Answer:
I hope you understand please follow me please
How many molecules are contained in 52.5 moles of C2H8?
please explain if you can
Answer:
3.1621 × 10²⁵ molecules
Explanation:
From the given information:
Moles of C2H8 = 52.5 moles
number of moles = mass/molar mass
molar mass of C2H8 = (6 *2) + (1*8)
= 12 + 8
= 20 g/mol
∴
52.5 moles = mass of C2H8 / 20 g/mol
mass of C2H8 = 52.5 moles × 20 g/mol
mass of C2H8 = 1050 grams
Recall that;
1 mole = 6.023 × 10²³ molecules
∴ 52.5 moles of C2H8 = (52.5 × 6.023 × 10²³) molecules
=3.1621 × 10²⁵ molecules
What is the PH of a solution with a concentration of 5.2 x 10-8 M H3O?
Answer:
7.28Explanation:
The pH of a solution can be found by using the formula
[tex]pH = - log [ { H_3O}^{+}][/tex]
From the question we have
[tex]ph = - log(5.2 \times {10}^{ - 8} ) \\ = 7.28399[/tex]
We have the final answer as
7.28Hope this helps you
What is the molar mass of a substance
A) the mass in grams of one mole of a substance
B) the number of particles in one gram of a substance
C) the number of moles in one gram of a substance
D) the mass in grams of one particle of a substance
thank you :)
Answer:
A) the mass in grams of one mole of a substance.
Explanation:
The molar mass of a substance is the mass in grams of 1 mole of the substance. As shown in this video, we can obtain a substance's molar mass by summing the molar masses of its component atoms. We can then use the calculated molar mass to convert between mass and number of moles of the substance.
How much energy would it take to freeze 12.5 g of water?
The amount of energy needed to freeze 12.5 grams of water into ice is equals to 14.295 kilo joules.
How do we calculate energy?Energy required to freeze water will be calculated by using the following equation as:
Q = mcT, where
m = mass of water = 12.5g = 0.0125kg
c = specific heat of water = 4.187 kJ/kg.K
T = temperature to freeze = 0 degree C = 273.15 K
On putting values we get,
Q = (0.0125)(4.187)(273.15)
Q = 14.295 kJ
Hence required amount of energy is 14.295 kJ.
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A gas mixture being used to simulate the atmosphere of another planet consists of 320 mg of methane, 175 mg of argon, and 225 mg of nitrogen. Th e partial pressure of nitrogen at 300 K is 15.2 kPa. Calculate (a) the volume and (b) the total pressure of the mixture.
Answer:
The total pressure is 61.4 kPa, and the volume is 1.31 L.
Explanation:
Based on the given information, a gas mixture comprising 320 mg or 0.320 grams of CH4, 175 mg or 0.175 grams of Ar, and 225 or 0.225 grams of N. The number of moles of the gases presents within the mixture can be determined by using the formula,
Number of moles = Mass/ molecular mass
The molecular mass of methane is 16.04 grams per mole, the molecular mass of Argon is 40 grams per mole, and the molecular mass of Nitrogen is 28.02 grams per mole.
Now, the number of moles of CH4 is,
= 0.320 grams/ 16.04 grams per mole
= 0.0199 moles
The number of moles of Ar is,
= 0.175 grams/40 grams per mole
= 0.0044 moles
The number of moles of N2 is,
= 0.225 grams/28.02 grams per mole
= 0.0080 moles
The partial pressure of nitrogen given is 15.2 kPa or 0.15 atm. Thus, the partial pressure of other two gases will be,
CH4 = (15.2 kPa) (0.0199 moles)/(0.0080 moles)
= 37.8 kPa
Ar = (15.2 kPa) (0.0044 moles)/(0.0080 moles)
= 8.36 kPa
Therefore, the total pressure is 15.2 + 37.8 + 8.36 = 61.4 kPa or 0.606 atm
The total volume can be determined by using the formula,
V = nRT/P
Here n is the total number of moles of the gas, which is 0.0323 moles.
Now putting the values we get,
V = (0.0323 moles) (0.0826 atm*L/mol*K)(300 K)/(0.606 atm)
V = 1.31 L
Use the following balanced equation to answer the questions below.
Would an electron in the 1s orbital of lithium require the same energy to move to a higher energy level as an electron in the
1s orbital of silver?
