Answer:
121
Explanation:
which wave characteristic is the same for all electromagnetic waves traveling through a vacuum?
Answer:
All waves travel at the same speed c.
How much power is required to light a lightbulb at 100V of voltage when the lightbulb has a resistance of 500 Ohms?
Answer:
20 Watt
Explanation:
Applying
P = V²/R................... Equation 1
Where V = Voltage, P = Power, R = resistance
From the question,
Given: V = 100V, R = 500 ohms
Substitute these values into equation 1
P = (100²)/500
P = 10000/500
P = 20 Watt.
Hence the power required to light the bulb is 20 W
in a Mercury thermometer the level of Mercury Rises when its bulb comes in contact with a hot object what is the reason for this rise in the level of Mercury
Answer:
because thermometric liquid readily expands on heating or contracts on cooling even for a small difference in the temperature of the body.
Find the acceleration due to gravity on the surface of a planet with a mass of 3.5 * 10^24 kg and an average radius of 4.5 * 10^6 m.
A truck is driving over a scale at a weight station. When the front wheels drive over the scale, the scale reads 5800 N. When the rear wheels drive over the scale, it reads 6500 N. The distance between the front and rear wheels is 3.20 m Determine the distance between the front wheels and the truck's center of gravity.
Answer:
[tex]x_2=1.60m[/tex]
Explanation:
From the Question We are told that
Initial Force [tex]F_1=5800N[/tex]
Final Force [tex]F_2=6500N[/tex]
Distance between the front and rear wheels \triangle x=3.20 m
Since
[tex]\triangle x=3.20 m[/tex]
Therefore
[tex]x_1+x_2=3.20[/tex]
[tex]x_1=3.20-x_2[/tex]
Generally the equation for The center of mass is at x_2 is mathematically
given by
[tex]x_2 =\frac{(F_1x_1+F_2x_2)}{(F_1+F_2)}[/tex]
[tex]x_2=3.20F_1-\frac{x_2F_1+F_2x_2}{(F_1+F_2)}[/tex]
[tex]2*F_1*x_2 =3.20F_1[/tex]
[tex]x_2=1.60m[/tex]
Center of gravity of a body is the sum of its moments divided by the overall weight of the object. The distance between the front wheels and the truck's center of gravity is 1.6 meters.
Given-
Scale reading value when the front wheels drive over the scale [tex]m_{1}[/tex] is 5800 N.
Scale reading value when the rear wheels drive over the scale [tex]m_{2}[/tex] is 6500 N
Distance between the front and rear wheel [tex]\bigtriangleup x[/tex] is 3.20 meters.
Let, the distance between the front wheels and the truck's center of gravity is [tex]x_{2}[/tex].
Since sum of the distance between front wheel to truck's center of gravity [tex]x_{1}[/tex], and rear wheel to truck's center of gravity [tex]x_{2}[/tex], is equal to the distance between the front and rear wheel [tex]\bigtriangleup x[/tex]. Therefore,
[tex]\bigtriangleup x=x_{1} +x_{2}[/tex]
[tex]3.20=x_{1} +x_{2}[/tex]
[tex]x_{1} =3.20-x_{2}[/tex]
For the distance between the front wheels and the truck's center of gravity is the formula of center of gravity can be written as,
[tex]x_{2} =\dfrac{m_{1}x_{1}+m_{2} x_{2} }{m_{1} +m_{2} }[/tex]
[tex]x_{2} =\dfrac{5800\times (3.20- x_{2})+6500\times x_{2} }{5800 +6500 }[/tex]
[tex]1230 x_{2} ={18560-5800 x_{2}+6500 x_{2} }[/tex]
[tex]x_{2}= 1.6[/tex]
Hence, the distance between the front wheels and the truck's center of gravity is 1.6 meters.
For more about the center of gravity, follow the link below-
https://brainly.com/question/20662119
An ideal spring is used to stop blocks as they slide along a table without friction. A 0.80 kg block traveling at a speed of 2.2 m/s can be stopped over a distance of 0.11 m once it makes contact with the spring.
A rectangular block on a level surface moves at velocity v to the right towards a spring that rests on the surface and is attached to a fixed mount on the right.
What distance would a 1.40 kg block travel after making contact with the spring if the block is traveling at a speed of 3.0 m/s before it makes contact with the spring?
Use the work-energy theorem: the total work done on the 0.80 kg block by the spring to make it come to a stop is equal to the change in the block's kinetic energy.
