How many dots belong in the electron dot diagram of a boron (B) atom?

three
five
eight
thirteen. pls let me know I have been working on this for 9 hours

Answer:

2Hz

Explanation:

Find the diagram attached

Using the formula;

v = fλ

v is the velocity

f is the frequency

λ is the wavelength

Given the following

v = 3.2m/s

λ = 4.8/3 = 1.6m

Get the frequency

f = v/λ

f = 3.2/1.6

f = 2Hertz

Hence the frequency of the wave is 2Hz

The frequency of the wave is equal to 2.0 Hertz.

Given the following data:

To calculate the frequency of the wave​:

First  of all, we would determine the wavelength of the wave in the image attached below:

Note: Wavelength is the successive distance between two (2) crests.

[tex]Wavelength = \frac{distance}{3} \\\\Wavelength = \frac{4.8}{3}[/tex]

Wavelength = 1.6 meter.

Mathematically, frequency is given by this formula:

[tex]Frequency = \frac{velocity}{wavelength} \\\\[/tex]

Substituting the given parameters into the formula, we have;

[tex]Frequency = \frac{3.2}{1.6}[/tex]

Frequency = 2.0 Hertz.

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Answer:

If an object is at rest, then the forces acting on both sides are equal and there is resultant force is 0.

Answer:

All matter is made up of atoms.

Answer:

Based on what we have learned so far, in what ways have the experiences of Asian-Canadians stayed the same over time? Why do you think these similarities exist? Please give specific examples to support your ideas.

Explanation:

Answer:

6.58×10⁶ F

Explanation:

Applying,

Q = CV..................... Equation 1

Where Q = charge of the capacitor, C = Capacitance of the capacitor, V = Volatage

Make C the subject of the equation

C = Q/V................. Equation 2

From the question,

Given: Q = 7.9×10⁷ C, V = 12.0 V

Susbtitute these values into equation 2

C = 7.9×10⁷/12

C = 6.58×10⁶ F

Answer:

9.7 miles per second

Explanation:

divide 200 by 20.6

Answer:

10N/m

Explanation:

Using F=kx

F=mg

k=mg/x

k=0.1*10/0.1 (kg*m/s^2)/m

10N/m

Answer: 43.7

Explanation: Simply round the number so that there are only three digits in the number.

We have that 43.659 rounded to three significant digits is

[tex]43.659=43.7[/tex]

From the Question we are Given

Integer=43.659

To round off to three significant digits means to represent only three digits

Therefore

43.659 in  three digits is

[tex]43.659=43.7[/tex]

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Answer is 29.1 mol or 525 g

Explanation:

Answer:

Algunos se mueven en dos direcciones y algunos se mueven en las cuatro direcciones.

Explicación:

Para investigar la posición del cuerpo en general, la posición de la cabeza, la posición de los brazos y manos y los pies tienen algunos movimientos específicos. Algunos se mueven hacia arriba y hacia abajo significa en dos direcciones mientras que el otro se mueve en todas las direcciones. Los brazos se mueven solo hacia adelante y hacia atrás, mientras que, por otro lado, los pies, la mano y la cabeza se mueven hacia la izquierda, la derecha y hacia arriba y hacia abajo.

Answer:

→Inverted image ( upside down )

→Real image ( because it is formed on the screen )

→Magified image ( image size is greater than object size)

F = ma

so, we can write it as;

= 5 = m × 20

= 5/20 = m

= 1/4 = m

= 0.25 kg = m

Light is a form of electromagnetic radiation with a wavelength which can be detected by the human eye. It is a small part of the electromagnetic spectrum and radiation given off by stars like the sun. Animals can also see light. The study of light, known as optics, is an important research area in modern physics.