Answer:
See explanation
Explanation:
We must remember that the energy required to move an electron from the 1s orbital to a higher energy level depends on the size of the nuclear charge.
The higher the nuclear charge, the more closely held the 1s electron of the atom is to the nucleus and the more difficult it is to excite this electron.
Hence, it requires more energy to excite the 1s electron of silver having a larger size of nuclear charge than it is to excite a 1s electron in lithium.
A peanut was burned in a calorimeter filled with 70g of water. The temperature
increased from 21°C to 87°C. How much heat was released by the peanut. The
specific heat of water is 4.18 J/gºC *
Answer:
[tex]heat = mc \triangle \theta \\ = 70 \times 4.18 \times (87 - 21) \\ = 19311.6 \: joules[/tex]
A mixture containing nitrogen, hydrogen, and iodine established the following equilibrium at 400 °C:2NH3(g) + 3I2(g) ⇌ N2(g) + 6HI(g)Use the information below to calculate Kc for this reaction.N2(g)+3H2(g)⇌2NH3(g) Kc1= 0.50 at 400CH2(g)+I2(g)⇌2HI(g Kc2= 50 at 400°C
Answer: The value of [tex]K_{c}[/tex] for this reaction is 250000.
Explanation:
The given equation is as follows.
[tex]2NH_{3}(g) + 3I_{2}(g) \rightleftharpoons N_{2}(g) + 6HI(g)[/tex]
[tex]N_{2}(g) + 3H_{2}(g) \rightleftharpoons 2NH_{3}(g); K_{c_{1}} = 0.50[/tex] ... (1)
[tex]H_{2}(g) + I_{2}(g) \rightleftharpoons 2HI(g); K_{c_{2}} = 50[/tex] ... (2)
To balance the atoms, multiply equation (2) by 3. Hence, the equation (2) can be re-written as follows.
[tex]3H_{2}(g) + 3I_{2}(g) \rightleftharpoons 6HI(g); K_{c_{2}} = (50)^{3}[/tex] ... (3)
Now, subtract equation (1) from equation (3). So, the equation formed will be as follows.
[tex]3I_{2} - N_{2} \rightleftharpoons 6HI - 2NH_{3}[/tex]
This equation can also be re-written as follows.
[tex]3I_{2} + 2NH_{3} \rightleftharpoons N_{2} + 6HI[/tex]
This equation is similar to the equilibrium equation given to us.
Therefore, during this subtraction the equation constants get divided as follows.
[tex]K^{'}_{c} = \frac{K_{c_{2}}}{K_{c_{1}}}\\= \frac{(50)^{3}}{0.50}\\= 250000[/tex]
Thus, we can conclude that the value of [tex]K_{c}[/tex] for this reaction is 250000.
Give the definition for diffusion. Group of answer choices gas molecules mix equally average distance between collisions gas molecules escape from a container into a vacuum through a small hole gas molecules mix unequally gas molecules spread out in response to a concentration gradient Next
Answer:
gas molecules spread out in response to a concentration gradient.
Explanation:
Diffusion can be defined as the movement of gas molecules from a region of high concentration to a region of lower concentration until an equilibrium is attained or reached. This mixing of gas molecules in the liquid or gaseous state is due to their kinetic energy of random motion i.e without requiring bulk motion.
This ultimately implies that, diffusion is a phenomenon through which gas molecules in either a gaseous or liquid state spread out in response to a concentration gradient, which is simply the difference in concentration of the gases across a space.
In conclusion, increasing the surface area of a gas increases its collision rate and it's considered to be an evolutionary strategy that maximizes the diffusion of gas molecules by catalysing the rate of a gaseous reaction.
A 0.2264 g sample of a pure carbonate, XnCO3(s) , was dissolved in 50.0 mL of 0.1800 M HCl(aq) . The excess HCl(aq) was back titrated with 24.90 mL of 0.0980 M NaOH(aq) . How many moles of HCl react with the carbonate
Answer:
6.56x10⁻³ mol
Explanation:
First we calculate how many HCl moles are there in 50.0 mL of a 0.1800 M solution:
0.1800 M * 50.0 mL = 9.00 mmol HClThen we need to calculate how many HCl moles were in excess, that number is the same as the number of NaOH moles they reacted with:
0.0980 M * 24.90 mL = 2.44 mmol NaOH = 2.44 mmol HClFinally we calculate the difference between the original number of HCl moles and the number remaining after the reaction with XnCO₃:
9.00 mmol - 2.44 mmol = 6.56 mmol6.56 mmol / 1000 = 6.56x10⁻³ molEnter the molecular formula for butane, C4H10
Answer:
C4H10
Explanation:
you already written it :)
how do I name cycloalkanes?
