺]We calculate [HA]:
[HA] = 0.138 MFinally we calculate the Ka:
Ka = [tex]\frac{[9.12x10^{-4}]*[9.12x10^{-4}]}{[0.138]}[/tex] = 6.02x10⁻⁶calculate the mass in grams for 3.01 x 10^23 of Sulfur
You heat a 5.05 g piece of titanium to 98.2 oC and place it into 20.00 mL of room temperature water (24.8 oC ). The temperature of the water rises to 27.3 oC. The specific heat of water is 4.184 J/goC. The density of water is 0.997 g/mL. A. How much heat is absorbed by the water (in units of J)
Answer: The heat absorbed by the water is 52.823 J.
Explanation:
Given: Mass of metal = 5.05 g
Specific heat of water = 4.184 [tex]J/g^{o}C[/tex]
Initial temperature = [tex]24.8^{o}C[/tex]
Final temperature = [tex]27.3^{o}C[/tex]
Formula used to calculate heat absorbed is as follows.
[tex]q = m \times C \times (T_{2} - T_{1})[/tex]
where,
q = heat
m = mass of substance
[tex]T_{1}[/tex] = initial temperature
[tex]T_{2}[/tex] = final temperature
Substitute the values into above formula as follows.
[tex]q = m \times C \times (T_{2} - T_{1})\\= 5.05 g \times 4.184 J/g^{o}C \times (27.3 - 24.8)^{o}C\\= 52.823 J[/tex]
Thus, we can conclude that heat absorbed by the water is 52.823 J.
B. Directions: Identify the factors affecting the different seasons in the Philippines.
1. Areas with less rainfall, has a pronounced dry
season. When it always rain, that place has wet season most of the year.
2. The higher the particular place, the cooler its
temperature.
3. Climate near in coastal areas is cooler because
water does not absorb heat as fast as land area.
4. . When large amount of warm air cool, if gives off
lots of rain over the land
5. Philippines lies near the equator, has warm climate
during certain times of the year.
Answer:
The correct answer is -
1. Latitude
2. Altitude
3. Bodies of water
4. Wind system
5. Amount of rainfall
Explanation:
Lattitude is the angle from the earth's equator towards the north or south to the poles. This is one of the important factors that lead to different seasons and define the temperature of the area.
Altitude is the elevation from the sea that also helps in affecting the seasons as the higher the altitude cooler the temperature. Water bodies like the sea affect the wind and climate as they are not able to absorb heat faster in comparison to the land.
Wind also affects the seasons and climate of the area as a large amount of warm air cools, it gives off lots of rain over the land. Precipitation or rainfall determines and influences the climate.
2Al + 6HCl → 2AlCl3 + 3H2
You want to make 10 moles of AlCl3. How many moles of HCl does that require?
Answer: If you want to make 10 moles of [tex]AlCl_{3}[/tex] then 30 moles of HCl are required in the given reaction.
Explanation:
The given reaction equation is as follows.
[tex]2Al + 6HCl \rightarrow 2AlCl_{3} + 3H_{2}[/tex]
Here, 6 moles of HCl reacts with 2 moles of [tex]AlCl_{3}[/tex]. This means that 1 mole of [tex]AlCl_{3}[/tex] is obtained as follows.
[tex]\frac{6}{2} HCl\\= 3 HCl[/tex]
Hence, 3 moles of HCl will give 1 mole of [tex]AlCl_3[/tex]. So, moles of HCl required to react with 10 moles of [tex]AlCl_{3}[/tex] is as follows.
[tex]1 mol AlCl_3 = 3 mol HCl\\10 mol AlCl_{3} = 3 \times 10 mol HCl\\= 30 mol HCl[/tex]
Thus, we can conclude that if you want to make 10 moles of [tex]AlCl_{3}[/tex] then 30 moles of HCl are required in the given reaction.
How does the neutron number in each compare
Answer:
Neutrons are all identical to each other, just as protons are. Atoms of a particular element must have the same number of protons but can have different numbers of neutrons.
Explanation:
Since the vast majority of an atom's mass is found its protons and neutrons, subtracting the number of protons (i.e. the atomic number) from the atomic mass will give you the calculated number of neutrons in the atom. In our example, this is: 14 (atomic mass) – 6 (number of protons) = 8 (number of neutrons).