Answer:

hope it is helpful to you

Answer:

it reheated and use form another

Answer:

-1m/s

Explanation:

We can calculate the speed of block A after collision

According to collision theory:

MaVa+MbVb = MaVa+MbVb (after collision)

Substitute the given values

5(3)+10(0) = 5Va+10(2)

15+0 = 5Va + 20

5Va = 15-20

5Va = -5

Va = -5/5

Va = -1m/s

Hence the velocity of ball A after collision is -1m/s

Note that the velocity of block B is zero before collision since it is stationary

Explanation:

During the day the sky looks blue because it's the blue light that gets scattered the most. It's redirected into many different directions all over the sky, whereas the other wavelengths aren't scattered as much. Sunlight reaches Earth's atmosphere and is scattered in all directions by all the gases and particles in the air. Blue light is scattered more than the other colors because it travels as shorter, smaller waves. This is why we see a blue sky most of the time. White light is composed of seven light and among them, blue light scatters the most as the wavelength of the blue light is comparable to the size of particles in the atmosphere. So, the sky appears blue. Hence, the sky appears blue because the fine particles in the atmosphere scatter light of shorter wavelengths! :D

Answer:

Explanation:

I'm assuming your charge is in Coulombs so I will proceed that way. The formula for this electric field problem is

[tex]E=\frac{kQ}{r^2}[/tex] where k = 9.0 × 10⁹. Filling in:

[tex]E=\frac{(9.0*10^9)(1.25*10^{-3})}{.4^2}[/tex] gives us an electric field value of

7.0 × 10⁷ N/C

Answer:

[tex]we \: know \: energy \: = \: force \: \times distance \\ e = f \times d \\ so \: f \: = \frac{e}{d} \\ so \: th \: force \: here \: = (\frac{2670}{3}) newton \\ = 890newton[/tex]

Hope it helps

Explanation:

hope it helps thanks

pls mark me as brainliest

Answer:

In the first one circle : luster

second circle: atsuete seeds

third: dentures

Explanation:

Well I ain’t sure

Answer:

Truss bridge, bridge with its load-bearing structures composed of a series of wooden or metal triangles, known as trusses. Given that a triangle cannot be distorted by stress, a truss gives a stable form capable of supporting considerable external loads over a large span.

Explanation:

Load-bearing capacity of truss bridges is huge due to the structure of interconnecting triangles. The structure effectively manages both compression and tension by spreading the load from the roadway throughout its intricate structure

Answer:

a

Explanation:

because it has  compact  molecules  

[tex] \orange{\underline{\huge{\bold{\textit{\green{\bf{QUESTION}}}}}}}[/tex]

The apparent depth of an object at the bottom of a tank filled with a liquid of refractive index 1.3 is 7.7 cm. What is the actual depth of the liquid in the tank?

[tex]{\bold{\blue{GIVEN}}}[/tex]

REFRACTIVE INDEX = 1.3

APPARENT DEPTH = 7.7 cm

[tex]{ \bold{\green{To \: Find}}}[/tex]

REAL DEPTH OF THE OBJECT.

[tex]{\red{FORMULA \: \: USED }}[/tex]

[tex]Reflective \: Index = \frac{Real \: Depth}{Apparent \: Depth } [/tex]

[tex] \huge\mathbb{\red A \pink{N}\purple{S} \blue{W} \orange{ER}}[/tex]

Refractive Index = 1.3

Apparent Depth = 7.7 cm

Putting the values in the formula:-

[tex]Reflective \: Index = \frac{Real \: Depth}{Apparent \: Depth } \\ \\ 1.3 = \frac{Real \: Depth}{7.7 \: cm} \\ \\ 1.3 \times 7.7 = Real \: Depth \\ \\ 10.01 \: \: cm = Real \: Depth[/tex]

Answer:

 U = 25 J

Explanation:

The energy in a set of charges is given by

          U = [tex]k \sum \frac{q_i}{r_i}[/tex]

in this case we have three charges of equal magnitude

          q = q₁ = q₂ = q₃

with the configuration of an equilateral triangle all distances are worth

          d = a

          U = k ( [tex]\frac{q_1q_2}{ r_1_2 } + \frac{q_1q_3}{r_1_3} + \frac{q_2q_3}{r_2_3}[/tex] )

we substitute

           15 = k q² (3 / a)

            k q² /a = 5

For the second configuration a load is moved to the measured point of the other two

          d₁₃ = a

The distance to charge 2 that is at the midpoint of the other two is

          d₁₂ = d₂₃ = a / 2

           U = k (\frac{q_1q_2}{ r_1_2 } + \frac{q_1q_3}{r_1_3} + \frac{q_2q_3}{r_2_3})