Answer:
[tex]{ \tt{aromatic \: alkanes}} \\ \\ { \underline{ \blue{ \tt{becker⚜jnr}}}}[/tex]
1. Determine the number of sides of the cyclic compound.
2. Use IUPAC theory, determine the functional group and its position.
1. Make ___________________
Observe an event. State only what we can
________ or ____________.
2. Ask ___________________
Ask a question that helps us find out _______ and _______ the event happened. We must be
able to answer the question with ________, or ________. We may need to __________ our question several times before it is__________.
3. Construct a_____________________
State the answer we think we’ll get when we ask
our question. This is called a
_________________. It’s based on our best
understanding of the event.
4. Test the hypothesis with an
_______________________
Test whether the hypothesis is ___________.
During the investigation, we collect _______ that
answers the testable question we asked.
Answer:
Explanation:
ANCHOR ANCHOR ANCHOR ANCHOR
Metallic Bond
When nitrogen shares electrons with oxygen, what kind of bond is made?
Answer: covalent bonds
Explanation:
The solubility of CaSO4 in pure water at 0oC is 1.09 gram(s) per liter. The value of the solubility product is g
Answer: See image attached!
Good luck with your future exams!
The value of the solubility of product for CaSO₄ in pure water at 0 °C is 1.1881
What is solubility of product?The solubility of product (Ksp) is defined as the concentration of products raised to their coefficient coefficients. This is illustrated below:
mA <=> nC + eD
Ksp = [C]^n × [D]^e
With the above information in mind, we can obtain the solubility of the product. This is illustrated below:
Dissociation equationCaSO₄(aq) → Ca²⁺(aq) + SO₄²⁻(aq)
From the balanced equation above,
1 mole of CaSO₄ contains 1 mole of Ca²⁺ and 1 mole of SO₄²⁻
How to determine the concentration of Ca²⁺ and SO₄²⁻From the balanced equation above,
1 mole of CaSO₄ contains 1 mole of Ca²⁺ and 1 mole of SO₄²⁻
Therefore,
1.09 g/L of CaSO₄ will also contain
1.09 g/L of Ca²⁺1.09 g/L of SO₄²⁻ How to determine the solubility of product Concentration of Ca²⁺ = 1.09 g/L Concentration of SO₄²⁻ = 1.09 g/L Solubility of product (Ksp) =?CaSO₄(aq) → Ca²⁺(aq) + SO₄²⁻(aq)
Ksp = [Ca²⁺] × [SO₄²⁻]
Ksp = 1.09 × 1.09
Ksp = 1.1881
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If a small amount of a strong base is added to buffer made up of a weak acid, HA, and the sodium salt of its conjugate base, NaA, the pH of the buffer solution does not change appreciably because:__________
a. the K, of HA is changed.
b. No reaction occurs.
c. the strong base reacts with A to give HA, which is a weak acid.
d. the strong base reacts with HA to give AOH and H'.
e. the strong base reacts with HA to give A, which is a weak base,
Answer:
e. the strong base reacts with HA to give A, which is a weak base
Explanation:
Let's consider a buffer made up of a weak acid, HA, and the sodium salt of its conjugate base, NaA. The function is a buffer system is to muffle the change in the pH when an acid or a base is added.
Let's suppose a strong base is added. Then, OH⁻ would be more available. OH⁻ ions react with the acid component of the buffer and its effect is reduced. The corresponding reaction is:
OH⁻ + HA ⇄ A⁻ + H₂O
As we can see, the strong base reacts with HA to give A, which is a weak base.
he specific heat capacity of a pure substance can be found by dividing the heat needed to change the temperature of a sample of the substance by the mass of the sample and by the change in temperature. The heat capacity of a certain substance has been measured to be
Complete question is;
The specific heat capacity of a pure substance can be found by dividing the heat needed to change the temperature of a sample of the substance by the mass of the sample and by the change in temperature. The specific heat capacity of a certain substance has been measured to be 3.52 J/g°C. Suppose 420.0 g of the substance is heated until the temperature of the sample has changed by 43.8 °C.