A solution has a [H3O+] 1 x 10^-3 what is the [OH-] of the solution
Answer:
OH- is 1x 10^ + 3
Explanation:
- and - = +
Write the Ka expression for an aqueous solution of hypochlorous acid: (Note that either the numerator or denominator may contain more than one chemical species. Enter the complete numerator in the top box and the complete denominator in the bottom box. Remember to write the hydronium ion out as , and not as )
Answer: The Ka expression for an aqueous solution of hypochlorous acid is [tex]K_{a} = \frac{[H_{3}O^{+}][OCl^{-}]}{[HClO]}[/tex].
Explanation:
The chemical formula of hypochlorous acid is HClO. So, when it is added to water (solvent) then its dissociation is as follows.
[tex]HClO + H_{2}O \rightarrow H_{3}O^{+} + Cl^{-}[/tex]
When we write the equilibrium constant for this reaction then it is called acid acid dissociated constant.
Hence, the expression for acid dissociation constant of this reaction is as follows.
[tex]K_{a} = \frac{[H_{3}O^{+}][OCl^{-}]}{[HClO]}[/tex]
Thus, we can conclude that the Ka expression for an aqueous solution of hypochlorous acid is [tex]K_{a} = \frac{[H_{3}O^{+}][OCl^{-}]}{[HClO]}[/tex].
gabriel created 270 grams of aluminum oxide from 145 grams of aluminum. what was his percent yield?
A. 99.1%
B. 98.6%
C. 97.2%
D.96.5%
( it’s not “D” because I got it wrong lol) pls help tho
Answer:
% yield = 200%
Explanation:
By using 145 gram of aluminium
Using 26.982 g/mol of Al, 101.96 g/mol of Aluminium oxide is produced
Using 145 grams of aluminium, the yield of Aluminium oxide would have been = (101.96 g/mol/26.982 g/mol)/145 grams
= 547.9282485 gram
Now % yield = actual yield /theoretical yield * 100
Substituting the given values, we get -
% yield = (547.928/270) *100
% yield = 200%
balance this equation plz
SO2+O2+H2O------->H2SO4
Answer: The balanced equation is [tex]2SO_{2} + O_{2} + 2H_{2}O \rightarrow 2H_{2}SO_{4}[/tex].
Explanation:
A chemical equation which contains same number of atoms on both reactant and product side is called a balanced chemical equation.
For example, [tex]SO_{2} + O_{2} + H_{2}O \rightarrow H_{2}SO_{4}[/tex]
Here, number of atoms present on reactant side are as follows.
S = 1O = 5H = 2Number of atoms present on product side are as follows.
S = 1O = 4H = 2To balance this equation, multiply [tex]SO_{2}[/tex] by 2 and [tex]H_{2}O[/tex] by 2 on reactant side. Also, multiply [tex]H_{2}SO_{4}[/tex] by 2 on product side.
Hence, the equation can be re-written as follows.
[tex]2SO_{2} + O_{2} + 2H_{2}O \rightarrow 2H_{2}SO_{4}[/tex]
Now, the number of atoms present on reactant side are as follows.
S = 2O = 8H = 4Number of atoms present on product side are as follows.
S = 2O = 8H = 4Since, the atoms present on both reactant and product side are equal. Hence, the equation is now balanced.
Thus, we can conclude that the balanced equation is [tex]2SO_{2} + O_{2} + 2H_{2}O \rightarrow 2H_{2}SO_{4}[/tex].
You calculate that 0.000345 m is the answer to a problem. You are asked to write
your answer in scientific notation. Which answer is correct? *
A~ 34.5 x 10^-5m
B~ 345 x 10^6m
C~ 3.45 x 10^-5 m
D~ 3.45 x 10^-4 m
g An ionic bond involves ____ a. molecules that gain or lose an atom to develop a bonding charge b. molecules that bond together through a weak force c. atoms that either lose or gain an electron in order to bond d. atoms that share an electron to tightly bond
Answer:
a. molecules that gain or lose an atom to develop a bonding charge
Explanation:
Write the balanced COMPLETE ionic equation for the reaction when aqueous NiCl₂ and aqueous Na₂S are mixed in solution to form solid NiS and aqueous NaCl. If no reaction occurs, simply write only NR.