            U = k q² (  [tex]\frac{2}{a} + \frac{1}{a} + \frac{2}{a}[/tex] )

            U = (kq² /a) 5

substituting

            U = 5 5

            U = 25 J

Answer:

Smart Meters measure both the amount of electrical energy used and the time at which it is being used because they are used to monitor the energy consumption at real time, such that the time of use of energy can be monitored, thereby enabling several utility functions for load sharing and maintenance, including;

i) Time of use  tariffs, where energy is billed based on peak and off peak periods, which increases profits to the producer, reduces cost for some consumers, encourages more even hourly and daily usage of electricity, lower maintenance cost, lower capital expenditure for peak stations, and reduces carbon emission

ii) Guarantees more accurate energy consumption measurement and billing

iii) Accurate crew dispatch to fault locations

iv) Prevent fraud due to tampering with meter

v) Increase customer confidence in billing

Explanation:

Answer:

8.5 Ω

Explanation:

La resistencia de un material es directamente proporcional a su longitud e inversamente proporcional al área de la sección transversal.

La fórmula de la resistencia (R) viene dada por:

R = ρL/A

Donde ρ es la resistividad del material, L es la longitud del material y A es el área de la sección transversal del material.

Dado que:

L = 1 km = 1000 m, A = 2 mm² = 2 * 10⁻⁶ m², ρ (cobre) = 1.7 * 10⁻⁸ Ωm

Sustituyendo da:

R = 1,7 * 10⁻⁸ * 1000/2 * 10⁻⁶

R = 8.5 Ω

Answer:

often Positive and negative charges balance each other which gives an overall neutral charge. if they are unbalanced then it will result in static electricity.

10. True

11. True

12. True

13. False

14. False

Hope this helps!!

Answer:

Explanation:

I got everything but i. Don't know why but it's eluding me. So let's do everything but that.

a. PE = mgh so

   PE = (2.5)(98)(14) and

   PE = 340 J

b. [tex]KE=\frac{1}{2}mv^2[/tex] so

   [tex]KE=\frac{1}{2}(2.5)(14)^2[/tex] and

   KE = 250 J

c. TE = KE + PE so

   TE = 340 + 250 and

   TE = 590 J

d. PE at 8.7 m:

   PE = (2.5)(9.8)(8.7) and

   PE = 210 J

e. The KE at the same height:

   TE = KE + PE and

   590 = KE + 210 so

   KE = 380 J

f. The velocity at that height:

   [tex]380=\frac{1}{2}(2.5)v^2[/tex] and

   [tex]v=\sqrt{\frac{2(380)}{2.5} }[/tex] so

   v = 17 m/s

g. The velocity at a height of 11.6 m (these get a bit more involed as we move forward!). First we need to find the PE at that height and then use it in the TE equation to solve for KE, then use the value for KE in the KE equation to solve for velocity:

   590 = KE + PE and

   PE = (2.5)(9.8)(11.6) so

   PE = 280 then

   590 = KE + 280 so

   KE = 310 then

   [tex]310=\frac{1}{2}(2.5)v^2[/tex] and

   [tex]v=\sqrt{\frac{2(310)}{2.5} }[/tex] so

   v = 16 m/s

h. This one is a one-dimensional problem not using the TE. This one uses parabolic motion equations. We know that the initial velocity of this object was 0 since it started from the launcher. That allows us to find the time at which the object was at a velocity of 26 m/s. Let's do that first:

   [tex]v=v_0+at[/tex] and

   26 = 0 + 9.8t and

   26 = 9.8t so the time at 26 m/s is

   t = 2.7 seconds. Now we use that in the equation for displacement:

   Δx = [tex]v_0t+\frac{1}{2}at^2[/tex] and filling in the time the object was at 26 m/s:

   Δx = 0t + [tex]\frac{1}{2}(-9.8)2.7)^2[/tex] so

   Δx = 36 m

i. ??? In order to find the velocity at which the object hits the ground we would need to know the initial height so we could find the time it takes to hit the ground, and then from there, sub all that in to find final velocity. In my estimations, we have 2 unknowns and I can't seem to see my way around that connundrum.