Write an equation that will let you calculate the last Q that was needed for this temperature change. Your equation should contain only symbols. Be sure to define each symbol.
Answer:
Q = m•c•Δt
Q = 64753.92 J
Explanation:
We are given;
Mass (m) = 420 g
Change in temperature; (Δt) = 43.8 °C
Specific heat capacity (c) = 3.52 J/g °C
The last Q is simply the heat energy that caused that temperature change.
This is given by the formula;
Q = m•c•Δt
Plugging in the relevant values;
Q = 420 × 3.52 × 43.8
Q = 64753.92 J
Draw the structure of the major organic product isolated from the reaction of 3-hexyne with hydrogen (1 mol), Lindlar palladium.
Answer:
See explanation and image attached
Explanation:
When 1 mole of hydrogen is added to 3-hexyne, the addition occurs on the same face or side of the triple bond to yield cis-2-hexene in the presence of lindlar catalyst which prevents further hydrogenation. This is known as syn addition.
The syn addition is achieved because the hydrogen molecule is first adsorbed on the surface of the palladium metal and is subsequently attached to the same face of the triple bond in 3-hexyne as shown in the image attached to this answer.
34. Which type of reaction is represented by the
equation?
CH. + Biz - CH.Br + HB,
A suhstitution
C. esterification
D. polymerization
Answer:
Option A. Substitution
Explanation:
To know which option is correct, let us define each option. This is illustrated below:
A substitution reaction is a reaction in which an halogen replaces hydrogen in a hydrocarbon to produce alkyl halide and the corresponding acid. For example:
RH + X₂ –> RX + HX
NOTE:
R => is an alkyl group
X => is an halogen (F₂, Cl₂, Br₂ or I₂)
Addition reaction is a reaction in which two reactants combined to form a new compound without any loss of the reactants. This reaction is peculiar to only unsaturated hydrocarbon. For example:
CₓHᵧ + A₂ —> ACₓHᵧA
NOTE:
CₓHᵧ => unsaturated hydrocarbon (alkene, alkyne)
A₂ => halogen (F₂, Cl₂, Br₂ or I₂) or HBr, HCl etc
Esterification is a reaction involving carbonxylic and alcohol to produce ester and water. For example:
RCOOH + HOR —> RCOOR + H₂O
NOTE:
R => is an alkyl group
Polymerization is a process of reacting smaller molecules called monomers to form a larger molecule called polymer.
With the information provided above, we can see that the reaction:
CH₄ + Br₂ —> CH₃Br + HBr
Is a substitution reaction since Br replaces H in CH₄ to produce CH₃Br and the corresponding acid i.e HBr
Helppppp
What is the mass of 4.09 x 10^22 molecules of oxygen gas?
1.09 grams
7.69 x 1044 grams
2.17 grams
0.0679 gram
Answer:
[tex]2.17gO_2[/tex]
Explanation:
Hello there!
In this case, according to the given information, it turns out possible for us to calculate the mass of 4.09 x 10^22 molecules of oxygen gas by firstly keeping in mind that that 1 mole of it has a mass of 32.0 g and secondly that 1 mole of any substance contains 6.022x10^23 representative units, in this case, molecules of O2, and thus, the appropriate setup to perform this conversion is shown below:
[tex]4.09x10^{22}molecules \ O_2*\frac{1molO_2}{6.022x10^{23}molecules \ O_2}*\frac{32.0gO_2}{1molO_2} \\\\2.17gO_2[/tex]
Regards!
What’s the correct answer
Answer:
I think it's 2-methylhept-2-ene
Explanation:
Hope this will help and correct me if I'm wrong.
Write the reaction of maleic acid with Br2
If a light beam strikes a shiny object at a 90-degree angle, to what are the angle of incidence and the angle of reflection equal?
Answer:
Angle of incidence = angle of reflection = 0
Explanation:
Given that,
A light beam strikes a shiny object at a 90-degree angle.
The angle made by incident ray and normal to the mirror is called the angle of incidence and the angle made by the reflected ray and the normal is called the angle of reflection.
Here, the beam strikes normally. So, the angle of incidence is 0.