Answer:
Explanation:
The chemical reaction of the well-balanced equation is as follows:
[tex]\mathbf{2NiCl_{2(aq)}+2Na_2S_{(aq)} \to 4NaCl_{(aq)}+2NiS_{s}}[/tex]
The aforementioned reaction's ionic equation is:
[tex]\mathbf{2Ni^{2+}_{(aq)}+4Cl^-_{(aq)}+ 4Na^+_{(aq)}+2S^{2-}_{(aq)} \to 4Na^+_{(aq)}+4Cl^-_{(aq)}+2NiS_{(s)}}[/tex]
From above; Na⁺ and Cl⁻ appear on both sides;
Hence, the net ionic equation is:
[tex]\mathbf{2Ni^{2+}_{(aq)}+2S^{2-}_{(aq)} \to 2NiS_{(s)}}[/tex]
PLS HELP THESE ARE RHE ONLY QUESTIONS I HAVE LEFT DUE SOON
Explanation:
Magnesium reacts with dilute hydrochloric acid in a conical flask which is connected to an inverted measuring cylinder in a trough of water. The volume of hydrogen gas produced is measured over a few minutes, and the results are used to plot a graph
This is intended as a class practical. It is best if the students work in pairs because setting up and starting the experiment requires more than one pair of hands. One student can add the magnesium ribbon to the acid and stopper the flask, while the other starts the stopclock. During the experiment, one student can take the readings while the other records them. The experiment itself takes only a few minutes. But allow at least 30 minutes to give students time to set up, take readings and draw graph.
please mark as brainliest
One gram of a compound requires the following quantities of solvent to dissolve: 47 mL of water, 8.1 mL of chloroform, 370 mL of diethyl ether, or 86 mL of benzene. Calculate the solubility of the compound in these four solvents (as g/100 mL). Estimate the partition coefficient of the compound between chloroform and water, ethyl ether and water, and benzene and water. Which solvent would you choose to extract the compound from an aqueous solution
Answer:
Chloroform.
Explanation:
Given,
Solvent requires 1g of compound per 100 mL
For water,
= 1g/47ml
= 2.1
For Chloroform,
= 1 g/8.1 mL
= 12.345679
For Diethyl ether,
= 1 g/370 mL
= 0.27
For Benzene,
= 1 g/86 mL
= 1.2
Partition coefficients:
Water = -
chloroform = 5.9
Diethyl = .13
Benzene = .57
The solvent chloroform would be chosen for drawing out the compound out of an aqueous solution as it has the maximum solubility.
Suppose a soap manufacturer starts with a triglyceride that has the fatty acid chains arachidic acid, palmitic acid and palmitic acid attached to the three backbone carbons. The manufacturer saponifies the triglyceride with NaOH. What are the fatty acid soaps that are produced in the process
Answer:
Sodium arachidate; Sodium palmitate and Sodium palmitate
Explanation:
Triglycerides are esters of fatty acids with glycerol. In triglycerides, three fatty acid molecules are linked by ester bonds to each of the three carbon atoms in a glycerol molecule. The fatty acids may be same or different fatty acid molecules. Hydrolysis of triglycerides yields the three fatty acid molecules and glycerol.
Saponification is the process by which a base is used to catalyst the hydrolysis of the ester bonds in glycerides. The products of this base-catalyzed hydrolysis of triglycerides are the metallic salts of the three fatty acids and glycerol. The salts of the fatty acids are known as soaps.
For a triglyceride that has the fatty acid chains arachidic acid, palmitic acid and palmitic acid attached to the three backbone carbons glycerol, the saponification of the triglyceride with NaOH will yield the sodium salts or soaps of the three fatty acids as well as glycerol.
Arachidic acid will react with NaOH to yield sodium arachidate.
The two palmitic acid molecules will each react with NaOH to yield sodium palmitate.
The molarity of an aqueous solution of hydrochloric acid, , is determined by titration with a M barium hydroxide, , solution. If 31.2 mL of barium hydroxide are required to neutralize 15.4 mL of the acid, what is the molarity of the hydrochloric acid solution?
Answer:
See explanation.
Explanation:
Hello there!