If we take the block's initial direction of motion to be positive, then the spring does negative work on the block, and
-1/2 k (0.11 m)² = 0 - 1/2 (0.80 kg) (2.2 m/s)²
Solve for the spring constant k :
k = (1/2 (0.80 kg) (2.2 m/s)²) / (1/2 (0.11 m)²) = 320 N/m
We can use the same equation as above to find the distance the 1.40 kg block would travel as it is slowed down by the same spring:
-1/2 (320 N/m) x ² = 0 - 1/2 (1.40 kg) (3.0 m/s)²
Solve for the displacement x :
x = √((1/2 (1.40 kg) (3.0 m/s)²) / (1/2 (320 N/m))) ≈ 0.20 m
Which statement describe. good hypothesis ? Check all that apply
How do we get heat on Earth? Does thermal energy travel directly from the sun?
A concert loudspeaker suspended high off the ground emits 26.0 W of sound power. A small microphone with a 1.00 cm2 area is 53.0 m from the speaker. Part A What is the sound intensity at the position of the microphone
Answer:
the sound intensity at the position of the microphone is 7.4 × 10⁻⁴ W/m²
Explanation:
Given the data in the question;
Sound power P = 26.0 W
Area of microphone A = 1.00 cm²
Radius r = 53.0 m
sound intensity at the position of the microphone = ?
Now, intensity at the position of the microphone can be determined using the following expression;
[tex]I[/tex] = P / 4πr²
We substitute
[tex]I[/tex] = 26.0 / ( 4 × π × (53.0 )² )
[tex]I[/tex] = 26.0 / ( 4 × π × 2809 )
[tex]I[/tex] = 26.0 / 35298.935
[tex]I[/tex] = 26.0 / ( 4 × π × (53.0 )² )
[tex]I[/tex] = 0.000736566
[tex]I[/tex] = 7.4 × 10⁻⁴ W/m²
Therefore, the sound intensity at the position of the microphone is 7.4 × 10⁻⁴ W/m²
acceleration of a refrigerator 30s after a person begins pushing it at a force of 400 N
Question: Find acceleration of a refrigerator 30s after a person begins pushing it at a force of 400 N, If the mass of the refrigerator is 10 kg.
Answer:
40 m/s²
Explanation:
Applying,
F = ma................Equation 1
Where F = Force applied to the refrigerator, m = mass of the refrigerator, a = acceleration of the refrigerator.
make a the subject of the equation
a = F/m............ Equation 2
From the question,
Given: F = 400 N, m = 10 kg
Substitute these values into equation 2
a = 400/10
a = 40 m/s²
A thermodynamic system consists of an ideal gas at a volume of 3.50 L and initial pressure of 6.2 × 104 Pa. As the volume is held constant, the pressure is increased to 8.2 × 104 Pa. What work is involved in this process?
Answer:
0 J
Explanation:
Since work done W = PΔV where P = pressure and ΔV = change in volume.
Since the volume is constant, ΔV = 0
So, Work done, W = PΔV = P × 0 = 0 J
So, the work done is 0 J.
Question 24 of 33 Which of the following is an example of uniform circular motion? A. A car speeding up as it goes around a curve O B. A car slowing down as it goes around a curve 2 C. A car maintaining constant speed as it goes around a curve D. A car traveling along a straight road
Answer:
Uniform Circular Motion is the Movement or Rotation of an Object along a circular Path at constant speed.
OPTION C IS YOUR ANSWER!.
You need to produce a set of cylindrical copper wire 3.5 m long that will have a
resistance of 0.125 Ω each. What will be the mass of each of these wires?
(ρ = 1.72X10-8 Ωm, density of copper = 8.9X103 kg/m3)
Solution :
We know, resistance is given by :
[tex]R = \dfrac{\rho l}{A}[/tex]
[tex]A = \dfrac{\rho l }{R}\\\\A = \dfrac{1.72\times 10^{-8} \times 3.5 }{0.125}\\\\A = 4.816 \times 10^{-7} \ m^2[/tex]
Now, we know mass of wire is given by :
[tex]Mass = Density \times Volume\\\\\M = 8.9 \times 10^3 \times 4.816 \times 10^{-7} \times 3.5 kg\\\\M = 0.01500\ kg\\\\M = 15.00\ gram[/tex]
Hence, this is the required solution.