A/c to the law of reflection,
Angle of incidence = angle of reflection
So, the angle of reflection is also equal to 0.
calculate to e amount of ammonium chloride needed to produce 200L of hydrogen chloride (HCL) gas at 1.22atm and 573k. NH4Cl ➡️NH3+HCl
Answer:
277.8g of NH4Cl are needed
Explanation:
Based on the reaction, 1mol of NH4Cl reacts producing 1 mole of HCl. To solve this question we must find the moles of HCl using ideal gas law. These moles = Moles NH4Cl:
Moles HCl = Moles NH4Cl
PV = nRT; PV/RT = n
Where P is pressure = 1.22atm,
V is volume = 200L,
R is gas constant = 0.082atmL/molK
And T is absolute temperature = 573K
Replacing:
1.22atm*200L/0.082atmL/molK*573K = n
n = 5.193 moles HCl = Moles NH4Cl
Mass NH4Cl -Molar mass: 53.491g/mol-
5.193 moles * (53.491g / mol) =
277.8g of NH4Cl are neededHow many liters of water would you need to add to 4.36 moles of NaCl to create a 9.4 M solution?
Answer:
0.464 L
Explanation:
Molarity (M) = number moles (n) ÷ volume (V)
According to the information given in this question:
number of moles (n) = 4.36 moles
Molarity = 9.4M
Volume = ?
Using M = n/V
9.4 = 4.36/V
9.4V = 4.36
V = 4.36/9.4
V = 0.464 L
Hence, 0.464L of water are needed the volume of water.
what happens to the volume of a gas if the pressure and temperature doubled
Hi there! Answer is below :)
Explanation:
For this question, we apply Boyle's Law and Charles' Law.
When you double the amount of pressure and temperature of a compound or mixture, the volume will decrease by a half. So, if the pressure and temperature are 2, and the volume is 1, and you double, your volume will be 0.5 and your pressure and temperature will be 4.
Best of Luck!
Which type of macromolecule carries genetic information from parents to
their children?
A. Nucleic acids
B. Carbohydrates
C. Proteins
D. Lipids
Answer: Its A nucleic acids
Explanation:
Nucleic acids, and DNA in particular, are key macromolecules for the continuity of life. DNA bears the hereditary information that's passed on from parents to children, providing instructions for how (and when) to make the many proteins needed to build and maintain functioning cells, tissues, and organisms.
Nucleic acids carry genetic information from parents to their children.
What are Nucleic acids?Nucleic acids are biopolymers, macromolecules, essential to all known forms of life.[1] They are composed of nucleotides, which are the monomers made of three components: a 5-carbon sugar, a phosphate group and a nitrogenous base. The two main classes of nucleic acids are deoxyribonucleic acid (DNA) and ribonucleic acid (RNA). If the sugar is ribose, the polymer is RNA; if the sugar is the ribose derivative deoxyribose, the polymer is DNA.
Nucleic acids are naturally occurring chemical compounds that serve as the primary information-carrying molecules in cells and make up the genetic material. Nucleic acids are found in abundance in all living things, where they create, encode, and then store information of every living cell of every life-form on Earth. In turn, they function to transmit and express that information inside and outside the cell nucleus to the interior operations of the cell and ultimately to the next generation of each living organism. The encoded information is contained and conveyed via the nucleic acid sequence, which provides the 'ladder-step' ordering of nucleotides within the molecules of RNA and DNA. They play an especially important role in directing protein synthesis.
Learn more about Nucleic acids
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If 12.5 grams of Hydrogen and 5.14 grams of Oxygen react in a container what would be the excess leftovers? Thanks! :)
Answer:
Explanation:
The reaction is 2H2 + O2 -> 2 H2O
So the molar ratio of H2 and O2 is 2:1
No. of moles of H2 = 12.5/2 = 6.25
No. of moles of O2 = 5.14/32 =0.16
As 6.25 > 0.16*2 = 0.32
there will be H2 leftovers of 6.25-0.32 = 5.93 moles or 11.86 grams
Answer:
Explanation:
2 H2 + 1 O2 => 2 H2O
molecular wt of H2 = 2
molecular wt of O2 = 32
so wt of H2 : wt of O2 = 2x2 : 16 = 4 : 16 = 1 : 4
there are way more H2 as 12.5 > 5.14/4 = 1.285
H2 leftovers = 12.5 - 1.285 = 11.215 gram
HCl(aq) and KOH(aq) Express your answer as a balanced chemical equation. Identify all of the phases in your answer.
Answer:
HCl(aq) + KOH(aq)---------->KCl (aq)+ H2O(l)