In this case, for this titration problem, we first need to set up the undergoing chemical equation between barium chloride and hydrochloric acid:
[tex]2HCl+Ba(OH)_2\rightarrow BaCl_2+2H_2O[/tex]
Which occurs in a 2:1 mole ratio of acid to base and thus, we can write the following:
[tex]2n_{base}=n_{acid}[/tex]
Which can be written in molarities and volumes:
[tex]2M_{base}V_{base}=M_{acid}V_{acid}[/tex]
And we solve for the molarity of the acid:
[tex]M_{acid}=\frac{2M_{base}V_{base}}{V_{acid}}[/tex]
Unfortunately, the molarity of the base was not given:
"The molarity of an aqueous solution of hydrochloric acid, , is determined by titration with a M barium hydroxide, , solution. If 31.2 mL of barium hydroxide are required to neutralize 15.4 mL of the acid, what is the molarity of the hydrochloric acid solution?"
Yet we can assume an arbitrary value, say 1.0 M in order to show you the solution so that you can modify it according to your given value:
[tex]M_{acid}=\frac{2(1.0M)(31.2mL)}{(15.4mL)}=4.05M[/tex]
So you just need to modify the (1.0 M) by the actually given molarity of the acid.
Regards!
The osmotic pressure exerted by a solution is equal to the molarity multiplied by the absolute temperature and the gas constant . Suppose the osmotic pressure of a certain solution is measured to be at an absolute temperature of .
Answer:
c = π/T*R
c = 0.199M
Explanation:
Is measured to be 5.1 atm at an absolute temperature of 312. K. Write an equation that will let you calculate the molarity c of this solution. Your equation should contain only symbols. Be sure you define each symbol other than R.
The osmotic pressure of a solution, π, is defined as:
π = c*T*R
As we know osmotic pressure π = 5.1atm, T = 312K and R = 0.082atmL/molK
we can replace in the equation as follows:
π= c*T*R
c = π/T*Rc = 5.1atm/312K*0.082atmL/molK
c = 0.199M
How many products might be formed on chlorination of o-xylene (o-dimethylbenzene), m-xylene, and p-xylene
1.Consider the molecule azulene and
a) set the secular determinant for azulene within the huckel approximation and using the out of plane C2p orbitals as basis set.
b) Estimate pi electron binding energy within the Huckel approximation
c) Approximate the delocalization energy
Someone pls help me ::/:/
How much energy must be added to 250.0 g of ice at 0.00 °C to raise the
temperature of the water to 50.0 °C? The heat of fusion for water is 334
J/g. The specific heat of water is 4.184 J/g.K.
Answer:
136 KJ
Explanation:
We'll begin by calculating the heat required to melt the ice. This can be obtained as follow:
Mass (M) = 250 g
Heat of fusion (Hբ) = 334 J/gºC
Heat (Q₁) required to melt the ice =?
Q₁ = MHբ
Q₁ = 250 × 334
Q₁ = 83500 J
Next, we shall determine the heat required to change the temperature. This can be obtained as follow:
Mass (M) = 250 g
Initial temperature (T₁) = 0 °C
Final temperature (T₂) = 50 °C
Specific heat capacity (C) = 4.184 J/gºC
Heat (Q₂) required to change the temperature =?
Q₂ = MC(T₂ – T₁)
Q₂ = 250 × 4.184 (50 – 0)
Q₂ = 1046 × 50
Q₂ = 52300 J
Next, we shall determine the total heat required.
Heat (Q₁) required to melt the ice = 83500 J
Heat (Q₂) required to change the temperature = 52300 J
Total heat (Qₜ) required =?
Qₜ = Q₁ + Q₂
Qₜ = 83500 + 52300
Qₜ = 135800 J
Finally, we shall convert 135800 J to KJ. This can be obtained as follow:
1000 J = 1 KJ
Therefore,
135800 J = 135800 J × 1 KJ / 1000 J
135800 J ≈ 136 KJ
Thus, the total heat required is 136 KJ.
A 59.0 mL portion of a 1.80 M solution is diluted to a total volume of 258 mL. A 129 mL portion of that solution is diluted by adding 183 mL of water. What is the final concentration
Answer:
0.170 M
Explanation:
As this is a series of dilutions, we can continuosly use the C₁V₁=C₂V₂ formula to solve this problem:
For the first step:
59.0 mL * 1.80 M = 258 mL * C₂C₂ = 0.412 MThen for when 129 mL of that 0.412 M are diluted by adding 183 mL of water:
V₂ = 129 mL + 183 mL = 312 mLUsing C₁V₁=C₂V₂:
129 mL * 0.412 M = 312 mL * C₂C₂ = 0.170 M1. An ion has a net charge of - 3, and 12 electrons, what is its atomic number? What element has that atomic number?