Given:
Length of wire, l = 3.5 mResistance, R = 0.125 ΩThe resistance will be:
→ [tex]R = \frac{\rho l}{A}[/tex]
or,
→ [tex]A = \frac{\rho l}{R}[/tex]
By substituting the values, we get
[tex]= \frac{1.72\times 10^{-8}\times 3.5}{0.125}[/tex]
[tex]= 4.816\times 10^{-7} \ m^2[/tex]
hence,
The mass will be:
→ [tex]Mass = Density\times Volume[/tex]
[tex]= 8.9\times 10^3\times 4.816\times 10^{-7}\times 3.5[/tex]
[tex]= 0.01500 \ kg[/tex]
[tex]= 15.00 \ g[/tex]
Thus the above answer is right.
Learn more about mass here:
https://brainly.com/question/17108656
A 45.00 kg person in a 43.00 kg cart is coasting with a speed of 19 m/s before it goes up a hill.Assuming there is no friction, what is the maximum vertical height the person in the cart can reach?
Answer:
the maximum vertical height the person in the cart can reach is 18.42 m
Explanation:
Given;
mass of the person, m₁ = 45 kg
mass of the cart, m₂ = 43 kg
velocity of the system, v = 19 m/s
let the maximum vertical height reached = h
Apply the principle of conservation mechanical energy;
[tex]P.E = K.E\\\\mgh_{max} = \frac{1}{2} mv^2_{max}\\\\gh_{max} = \frac{1}{2} v^2_{max}\\\\h_{max} = \frac{v_{max}^2}{2g} \\\\h_{max} = \frac{19^2}{2\times 9.8} \\\\h_{max} = 18.42 \ m[/tex]
Therefore, the maximum vertical height the person in the cart can reach is 18.42 m
A gymnast is swinging on a high bar. The distance between his waist and the bar is 1.06 m, as the drawing shows. At the top of the swing his speed is momentarily zero. Ignoring friction and treating the gymnast as if all of his mass is located at his waist, find his speed at the bottom of the swing.
Answer: The speed of gymnast at the bottom of the swing is 6.44 m/s.
Explanation:
Given: Distance = 1.06 m
According to the law of conservation of energy, the speed is calculated as follows.
[tex]mgh = - mgh + \frac{1}{2}mv^{2}\\gh = - gh + \frac{1}{2}v^{2}\\v = \sqrt{4gh}[/tex]
where,
g = acceleration due to gravity = 9.8 [tex]m/s^{2}[/tex]
h = distance
v = speed
Substitute the values into above formula as follows.
[tex]v = \sqrt{4gh}\\= \sqrt{4 \times 9.8 m/s^{2} \times 1.06}\\= 6.44 m/s[/tex]
Thus, we can conclude that speed of gymnast at the bottom of the swing is 6.44 m/s.
Si un electrón recorre el acelerador lineal de Stanford de 2 millas de longitud a 99% de la velocidad de la luz, ¿Cuál es la longitud del acelerador según el electrón?
What can/should we be doing now to prepare for the mass migration to come?
Answer:
Here are a few recommendations based on IOM's Migration Governance Framework: Countries should promote stability, education and employment opportunities and reduce the drivers of forced migration, including by promoting resilience, thereby enabling individuals to make the choice between staying or migrating.
Explanation:
thank me later
The area around a magnet containing all of magnetic Lines of force is called
Answer:
Magnetic Field
Explanation:
The area around a magnet containing all of magnetic Lines of force is called the magnetic field.
Two people are paddling a canoe downstream with a speed of 5 km/h relative to the river. If the river is flowing at 15 km/h, how long will it take them to reach the canoe dock 30 km away?
A 1.5 h
B 1.0 h
C 0.5h
D 3.0h
HELPPP
The height of the mercury column in a barometer is 756 mm Hg on
a cloudy day.Calculate the atmospheric pressure at that time in pascal.
( Density of mercury p= 13 600 kg/m^3, gravitational acceleration, g = 9.81m/s²)
Answer:
p = 1.0076 10⁵ Pa
Explanation:
Atmospheric pressure is given by the relation
P = rho g h
In this case they indicate that the height of the column of mercury is h = 756 mm Hg
let's reduce the height to the SI system
h = 756 mm (1m / 1000 mm)
h = 0.756 m
let's calculate
P = 13600 9.8 0.756
p = 1.0076 10⁵ Pa
An ideal spring is fixed at one end. A variable force F pulls on the spring. When the magnitude of F reaches a value of 43.8 N, the spring is stretched by 15.5 cm from its equilibrium length. Calculate the additional work required by F to stretch the spring by an additional 10.4 cm from that position. (in J)
A force of 43.8 N is required to stretch the spring a distance of 15.5 cm = 0.155 m, so the spring constant k is
43.8 N = k (0.155 m) ==> k = (43.8 N) / (0.155 m) ≈ 283 N/m
The total work done on the spring to stretch it to 15.5 cm from equilibrium is
1/2 (283 N/m) (0.155 m)² ≈ 3.39 J
The total work needed to stretch the spring to 15.5 cm + 10.4 cm = 25.9 cm = 0.259 m from equilibrium would be
1/2 (283 N/m) (0.259 m)² ≈ 9.48 J
Then the additional work needed to stretch the spring 10.4 cm further is the difference, about 6.08 J.