2. An ion of Celsius has a net charge of -5, how many electrons does it have?
3. Some atom has an atomic number of 46, how many electrons does it have if it has a net charge of +2?
4. How many neutrons are in an atom of Helium, and what is its mass number?
5. There are 3 neutrons in an isotope of Helium, what is its mass number?
6. n isotope has 83 neutrons and a mass number of 167, what is its atomic number? What element is defined by that atomic number?
7. What element has 54 neutrons and a mass number of 112?
8. What element has 10 electrons, a net charge of -2?
Answer:
19 because it gained 3 electron so 12-3=9 beryllium
2
3 is 46-2=44
4 is 2
5 is 5
6 84 polonium
7
8 oxygen
Explanation:
plz let me know if they are right or wrong:)
. Which is instinctive behavior? A. A puppy cuddling its human owner.C. A young child learned how to read. B. A duckling swimming after its mother.D. A kitten learning to use a litter box.
Answer:
A duckling swimming after its own mother
Explanation:
How many grams of 02 are present in 7.49 L of oxygen gas?
Answer:
10.70grams
Explanation:
Density of a substance = mass/volume
At STP of a gas (standard temperature and pressure), the density of oxygen gas is 1.429 g/L
Hence, according to this question, in 7.49 L of oxygen gas, there would be:
Using D = m/V
1.429 = m/7.49
m = 1.429g/L × 7.49L
m = 10.70g
A 100.0 mL sample of natural water was titrated with NaOH. The titration required 14.53 mL of 0.1031 M NaOH solution to reach a light pink phenolphthalein end point.
Calculate the number of millimoles of NaOH required for the titration.
Answer:
The correct answer is 1.498.
Explanation:
Based on the given information, the volume of NaOH needed for the titration is 14.53 ml, and the concentration of NaOH given is 0.1031 M.
The volume of NaOH, that is, 14.53 ml can also be written as 14.53 × 10⁻³ L.
The concentration of NaOH, that is, 0.1031 M can also be written as 0.1031 moles/Litre.
Molarity (M) is determined as,
M = No of moles/Volume in litres
No of moles = Molarity × Litres
No of moles = 0.1031 moles/Litres × 14.53 × 10⁻³ L
No of moles = 1.498 × 10⁻³ L
Now, number of millimoles = 1.498 × 10⁻³ L × 1000 (millimoles = moles × 1000)
Number of millimoles = 1.498
The number of millimoles of NaOH required for the titration is 1.50 mmol
From the question,
We are to determine the number of millimoles of NaOH required for the titration
From the given information
The titration required 14.53 mL of 0.1031 M NaOH solution
From the formula
Number of moles = Concentration × Volume
Concentration of the NaOH = 0.1031 M
Volume of the NaOH = 14.53 mL
∴ Number of millimoles of NaOH required = 0.1031 × 14.53
Number of millimoles of NaOH required = 1.498043 mmol
Number of millimoles of NaOH required ≅ 1.50 mmol
Hence, the number of millimoles of NaOH required for the titration is 1.50 mmol
Learn more here: https://brainly.com/question/21086618
A solution has a pH of 2.5. what is the H+
Answer: The concentration of [tex]H^+[/tex] in the solution is [tex]3.16\times 10^{-3}M[/tex]
Explanation:
pH is defined as the negative logarithm of hydrogen ion concentration present in the solution.
[tex]pH=-\log [H^+][/tex] .....(1)
We are given:
pH of solution = 2.5
Putting values in equation 1, we get:
[tex]2.5=-\log [H^+][/tex]
[tex][H^+]=10^{-2.5}[/tex]
[tex][H^+]=3.16\times 10^{-3}M[/tex]
Hence, the concentration of [tex]H^+[/tex] in the solution is [tex]3.16\times 10^{-3}M[/tex]
What mass of sodium hydroxide is needed to make 12.5 L of a 0.150M solution?
a) 1.88g
b) 40.0g
c) 75.0g
d) 83.0g
Answer:
75g
Explanation:
n=Cmxv
=0,15x12,5
=1,875 mol
m=nxM
=1,875x40
=75g