Which of the following never cause a change in the motion of an object? O A. Net forces O B. Unbalanced forces C. Balanced forces D. Contact forces
Answer:
Hello There!!
Explanation:
The answer is C. Balanced forces.
hope this helps,have a great day!!
~Pinky~
Balanced forces never cause a change in the motion of an object. Hence, option C is correct, rest are not correct.
What is a Balanced Force?Unless another force is added, forces will always be in balance. The forces are equal, for instance, when the paper, pencil, and pen are set. Selfishly, they push and pull. However, when gravity is added, it pulls the object down, causing it to fall.
When two forces are equal in size and have the same direction, they are said to be balanced. They are thought of as being in an equilibrium state. The motion or direction of an object cannot be changed by balanced forces; instead, they maintain the object's motion at a constant speed.
A force that is exerted in one direction more than it is in the other is said to have imbalanced forces. An object's speed and/or direction change when unbalanced forces are exerting pressure on it.
To get more information about balanced forces :
https://brainly.com/question/19127263
#SPJ2
What are vectors and Scalar?
Answer:
vectors are the quantities that are described by both magnitude and direction
scalar are the quantities that are described by magnitude only
I hope it helps
Answer:
scalar : just magnitude
vector : magnitude and direction
Explanation:
Scalar And Vector. ... A scalar quantity is defined as the physical quantity that has only magnitude, for example, mass and electric charge. On the other hand, a vector quantity is defined as the physical quantity that has both magnitude as well as direction like force and weight.
QUESTION 5 (Start on a new page.)
A roller-coaster car of mass 200 kg, with the engine switched off, travels along
track ABC which has a rough surface, as shown in the diagram below. At point A,
which is 10 m above the ground, the speed of the car is 4 m.s.
At point B, which is at a height h above the ground, the speed of the car is 2 m.st.
During the motion from point A to point B, 3,40 x 10 J of energy is used to overcome
friction.
Ignore rotational effects due to the wheels of the car.
4 m.s
2 m.s1
22 m
B
h
10 m
(2)
5.1
Define the term non-conservative force.
botravelled from
A man's face is at a distance p = 15 cm in front of a concave spherical shaving mirror. If the image is erect (upright) and 1.5 times largen than the object, what is the radius of curvature of the mirror? O R = 90 cm R = 180 cm R = 36 cm R = 60 cm O R = 30 cm
Answer:
f5iftdihv
yor68ruo
Explanation:
475y8
One way to ensure that the race ends up in a tie is to have the person who lost the original race run a shorter distance before turning around. Instead of 80.0 m, what should that distance be
Answer:
The appropriate answer is "72.8 m".
Explanation:
Let the distance be "x".
As per the question, we get
⇒ [tex]T_{Mia}=T_{Brandi}[/tex]
or,
⇒ [tex]\frac{x}{13} +\frac{x}{7}=\frac{\80}{10} +\frac{80}{10}[/tex]
By taking L.C.M, we get
⇒ [tex]\frac{20x}{91}=16[/tex]
By applying cross-multiplication, we get
⇒ [tex]20x=1440[/tex]
⇒ [tex]x=\frac{1456}{20}[/tex]
⇒ [tex]=72.8\ m[/tex]
What is the ratio of W|| to weight of the brick
Answer:
0.87 C.
What is the ratio of Wto the Weightof the brick? 0.87 C. Sine (sin), cosine (cos), and tangent (tan) are ratios of the lengths of a right triangle'ssides.Explanation:
Lab: Kinetic EnergyIn Part I, the independent variable was . In Part II, the independent variable changed to . The dependent variable for both Part I and Part II was .
Answer:
motion
is form of energy
Answer:
1) mass
2) speed
3) kinetic energy
Explanation:
Nature I guess......
what are adaptive animals
Explanation:
Adaptations are any behavioral or physical characteristics of an animal that help it to survive in its environment
a 4 kg block of iron weighs about
a.) 4 N
b.) 40 N
c.) 0.4 N
d.) more than 400 N
Answer:
40 N
Explanation:
[tex]w = mg \\ w = 4 \times 9.81 \\ w = 39.24 = 40 \: [/tex]
